Antonio wants to examine the sales in a restaurant during a period of time from 2 hours before to 2 hours after the peak dinner time and graph his results. If the peak dinner time is considered to be at 6 p.m., what would be the domain for the graph Antonio is creating?

Answer:

Step-by-step explanation:

She is missing 3. 235 plus 20 is 255 but the answer is 258 so she is missing 3

The value of x from the given equation is -1

Given the equation expressed as:

[tex]3(x - 10) - 5x = 2x - 26[/tex]

Expand using the distributive law as shown:

3x - 3(10) - 5x = 2x - 26

3x - 30 - 5x = 2x - 26

Collect the like terms to have:

3x - 5x - 2x = -26 + 30

-2x - 2x = -26 + 30

Simplify the result by addition and subtraction:

-4x = 4

Divide both sides by -4 (Division property of equality)

-4x/-4 = 4/-4

x = -1

Hence the value of x from the given equation is -1

Learn more equations here: https://brainly.com/question/22688504

Answer:

1) 9

2) 34

Step-by-step explanation:

For the first one, it would be

= (6×3)/2

= 18/2

= 9

The second one is,

= 36- (12/6)

= 36 - 2

= 34

Answer:

Part A - he will need 2 cups of sugar  

Part B - 12 : 6 : 3

Step-by-step explanation:

Part A :

8 divided by 4 is 2

Part B :

Multiply all the numbers by 3

Hope this helped! :)

Answer:

42 rats.

Step-by-step explanation:

since the ratio of mice to gerbils is 7:4, given that there are 32 gerbils, that means 32/4=8 gerbils; in other words, 56mice:32gerbils. Then, to find the # of rats, the ratio is 4:3, so you take the previous value of the # of mice and divide it by 4 to get 14(3)= 42

To understand this question, we need to know what it's asking and what's important and what is not important. Many people skip this step, but it is very important.

It is asking us to Find how many Rats there are.

This problem is defiantly reduced to the simplistic ratio

The next step is to Find clues

The clues are 32 Gerbils, 7:4 and 4:3

Now i like to make a chart but you may skip this step if you want

Gerbils=32

Mice=??

Rats=??

First, we have to find the numbers of Mice.

(Reducing Ratios divide them by a number like 2:4=1:2)

If you have 32 Gerbils and you reduced it to 4, what did you dived?

32/4=8

So, you multiply 7x8=56

There is 56 Mice.

Our table looks like this

Gerbils=32

Mice=56

Rats=??

Now we use the ratio 4:3 to find the numbers of Rats

If there are 56 mice, and it is reduced to 4, we have to do 56/4 to find out what we have to multiply 3 by to get the total numbers of rats (Inverse Operation) by. We get 14.

So now we do 3x14 in which we get 42.

Our chart now looks like this

Gerbils=32

Mice=56

Rats=42

I Hope this helped if you have any questions just tell me

Answer:

what ang hirap nmn anong grade ka na ba

Answer:

22.5 degrees

Step-by-step explanation:

Complementary angles add up to be 90 degrees. You can model the simple equation [tex]x+3x=90[/tex] where is x is the small angle and 3x is the large angle.

[tex]4x=90\\x=22.5[/tex]

the smaller angle is 22.5 degrees

Answer:

27

Step-by-step explanation:

Because OC biscts AOB, then COA=COB

Therefore AOB is twice COB

10x+4 = 2(6x-3)

10x+4 = 12x -6

2x = 10

x = 5

Therefore COA is 5x6-3 = 27

Answer:

9 degrees

Step-by-step explanation:

OK so we know that m<AOB is equal to the equation 10x+4. With this in mind, we also know that m<COB equals 6x-3. The ray OC intersects m<AOB, so this means that m<COB plus m<COA equals m<AOB.

First, we find m<COA by reversing the equation around to solve for m<COA.

m<AOB - m<COB = m<COA

Then, we Pug in the angles and solve.

m<AOB = 10x+4

m<COB = 6x-3

10x+4 - 6x-3 = 4x+1

Here is where things get interesting. See those 2 lines in each angle? That means they are equal in measure.

So what you do is simple, find what x equals in order to make this equation below true.

6x-3 = 4x+1

The answer for x is 2. So then just plug in to solve for m<COA and you're done!!

4(2)+1 =9

lil bonus: you can also get the same angle degree by plugging  2 into m<COB

Answer: The answer is C, 4 to the 21st over 5 to the 6th power.

