Billy throws a peach vertically upward. It takes 3 seconds for the peach to land back in his hand. How fast did Billy throw the peach?

Answers

Answer 1

Answer:

  48 ft/s

Explanation:

Acceleration due to gravity decreased the upward velocity to zero in 1.5 seconds (half the total time), so the initial velocity must have been ...

  (32 ft/s^2)(1.5 s) = 48 ft/s


Related Questions

A physical property is a characteristic of a substance that can be observed or measured without changing the identity of the substance. Physical properties include color, density, hardness, and melting and boiling points. A chemical property describes the ability of a substance to undergo a specific chemical change.

Answers

Answer:

True

Explanation:

The main differences between a physical property and a chemical property are mentioned below:

A physical property is a characteristic of a substance that can be observed or measured without changing the identity of the substance. Physical properties include color, density, hardness, and melting and boiling points.

While A chemical property describes the ability of a substance to undergo a specific chemical change.

Radioisotopes often emit one or more types of radiation, including alpha particles, beta particles, and gamma rays. The distance the radiation travels through matter before being absorbed increases in order from alpha to gamma. Which statement describes the best radioisotope that can be used for radioisotope imaging and for radionuclide therapy?

It emits only gamma rays.
It emits only alpha particles.
It emits alpha and beta particles.
It emits beta particles and gamma rays.

Answers

Answer:

The most correct option is the last option

Explanation:

During radioisotope/nuclear imaging in diagnosis, the radioisotope must emit gamma rays from within the body. However, in the case of radionuclide therapy, most radionuclides emit beta particles while some others also emit gamma rays.

Answer:

D

Explanation:

HELP ASAP!! WILL TRY TO GIVE BRAINLIEST

Outline the cell cycle

Answers

Answer:

The cell cycle has four stages: during the first three, the cell is in interphase, and in the last one, the cell is dividing itself. Also, there is a resting stage when the cell is not preparing itself for the division.

G0: the cell is not in the cell cycle. It is resting and not preparing itself for the division.

G1: the cell grows and synthesizes proteins and other elements that the cell will need for the next stage.

S: In this phase, which is called Synthesis, the cell synthesizes the DNA.

G2: the cell continues to grow. It synthesizes more proteins, RNA, and other elements that it will need for mitosis.

Mitosis: the division of the cell takes place, and as a result, there are two daughter cells. This phase has four stages, prophase, metaphase, anaphase, and telophase.

Explanation:

The cell cycle has four stages. Each of them has a role in the division of the cell. The first one is Gap 1 or G1, then the Synthesis or S phase follows, after S, Gap 2 takes place, and finally, Mitosis.

We can divide the cell cycle into two big groups: interphase, which includes G1, S, and G2, and the changes that the cell suffer can not be appreciated. The other group is the One where the cell division happens, and it includes Mitosis.

G0 is not part of the cell cycle. It is a state where the cell doe not prepares itself for the division. It is resting.

The negatively charged particle in an atom is a(n):

Answers

Answer: Electron

Explanation:A negatively charged particle found circling or orbiting an atomic nucleus. An electron, like a proton is a charged particle, although opposite in sign, but unlike a proton, an electron has negligible atomic mass. Electrons contribute no atomic mass units to the total atomic weight of an atom.

Hope this helps!!Brainlist?

Bernoulli's principle is responsible for most of the lift produced by an airplane wing.
True
False

Answers

Answer:

huiiiiuuu beautiful...

A grinding wheel, initially at rest, is ro-tated with constant angular acceleration of2.52 rad/s2for 7.03 s. The wheel is thenbrought to rest with uniform deceleration in11.9 rev.Find the angular acceleration required tobring the wheel to rest. Note that an in-crease in angular velocity is consistent with apositive angular acceleration.Answer in units of rad/s2.

Answers

Starting from rest, the wheel accelerates to an angular velocity of

ω = (2.52 rad/s²) (7.03 s) ≈ 17.7 rad/s

then undergoes a new acceleration α until it comes to a rest. It does so in 11.9 revolutions, or with an angular displacement of (11.9 rev) • (2π rad/rev) = 23.8π rad. So α satisfies

0² - ω² = 2 α (23.8π rad)

α = - ω² / (47.6π rad)

α ≈ -2.10 rad/s²

The accepted equations for force and elastic potential energy for a spring include a term called the spring constant, k (in N/m). How could you find the spring constant from a force vs displacement graph? Explain.

