Answer:
MOMENTUM= FORCE*MASS
= 140*5
= 700 kg⋅m/s
ANSWER ASP Please help will give brainliest
heeelppp what quantity measures the amount of matter in an object
A . Volume
B . Temperature
C . Mass
D . Density
Answer:
Your answer is MASS.
Explanation:
Volume measures how much space an item takes up.
Temperature measures how hot or cold something is.
Density is the degree of compactness of a substance.
Mass measures the amount of matter in an object.
Sarah throws a ball directly upward at the edge of a cliff with a starting velocity of 3.0 \, \dfrac{\text m}{\text s}3.0 s m 3, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction. It lands on the ground with a final speed of 6.0 \, \dfrac{\text m}{\text s}6.0 s m 6, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction. How long is the ball in the air?
Answer:
t = 0.3 seconds
Explanation:
Given that,
Initial velocity of a ball, u = 3 m/s
Final velocity of the ball, v = 6 m/s
We need to find the time for which the ball is in the air. As the ball was directed upwards, it would mean that the acceleration of the ball is -g or -9.8 m/s².
Using the first equation of motion to find the time. So,
v=u+at
or
v=u-gt
[tex]t=\dfrac{v-u}{-g}\\\\t=\dfrac{6-3}{-9.8}\\\\t=-0.3\ s[/tex]
or
t = 0.3 seconds
So, the ball is in the air for 0.3 seconds.
Answer: t= 0.92 s
Explanation: the formula you use it’s v=vinitial + at and you rearrange it to make (t= vfinal - vinitial /a) using this you get 0.92s
What is the electrical force between q2 and q3? Recall that k = 8. 99 × 109 N•meters squared over Coulombs squared. 1. 0 × 1011 N –1. 1 × 1011 N –1. 6 × 1011 N 1. 8 × 1011 N.
Force on the particle is defined as the application of the force field of one particle on another particle. the electrical force between q₁ and q₃ will be –1. 1 × 10¹¹ N.
What is electric force?Force on the particle is defined as the application of the force field of one particle on another particle. It is a type of virtual force.
The electric force in the second case will be the same as in the first case. Therefore the force on the particle will be the same.
[tex]\rm F= K\frac{q_2q_3}{r^2}[/tex]
[tex]\rm F= 9\times 10^9 \times \frac{1.6 \times 10^{-13}\times 1.6\times10^{-13}}{(0.5)^2}[/tex]
[tex]\rm F= - 1. 1 \times 10^{11 }N[/tex]
Hence the electrical force between q₁ and q₃ will be –1. 1 × 10¹¹ N.
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A statue and a coin are made out of exactly the same materials. Which property would you claim will likely be the same for both the statue and the coin?
mass
reactivity
volume
shape
I believe that the correct answer is reactivity.
10 20 30 40 50 60 70 80 90 100 110 120 130. Which end of the scale (left or right) has the loudest sounds?
Answer:
I'm From Philippines
I hope we can be friends.
25 POINTS will mark brainliest if correct
The radius of Neptune is 2.48 x 107m. The radial acceleration of an object at the equatorial surface of
The radius of Neptune is 2.48*10^7m. The radical acceleration of an object at the equatorial surface of Neptune is 0.292 m/s2. What is Neptune's period of rotation in seconds?
A.18,000 s
B.1200 s
C.58,000 s
D.9200 s
Answer: The answer is C. 58,000
Explanation:
What kind of energy could be directly used to solve for the launch velocity?
A box is sliding with a speed of 4.50 m/s on a horizontal surface when, at point P, it encounters a rough section. On the rough section, the coefficient of friction is not constant, but starts at 0.100 at P and increases linearly with distance past P, reaching a value of 0.600 at 12.5 m past point P.
(a) Use the work energy theorem to find how far this box slides before stopping.
(b) What is the coefficient of friction at the stopping point?
(c) How far would the box have slid iff the friciton coefficient didn't increase, but instead had the constant value of .1?
Answer:
(a). The value of distance is 5.043 m
(b). The coefficient of friction is 0.302.
(c). The distance is 10.33 m
Explanation:
Given that,
Speed = 4.50 m/s
Minimum friction = 0.1
Maximum friction = 0.6
Distance = 12.5 m
We know that,
The newton's second law
[tex]F_{net}=-\mu N[/tex]
[tex]F_{net}=-\mu mg[/tex]
We know that,
The frictional coefficient is directly proportional to the distance.
