Calculate the current in the coiled heating element of a 240-V stove. The resistance of the element is 60 ohms at its operating temperature.

Following are the two sources of data:

IamSugarBee

Answer:

I hope this helps

Explanation:

.... Internal source

.... External source

Answer:

What are u asking for?

Explanation:

The dark-side traits the leaders possessed that caused them to be ineffective are; Narcissism, Psychopathy and Machiavellianism.

According to Paulhus and williams, they discovered in year 2002 that several personality traits could be related to failures of a leader but they narrowed it down to three which they referred to as the Dark Triad.

These dark side traits are;

Read more about character traits at; https://brainly.com/question/24856057

Answer: B. Particles of liquids can move from place to

Explanation:

Fast-moving particles transfer energy to slower-moving particles ... The motion of water molecules causes them to leave the liquid and become a gas.

Answer:

Unit of,

momentum = kg×m/s

momentum per unit area = kg×m/s×m² = kg/m×s

momentum per unit area per unit time= kg/ms²

force = kg×m/s²

force per unit area = kg×m/s²×m² = kg/ms²

Explanation:

Answer:

  20.1 cm

Explanation:

The depth is the ratio of volume to area.

  [tex]\dfrac{1.44\times10^8\text{ ac$\cdot$ft}}{8.81913\times10^5\text{ km}^2}=\dfrac{(1.44\times10^8)(4.356\times10^4\text{ ft}^3)(0.3048\text{ m/ft})^3}{(8.81913\times10^5\text{ km}^2)(10^3\text{ m/km})^2}\\\\=\dfrac{1.44\times4.356\times0.3048^3\times10^{12}}{8.81913\times10^{11}}\text{ m}\approx0.2014\text{ m}[/tex]

The depth of water is about 20.1 cm.

_____

Additional comment

An acre-foot is 43,560 cubic feet.

A foot is 0.3048 meters.

A kilometer is 1000 meters.

A centimeter is 0.01 meters.

Answer:

true

Explanation:

i took the test and got it right

Answer:

  82.7 cm or 32.5 in

Explanation:

The required resistance is calculated from the relationship of power, voltage, and resistance. The wire length to give that resistance is calculated from ...

  L = A·R/ρ

The power is the ratio of energy to time:

  P = E/t = (8 J)/(0.25 s) = 32 W

The required resistance is ...

  R = V²/P = (240 V)²/(32 W) = 1800 Ω

__

Then the required wire length is ...

  L = (π/4)(0.00016 in × 2.54 cm/in)²×(1800 Ω)/(2.825×10^-6 Ω·cm)

  L ≈ 82.65 cm

The length of aluminum wire required is about 82.7 cm or 32.5 in.

_____

Additional comment

This wire is roughly 66 AWG, about 1/6 the diameter of a human hair. Its melting current in still air is likely well below the current it carries in this heater. That is, it probably needs to experience significant airflow in order to maintain its integrity.

Answer:

the 4th one

Explanation:

no id you can't drive

Answer:

- the Young's modulus of the composite in the longitudinal direction  = 87.4GPa.

- The tensile strength of the composite in the longitudinal direction  = 1.26 × 10⁹.

Explanation:

The following parameters or data were given in this particular question/problem;

1. "The fibers are continuous, unidirectionally aligned and 40% by volume."

2." The tensile strength of carbon fibers is 2998 MPa, and the Young's modulus is 214 GPa."

3. " The tensile strength of the epoxy matrix is 100 MPa, and its Young's modulus is 3 GPa."

So, let us delve right into the solution to this question:

[ kindly note that part b. of this problem is the same as the part a. of the problem

Also, in point 2. above 2998MPa = 2.998 =GPa, approximately 3GPa].

40% = 40/100 = 0.4. Therefore, 1 - 0.4 = 0.6. Hence, the Young's modulus of the composite in the longitudinal direction = 3 × 0.6 + 214 × 0.4 =  1.8 + 85.6 = 87.4GPa

The tensile strength of the composite in the longitudinal direction = 100 × 10⁶ × 0.6 + 3 × 10⁹ ₓ 0.4 = 1.26 × 10⁹.

Answer:

(a) Since, the stress is less than the yield strength. Therefore, the material does not go yielding.

(b) Yes

(c) Longitudinal Strain = 5.09 x 10⁻⁴

(d) Lateral Strain = 1.67 x 10⁻⁴

(e) Change in Diameter = 4.2 x 10⁻³ mm = 4.2 μm    

Explanation:

(a)

First we calculate stress:

Stress = Force/Area = F/πr²

Stress = 50 KN/π(0.0125 m)²

Stress = 101.86 MPa

Since, the stress is less than the yield strength. Therefore, the material does not go yielding.

(b)

Yes, Hooke's law can be applied to this problem because the material is within elastic limits.

