4.
Mental Math Write the ratio
7
to 10 as a fraction in simplest form.
The ratio in simplest form is
(Type the ratio as a simplified fractional

Answer:

B

Step-by-step explanation:

20x^2 - 12x - 8

4 ( 5x^2 - 3x - 2 )

5 * - 2 = - 10

Factors of - 10

1 , - 10

10, - 1

2, - 5

5, - 2

5x^2 - 5x + 2x - 2

5x (x - 1)  2 (x - 1)

4 (x - 1) (5x + 2)

(4x - 4) (5x + 2)

Answer:

A. is the correct answer.

Step-by-step explanation:

Answer:

h

Step-by-step explanation:

Answer:

The answer is 8

Step-by-step explanation:

Answer:

wheres the graph if u show me the graph ill be glad to help u

Step-by-step explanation:

Answer:

A circle graph

Step-by-step explanation:

This only applies if the question means a pie chart when it says "circle graph".

Answer:

1. y= 1/3x+2

2.y=-3/4x-5

Step-by-step explanation:

Answer:

H. Reflection over the x-axis.

Hope that helps!

Answer:

.92

Step-by-step explanation:

multiplication

Answer:

The supplementary angle is 137.11.

Step-by-step explanation:

180-42.89 = 137.11

Hope this helps!

Answer:

B. 4.73 and 4.97

Step-by-step explanation:

To solve this question, we need to understand the Empirical Rule and the Central Limit Theorem.

Empirical Rule:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Standard deviation of 0.92, sample of 500:

This means that [tex]\sigma = 0.92, n = 500, s = \frac{0.92}{\sqrt{500}} = 0.04[/tex]

By the central limit theorem, which interval do 99.7% of the sample means fall within?

Within 3 standard deviations of the mean. So

4.85 - 3*0.04 = 4.85 - 0.12 = 4.73

4.85 + 3*0.04 = 4.85 + 0.12 = 4.97

So, option B.

Answer:

4.73 and 4.97

Please give me brainliest, I really need it.

Answer:

may be...

P(for green)= 3/20

P(for black)=4 /20

Answer:

yes get that one 0.78.10

Step-by-step explanation:

Answer:

sorry no idea

Step-by-step explanation:

Answer:

252 Cake Cones

Step-by-step explanation:

You have to make your own formula with the numbers in the problem. Here's how I set it up:

w= number of waffle cones

c=number of cake cones

We know that the number of waffle cones is the number of cake cones plus 50, so we write that out here: w=c+50

And we know that the sales total was $1422.50. That is, the number of waffle cones times the cost per cone plus the number of cake cone times their cost per cone, and we can write that out here: (3.25× w) + (1.75×c) =1,422.50.

Now, we can substitute our first formula into the second formula to solve for  C. The new equation reads: 3.25(c+50) + 1.75c=1,422.50

Distribute 3.25 to c and 50: 3.25c +162.50+1.75c=1,422.50

Combine like terms: 5c +162.50=1422.50

Subtract 162.50 from both sides: 5c=1260

Divide both sides by 5: C=252

TO CHECK YOUR WORK

Now that you have solved for C, plug that figure back into the first equation to solve for w: (252)+50=w, W=302

Now plug both numbers into your equation for the total cost:

3.25(302) + 1.75(252)=1,422.50

981.5+441= 1,422.50

You're done!

Answer:

iyou tell me

Step-by-step explanation:

Answer:

96.25

Steps:

35 × 275 / 100 = 9625 / 100 = 96.25

Answer:

2(4x-3) + 6(3y-5)

X=5 and y=7

2(4(5)-3) + 6(3(7)-5)

2(20-3) + 6(21-5)

2(17) + 6(16)

34 + 96

130

Step-by-step explanation:

Answer:the number is negative

Step-by-step explanation:

The true statement about Joe's number is that it will be a negative number. It will be less than zero. the correct option is A.

Expression in maths is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

The only way to get a number greater than the one you started with is to get the opposite of a negative number because positive numbers are always greater than negative ones.

Therefore, the true statement about Joe's number is that it will be a negative number.

To know more about Expression follow

brainly.com/question/723406

#SPJ2

Answer:

increasing sequence of +7

Step-by-step explanation:

please mark brainiest

please give 5 stars

thank you

Answer:

Option A and D will be your answer

Step-by-step explanation:

hope it helps

Answer:

73

Step-by-step explanation:

Answer:

73

Step-by-step explanation:

Answer:

The answer is 3

Step-by-step explanation:

if the other side is 10 then 2x+4 should be 10

2*3+4=10

Answer:

63.62

Step-by-step explanation:

pie X r^2

Answer:

0.7823 = 78.23% probability that the response time is between 3 and 9 minutes.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 7.2 minutes and a standard deviation of 2.1 minutes.

This means that [tex]\mu = 7.2, \sigma = 2.1[/tex]

For a randomly received emergency call, find the probability that the response time is between 3 and 9 minutes.

This is the pvalue of Z when X = 9 subtracted by the pvalue of Z when X = 3.

X = 9

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{9 - 7.2}{2.1}[/tex]

[tex]Z = 0.86[/tex]

[tex]Z = 0.86[/tex] has a pvalue of 0.8051

X = 3

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{3 - 7.2}{2.1}[/tex]

[tex]Z = -2[/tex]

[tex]Z = -2[/tex] has a pvalue of 0.0228

0.8051 - 0.0228 = 0.7823

0.7823 = 78.23% probability that the response time is between 3 and 9 minutes.