Answers

Explanation:

Accordibg to Hooke's law ,

F=-kx

the minus sign indicates that the force exerted by the spring is opposite to that of extension and the relation between force and extension is a linear one so in the graph it wll pass through the origin and x=0 F=0 and the k (spring constant) will be a constant

  URGENT )If you drive your 1,000 kg car from sea level up to the mountain, which is 366 m above sea level, how much will you have increased your car's potential energy?(consider : g=10m/s2)

1 point

a) 366,000 J

b) 3,660,000 J

c) 2.73 J

d) 20.73 J​

Answers

Answer:

(B) the increase in the car's potential energy is 3,660,000 J

Explanation:

Given;

mass of the car, m = 1,000 kg

height through the car was drove, h = 366 m

acceleration due to gravity, g = 10 m/s²

The increase in the car's potential energy is calculated as;

P.E = mgh

P.E = 1000 x 10 x 366

P.E = 3,660,000 J

Therefore, the increase in the car's potential energy is 3,660,000 J

The (nonconservative) force propelling a 1.50 103-kg car up a mountain road does 5.10 106 J of work on the car. The car starts from rest at sea level and has a speed of 24.0 m/s at an altitude of 2.20 102 m above sea level. Obtain the work done on the car by the combined forces of friction and air resistance, both of which are nonconservative forces.

Answers

We know, Work done by all the forces is equal to change in potential energy :

[tex]W_{friction} + W_{air} + W_{engine} = \dfrac{(mv_f^2 + mgh_f)}{2}-\dfrac{(mv_i^2+mgh_i)}{2}[/tex]

Here,

[tex]h_i=0\ m\\\\v_i = 0\ m/s[/tex]

Putting all given values, we get :

[tex]W_{friction} + W_{air} + 5.10\times 10^6 = m\dfrac{(v_f^2 + gh_f)}{2}-0\\\\W_{friction} + W_{air} =1.5\times 10^3 \times \dfrac{(24^2 + (9.8\times 2.2\times 10^2))}{2}-5.10\times 10^6\\\\W_{friction} + W_{air} = -3.051\times 10^6\ J[/tex]

Hence, this is the required solution.

Why does the Sun appear white at noon?​

Answers

In the noon because the sun is overhead, there is least amount of scattering and hence appears white. When it is overhead, it has lesser air to travel through and scattering results from dust and other particles which will be reduced if the distance to be traveled in air is reduced.

What is string theory? Need answer in own word​

Answers

Answer:

When point particals are replaced by string like particals

Explanation:

Why would the solstice be important to
an ecosystem?

Answers

Answer:

marks an important milestone. It's the shortest day of the year and the longest night of the year, and signals a powerful transition point between seasons that is impossible to ignore. ... In Pagan times the winter solstice was referred to as Yule and was a celebration of the Goddess (Moon) energy

Explanation:

4) Bunny pushes on Monkey to the right with a 95N force while Deer pushes on Monkey Tom Lee
with a 75N force. Monkey weighs
50N.

Answers

Answer:

-30N to the left

Explanation:

Step one:

Given data

the mass of the monkey is 50N

Step two:

Required is the net force acting on the monkey

Now to the right Bunny is applying 95N,

Deer pushes on Monkey Tom Lee

with a 75N the net force acting on the monkey to move it is

= 95-50-75= -30N to the left

the other user said:

-30N to the left

You have a cup full of water and a bathtub full of water. Both samples of water have a temperature of 30°C. Which sample has greater amount of heat?

Answers

Answer:

 temperature is -10

Explanation:

What is the acceleration of a car initially traveling at -5m/s and
reaching -22m/s in 3s.

Answers

Answer:

[tex]a=-5.67\ m/s^2[/tex]

Explanation:

Given that,

Initial velocity, u = -5 m/s

Final velocity, v = -22 m/s

Time, t = 3s

We need to find the acceleration of the car. The formula of it is given by :

Acceleration,

[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{(-22)-(-5)}{3}\\\\a=-5.67\ m/s^2[/tex]

So, the acceleration of the car is [tex]-5.67\ m/s^2[/tex].

help!!!! please!!! i’m not sure what the answer is for both questions please

Answers

Answer:

a.) 600N

b.) 2 m/s^2

Explanation:

a.)

In order to solve for the needed force, you must use Newton's 2nd law which states that a force is equal to mass multiplied by acceleration.

Basically: Force = mass * acceleration ; F = ma

Since both mass and acceleration are already given, just plug them into the formula and solve for force:

Mass = 200kg

Acceleration = 3m/s^2

F = m * a = 200 * 3 = 600kg * m/s^2 = 600N

b.)

In order to find the acceleration, like the hint already says, you need to find the net force first and then use Newton's 2nd law.

To calculate net force:

Since both forces are parallel (affect the same axis) and in opposite directions, you can subtract the two in order to find resultant magnitude. The resultant direction is the direction of the force with the large magnitude.

Net Force: 8N - 4N = 4N

Net Force Direction: since 8N > 4N, the direction is in the same direciton as the 8N force = Left

Finally, you find acceleration using newton's 2nd law, F = ma.