We need to calculate the value of coefficient
Using general equation of frictional coefficient
[tex]\mu(x)=Ax+B[/tex]....(I)
At x= 0,
[tex]\mu(0)=0+B[/tex]
Put the value into the formula
[tex]B=0.1[/tex]
Now for value of A
Put the value in equation (I)
[tex] 0.6=A12.5+0.1[/tex]
[tex]A=\dfrac{1}{25}[/tex]
Put the value in equation (I)
[tex]\mu(x)=\dfrac{x}{25}+0.1[/tex]......(II)
We need to calculate the work done
Using work energy theorem
[tex]W=\int_{0}^{x}{F_{net} dx}[/tex]
[tex]W=\int_{0}^{x}{-\mu_{x}mgdx}[/tex]
[tex]W=-mg\int_{0}^{x}{(\dfrac{x}{25}+0.1)dx}[/tex]
[tex]W=-mg(\dfrac{x^2}{50}+0.1x)[/tex]....(III)
(a). We need to calculate the distance
Using difference of kinetic energy
[tex]W=\dfrac{1}{2}m(v_{f}^2-v_{0}^2)[/tex]
[tex]-mg(\dfrac{x^2}{50}+0.1x)=\dfrac{1}{2}m(0-(4.50)^2)[/tex]
[tex]\dfrac{x^2}{50}+0.1x=1.013[/tex]
[tex]x^2+5x=50.65[/tex]
[tex]x^2+5x-50.65=0[/tex]
[tex]x=5.043\ m[/tex]
(b). We need to calculate the coefficient of friction at the stopping point
Using equation (III)
[tex]\mu(5.043)=\dfrac{5.043}{25}+0.1[/tex]
[tex]\mu(5.043)=0.302[/tex]
(c). We need to calculate the distance
Using formula work done
[tex]W=-fx_{2}[/tex]
[tex]W=-\mu mgx_{2}[/tex]
[tex]-\dfrac{1}{2}mv_{0}^2=-\mu mgx_{2}[/tex]
[tex]x_{2}=\dfrac{v_{0}^2}{2\mu g}[/tex]
Put the value into the formula
[tex]x_{2}=\dfrac{(4.5)^2}{2\times0.1\times9.8}[/tex]
[tex]x_{2}=10.33\ m[/tex]
Hence, (a). The value of distance is 5.043 m
(b). The coefficient of friction is 0.302.
(c). The distance is 10.33 m
The tidal bulge on earth follows the movement of the:.
Answer:
The moon and sun cause tidal bulges to move around the planet in perfect sync and unison.
Explanation:
However, do not consider these to be large oceans of water moving in relation to continents. Only the fluctuations in water level—the water's surface profile—follow the moon's and sun's positions in the sky.
A car of mass 1500kg is brought to rest from a velocity of 25m/s by a constant force of 3,000N. Determine the change in momentum produced by the force and the time it takes for the car to come to rest.
change in momentum = 37,500kg.m/s in the opposite direction
time it takes = 12.5s
u=25m/s
v=0m/s
F=ma
-3000=(1500)(a)
-3000÷1500=a
a= -2m/s^2
Change in momentum=mv-mu
(1500)(0)-(1500)(25)
= -37,500kg.m/s
relax the( - ) represents direction
v=u-at
0=25-2t
2t=25
t= 12.5s
A room measures 3 meter wide, 4 meters long, and 2.5 meters high. a. What is the surface area of the room in square meters (including the ceiling and the floor)? b. If a certain paint covers 25 square meters per gallon, how many gallons will it take to paint the walls and ceiling, but not the floor?
Answer:
Explanation:
The total surface area of the room is expressed as;
TSA = 2(LW+LH+WH)
L is the length
W is the width.
H is the height
Given
L = 4m
W = 3m
H = 2.5m
.TSA = 2{4(3)+3(2.5)+4(2.5)}
TSA = 2(12+7.5+10)
TSA = 2(29.5
TSA = 59m²
TSA (without the floor) = 2(3(2.5)+4(2.5))
TSA = 2(7.5+10)
TSA = 2(17.5)
TSA = 35m²
If a certain part covers 25 square meters per gallon, the amount of gallon needed will be 35m²/25m²
= 1.4gallons
a meteor is falling towards earth with 4m/s^2 acceleration due to gravity. if mass and radius of the earth are 6*10^24kg and 6.4*10^6m respectively, find the height of meteor.
