Answer:
Q= ms∆T
Where, m is mass of substance
S is specific heat
∆T is temperature change
As in question , m=8.21 ,s=0.13 ,∆T =6.2
So, Q = 8.21×0.13×6.2=6.61 J
How many theoretical plates produce a chromatography peak eluting at 12.83 min with a width at half-height of 8.7 s
The density of crystalline cl2 at 160K is 2.02g/cm3. calculate the molar volumes
The molar volume (Vm) is the volume occupied by one mole of a chemical element or chemical compound at standard temperature and pressure (STP). The molar volume of Cl₂ is 35.10 cm³/mol.
One mole of any gas has a defined volume when it is at a particular temperature and pressure. The relationship between molar mass and molar volume is direct and inverse, respectively.
Two gases have equal molecules if their volumes are the same at a given temperature and pressure. A gas's volume is directly proportional to the number of moles it contains. One mole of any gas takes up 22.4 L of space at STP.
The expression used to calculate molar volume is:
Molar volume = Molar mass / Density
The molar mass of Cl₂ = 70.906 g/mol
Molar volume = 70.906 / 2.02
Molar volume = 35.10 cm³/mol
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pa help po science po
Answer:
1. molecule, cell, tissue, organ, organ system, organism, population, community, ecosystem, biosphere
2. A
3. D
4. C
5. C
6. C
7. C
8. B
9. Sorry I don't know :(
10. B
11. A
12. C
13. Sorry :((
14. C
15. a
16. d
Sorry I don't know the rest.. I hope this helps though!!
I need the skeleton equation for the following sentence!
Carbon dioxide gas and solid calcium oxide are produced in the decomposition of solid calcium carbonate.
Answer:
A. CaCO(s)+SO(g)+O(g) --> CaSO(s)+CO(g)
A. CaCO(s)+SO(g)+O(g) --> CaSO(s)+CO(g)
Consider a box divided in half. One side is filled with 1 mol Ne at 300. Kelvin, and the other is filled with 1 mol Rn at 300. Kelvin. A small hole is opened in the divider between the sides, allowing the gases to mix. Suppose it takes 4.0 minutes for the Rn pressure to equilibrate between the two sides. How long (min) will it take the Ne pressure to equilibrate? Enter your answer to 1 decimal place.
It will take the Ne gas approximately 1.2 s to equilibrate between the two sides.
We know that the time taken for a gas to diffuse is dependent on the molar mass of the gas. This is one of the interpretations of Graham's law of diffusion in gases. Thus, Let;
t1 = time taken for Rn to equilibrate = 4.0 s
t2 = time taken for Ne to equilibrate = ?
M1 = molar mass of Rn = 222g/mol
M2 = molar mass of Ne = 20 g/mol
Using
t1/t2 = √M1/M2
4/t2 = √222/20
4/t2 = 3.33
t2 = 4/3.33
t2 = 1.2 seconds
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What does Bromine-80 decays by beta decay to?
Answer:
beta to Kr-80 or Se-80
Explanation:
sorry if wrong
Nitrogen H2 has :
a)Double bonds
b)Bounded by 6 electrons
c) The bond is ionic
d) Can forms der Waals bonds
e) B& d
Answer:
the bond is ionic
Explanation:
Heart, 5 stars, Brainiest, and 40 coins if right! Answer needed ASAP
Which statement describes what happens when Bret runs up a flight of stairs?
A. His kinetic energy is destroyed.
B. His potential energy decreases.
C. His kinetic energy is converted into potential energy.
D. His potential energy is converted into kinetic energy.
Answer:
His kinetic energy is converted into potential energy.
Explanation:
Why was the war in Peru difficult?
Answer:
in contrast, peru and Bolivia entered the war hindered by numerous domestic fractures and by an economic and insititutional backwardness that nearly prevented the two countries from fighting the war at all
What is the required mass to prepare a 0.5M potassium chloride solution using 250mL of water
When vectors are added or subtracted, the net force is called the _____.
will give brainliest to whoever gets it right
Answer:
resultant
Explanation:
need little help pls
Answer:
0.354 molal
Explanation:
The molarity (M) or the concentration of a solution is defined as the number of moles of a compound in the solution per liter of solution (mol/L), whereas molality, is defined as the number of moles of a compound in the solution per kg of the compound (mol/kg).
Given that the density of the solution is 1.202 g/mL, which is equivalent to 1.202 kg/L. Since the prefix mili- denotes a factor of one thousandth ( [tex]10^{-3}[/tex] ) and kilo- denotes a factor of one thousand ( [tex]{10}^3[/tex] ),
[tex]1.202 \ \frac{g}{mL} \ = \ 1.202 \ \frac{g}{(10^{-3}) L} \ = \ 1.202 \ \frac{{10}^3g}{L} \ = \ 1.202 \ \frac{kg}{L}[/tex].
To calculate the corresponding molality of the solution, the formula
[tex]Molality \ (mol/kg) \ = \ \frac{Molarity \ (mol/L)}{Density \ (kg/L)}[/tex] is used.