Since you already know mass and net force, plug in to solve for acceleration:

4N = 2kg * a

a = 4 N / 2kg = 2m/s^2

Two go-carts, A and B, race each other around a 1.0 track. Go-cart A travels at a constant speed of 20.0 /. Go-cart B accelerates uniformly from rest at a rate of 0.333 / ଶ . Which go-cart wins the race and by how much time?

Answers

Complete Question

Q. Two go-carts, A and B, race each other around a 1.0km track. Go-cart A travels at a constant speed of 20m/s. Go-cart B accelerates uniformly from rest at a rate of 0.333m/s^2. Which go-cart wins the race and by how much time?

Answer:

Go-cart A is faster

Explanation:

From the question we are told that

       The length of the track is [tex]l = 1.0 \ km = 1000 \ m[/tex]

       The speed of  A is  [tex]v__{A}} = 20 \ m/s[/tex]

       The uniform acceleration of  B is  [tex]a__{B}} = 0.333 \ m/s^2[/tex]

  Generally the time taken by go-cart  A is mathematically represented as

              [tex]t__{A}} = \frac{l}{v__{A}}}[/tex]

=>          [tex]t__{A}} = \frac{1000}{20}[/tex]

=>           [tex]t__{A}} = 50 \ s[/tex]

  Generally from kinematic equation we can evaluate the time taken by go-cart B as

             [tex]l = ut__{B}} + \frac{1}{2} a__{B}} * t__{B}}^2[/tex]

given that go-cart B starts from rest  u =  0 m/s

So

            [tex]1000 = 0 *t__{B}} + \frac{1}{2} * 0.333 * t__{B}}^2[/tex]

=>         [tex]1000 = 0 *t__{B}} + \frac{1}{2} 0.333 * t__{B}}^2[/tex]            

=>         [tex]t__{B}} = 77.5 \ seconds[/tex]  

 

Comparing  [tex]t__{A}} \ and \ t__{B}}[/tex]  we see that [tex]t__{A}}[/tex] is smaller so go-cart A is  faster

   

       

I am traveling at 100 m/s, I hit the brakes and my speed goes down to 50 m/s. It took 30 seconds to slow down. What was my acceleration?

A.5 m/s2
B.-5 m/s2
C.1.7 m/s2
D.-1.7 m/s2

Answers

Answer:

D. -1.7m/s2

Explanation:

the car starts at 100m/s so this is the initial velocity. It ends at 50m/s so this is the final velocity. it took 30 seconds so the time is 30.

[tex]v_{f}=v_{i}+at[/tex]

[tex]a=\frac{\left(v_{f}-v_{i}\right)}{t}[/tex]

[tex]a=\ \frac{\left(50-100\right)}{30}[/tex]

[tex]a=-1.66666666667[/tex][tex]m/s^{2}[/tex]

Therefore, the answer is D

We only see objects because they absorb light.
True or False?

Answers

Answer:

true

Explanation:

i think it's true because I took a quiz on this

In Space, an astronaut releases a wrench from his hand. The wrench has a mass of 4 grams and is traveling with a velocity of -15m/s. The Astronaut’s mass is 70kg. What is his Velocity?

Answers

Answer:

The velocity of the astronaut is approximately 0.0008571 m/s

Explanation:

The mass of the the wrench, m₁ = 4 grams = 0.004 kg

The velocity of the wrench, v₁ = -15 m/s

The mass of the astronaut, m₂ = 70 kg

The velocity of the astronaut = v₂

Whereby the astronaut and the wrench were initially at rest, we have;

The total initial momentum = 0 kg·m/s

The total final momentum = m₁ × v₁ + m₂ × v₂ = 0.004 kg × (-15 m/s) + 70 kg × v₂

By the conservation of momentum principle, we have;

The total initial momentum = The total final momentum

Therefore, we have;

0 kg·m/s = 0.004 kg × (-15 m/s) + 70 kg × v₂

Which gives;

0.004 kg × (-15 m/s) = 70 kg × v₂

70 kg × -v₂ = 0.004 kg × (-15 m/s)

-v₂ = 0.004 kg × (-15 m/s)/(70 kg) ≈ -0.0008571 m/s

-v₂ ≈ -0.0008571 m/s

v₂ ≈ 0.0008571 m/s

The velocity of the astronaut = v₂ ≈ 0.0008571 m/s

An icicle falls off of a skyscraper from rest and falls for 34 seconds. How fast will that icicle be moving after that time? Show all work and units. (a = g = 9.81 m/s^2) *

Answers

Answer:

The icicle will be moving at 333.54 m/s

Explanation:

Free Fall Motion

A free-falling object falls under the sole influence of gravity. Any object that is being acted upon only by the force of gravity is said to be in a state of free fall. Free-falling objects do not encounter air resistance.