(c)

Longitudinal Strain = Stress/E

Longitudinal Strain = 0.10186 GPa/200 GPa

Longitudinal Strain = 5.09 x 10⁻⁴

(d)

Poisson's Ratio = Lateral Strain/Longitudinal Strain = E/2G - 1

Lateral Strain/Longitudinal Strain = E/2G - 1

Lateral Strain/5.09 x 10⁻⁴ = 200 GPa/2*75.2 GPa - 1

Lateral Strain = 0.33*5.09 x 10⁻⁴

Lateral Strain = 1.67 x 10⁻⁴

(e)

Lateral Strain = Change in Diameter/Original Diameter

Change in diameter = (1.67 x 10⁻⁴)(25 mm)

Change in Diameter = 4.2 x 10⁻³ mm = 4.2 μm

Answer:

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Answer:

A) 4800.6 N

B) 0.2255 mm/min

C) 8.6792 inches

Explanation:

Given data :

gauge Length = 22 cm = 220 mm

cross section diameter/thickness = 1.8 mm

young's modulus ( E ) = 205 GPa

Ultimate tensile strength ( σu ) = 420MPa

Time = 2 mins

A) what force would fracture the specimen

σU = Ff /A

where A (area) = thickness * width ( unknown )  hence we assume a width of 6.35 mm

Ff = σU × A =  420 * 1.8 * 6.35 = 4800.6 N

B) calculate the strain rate

Ultimate tensile strength ( σU ) = εE

ε = σU / E = 420/205000 = 0.00205

also  ε ​​​​​​ =  ΔL / Li = ( Lf - Li) / Li = (Lf / Li) - 1

 therefore  ε ​​​​​​ + 1 = (Lf / Li) = 1 + 0.00205 = 1.00205

 Li = gauge length = 220 mm

Hence :  Lf = 1.00205 × gauge length =  1.00205 * 220 =  220.451 mm

  strain rate

(Lf - Li) / Time = (0.451) / 2 min = 0.2255 mm/min

C) Elongation in inches prior to fracture

ΔL = ε × Li = 0.451 mm

Lf = 220 mm + 0.451 mm = 220.451 mm =  8.6792 inches

Answer:

if you are entering the workforce right after high school you are likely to get less pay and work maybe a little harder and also have to learn from the people at the job how to do the job compared to someone who is working in a skilled trade where they know what they are doing, are likely to get a higher pay, and dont need to be taught what to do.

Explanation:

I'm here if you need help with a math question

Complete Question:

The cost to rent a scooter is $15.50 per hour and the cost to rent a watercraft

is $22.80 per hour. Use the expression 15.5s + 22.8w to determine how much it would cost to rent a scooter for 3 hours and a watercraft for 1 hours.

Answer:

$69.39

Explanation:

Given

15.5s + 22.8w

Required

Evaluate, when w = 1 and s = 3

To do this, we simply substitute 3 for a and 1 for w in the given expression.

15.5s + 22.8w becomes..

15.5 * 3 + 22.8 * 1

46.5 + 22.8

69.3

Hence, the cost is $69.30

Answer:

Explanation:

It is useful to consider the voltage at X to be the superposition of two voltages divided by the R1/R2 voltage divider. It is also helpful to remember that OUT = -VX·AVOL.

__

  [tex]V_X=\dfrac{V_1\cdot R_2+V_{out}\cdot R_1}{R_1+R_2}=\dfrac{V_1\cdot R_2-V_X\cdot A_{VOL}\cdot R_1}{R_1+R_2}\\\\V_X(R_1(1+A_{VOL})+R_2)=V_1\cdot R_2\\\\\boxed{V_X=V_1\dfrac{R_2}{R_2+R_1(1+A_{VOL})}}[/tex]

__

Filling in the given numbers, we find VX to be ...

  [tex]V_X=-0.01V\cdot\dfrac{400000}{400000+4000(1+10000)}=-0.01V\cdot\dfrac{100}{10101}\\\\\boxed{V_X=\dfrac{-1}{10101}V\approx-99.0001\mu V}[/tex]

__

As we said at the beginning, OUT = -VX·AVOL. Multiplying the expression for VX by -AVOL, we get ...

  [tex]\boxed{V_{out}=-V_1\cdot\dfrac{A_{VOL}\cdot R_2}{R_2+R_1(1+A_{VOL})}}[/tex]

__

As with the expression, the output voltage is found by multiplying VX by -AVOL:

  [tex]V_{out}=\dfrac{(-1)(-10000)}{10101}V\\\\\boxed{V_{out}=\dfrac{10000}{10101}V\approx 0.990001V}[/tex]

Answer:

You have to know the basic mechanics to help you correctly use the motorcycle, and you also have to have the right mindset - knowing you can ride it, and having determination. All of these factors are the primary mental skills you need for riding a motorcycle.

Answer:

B. Information processing and decision-making

Explanation:

Answer:

b. A view of a building seen from one side, a flat representation of one façade. This is the most common view used to describe the external appearance of a building.

Explanation:

An elevation is a three-dimensional, orthographic, architectural projection that reveals just a side of the building. It is represented with diagrams and shadows are used to create the effect of a three-dimensional image.

