Assuming a current is flowing, what increases the strength of the magnetic field of a coiled electrical wire? Select all that apply. Straightening the wire changing the direction of the current flow adding more coils to the wire placing a metal bar within the coils stopping the current.

Answer:

1kW = 1000W

600W = 0.6kW

Cost of electric bill = 0.6kWh × 24 × 30 × $0.05

                               = $21.60

The relation of the kinetic energy allows to find the correct result for the energy stored in the electromagnet is:

B) 283 MJ

Kinetic energy is the energy due to the movement of bodies.

          K = ½ m v²

Where K is the kinetic energy, m is  the mass and v the spped.

They indicate that the weight of the bodye is W = 981 N and its final velocity is v = 7 [tex]v_s[/tex].

          W = m g

Since the projectile starts from rest, its initial velocity is zero, therefore the change in energy is

        ΔK = [tex]K_f - K_o = K_f[/tex]  

we substitute

        ΔK = ½ 981 / 9.8 (7 340) ²

         ΔK = 2.835 10⁸ J

They indicate that all the energy of the electromagnet is transformed into the energy of the projectile,

          Em = K

When reviewing the results, the correct one is:

       B) 283 MJ

In conclusion, using the relationship of kinetic energy we can find the correct result for the energy stored in the electromagnet is:

   B)  283 MJ

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Answer:

Morphology and phylogenetics revealed by fossils. Perhaps the strongest evidence to support the Cambrian evolutionary explosion of animal forms is the first clear appearance, in the Early Cambrian, of skeletal fossils representing members of many marine bilaterian animal phyla

Answer:

Die Antwort lautet: Weniger Umweltverschmutzung als Kraftwerke mit fossilen Brennstoffen

Explanation:

hoffe das hat geholfen!! :))

Answer:

Changes to regional landscapes

Explanation:

It would be D because this is a cost or drawback and geothermal energy production would cause changes to the landscape, unlike how fossil fuels would.  I also got this right on the quiz.

Hope this helps!

Answer:

4.80 mol N2O5/min

Explanation:

The balanced equation tells us that 2 moles of N2O5 are required for every 1 mole of O2.  Therefore:

(2.40 mol O2/min)*(2 mol N2O5/mol O2) = 4.80 mol N2O5/min

Answer:

the slope of velocity-time graph represent an object acceleration

Answer:

Forces come in pairs.

Explanation:

Distances are between two points. The distance from A to B is equal but opposite the distance from B to A.

To Find The Acceleration of  A Car Slowing Down:

The change in speed is the final speed minus the initial speed. To find acceleration, divide the change in velocity by the length of time during which the velocity changed.

Average velocity is defined as the ratio in change in position to change in time,

v[ave] = ∆x/∆t

which on its own doesn't have anything to do with acceleration.

If acceleration is constant, the average velocity is the literal average of the initial and final velocities,

v[ave] = (v[final] + v[initial]) / 2

If this constant acceleration has magnitude a, the final velocity can be expressed in terms of the initial velocity by

v[final] = v[initial] + a*t

and plugging this into the previous equation gives

v[ave] = (v[initial] + a*t + v[initial])/2

v[ave] = v[initial] + 1/2*a*t

If the body in consideration is initially at rest, then

v[ave] = 1/2*a*t

which might be the relation you're looking for. But bear in mind the conditions I've underlined.

If acceleration is not constant and changes over time, so that the acceleration is some function of time a(t), then you can determine the velocity function v(t) by using the fundamental theorem of calculus. You need to know a particular velocity for some time to completely characterize v(t), though. For example, if you're given the initial velocity v[initial] = v(0), then

[tex]\displaystyle v(t) = v(0) + \int_0^t a(u) \, du[/tex]

or if you know any other velocity for some time t₀ > 0,

[tex]\displaystyle v(t) = v(t_0) + \int_{t_0}^t a(u) \, du[/tex]

By Newton's second law, the net force acting on the block in the vertical direction is

∑ F [ver] = n - mg = 0

where n = magnitude of normal force and mg = weight of the block. It follows that n = mg.

When the block is at rest, the applied force X will not be enough to move the box until it can overcome the maximum mag. of static friction. If µ[s] is the coefficient of static friction, then the maximum mag. of the frictional force is

f = µ[s] n = µ[s] mg

The net horizontal force would be

∑ F [hor] = X - µ[s] mg = 0

so a minimum force of X = µ[s] mg is required to get the block moving. Any mag. smaller than this and the block stays at rest/in equilibrium.