Answer:
3.6×10⁶ m
Explanation:
g = GM / R²
4 m/s² = (6.67×10⁻¹¹ m³/kg/s²) (6×10²⁴ kg) / (6.4×10⁶ m + h)²
(6.4×10⁶ m + h)² = 1.00×10¹⁴ m²
6.4×10⁶ m + h = 1.00×10⁷ m
h = 3.6×10⁶ m
When using the right-hand rule to determine the direction of the magnetic force on a charge, which part of the hand points in the direction of the magnetic field? palm fingers back thumb
When using the right-hand rule to determine the direction of the magnetic force on a charge, the thumb is in the direction of the magnetic field.
What is the right-hand thumb rule?The right-hand thumb rule is the method to recognize that there is only one velocity, which is symbolized by the thumb. There are a lot of field lines, which are symbolized by the fingers.
The force is directed in the direction in which you would press your palm. The force acting on a negative charge is the polar opposite of that acting on a positive charge.
A pure magnetic field will not accelerate a charged particle in a single direction since the force is always perpendicular to the velocity vector, but it will create circular or helical motion
It's worth noting that a magnetic field has no effect on a static electric charge. These two findings are consistent with the rule that magnetic fields are polarized.
Hence using the right-hand rule to determine the direction of the magnetic force on a charge, the thumb is in the direction of the magnetic field.
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Answer:
D, thumb
Explanation:
edge 2022
Large amplitude of sound vibrations will produce.....
Answer:
louder sound.
Explanation:
The amplitude of a sound wave determines its loudness or volume. A larger amplitude means a louder sound
When wood is burned, energy is released in the form of heat and light. Describe the reaction, and explain why the reaction does not violate the law of conservation of energy.
-Physical science
Answer:
the reaction is a physical reaction and it is exothermic as it releases heat to the sorrounding
Explanation:
because the mass of paper burnt is equal to the mass of products which are ashes
Which form of electromagnetic light can be used for cooking food?
A) X-rays
B) Ultra-violet (UV) light
C) Gamma Rays
D) Microwaves
Answer:
Microwaves (D
Explanation:
I'm not sure! But I think it's Microwaves!
What is the relationship between current and power in a circuit?
O A. A circuit that has more current will have more power.
B. The amount of current in a circuit has no relation to its power.
C. A circuit that has more current will have less power.
D. The amount of current a circuit has is equal to its power.
Answer: A
Explanation: a p e x
Answer:
the guy above is right, it is A
Explanation:
A p E x
An airplane travels 280m down the runway before taking off. If it starts from rest, moves with constant acceleration, and becomes airborne in 8.00 s, what is its speed, in m/s, when it takes off?
Answer:
the average speed is ... 280 m / 8.00 s = 35 m/s
the initial speed is zero (rest), so the final speed (take off) is
... ave = (init + fin) / 2 ... 35 = (0 + f) / 2 ... f = 70 m/s
Explanation:
Select the correct answer. What can be found by counting the number of troughs per second in a wave diagram? A. Amplitude B. Direction C. Frequency D. Speed E. Wavelength.
Option C is correct. Frequency can be found by counting the number of troughs per second in a wave diagram.
What is the frequency?Frequency is defined as the number of repetitions of waves occurring in 1 second. It can also be said that Frequency is defined as the number of cycles completed in 1 second.
Frequency is given by the formula as,
[tex]\rm f=\frac{1}{t}[/tex] Hz.
Hence option C is correct. Frequency can be found by counting the number of troughs per second in a wave diagram.
To learn more about the frequency refer to the link;
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Answer:
C is correct
Explanation:
"Angel Falls in southeastern Venezuela is the highest uninterrupted waterfall in the world, dropping 979 m (3212 ft). Ignoring air resistance, it would take 14 s for the water to fall from the lip of the falls to the river below. If the water lands 50 m from the base of the verti-cal cliff, what was its horizontal speed at the top"
Complete Question
The complete question is shown on the first uploaded image
Answer:
The value is [tex]v = 3.57 \ m/s [/tex]
Explanation:
From the question we are told that
The depth is [tex]d = 979 \ m[/tex]
The time taken for water to fall to below the river is [tex]t = 14 \ s[/tex]
The horizontal distance from the base of the vertical cliff is [tex]h = 50 \ m[/tex]
Generally the horizontal speed at the top is mathematically represented as
[tex]v = \frac{h}{t}[/tex]
=> [tex]v = \frac{ 50}{ 14 }[/tex]
=> [tex]v = 3.57 \ m/s [/tex]
A positive charge of 6.0 × 10-4 c is in an electric field that exerts a force of 4.5 × 10-4 n on it. what is the strength of the electric field? startfraction n over c endfraction
The strength of the electric field will be 0.75 NC⁻¹.
