Apply the zero product property to solve the equation below:
x (x + 2) = 0

Answer:

The square root of 10 is expressed as √10 in the radical form and as (10)½ or (10)0.5 in the exponent form. The square root of 10 rounded up to 10 decimal places is 3.1622776602

Step-by-step explanation:

hope this is correct

Answer:

The length of side j is 11.85cm

Step-by-step explanation:

Given that

In triangle JKL,

Side k=LJ=3.7cm

To find side j=KL:

By using sine rule,

We can write as

Using property of triangle,

Thus,

The length of side j is 11.85cm

Answer:

5

Step-by-step explanation:

4+2=6

30 berrys so you do 30/6=5

Check the picture below.

so then γ ≈ 180 - 69 - 43, γ ≈ 68.

Answer:

width(w)= 20inches

Step-by-step explanation:

solution,

given,

perimeter of a rectangle (P)=68inches

length of rectangle= 14 inches

we know,

perimeter of a rectangle=2L + 2W

or,68=2×14+2×w

or,68-28=2w

or,40=2w

or,w=40÷2

or,w=20inches.

We have:   2log₃(8) - 3log₃(2) = 2log₃(8) - log₃(2³)

= 2log₃(8) - log₃(8) =  log₃(8)

= 1,892789261 ≈ 1,9

ok done. Thank to me :>

Answer:

~1.8928 or 3log_3 (2)

Step-by-step explanation:

change 8 to 2^3 and move to front

=2*3log_3 (2) -3log_3 (2)

=6log_3 (2) -3log_3 (2)

with subtraction

=3log_3 (2)

approx with calculator

~1.8928

Answer:

so where does that line intersect the y axis? just plug in x=0 and you see y= -1. so (0, -1)

y = -x -1 is parallel because it has the same slope and goes through the right point

slope:change in x\change in y

Answer: bro I don’t if this is correct but try 11+3i

Answer:

[tex]Fourth \: option: y^2=9^2+19^2-2(9)(19) cos(41°)[/tex]

[tex]The \: law \: of \: cosines \: to \: solve \: for \: one \: side  \: is:[/tex]

[tex]c^2=a^2+b^2-2ab \: cos \: C[/tex]

We must know the other two sides (a and b) and the angle between these sides (angle C, the opposite to the side that we want to determine)

In this case c=y, a=9, b=19, and C=41°, then:

[tex]y^2=9^2+19^2-2(9)(19) \: cos \: (41°)[/tex]

Answer:

it correct because i took this before

Answer:it's a for sure I think

Answer:

  SAS similarity

Step-by-step explanation:

You have two side ratios and the angle between the sides with those ratios. The appropriate similarity theorem is SAS.

Answer:

rthrthrt

Step-by-step explanation:

Answer:

559

Step-by-step explanation:

The equation has the same solution as w / 3.9 = 3 is w+0.6=1.9

Given:

w / 3.9 = 3

cross multiply

w × 3 = 3.9

3w = 3.9

divide both sides by 3

w = 3.9 / 3

w = 1.3

Check all that applies

A. w+0.6=1.9

w = 1.9 - 0.6

w = 1.3

B. w-0.6 = 11.1

w = 11.1 + 0.6

w = 11.7

C. w+1.03=2.93

w = 2.93 - 1.03

w = 1.9

D. w-1.03=8.24

w = 8.24 + 1.03

w = 9.27

Therefore, the equation has the same solution as w / 3.9 = 3 is w+0.6=1.9

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Explanation:

A buying incentive is anything that encourages any potential customers to become actual customers. Ideally, those people are repeat customers down the road as well (even if such buying incentives are no longer in place).

If someone sees a coupon or a rebate, then they'll be more likely to buy the item since the price is lower. A coupon is an immediate discount right on the spot, whereas a rebate is when you get a discount later on. A rebate means you have to mail in proof of purchase, and the company will send money back. These are two ways to apply a discount.

A third way to entice customers is to offer prizes. An example of this is a "buy one get one" sale (often abbreviated as BOGO). The company may lose money doing this, but they do so in the hopes of gaining new customers. Plus word of mouth tends to spread more often when such sales occur.

With everything discussed so far, this allows us to rule out choices A, C and D. They are all some kind of way to encourage potential buyers. Choice B is the answer because a display simply shows the price and any other relevant info to the product. Displays are neutral in the sense that they don't encourage a purchase and rather just convey information. When I mention this, I'm not talking about displays that advertise discounts or coupons.

Answer:

Yes Jeff is the correct answer

Step-by-step explanation:

Answer:

$225

Step-by-step explanation:

$120 for 2 4-hour shifts, $120 in 8 hours

$15 every 1 hour

Money for 15 hours: 15 x 15 = $225

The office clerk earns $225 for 15 hour of work .

The formula of the unitary method is to find the value of a single unit and then multiply the value of a single unit to the number of units to get the necessary value.