Therefore,
[tex]Molality \ = \ \frac{0.426 \ mol/L}{1.202 \ kg/L} \ = \ 0.354 \ mol/kg \ \ (3 \ s.f.)[/tex]
Which element(s) would you expect to behave similarly to Gadolinium? What properties of would you expect to be the same, what would be different?
The elements in the lanthanide series are similar to gadolinium.
The periodic table is arranged in groups and periods. Elements in the same group have similar properties. At the bottom row of the periodic table lies a group of elements that have unique properties called the lanthanides. This is where Gadolinium belongs.
The elements in the lanthanide series such as europium and terbium are similar to gadolinium. The lanthanides are similar in chemical reactivity and appearance. However, the density of the metals differ because it increases with increase in atomic number.
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How many K are in 32 o C?
Answer:
273.15 Kelvins
Explanation:
Hope this helps !!!If you add the same amount of heat to two different substances, will they both change phase?
Answer:
It depends on their melting and/or their boiling points, because the heat provides the particles with kinetic energy to break the electrosatic bonds in the substances, which can differ in strength
Explanation:
13. Which has the largest atomic radius?
A. fluorine B. chlorine C. bromine
D. a bromine anion with a charge of 1-
Answer:
bromine
Explanation:
Select True or False: The entropy of a perfectly ordered crystalline substance at 0 K is 0 J/mol. Bloom's Level: Understand
True, the entropy of a perfectly ordered crystalline substance at 0 K is 0 J/mol.
The third law of thermodynamics states that, the entropy of a system approaches a constant value as the temperature of the system approaches absolute zero.
The entropy of any perfectly ordered, crystalline substance at absolute zero temperature is zero. That is, the entropy of a pure, perfect crystalline substance at 0 K is 0 J/K.
Thus, we can conclude that the given statement is true. The entropy of a perfectly ordered crystalline substance at 0 K is 0 J/mol.
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I figured it out no problem
Answer:
good job ;0
Explanation:
How do plants use the energy from the sunlight?
Answer:
Hey mate....
Explanation:
This is ur answer....
Plants use a process called photosynthesis to make food. During photosynthesis, plants trap light energy with their leaves. Plants use the energy of the sun to change water and carbon dioxide into a sugar called glucose. Starch is stored in seeds and other plant parts as a food source.
Hope it helps!
Brainliest pls!
Follow me! :)
Answer:
Plants use photosynthesis to convert sun light into their own food to consume. Green plants use this light energy to change water and carbon dioxide into oxygen and nutrients called sugars. The plants use some of the sugars and store the rest. The oxygen is released into the air.
How many moles are in 50 g of CO2
Answer:
1.1 mol
Explanation:
n=m/M, where n is moles, m is mass, and M is molar mass.
M of CO2 = 12.01+16.00+16.00 = 44.01g/mol
n=50g/44.01g/mol
n = 1.13610543 mol
n ≈ 1.1 mol
Hope that helps
if one gram of sulphur dioxide contains x molecules what will be the number of molecules in 1g of methane
The ratio of molecules in sulphur dioxide and methane will be the same as the ratio of their moles. So, first of all we should find out the number of moles of sulphur dioxide in 1 gram of sulphur dioxide in 1 gram of sulphur dioxide, and the number of moles of methane in 1 gram of methane. This can be done as follows :
(i) The molecular formula of sulphur dioxide is [tex]SO_{2}[/tex]
So, [tex]1[/tex] mole of [tex]SO_{2}[/tex] = [tex]Mass[/tex] [tex]of[/tex] [tex]2'O'[/tex]
[tex]=32+2*16[/tex]
[tex]= 64[/tex] grams
Now, [tex]64g[/tex] of sulphur dioxide [tex]= 1[/tex] mole
So, [tex]1g[/tex] of sulphur dioxide = [tex]\frac{1}{64}[/tex] mole
Thus, we have [tex]\frac{1}{64}[/tex] mole of sulphur dioxide and it contains molecules in it. Now, since equal moles of all the substance contain equal number of molecules, therefore, [tex]\frac{1}{64}[/tex] mole of methane will also contain x molecules of methane.
(ii) Molecular formula of methan is [tex]CH_{4}[/tex]
So, 1 mole of [tex]CH_{4}[/tex] = Mass of C + Mass of 4 H
[tex]=12+4*12[/tex]
Now, 16g of methane = 1 mole
So, 1 g of mathane = [tex]\frac{1}{16}[/tex] mole
We know that:
[tex]\frac{1}{64}[/tex] mole of methane contains = x molecules
So, [tex]\frac{1}{16}[/tex] mole of contains will contain =[tex]\frac{x*64}{16}[/tex] molecules
=[tex]4x[/tex] molecules
Which element is shown below? How do you know?
Producers are the most numerous group in an ecosystem. Why?
-------------------------------------------------------------------------------------------------
Producers produce food energy for themselves and all the other levels. ⬜
Soil and temperature conditions in an ecosystem always favor producers. ⬜
As energy flows through the ecosystem, some energy is added at each step. ⬜
There is more room for small organisms than there is for large ones. ⬜
Answer:
The primary producer uses some of that energy. Because we lose energy each time we move up a trophic level, we have more producers than consumers, more herbivores than carnivores, more primary consumers than secondary consumers. See this Socratic answer for more detail.