What is the strength of the electric field?The strength of the electric field is the ratio of electric force per unit charge. Its unit is NC⁻¹.
The given data in the problem is;
q is the positive charge = 6.0 × 10-4 C
F is the electric force of 4.5 × 10-4 N
E is the electric field intensity=?
The electric force is given by;
[tex]\rm F= q \times E \\\\ \rm E= \frac{F}{q} \\\\ \rm E= \frac{4.5 \times 10^4}{6 \times 10^{-4}} \\\\ \rm E=0.75 \ NC^{-1}[/tex]
Hence the strength of the electric field will be 0.75 NC⁻¹.
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Two observers times the motion of a car from one place to another. The first observer's clock read 262 seconds at the start and 375 seconds at the end of the car's motion. The second observer's clock read -86 seconds at the start. What did it read at the end?
Answer:
The time of the second observer at the end of the car motion is 27 s
Explanation:
Initial time of the first observer, t₁ = 262 s
final time of the first observer, t₂ = 375 s
The time of the car motion, t = t₂ - t₁
t = 375 s - 262 s
t = 113 s
Initial time of the second observer, t₁ = -86 s
final time of the second observer, t₂ = ?
The time of the car motion, t = t₂ - t₁
113 = t₂ - t₁
113 = t₂ - (-86)
113 = t₂ + 86
t₂ = 113 - 86
t₂ = 27 s
Therefore, the time of the second observer at the end of the car motion is 27 s
Which of the following is not a step toward planning your goals?
C. Disregard a goal if you don’t achieve it
Answer: A. Disregard a goad if you don't achieve it.
Explanation:
The Explanation is if you don't achieve the goal that is not right so your job is to disregard the goal.
If wooden ball has a mass of 2.4g and a volume of 6cm3. What is it’s density
Answer:
0.4 g/cm^3. is the answer of this question..Thank you ☺️☺️
Answer:
0.4 g/cm^3
Explanation:
As density=m/v
=2.4/6
=0.4g/cm^3
A shell is fired from the ground with an initial speed of 1.60 × 10^3 m/s (approximately five times the speed of sound) at an initial angle of 68.0◦ to the horizontal. The acceleration of gravity is 9.81 m/s^2 Neglecting air resistance, find the shell's horizontal range? Answer in units of m
Answer:
181276.802 m
Explanation:
The computation of the horizontal range of the shell is shown below:
As we know that
range = u × usin2θ ÷ g
where,
u = 1600 m/s
θ = 68
g=9.81
NowPut these values to the above formula
So, the value of the horizontal range of the shell is
R = 181276.802 m
= 181276.802 m
We simply applied the above formula and the same is to be considered
On Earth, a board is supported near the ends by Laney and Mia. If Laney exerts 52N upward and
Mia exerts 35 N upward, find the mass of the board if it is in Translational Equilibrium. (Type
answer with 2 significant digits)
Answer:
??? this makes no sense give more info
Explanation:
7. A sprinter accelerates from rest to a velocity of 12 m/s in the first 6
seconds of the 100-meter dash.
What is the acceleration in the first 6 seconds?
b. How far does the sprinter travel during the first 6 seconds?
Answer: a) 36 m/s
B) 64 m
Explanation:
A) d= ½ (Vi+Vf)t
d= ½ (0+12)6
d= 36 m/s
B) 100 – 36 = 64
The pressure resulting from a force of 50 N exerted over an area of 5 m² is
P = F/A
P = 50/5
P = 10 Pa
Hope it helps :)
Please select the word from the list that best fits the definition increases in the number of ______ can lead to warmer climates
The word from the list that best fits the definition increases the number of sunspots that can lead to warmer climates.
What is a sunspot?Sunspots are transitory spots on the Sun's photosphere that appear to be deeper than the surrounding areas.
They are zones of reduced surface heat caused by magnetic field flux concentrations that prevent convection.
Sunspots usually form in pairs with opposite magnetic polarities. This has an impact on the temperature on Earth, as well as radio reaction. The Earth would presumably be colder if sunspots didn't exist.
When sunspots form, they produce an increase in UV radiation that radiates from the sunspots' outer ring as they approach Earth.
This increase in UV radiation has an impact on the chemistry of the outer environment as well as the Earth's energy balance.
The idea that sunspots have an impact on Earth's ecology is still controversial, although it does exist.
Hence the words from the list that best fits the definition increase the number of sunspots that can lead to warmer climates.
To learn more about the sunspot refer to the link;
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