Once the mag. of X exceeds µ[s] mg, the block will begin to move. At that point, if the coefficient of kinetic friction is µ[k], then the net force on the block is

∑ F [hor] = X - µ[k] mg = 0

so a minimum force of X = µ[k] mg would be needed to keep the block moving at constant speed, or otherwise X = µ[k] mg + ma if the block is accelerating with mag. a.

The principles here are captured in the attached plot.

Using Newton's second law

[tex]\\ \sf\Rrightarrow F=ma[/tex]

[tex]\\ \sf\Rrightarrow 300=2m[/tex]

[tex]\\ \sf\Rrightarrow m=150kg[/tex]

Hey there!

The formula of “mass” in physics is:

m = F/a

Whereas “f” is ‘force’, “a” is ‘acceleration’, & “m” is your ‘mass’ of course.

mass = 300 Net force/2 acceleration

300 Net force/2 acceleration = m

mass = 150

Therefore, your answer is: 150 kg

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

Answer:

Vertebrate zoology

Explanation:

Have a great day!

Answer:

Approximately [tex]5.11 \times 10^{-19}\; {\rm J}[/tex].

Explanation:

Since the result needs to be accurate to three significant figures, keep at least four significant figures in the calculations.

Look up the Rydberg constant for hydrogen: [tex]R_{\text{H}} \approx 1.0968\times 10^{7}\; {\rm m^{-1}[/tex].

Look up the speed of light in vacuum: [tex]c \approx 2.9979 \times 10^{8}\; {\rm m \cdot s^{-1}}[/tex].

Look up Planck's constant: [tex]h \approx 6.6261 \times 10^{-34}\; {\rm J \cdot s}[/tex].

Apply the Rydberg formula to find the wavelength [tex]\lambda[/tex] (in vacuum) of the photon in question:

[tex]\begin{aligned}\frac{1}{\lambda} &= R_{\text{H}} \, \left(\frac{1}{{n_{1}}^{2}} - \frac{1}{{n_{2}}^{2}}\right)\end{aligned}[/tex].

The frequency of that photon would be:

[tex]\begin{aligned}f &= \frac{c}{\lambda}\end{aligned}[/tex].

Combine this expression with the Rydberg formula to find the frequency of this photon:

[tex]\begin{aligned}f &= \frac{c}{\lambda} \\ &= c\, \left(\frac{1}{\lambda}\right) \\ &= c\, \left(R_{\text{H}}\, \left(\frac{1}{{n_{1}}^{2}} - \frac{1}{{n_{2}}^{2}}\right)\right) \\ &\approx (2.9979 \times 10^{8}\; {\rm m \cdot s^{-1}}) \\ &\quad \times (1.0968 \times 10^{7}\; {\rm m^{-1}}) \times \left(\frac{1}{2^{2}} - \frac{1}{8^{2}}\right)\\ &\approx 7.7065 \times 10^{14}\; {\rm s^{-1}} \end{aligned}[/tex].

Apply the Einstein-Planck equation to find the energy of this photon:

[tex]\begin{aligned}E &= h\, f \\ &\approx (6.6261 \times 10^{-34}\; {\rm J \cdot s}) \times (7.7065 \times 10^{14}\; {\rm s^{-1}) \\ &\approx 5.11 \times 10^{-19}\; {\rm J}\end{aligned}[/tex].

(Rounded to three significant figures.)

Hi there!

We can use the same equation for Gravitational Force:

[tex]\large\boxed{F_g = G\frac{m_1m_2}{r^2}}[/tex]

Fg = force due to gravity (N)

G = gravitational constant

m1,m2 = masses of objects (kg)

r = distance between objects (m)

Plug in the values provided:

[tex]F_g = (6.67*10^{-11})\frac{(2500)(3000)}{8^2} = \large\boxed{7.814 * 10^{-6}N }[/tex]

[tex]\huge\bf\underline{\underline{\pink{A}\orange{N}\blue{S}\green{W}\red{E}\purple{R:-}}}[/tex]

Here we've been given,

We have to find the gravitational attraction force (Fg) = ?

The standard formula to solve is given by,

[tex]:\implies\tt{F_g = g \frac{m_1m_2}{ {r}^{2} } } [/tex]

[tex]:\implies\tt{F_g = 6.67 \times {10}^{ - 11} \times \frac{(2500 )(3000)}{ {8}^{2} } }[/tex]

[tex]:\implies\tt{F_g = 6.67 \times {10}^{ - 11} \times \frac{7500000}{64} }[/tex]

[tex]:\implies\tt{F_g = 7.814 \times {10}^{ - 6} }[/tex]

Answer:

hottest plant: vensus, close to the sun

coldest plant: Neptune, farthest from the sun

Explanation:

Answer:

i can

Explanation:

i know what's the answer

Answer:

2,500g is the answer yes

Answer:

You should try your best to answer the question.

