Answer:
C. 1.2 x 10^-11
Explanation:
pOH = 14 - pH = 14 - 3.08 = 10.92
[OH-] = 10^-pOH = 10^-10.92 = 1.2 x 10^-11
How does temperature affect the rate constant for a reaction?
Answer:
d
Explanation:
increasing the temperature the fraction of molecules which collide with energy greater than Ea increase and hence the rate constant
In general, what is the effect of increased temperature on the solubility of a gas?
A. It is uniform
B.The solubility increases.
C. The solubility decreases
D.The saturation increases
E. The effect cannot be determined
Answer:
C. The solubility decreases.
Explanation:
Took the plato test!
Of the three Intermolecular forces, the type with the largest dissociation energy is ________.
A. Dipole-dipole interactions
B. Dispersion forces
C. Hydrogen bonds
Answer:
C. Hydrogen bonds
Explanation:
Strongest intermolecular force
Hydrogen Bonding (H-Bonding)
Hydrogen bonds are caused by highly electronegative atoms. They only occur between hydrogen and oxygen, fluorine or nitrogen, and are the strongest intermolecular force.
Answer: C hydrogen bonds
Explanation:
How many grams of CaCl 2 are in .48 moles ?
Answer:
We assume you are converting between moles CaCl2 and gram. You can view more details on each measurement unit: molecular weight of CaCl2 or grams This compound is also known as Calcium Chloride. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles CaCl2, or 110.984 grams.
The mass of calcium chloride is 53.27 grams.
Given:
Moles of CaCl₂ = 0.48 moles
Molar mass of CaCl₂ = 110.98 g/mol
To find:
Mass of CaCl₂ = ?
Number of moles:It is defined as given mass over molar mass.
Number of moles = Mass / Molar mass
Mass = Number of moles * Molar mass
Mass = 0.48 moles * 110.98 g/mol
Mass = 53.27 grams
Thus, the mass of calcium chloride is 53.27 grams.
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A 20.0 L container at 303 K holds a mixture of two gases with a total pressure of 5.00 atm. If there are 2.00 mol of Gas A in the mixture, how many moles of Gas B are present?
The number of moles of Gas B in the gas mixture is equal to 2.00 mol.
What is the ideal gas equation?The ideal gas equation can be explained as an equation that describes the state of an ideal gas. This equation gives the product of the volume and pressure of ideal gas equal to the multiplication of the universal gas constant, absolute temperature, and moles of gas.
The mathematical form of the ideal gas equation mentioned below:
PV = nRT
Where P is the pressure, V is the volume, n is the moles, and R is the gas constant.
Given, the volume of the gas mixture, V = 500 ml = 0.5 L
The temperature of the gas mixture, T = 303 K
The pressure of the gas mixture = 5 atm
The value of gas constant, R =0.082 atmL/K mol
Substituting the values R, V, P, and T in the ideal gas law, we get:
The number of moles of the gas mixture, n = PV/RT
n = 5 ×20/(0.082 × 303)
n = 4.00 mol
The total number of moles of gas mixture = 4.00 mol
The moles of Gas A = 2.00 mol
The moles of Gas B = 4 - 2 = 2.00 mol
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A student uses a sample of KOH stock solution and dilutes it to a total of 120 mL. If the diluted solution is 0.60 M KOH and its original concentration was 2.25 M, what was the volume of the original sample? *
1.4 mL
89 mL
32 mL
5.5 mL
(DON'T POST LINKS PLEASE)
Answer:
5.5
Explanation:
i think so?????????
The diluted solution of volume 120 ml has the molarity of 0.60 M. Then, the volume of the original solution with a molarity of2.25 M is 32 ml.
What is molarity ?The molarity of a solution is the ratio of the number of moles of its solute particles to the volume of solution in liters.
To solve the given problem, we can use the formula for dilution:
C1V1 = C2V2
where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.
We are given that the diluted solution has a concentration of 0.60 M and a total volume of 120 mL. We are also given that the original concentration was 2.25 M, and we want to find the original volume.