#1

[tex]\\ \sf\hookrightarrow -5x+4=-1[/tex]

[tex]\\ \sf\hookrightarrow -5x=-5[/tex]

[tex]\\ \sf\hookrightarrow x=1[/tex]

Incorrect

#2

[tex]\\ \sf\hookrightarrow 4x-3=-7[/tex]

[tex]\\ \sf\hookrightarrow 4x=-4[/tex]

[tex]\\ \sf\hookrightarrow x=-1[/tex]

Correct

#3

[tex]\\ \sf\hookrightarrow 3y-4=5[/tex]

[tex]\\ \sf\hookrightarrow 3y=9[/tex]

[tex]\\ \sf\hookrightarrow y=3[/tex]

Ans not given

#4

[tex]\\ \sf\hookrightarrow -2y+7=12[/tex]

[tex]\\ \sf\hookrightarrow -2y=5[/tex]

[tex]\\ \sf\hookrightarrow y=-5/2[/tex]

Incorrect

#5

[tex]\\ \sf\hookrightarrow 3a-6=18-a[/tex]

[tex]\\ \sf\hookrightarrow 4a=24[/tex]

[tex]\\ \sf\hookrightarrow a=6[/tex]

Incorrect

#6

[tex]\\ \sf\hookrightarrow 5(2t-1)=2[/tex]

[tex]\\ \sf\hookrightarrow 10t=7[/tex]

[tex]\\ \sf\hookrightarrow t=7/10[/tex]

Incorrect

#7

[tex]\\ \sf\hookrightarrow ax-b=0[/tex]

[tex]\\ \sf\hookrightarrow x=\dfrac{b}{a}[/tex]

Correct

Done

Answer:

part A: median is 12

part B: interquartile rage is 10

Step-by-step explanation:

Part A: to find your median on a box and whisker plot, you just need to look at your middle line in your box. In this case it's 12.

Part B: to find your interquartile range on a box and whisker plot, you subtract your Q1 and Q3. Your Q1 and Q3 will be the two outside lines that make up the rest of your box, in this case would be 6 and 16. To find your Q1 if you don't already have your plot set up, you separate the numbers that are given to you in half and find the median of each side. The first half will be your Q1 and the second half your Q3.

Answer:

Oook, quick setup: pick a cartesian plane, be [tex](0;y(t))[/tex]the position of the helicopter as time passes, and [tex](x(t);0)[/tex] your position as you start running. In my horrible sketch, the green line is the distance when you start running, the red line is the distance you need,  in general what you want is to move one end of the segment up, the other right, and stretch it.

That distance is easily found with the formula for the distance between two points in the plane, or [tex]d=\sqrt{(\Delta x)^2+(\Delta y)^2}= \sqrt{x^2(t)+y^2(t)}[/tex] (playing a bit with the squares). At this point we need to write down expressions for both [tex]x(t), y(t)[/tex] and find at what value of t we need to evaluate our distance.

For the sake of semplicity, let's start measuring times the moment you start running. Since speed is constant, both expressions will be of the form [tex]s=vt+s_0[/tex]

The equation for the runner becomes simply [tex]x(t)=10t[/tex], since you haven't moved until the heli is high enough.

The equation of the helicopter is [tex]y=25t+30[/tex] since the heli is 30ft above ground when you start running.

Finally, we need to know how many seconds have passed when the heli is at 60 ft above ground. that happens when [tex]60=25t+30 \rightarrow t=\frac{30}{25} = 1.20s[/tex]. in this time, you are at  [tex]x(1.2)=10(1.2)=12ft[/tex] from the origin.

Plugging it in the distance formula you get: [tex]\sqrt{12^2+60^2}= \sqrt{144+3600}=4\sqrt {234}\approx 61.2ft[/tex]

Answer:

x=-10

Step-by-step explanation:

since there's a given 120 degrees, and it's a isosceles triangle, we know that the line adds up to 180 (where the 120 degrees is). so 120+x=180, the interior angle measures 60 degrees. That being said, the 3 angles measure 60 degrees also. now there's a right angle mark on top, so we find the angle of the smaller triangle (near angle 2) by doing 90-60=30 degrees.

angle 2 is said to be x+160, and there's a line, which tells us that they must add to 180.. so x+160+30=180

x+190=180

x=-10.

Answer:

-270,810

Step-by-step explanation:

c.r.  r=-30/-10=3

[tex]a_{n} =a_{1}r^{n-1} \\a_{4}=-10(3)^{4-1}\\=-10(3)^3=-10 \times 27=-270\\a_{5}=-10 \times(3)^{5-1}\\=10 \times3^4\\=-810[/tex]

Answer:

a- (1,1) (3,4) (9,7)

Hope you could get an idea from here.

Doubt clarification - use comment section.

Answer: x=-1, y=-8

Step-by-step explanation: solve for the first variable in one of the equations then subsitutte the result into the other equation

The inequality which represents the constraints of the range is D. p(m) ≥ -875

Since the PTA was doing fundraiser and bought 500 megaphones to sell for the pep rally, and the profit, p, from the sale of megaphones can be represented by p(m) = 3.5m - 875 where m = number of megaphones sold.

To find the inequalities represents the constraints of the range of p(m), we need to know the domain of m.