If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is [tex]g = 9.81 m/s^2[/tex].

The final velocity of a free-falling object after a time t is given by:

vf=g.t

The icicle falls from rest for 34 seconds. We need to find the speed after that time:

vf = 9.81*34

vf = 333.54 m/s

The icicle will be moving at 333.54 m/s

If an object is resting on a surface it "crunches" the atoms underneath it. According to Newton's Third Law the surface pushes back on the object. What is the name given to this force that acts perpendicular to the surface?

Answers

Answer:

Normal force

Explanation:

Normal force is the force that surfaces employ so that solid objects are disallowed from passing through each other.

HELP ASAP!!!! WILL TRY TO GIVE BRAINLIEST!

Identify the structure that separates the nuclear contents from the cytoplasm.

Answers

Answer:nuclear membrane

Explanation:

Answer:

Nuclear envelope. Hope this helps.

A 2.0 kg block is released from rest at the top of a curved incline in the shape of a quarter of a circle of radius R = 3.0 m. The block then slides onto a horizontal plane where it finally comes to rest a distance D from the beginning of the plane. The curved incline is frictionless, but there is a coefficient of friction, μ = 0.5, on the horizontal plane. Determine the velocity of the box at maximum kinetic energy

Answers

The block has maximum kinetic energy at the bottom of the curved incline. Since its radius is 3.0 m, this is also the block's starting height. Find the block's potential energy PE :

PE = m g h

PE = (2.0 kg) (9.8 m/s²) (3.0 m)

PE = 58.8 J

Energy is conserved throughout the block's descent, so that PE at the top of the curve is equal to kinetic energy KE at the bottom. Solve for the velocity v :

PE = KE

58.8 J = 1/2 m v ²

117.6 J = (2.0 kg) v ²

v = √((117.6 J) / (2.0 kg))

v ≈ 7.668 m/s ≈ 7.7 m/s

The velocity of the block at maximum kinetic energy is 7.668 m/s.

From  potential energy formula,

PE = m g h

Where,

m = mass = 2 kg

g -gravitational acceleration = 9.8 m/s²

h - height = 3 m

Put the values in the formula,

PE = (2.0 kg) (9.8 m/s²) (3.0 m)  

PE = 58.8 J

Since,  

PE = KE

Thus,

58.8 J = 1/2 m v ²  

117.6 J = (2.0 kg) v ²  

v = √((117.6 J) / (2.0 kg))  

v = 7.668 m/s

Therefore, the velocity of the block at maximum kinetic energy is 7.668 m/s.

To know more about  potential energy

https://brainly.com/question/21288807

1 point
Which will hit the ground first, if both objects are dropped from the same
height at the same time IN AIR?*
O an icicle
O a snow flake
O both hit the ground at the same time

Answers

Answer:

an icicle

Explanation:

and icicle has less air resistance compared to that of a snow flake

WILL GIVE BRAINLIEST
Lila is a track and field athlete. She has to complete four laps around the track, which is 400 meters. The race took her 6 minutes to complete. What is her average speed to the first decimal point in m/s?

Answers

Answer:

4.44m/s

 

Explanation:

Given parameters:

Number of laps  = 4

Length of track  = 400m

Time taken  = 6min

Unknown:

Average speed  = ?

Solution:

The average speed is the total distance covered divided by the time taken.

It is mathematically expressed as;

  Average speed  = [tex]\frac{total distance}{time taken}[/tex]  

Total distance  = number of laps x length of track  = 4 x 400  = 1600m

Now convert the time to seconds;

         60s  = 1 min

             6 minutes will be 6 x 60 = 360s

So;

  Average speed  = [tex]\frac{1600}{360}[/tex]  = 4.44m/s

 

The sun shines equally on both hemispheres during the summer and winter solstices.

True
False

Answers

False it says that he shines equally during the equinox

1.
A car is moving in a circle or radius r = 25 meters, in a parking lot at 10 m/s. What is the car's
centripetal acceleration?

Answers

A :-) a = v^2 by r
Given - radius = 25 m
velocity = 10 m/s
Solution -
a = v^2 by r
a = ( 10 )^2 by 25
a = 100 by 25
( cut 25 and 100 because 25 x 4 = 100 )
a = 4 m/s^2

.:. The centripetal acceleration of the car
= 4 m/s^2.

how does a plane mirror work

Answers

Answer:

Plane mirrors work because the light rays create a virtual image behind the mirror. Light rays from the object strike the mirror and reflect according to the law of reflection. ... Therefore, our eye and brain track the light rays backward to a position from which they appear to have come.

Mr. Davis is riding his bike at a speed of 5 meters per second for 3600 seconds how far did he ride?

Answers

Answer:18,000 meters

Explanation:3600x5=18,000.

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