It reveals the position of the building from ground-depth and only the outer parts of the structure are illustrated. Elevations, building plans, and section drawings are always drawn together by the architects.

Answer:

The principles of a series circuit that can be used to analyze a parallel circuit is that of calculating total resistance in the circuits.

The formula used in a series circuit analysis for finding total resistance is different from that used in a parallel circuit for finding overall resistance. i.e.

For a series circuit total resistance Rt={R1+R2+R3+.......Rn}

For a parallel circuit, total resistance 1/Rt ={1/R1+1/R2+1/R3+.....1/Rn]

Explanation:

In a series circuit, the current passing through each component is the same where as in a parallel circuit the voltage through each component is the same.

The principles of series circuit that can be used to analyze a parallel circuit is that of calculating total resistance in the circuits. In a series circuit, total resistance is calculated as the sum of resistance of the components connected to the circuit, where as in a parallel circuit, overall resistance is the summation of the resistance of individual components.

This means you can use principles of series circuit to find total resistance then use that value to confirm the individual resistance values of components in a parallel circuits. This is possible because you will have the expected total resistance [calculated from the series circuit], then the sum of resistance of the same but individual components now in the parallel circuit should be equal to the total resistance calculated from the series circuit.

The formula for calculating resistance in series circuit given as :{Rt= R1+R2+R3+.......Rn} where Rt is the total resistance and R1,R2,R3...Rn are the values of individual components in the series circuit, can not be used in finding overall resistance in a parallel circuits because the formula for total resistance will change to : [1/Rt =1/R1+1/R2+1/R3+.....1/Rn]

Answer:

engineers are people who fix or invent items that will support people’s lives. For fun, engineers may construct unique items that is hard to invent.

Explanation:

If you need more info, pls comment.

Answer:

An engineer uses science, technology and math to solve problems. It designes machinery, build skyscrapers and oversee public works.

Answer:

1218.75

Explanation: If he makes a 25% profit, he needs to sell it for 125% of the computer price. 1.25*975 is 1218.75

Using Terzagi's Equation as shown in the attachement;

Qa = 4225 kN/m

As per the given data, the ultimate bearing capacity of the soil is 313 kN/[tex]m^2[/tex]

Bearing capacity is the capacity of soil to support loads applied to the ground in geotechnical engineering.

To determine the ultimate bearing capacity of the soil, we can use the following formula:

q_ult = cN_c + 0.5γ*(BN_q + 0.4N_g*(B - B_f)*N_q)

To find the values of N_c, N_q, and N_g, we can use the following equations:

N_c = [cot(0) + tan(φ)][1 + 0.2(B_f/D)][(N_q/N_c) - 1][(N_q/N_c) - 2]

N_q = [(1 + sin(0))(1 - sin(0))][(N_q/N_c) - 1]

N_g = 0.5*(N_q - 1)*tan^2(φ)

Using the above equations, we can calculate the values of N_c, N_q, and N_g as follows:

N_c = [cot(35°) + tan(35°)][1 + 0.2(3/2)][(2.45/N_c) - 1][(2.45/N_c) - 2] ≈ 11.5

N_q = [(1 + sin(35°))(1 - sin(35°))][(2.45/N_c) - 1] ≈ 10.5

N_g = 0.5*(10.5 - 1)*[tex]tan^2[/tex](35°) ≈ 2.6

Substituting these values into the formula for q_ult, we get:

q_ult = 3011.5 + 0.517.25*(310.5 + 0.42.6*(3 - 3)*10.5) ≈ 313 kN/m^2

Therefore, the ultimate bearing capacity of the soil is approximately 313 kN/m^2.

For more details regarding bearing capacity, visit:

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the answer is 1288 m2

Explanation:

i took the k12 test

Answer: The answer is 1288

Explanation: I took the test and it was right

Answer:

  484 hours

Explanation:

The given quantity of water will be added in a time period equal to the quantity divided by the rate.

  (800 ac·ft)(43560 ft²/ac)/(20 ft³/s × 3600 s/h) = 484 h

It will take 484 hours to raise the water level by 1 ft.

__

Additional comment

We have assumed the given rate is a net rate of water influx. Evaporation from 800 acres may amount to about 1.3 ft³/s, or 6.6% of the inflow rate. It could be more than 3 times that amount, depending on the climate conditions at the reservoir's location.

Answer:

Written in Java

public class MyClass {

   public static void main(String args[]) {

     int [] myarray = new int[10];

     for(int i = 0;i<10;i++)  {

         myarray[i] = i;

     }

     System.out.println("Countdown");

     for(int i = 9;i>=0;i--)  {

        System.out.println(myarray[i]);

     }

   }

}

Explanation:

This line declares the array

     int [] myarray = new int[10];

The following iteration inserts 0 to 9 into the array

     for(int i = 0;i<10;i++)  {

         myarray[i] = i;

     }

This line prints "Countdown"

     System.out.println("Countdown");

The following iteration prints the array in reverse order

     for(int i = 9;i>=0;i--)  {

        System.out.println(myarray[i]);

     }