Answer:

The probability that a given lot will violate this guarantee is [tex]1 - e^{-200x}[/tex], in which x is the probability of a resistor being defective.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

In which

x is the number of sucesses

e = 2.71828 is the Euler number

[tex]\mu[/tex] is the mean in the given interval.

The probability of a resistor’s being defective is x:

This means that [tex]\mu = nx[/tex], in which n is the number of resistors.

The resistors are sold in lots of 200

This means that [tex]n = 200[/tex], so [tex]\mu = 200x[/tex]

What is the probability that a given lot will violate this guarantee?

This is:

[tex]P(X \geq 1) = 1 - P(X = 0)[/tex]

In which

[tex]P(X = 0) = \frac{e^{-200x}*(200x)^{0}}{(0)!} = e^{-200x}[/tex]

So

[tex]P(X \geq 1) = 1 - e^{-200x}[/tex]

The probability that a given lot will violate this guarantee is [tex]1 - e^{-200x}[/tex], in which x is the probability of a resistor being defective.

Answer:

There are 1.6875,  2/3's in 9/8

Step-by-step explanation:

To figure this out you would take 9/8 and divide it by 2/3.

(9/8)/(2/3)=1.6875

Answer:

bq XK

Step-by-step explanation:

                             nnnnnnnnnnn

Answer is in the file below

tinyurl.com/wpazsebu

cool can i have brainliest

Answer: nice the answer is ummmm I don’t know

Step-by-step explanation:

Answer:

A) The null hypothesis is H₀; [tex]\overline x_1[/tex] = [tex]\overline x_2[/tex]

The alternative hypothesis is Hₐ; [tex]\overline x_1[/tex] ≠ [tex]\overline x_2[/tex]

B) The critical value is 4.604

C) The pooled variance is 11,870.2777

D) The standard error is-0.2321

E) The obtained is -0.2040  

Step-by-step explanation:

The given values are;

[tex]\overline x_1[/tex] = 23.76, [tex]\overline x_2[/tex] = 34.54

s₁ = 123.43, s₂ = 105.65

n₁ = 5, n₂ = 20

A) The null hypothesis, H₀; [tex]\overline x_1[/tex] = [tex]\overline x_2[/tex]

The alternative hypothesis, Hₐ; [tex]\overline x_1[/tex] ≠ [tex]\overline x_2[/tex]

B) The degrees of freedom, df = 4 - 1 = 3

The critical t-value is given at α = 0.01 is given on the t-table for two tailed test as t = 4.604

C) The pooled variance is given by the following formula;

[tex]S_P^2 = \dfrac{(n_1 - 1) \cdot s_1^2 + (n_2-1) \cdot s_2^2}{n_1 + n_2 - 2 }[/tex]

Plugging in the values gives;

[tex]S_P^2 = \dfrac{(5 - 1) \cdot 123.43^2 + (20-1) \cdot 105.65^2}{5+ 20 - 2 } = 11,870.2777[/tex]

The pooled variance, [tex]s_p^2[/tex] = 11,870.2777

D) The standard error, SE, is given as follows;

[tex]t=\dfrac{(\bar x_{1}-\bar x_{2})}{\sqrt{\dfrac{s_{1}^{2} }{n_{1}}-\dfrac{s _{2}^{2}}{n_{2}}}}[/tex]

Therefore, we get;

[tex]t=\dfrac{(23.76-35.34)}{\sqrt{\dfrac{123.43^{2} }{5}-\dfrac{105.65^{2}}{20}}} = -0.2321[/tex]

The standard error, SE ≈ -0.2321

E) The obtained 't' is given as follows;

[tex]\sigma _{\overline x_1 - \overline x_2} = \sqrt{\dfrac{s_1^2}{n_1-1} +\dfrac{s_2^2}{n_2-1} }[/tex]

Therefore, we have;

[tex]\sigma _{\overline x_1 - \overline x_2} = \sqrt{\dfrac{123.43^2}{5-1} +\dfrac{105.65^2}{20-1} } \approx 56.7564[/tex]

The obtained t is given as follows;

[tex]t(Obtained)=\dfrac{(\bar x_{1}-\bar x_{2})}{\sigma _{\overline x_1 - \overline x_2} }[/tex]

Therefore, we get;

[tex]t(Obtained)=\dfrac{(23.76-34.54)}{56.7564} \approx -0.2040[/tex]

The obtained t = -0.2040

Answer:

Answered and explained below

Step-by-step explanation:

A) We are told that frequency of the trait is still 1 in 8. Thus, population proportion; p = 1/8 = 0.125

Sample size; n = 150

Formula for mean is;

μ = np

μ = 150 × 0.125

μ = 18.75

Formula for standard deviation is;

σ = √(np(1 - p))

σ = √(150 × 0.125(1 - 0.125))

σ = √16.40625

σ = 4.05

B) usually, when np ≥ 10 , we make use of normal distribution.

I'm this case, it is 18.75 which is greater than 10.

Thus,we can use a normal model to approximate the distribution.

C) we are told that he found the trait in 22 of the frogs.

Thus;

Proportion is now; 22/150 = 0.1467

This is a higher probability that the initial one of 0.125 and we can say that the trait has become more common.