Since we have 500 megaphones and we can sell from 0 to 500 inclusive. So, the domain of m is 0 ≤ m ≤ 500.

To determine the range of p(m), we insert the values of m at its extreme points into p(m).

So, when m = 0

p(m) = 3.5m - 875

p(0) = 3.5(0) - 875

p(0) = 0 - 875

p(0) = -875

when m = 500

p(m) = 3.5m - 875

p(500) = 3.5(500) - 875

p(500) = 1750 - 875

p(500) = 875

Since for a profit, m ≥ 0. So, p(m) ≥ p(0) = -875

So, p(m) ≥ -875

So, the inequality which represents the constraints of the range is D. p(m) ≥ -875

Learn more about inequalities here:

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Answer:

8 • 54=8 • 50 + 8 • 4

Option C is the right answer

Step-by-step explanation:

Answer:

C I think, sorry if I'm wrong

Answer:

two negitives equals a positive so C none of the above

Hope This Helps!!!

Answer:

A and B

Step-by-step explanation:

Answer:

#1 matches with the pizza scenario

#2 matches with the present scenario

#3 matches with the Sarah scenario

Step-by-step explanation:

Look for keywords at the end of the questions and if they go hand and hand (such as in 7 hours / yield 20 servings) then they go together as a pair

Given :-

To Find :-

Solution :-

The given triangle is a right isosceles triangle . So here we can use the Pythagoras theorem as ,

[tex]\longrightarrow[/tex] hypotenuse² = perpendicular ² + base²

[tex]\longrightarrow[/tex] x² = 4² + 4²

[tex]\longrightarrow[/tex] x² = 16 + 16

[tex]\longrightarrow[/tex] x² = 32

[tex]\longrightarrow[/tex] x = √32

[tex]\longrightarrow[/tex] x = √2⁵

[tex]\longrightarrow[/tex] x = 4 × 1.732

[tex]\longrightarrow[/tex] x = 6.928 ≈ 7

Answer:

1) 1584.72

2) 4811.2

3) 2381.721

4) 1672.376

5) 3901.59

Step-by-step explanation:

Answer:

A, D, G, H

Step-by-step explanation:

Look at the pink(or purple) lines. R and F both have 4 lines, so they're congruent. S and G both have 1 line, so those are congruent too.

-hope it helps

Answer:

1st option: ∠S ≅ ∠G

4th option: ∠T ≅ ∠H

7th option: ∠Q ≅ ∠E

8th option: ∠R ≅ ∠F

Step-by-step explanation:

Side lengths are unnecessary you just look at those loop things. Angles with the same number of "loops" are congruent like how ∠Q and ∠E both have 3 "loops", this means those angles are congruent.

Answer:2

Step-by-step explanation:

x+3=5

subtract 3 from both sides

x=5-3

x=2

Answer:

x=    2

Step-by-step explanation:

[tex] \rm \frac{19}{12} - \frac{3}{4} = \frac{9}{12} - \frac{9}{12} = \frac{9 - 9}{12} = \frac{0}{12} = \bf0 \: \: (done.)[/tex]

Answer:

[tex]\frac{19}{12} - \frac{3}{4}=\frac{5}{6}[/tex]

Step-by-step explanation:

[tex] \frac{19}{12} - \frac{3}{4} [/tex]

[tex] = \frac{19 \times 4}{12 \times 4} - \frac{3 \times 12}{4 \times 12}[/tex]

[tex] = \frac{76}{48} - \frac{36}{48} [/tex]

[tex] = \frac{76 - 36}{48}[/tex]

[tex]= \frac{40}{48} [/tex]

[tex] = \frac{40 \div 8}{48 \div 8} [/tex]

[tex] = \frac{5}{6}[/tex]

The car overtakes the cyclist at a distance of 72 miles from the starting point.

,Speed is the ratio of distance travelled to time taken. It is given by:

Speed = distance / time

Let the car overtake the cyclist at distance d and time t.

For the car:

48 = d / t

d = 48t

For the cyclist:

16 = d / (t + 3)

d = 16t + 48

48t = 16t + 48

32t = 48

t = 1.5 hours

d = 48(1.5) = 72 miles

The car overtakes the cyclist at a distance of 72 miles from the starting point.