Using the formula for dilution, we can write:
2.25 M x V1 = 0.60 M x 120 mL
Simplifying, we get:
V1 = (0.60 M x 120 mL) / 2.25 M
V1 = 32 mL
Therefore, the original volume of the KOH stock solution was 32 mL.
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the form of EMR that has less energy per photon than microwaves is ____?
Answer: radio wave frequencies have longer wavelengths and smaller
Energies per photon
phenol used in DNA extractiom
Answer:
This is thought to aid in the extraction, as this dissolved phenol helps denature proteins while they are still in the aqueous solution. ... Phenol/Chloroform – This is a mixture of buffer-saturated phenol and chloroform, usually close to 1:1 for DNA purification with other ratios sometimes used for RNA purification
Explanation:
Hope it helps!
If you dont mind can you please mark me as brainlest?
Answer:
This is thought to aid in the extraction, as this dissolved phenol helps denature proteins while they are still in the aqueous solution. ... Phenol/Chloroform – This is a mixture of buffer-saturated phenol and chloroform, usually close to 1:1 for DNA purification with other ratios sometimes used for RNA purification
Calculate the pH at the equivalence point when 22.0 mL of 0.200 M hydroxylamine, HONH2, is titrated with 0.15 M HCl. (Kb for HONH2
Answer:
pH = 3.513
Explanation:
Hello there!
In this case, since this titration is carried out via the following neutralization reaction:
[tex]HONH_2+HCl\rightarrow HONH_3^+Cl^-[/tex]
We can see the 1:1 mole ratio of the acid to the base and also to the resulting acidic salt as it comes from the strong HCl and the weak hydroxylamine. Thus, we first compute the required volume of HCl as shown below:
[tex]V_{HCl}=\frac{22.0mL*0.200M}{0.15M}=29.3mL[/tex]
Now, we can see that the moles of acid, base and acidic salt are all:
[tex]0.0220L*0.200mol/L=0.0044mol[/tex]
And therefore the concentration of the salt at the equivalence point is:
[tex][HONH_3^+Cl^-]=\frac{0.0044mol}{0.022L+0.0293L} =0.0858M[/tex]
Next, for the calculation of the pH, we need to write the ionization of the weak part of the salt as it is able to form some hydroxylamine as it is the weak base:
[tex]HONH_3^++H_2O\rightleftharpoons H_3O^++HONH_2[/tex]
Whereas the equilibrium expression is:
[tex]Ka=\frac{[H_3O^+][HONH_2]}{[HONH_3^+]}[/tex]
Whereas Ka is computed by considering Kw and Kb of hydroxylamine:
[tex]Ka=\frac{Kw}{Kb}=\frac{1x10^{-14}}{9.10x10^{-9}} \\\\Ka=1.10x10^{-6}[/tex]
So we can write:
[tex]1.10x10^{-6}=\frac{x^2}{0.0858-x}[/tex]
And neglect the x on bottom to obtain:
[tex]1.10x10^{-6}=\frac{x^2}{0.0858}\\\\x=\sqrt{1.10x10^{-6}*0.0858}=3.07x10^{-4}M[/tex]
And since x=[H3O+] we obtain the following pH:
[tex]pH=-log(3.07x10^{-4})\\\\pH=3.513[/tex]
Regards!
Calculate the pH of a solution formed by mixing 550.0 mL of 0.30 M HClO with 275.0 mL of 0.20 M CsClO. The Ka for HClO is 2.9 × 10-8.
Answer:
pH = 7.08
Explanation:
We can solve this problem using Henderson-Hasselbach's equation:
pH = pKa + log[tex]\frac{[ClO^-]}{[HClO]}[/tex]With the given concentrations and volumes, we can calculate the new values for [ClO⁻] and [HClO] when the solutions are mixed:
Total volume = 550.0 mL + 275.0 mL = 825.0 mL[HClO] = 550 mL * 0.30 M / 825 mL = 0.20 M[ClO⁻] = 275 mL * 0.20 M / 825 mL = 0.07 MNow we calculate pKa:
pKa = -log(Ka) = 7.54Finally we calculate the pH:
pH = 7.54 + log[tex]\frac{0.07}{0.2}[/tex] = 7.08can u identify a chemical equation for the saponification of olive oil as per your experiment?