According to the question

An office clerk earns $120 for two 4-hour work shifts.

i.e

In 2 * 4-hour work shifts office clerk  earns = $120

or

In 8 hour work shifts office clerk earns = $120

Now ,

By using unitary method

In 1 hour  work shifts office clerk earns = $[tex]\frac{120}{8}[/tex]

                                                                = $15

Therefore, for 15 hours of work shifts office clerk earns =  $15 * 15

                                                                                          = $225

Hence, The office clerk earns $225 for 15 hour of work .

To know more about unitary method here:

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Answer:

  a.  39 ft²

  c. 2x² +11x +12

  e. 35 yd²

Step-by-step explanation:

The missing vertical dimension is 5-3 = 2'. The missing horizontal dimension is 11-8 = 3'. Then the figure can be decomposed into a rectangle 11'×3' and one that is 3'×2'. The sum of those areas is ...

  total area = (11 ft)(3 ft) +(3 ft)(2 f) = (3 ft)(11 +2 ft) = (3 ft)(13 ft) = 39 ft²

__

We don't know what to make of the rectangles in each corner, so we'll assume they are distorted right-angle indicators. The area is the product of the dimensions shown:

  A = LW

  A = (2x +3)(x +4) = 2x² +11x +12 . . . area of figure

__

The shaded area is half the area of the rectangle. That is the same area you get if you use the triangle formula for the area of the shaded triangle.

  A = 1/2(14 yd)(5 yd) = 35 yd²

Answer:

the length of the rectangle is 13 ft.

Step-by-step explanation:

width of a rectangle x ft

length of a rectangle x+6 ft

the perimeter of the rectangle is 40 ft,

2(x+x+6) = 40

2x+6 = 20

2x = 14

x = 7

So the length of the rectangle is x+6 = 7+6 = 13 ft

congrats you're right (≧▽≦)!!

Answer:

The correct answer ia A)13 ft

Step-by-step explanation:

hope this helps

Answer:

y=5/4x -7

Step-by-step explanation:

Hope this helps!

is 1.25 because you just add them together

Check the picture below.

there are a few angles shaded, I'll call that angle at O ∡O, and that angle at "x" ∡x and the green angle at A, ∡A, and the angle at B, ∡B, just so you know which angle we're referring to.

well, first off let's notice that B and C are points of tangency, meaning we get right-angles as you see in the picture, if we run an angle bisector from ∡x, towards point O, we get two congruent triangles, lemme shorten that up some, 90 + 90 + ∡O +∡x = 360, which means that ∡O + ∡x = 180,  meaning that ∡O = 180 - ∡x, if that's so, the angle at point O across the shade, is 360 - ∡O or 360 - (180 - ∡x).

alrighty, by the inscribed angle theorem, ∡A is half of ∡O.

let's now focus on the triangle AOB, we'll be using half of ∡A and half of ∡O and ∡B on that triangle, let's proceed.

[tex]\measuredangle x + \measuredangle O=180\implies \measuredangle O=180-\measuredangle x \\\\\\ \measuredangle A = \cfrac{\measuredangle O}{2}\implies \measuredangle A = \cfrac{180-\measuredangle x}{2} \\\\\\ \stackrel{\textit{the angle across from }\measuredangle O~is}{360-\measuredangle O}\implies 360-(180 - \measuredangle x)\implies 180+\measuredangle x \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{\textit{\large the sum of all three angles at }\triangle AOB}{\stackrel{\textit{half of }\measuredangle A}{\cfrac{1}{2}\cdot \cfrac{180-\measuredangle x}{2}}~~ + ~~\stackrel{\textit{half the angle across from }\measuredangle O}{\cfrac{180+\measuredangle x}{2}}~~ +~~\measuredangle B~~ =~~180} \\\\\\ \cfrac{180-\measuredangle x}{4}+\cfrac{180+\measuredangle x}{2}+\measuredangle B = 180[/tex]

now, let's multiply both sides by the LCD of all denominators, hmmmm in this case that'll be 4, so multiplying both sides by the LCD will do away with the denominators, so let's do so.

[tex]4\left( \cfrac{180-\measuredangle x}{4}+\cfrac{180+\measuredangle x}{2}+\measuredangle B \right) = 4(180) \\\\\\ (180-\measuredangle x)+2(180+\measuredangle x)+4\measuredangle B = 720 \\\\\\ (180-\measuredangle x)+(360+2\measuredangle x)+4\measuredangle B = 720\implies 540+\measuredangle x+4\measuredangle B = 720[/tex]

[tex]\measuredangle x+4\measuredangle B = 180\implies 4\measuredangle B = 180-\measuredangle x\implies \measuredangle B = \cfrac{180-\measuredangle x}{4} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \measuredangle B = 45 - \cfrac{\measuredangle x}{4}~\hfill[/tex]