Explanation:
Answer:
Producers produce food energy for themselves and all the other levels
Explanation:
The ion of aluminum is
Al+
Al2-
Al2+
Al3+
Al3-
Answer:
A13+
Explanation:
I took a test that had this question.
How is a mixture different from a compound?
Answer:
A compound is something like atoms coming together as a team, and a mixture is 2 or more substances mixing together.
Explanation:
Nitric oxide (NO) from car exhaust is a primary air pollutant. Calculate the equilibrium constant for the reaction
N2(g) + O2(g) equilibrium reaction arrow 2 NO(g)
at 25°C using the data listed in the supporting materials.
Calculate the equilibrium constant at 1496°C, which is a typical temperature inside the cylinders of a car's engine after it has been running for some time. (Assume that both ΔrH° and ΔrS° are temperature independent.)
This problem is asking for the equilibrium constant at two different temperatures by describing the chemical equilibrium between gaseous nitrogen, oxygen and nitrogen monoxide at 25 °C and 1496 °C as the room temperature and the typical temperature inside the cylinders of a car's engine respectively:
N₂(g) + O₂(g) ⇄ 2 NO(g)
Thus, the calculated equilibrium constants turned out to be 6.19x10⁻³¹ and 9.87x10⁻⁵ at the aforementioned temperatures, respectively, according to the following work:
There is a relationship between the Gibbs free energy, enthalpy and entropy of the reaction, which leads to the equilibrium constant as shown below:
[tex]\Delta _rG=\Delta _rH-T\Delta _rS\\\\\Delta _rG=-RT ln(K)[/tex]
Which means we can calculate the enthalpy and entropy of reaction and subsequently the Gibbs free energy and equilibrium constant. In such a way, we calculate these two as follows, according to the enthalpies of formation and standard entropies of N₂(g), O₂(g) and NO(g) since these are assumed constant along the temperature range:
[tex]\Delta _rH=2*90.25 kJ/mol - (0 kJ/mol+0 kJ/mol)=180.5kJ/mol\\\\\Delta _rS=2*(0.211 kJ/mol*K)-(0.192kJ/mol*K+0.205kJ/mol*K)=0.025kJ/mol*K[/tex]
Then, we calculate the Gibbs free energy of reaction at both 25 °C and 1496 °C:
[tex]\Delta _rG_{25\°C}=180.5-(25+298.15)*0.025=172.42kJ/mol\\\\\Delta _rG_{1496\°C}=180.5-(1496+298.15)*0.025=135.65kJ/mol[/tex]
And finally, the equilibrium constants derived from the general Gibbs equation and Gibbs free energies of reaction:
[tex]K=exp(-\frac{\Delta _rG}{RT} )\\\\K_{25\°C}=exp[-\frac{172420 J/mol}{(8.3145\frac{J}{mol*K})(298.15K)} ]=6.19x10^{-31}\\\\K_{1496\°C}=exp[-\frac{135650J/mol}{(8.3145\frac{J}{mol*K})(1769K)} ]=9.87x10^{-5}[/tex]
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(Gibbs free energy) https://brainly.com/question/15213613How is the atomic mass of an element related to a mole?
O A. The atomic mass, in grams, is the mass of 6.02 x 1023 moles.
O B. The atomic mass, in grams, is the mass of 6.02 x 1023 electrons.
O C. The atomic mass, in grams, is the mass of one mole of atoms.
O D. The atomic mass, in grams, is the mass of one mole of protons.
Answer:
i the answer to your question should be C
Explanation:
Hope this helps!
The atomic mass of an element related to a mole in grams, is the mass of one mole of atoms. Therefore, option C is correct.
What is an atomic mass ?An atom's mass is its atomic mass. Although the kilogramme is the SI measure of mass, the unified atomic mass unit, or dalton, is a common way to express atomic mass. An unbound carbon-12 atom in its ground state has a mass of 112 of a Da.
A mass that is one-twelfth the mass of an atom of carbon-12 is known as an atomic mass unit. Any isotope of any element's mass is represented in terms of the carbon-12 reference standard.
The size of an atom is indicated by its atomic mass. Technically speaking, an atom's mass is the total weight of its protons, neutrons, and electrons.
Thus, option C is correct.
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Make a atomic model of carbon-12 in mine craft
(If it's good I'll give a lot of points)
Here is the atomic model in the picture.
How many moles in 44.7 kg of carbon dioxide
Answer:
What is the number of moles of carbon present in 44 grams of carbon dioxide? One. 44 grams is a mole of carbon dioxide and there is one carbon atom in CO 2 so there is one mole of carbon. That’s how chemistry works.
Explanation:
What is the number of moles of carbon present in 44 grams of carbon dioxide? One. 44 grams is a mole of carbon dioxide and there is one carbon atom in CO 2 so there is one mole of carbon. That’s how chemistry works.
what is the element found in all living matter.
Answer:
There are four elements that are found in all living animals, that are:
Oxygen (O)
Carbon (C)
Hydrogen (H)
Nitrogen (N).