Newton's second law.

__________________

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The impulse-momentum relationship is a direct result of Newton's second law of motion.

The impulse-momentum theorem states that the impulse applied to an object is equal to the change in its momentum. It proves that the change in momentum of an object depends not only on the amount of force applied but also on the duration of force applied.

Newton's second law states that the force acting on an object is equal to the rate of change of its momentum.

This means that a force applied to an object will cause a change in its momentum. The impulse-momentum relationship describes the relationship between the force applied to an object and the resulting change in its momentum.

The impulse-momentum relationship states that the impulse acting on an object is equal to the change in its momentum.

Impulse is defined as the force applied to an object over a period of time, while momentum is the product of an object's mass and velocity. Therefore, the impulse-momentum relationship can be expressed as:

Impulse = Change in momentum

This relationship is important in understanding the behavior of objects in motion, particularly in collisions or other situations where forces act over a period of time.

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Answer:

Give person above me brainliest

Explanation:

Answer: 300N

Explanation:

Impulse= Mass * Velocity

F.T = M * V

F= MV/T

F= (0.15*20)/ 0.01

F= 300N

Answer:

D. a plane landing on an aircraft carrier

E. rain sticking to a window

F. two train cars coupling together

Explanation:

Explanation:

hope it's useful for you knows

The magnitude of the magnetic field 0.01 m from the same wire is 0.2 T.

Given to us:

Magnetic field, [tex]B_1 = 0.1\ T[/tex]

Radius of wire, [tex]R_1 = 0.02\ m[/tex]

To find out the magnitude of the magnetic field 0. 01 m from the same wire, we need to find out current first. we will use the formula,

[tex]B = \dfrac{\mu_oI }{2\pi R},\\\rn\\where,\\B= magnetic\ field\\\mu_o = 4\pi\times 10^{-7} m\cdot kg\cdot s^{-2} A^{-2}\ is\ the\ magnetic\ constant\\I= current\\R= radius\ of\ the\ wire[/tex]

Putting the values,

[tex]B_1 = \dfrac{\mu_oI }{2\pi R_1},\\\rn\\\\0.1= \dfrac{4\times \pi \times 10^{-7}\times I}{2\times \pi\times0.02}\\\\I=10,000\ A[/tex]

Now, for [tex]B_2[/tex]

[tex]B_2 = \dfrac{\mu_oI }{2\pi R_2},\\\rn\\\\B_2= \dfrac{4\times \pi \times 10^{-7}\times 10,000}{2\times \pi\times0.01}\\\\B_2= 0.2\ T[/tex]

Hence, the magnitude of the magnetic field 0. 01 m from the same wire is 0.2 T.

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Answer:

potential energy = mgh = 300 × 10 × 6m = 18000 joule or 18 kilo joule.

Explanation:

Answer:

mountains are limited in their theoretical height by several processes. First is isostasy: the bigger a mountain gets, the more it weighs down its tectonic plate, so it sinks lower. ... Bottom line: mountains can get taller than Mount Everest in earth gravity, like the Appalachians probably did—but not much taller.

Answer:

It probably won't get any taller, though. From a geological standpoint, the Appalachians haven't seen much growth in quite a while. Since the dawn of the dinosaurs about 225 million years ago, this range has been getting whittled down by weathering forces.

Explanation:

Answer:

he was a random act like you to be the first time I see is a great day and night to get a very happy to see you soon I hope that the world is not the same thing to say about this

a) When a box slides across a rough surface, eventually coming to rest, its kinetic energy is used during work done against frictional resistance force.

b) This work done is stored in the box as a potential energy. Thus the motion of the box is consistent with the Law of Conservation of Energy.

According to the work-energy theorem, the work done by the net force acting on a body equals the change in kinetic energy.

It can simply be written as:

Work done = initial kinetic energy - final kinetic energy

The work energy theorem equation is the one presented above.

Now when a box slides across a rough surface, eventually coming to rest, frictional force comes into play. This force is opposite to the direction of motion of the box. Hence, the kinetic energy of the box is used during work done against frictional resistance force and stored in the box as a potential energy and thus  Law of Conservation of Energy followed.

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Answer:

0.1g to 0.0000001g hope it helps uu