I
What is the molality of a 10.0 % by mass solution of NaCl?
(molar mass of NaCl = 58.44 g/mol)
mol/kg
On CK-12 all of these answers are correct
1.9
1.888
1.89
1.88
The molality of a 10.0 % by mass solution of sodium chloride (NaCl) is 1.7M.
How do we calculate molarity?Molarity of any solution will be calculated as number of moles of solutes present in per litre of the solution.
Moles of the substance will be calculated as:
n = W/M, where
W = given mass
M = molar mass
Given that percent mass of NaCl = 10% i.e. 10g of NaCl is present in 100 g of solution.
We know that 1 g = 0.001 L
100 g = 0.1 L
Moles of NaCl = 10g / 58.44g/mol = 0.17 mol
Molarity of NaCl = 0.17 / 0.1 = 1.7M
Hence required molarity is 1.7 M.
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I have to make this question longer so im just typing thisgjfgjfjvndfi nufnvfjnvfjnjn vnfj
(Go all the way to the bottom)
Don't forget to drink water
Answer:
Ok, thank you
Explanation:
Based on the graph, which statement about human use of natural resources is most likely false?
Hey love! <3
Answer:
C. Resource use by humans has gone up and down over the years is a false statement
Explanation:
In the graph you can make an observation on how the increase of human population is directly positive.
The resource use either has a positive or negative correlation, making it impossible for the usage to fluctuate over the years.
Hope this brightens up your day a little! ❀‿❀ Sincerely, Kelsey from Brainly.
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g You are given a 1.25 gram mixture of calcium nitrate and calcium chloride. You dissolve this mixture in 200.0 mL of water and add an excess of 0.300 M silver nitrate. You collect and dry the white precipitate which forms and find it has a mass of 0.535 grams. Calculate the percent calcium chloride by mass in the original mixture.
Answer:
16.51%
Explanation:
The reaction that takes place is
CaCl₂(aq) + 2AgNO₃(aq) → 2AgCl(s) + Ca(NO₃)₂(aq)Meaning that the white precipitate that formed is AgCl. Now we convert 0.535 g of AgCl into moles, using its molar mass:
0.535 g ÷ 143.43 g/mol = 0.00373 mol AgClThen we convert 0.00373 moles of AgCl into moles of CaCl₂, using the stoichiometric coefficients:
0.00373 mol AgCl * [tex]\frac{1molCaCl_2}{2molAgCl}[/tex] = 0.00186 mol CaCl₂We convert moles of CaCl₂ into grams, using its molar mass:
0.00186 mol CaCl₂ * 110.98 g/mol = 0.206 gFinally we calculate the percent of CaCl₂ by mass in the original mixture:
0.206 g / 1.25 g * 100% = 16.51%The percent calcium chloride by mass in the original mixture is 16.4%
The equation of the reaction between calcium nitrate and silver chloride is:
[tex]\mathbf{CaCl_2 + 2AgNO_3 \to 2 AgCl+Ca(NO_3)_2}[/tex]
Given that;
the weight mass of the white precipitate formed is = 0.535 gramsthe number of moles of the precipitated AgCl is:
= 0.535 g / 143.32 g/mol
= 0.0037 moles
From the above reaction, If 2 moles of AgCl are formed by 1 mole of CaCl2
Then, 0.0037 moles of AgCl will form (0.0037 × 1)/2 moles of CaCl2.
0.0037 moles of AgCl will form 0.00185 moles of CaCl2.
Now, we can say that the number of moles of CaCl2 present in the mixture is = 0.00185 moles
Mass amount of CaCl2 present = 0.00185 moles × 110.98 g/mol
Mass amount of CaCl2 present = 0.205 grams
Finally, the mass percentage [tex]\mathbf{=\dfrac{0.205}{1.25}\times 100\%}[/tex]
= 16.4%
Therefore, we can conclude that the percent calcium chloride by mass in the original mixture is 16.4%
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what is the molecular formula of a compound with the empirical SO and molecular weight 96.13?
Answer:
Explanation: A compound with the empirical formula SO has a molecular weight of 96.13
what climate is Colorado in?