Find out more on speed at: https://brainly.com/question/3004254

Answer:

9) 21

10) 70

11) 34

12) 31

13) 50

14) 31

15) 137

16) 101

Step-by-step explanation:

9)

20+40=60

60 + b =180 ( sum of the interior angles on a triangle is 180 )

b = 180 - 60

b = 120

39 + c + ? = 180 ( sum of the interior angles on a triangle is 180 ) c =120 ( vertically opposite angles are equal )

39 + 120 + ? = 180

159 + ? = 180

? = 180 - 159

? = 21

________________________________________________________________________________________

10)

60 + 65 + b = 180 ( sum of the interior angles on a triangle is 180 )

125 + b = 180

b = 180 - 125

b = 55

50 + b + c = 180 ( sum of the angels on a straight line is 180 )

50 + 55 + c = 180

105 + c = 180

c = 180 - 105

c = 75

35 + c + ? = 180

35 + 75 + ? = 180

110 + ? = 180

? = 180 - 110

? = 70

________________________________________________________________________________________

11)

84 + 36 + b = 180 ( sum of the interior angles on a triangle is 180 )

120 + b = 180

b = 180 - 120

b = 60

86 + b + ? = 180 ( sum of the interior angles on a triangle is 180 )

86 + 60 + ? = 180

146 + ? = 180

? = 180 - 146

? = 34

________________________________________________________________________________________

12)

35 + 23 + b = 180 ( sum of the interior angles on a triangle is 180 )

58 + b = 180

b = 180 - 58

b = 122

27 + c + ? = 180 ( sum of the interior angles on a triangle is 180 ) c =122 ( vertically opposite angles are equal )

27 + 122 + ? = 180

149 + ? = 180

? = 180 - 149

? =31

________________________________________________________________________________________

13)

115 + b = 180 ( sum of the angels on a straight line is 180 )

b = 180 - 115

b = 65

65 + 90 + c = 180 ( sum of the angels on a straight line is 180 )

155 + c = 180

c = 180 - 155

c = 25

155 + d = 180 ( sum of the angels on a straight line is 180 )

d = 180 - 155

d = 25

c + d + e = 180 ( sum of the interior angles on a triangle is 180 )

25 + 25 + e = 180

50 + e = 180

e = 180 - 50

e = 130

e + ? = 180 ( sum of the angels on a straight line is 180 )

130 + ? = 180

? = 180 - 130

? = 50

________________________________________________________________________________________

14)

35 + 20 + b = 180 ( sum of the interior angles on a triangle is 180 )

55 + b = 180

b = 180 - 55

b = 125

156 + c = 180 ( sum of the angels on a straight line is 180 )

c = 180 - 156

c = 24

c + e + ? = 180 ( sum of the interior angles on a triangle is 180 ) e= 125 ( vertically opposite angles are equal )

24 + 125 + ? = 180

149 + ? = 180

? = 180 - 149

? = 31

________________________________________________________________________________________

15)

b = 45 ( vertically opposite angles are equal )

b + 60 + c = 180 ( sum of the interior angles on a triangle is 180 )

45 + 60 + c = 180

105 + c = 180

c = 180 - 105

c = 75

68 + 75 + e = 180 ( sum of the angels on a straight line is 180 )

143 + e = 180

e = 180 - 143

e = 37

100 + 37 + j = 180 ( sum of the interior angles on a triangle is 180 )

137 + j = 180

j = 180 - 137

j = 43

j + ? = 180 ( sum of the angels on a straight line is 180 )

43 + ? = 180

? = 180 - 43

? = 137

________________________________________________________________________________________

16)

b = 75 ( vertically opposite angles are equal )

c = 45 ( vertically opposite angles are equal )

b + c + e = 180 ( sum of the interior angles on a triangle is 180 )

75 + 45 + e = 180

120 + e = 180

e = 180 - 120

e = 60

e + 79 + j = 180 ( sum of the angels on a straight line is 180 )

60 + 79 + j = 180

139 + j = 180

j = 180 - 139

j = 41

j + 60 + s = 180 ( sum of the interior angles on a triangle is 180 )

41 + 60 + s = 180

101 + s = 180

s = 180 - 101

s = 79

s + ? = 180 ( sum of the angels on a straight line is 180 )

79 + ? = 180

? = 180 - 79

? = 101

________________________________________________________________________________________

hope this helps☆☆☆

it took soooo long to do btw ⊙•⊙

[tex]f(x) = ab^x~\hfill \begin{array}{llll}\textit{we know that}~f(0)=-4\begin{cases}x=0\\f(x)=-4\end{cases}\\\\-4=ab^0\implies -4=a(1)\implies -4=a\end{array}\\\\\\\stackrel{therefore}{f(x)=-4b^x}~\hfill \textit{we also know that}~f(-2)=-64\begin{cases}x=-2\\f(x)=-64\end{cases}[/tex]

[tex]-64=-4b^{-2}\implies \cfrac{-64}{-4}=b^{-2}\implies 16=b^{-2}\implies 16=\cfrac{1}{b^2} \\\\\\ b^2=\cfrac{1}{16}\implies b=\sqrt{\cfrac{1}{16}}\implies b = \cfrac{\sqrt{1}}{\sqrt{16}}\implies b = \cfrac{1}{4} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill f(x)=-4\left( \frac{1}{4} \right)^x~\hfill[/tex]