A.Most Subtropical Mid-Latitude
B.Polar
C.Moist ContinentaMid-Latitiude
D.Dry
Answer:
b
Explanation:
Answer:
D. Dry
Explanation:
Colorado's combination of high elevation, midlatitude, and continental interior geography results in a cool, dry climate.
Select the correct term(s) to complete each sentence. a) The ____ is assigned a relative intensity of 100. base peak molecular ion peak b) The ____ is the most intense peak in the mass spectrum. molecular ion peak base peak c) The ____ represents the original molecule that has only lost an electron. molecular ion peak base peak d) ____ could be/represent a smaller, charged fragment of the original molecule. The base peak The molecular ion A radical cation e) ____ is/represents a positively charged species. The base peak The parent ion The molecular ion A radical cation
Answer:
a) Base Peak
b) Base Peak
c) Molecular Ion
d) Base Peak and Radical Cation
e) The Parent Ion, Molecular Ion, the Radical Cation and the Base Peak
Explanation:
a) The Base Peak is assigned a relative intensity of 100.
b) The Base Peak is the most intense peak in the mass spectrum.
c) The Molecular Ion Peak represents the original molecule that has only lost an electron.
d) Base Peak and Radical Cation could be/represent a smaller, charged fragment of the original molecule.
e) The Parent Ion, the Molecular Ion, the Radical Cation/ the Base Peak is/represents a positively charged species.
Practice: A gas reaction is allowed to take place in a canister while submerged in water at a temperature of 25oC. The gas expands and does P-V work on the surroundings equal to 385 J. At the same time, the temperature of the water decreases to 20oC as the energy in the gas reaction reaches 364 J. What is the change in energy of the system
Answer:
change in energy of the system = - 21 J
Explanation:
Δu = q + w
q = 364 J
w = - 385
Temperature of system drops from 25°c to 20°c
hence
Δu ( change in energy ) = q - w
= 364 - 385
= -21 J
Select the correct answer.
The presence of which ion will not affect the pH of a solution?
A.
OH-
B.
H3O+
C.
H+
D.
Na+
Answer:
D. Na+
Explanation:
Na+ is the only ion here that is not related to pH. Adding OH- increases pH, and adding H3O+ or H+ (the two are interchangeable) decreases pH.
If 5.00 g of O2 gas has a volume of 7.20 L at a certain temperature and pressure, what volume does 15.0 g of O2 have under the same conditions?
The volume 15.0 g of O₂ has at a certain temperature and pressure is 2.16 L.
What is volume?Volume is the space occupied by a three-dimensional object.
By the law of dilution
M₁/V₁ = M₂/V₂
Mass 1 is 5.00
Volume 1 is 7.20 L
Mass 2 15.0 g
Volume 2 is to find
Putting the value in the equation
5.00/ 7.20 = 15.0 / V₂
V₂ = 7.20 × 15.00/ 5.00 = 21.6
Thus, the volume will be 21.6 L.
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A buffered solution is made by adding 50.0g NH4Cl to 1.00 L of a 0.75M solution of NH3. Calculate the pH of the final solution. (assume no volume change).
Answer:
9.15
Explanation:
To solve this problem we'll use Henderson-Hasselbach's equation:
pH = pKa + log[tex]\frac{[A^-]}{[HA]}[/tex]For this problem:
pH = 9.25 + log[tex]\frac{[NH_3]}{[NH_4Cl]}[/tex]Now we calculate [NH₄Cl], first by converting 50.0 g of NH₄Cl into moles using its molar mass:
50.0 g NH₄Cl ÷ 53.491 g/mol = 0.935 molMeaning that [NH₄Cl] = 0.935 mol / 1.00 L = 0.935 M
Finally we calculate the pH:
pH = 9.25 + log[tex]\frac{0.75M}{0.935 M}[/tex] = 9.15The pH can be defined as the hydrogen ion concentration in the solution. The pH of ammonium chloride solution in ammonia is 9.16.
What is molarity?The molarity is the moles of a compound in the liter of solution. The molarity of 50 grams ammonium chloride in a liter of solution is given as:
[tex]\rm Molaity=\dfrac{mass}{molar\;mass\;\times\;volume(L)} \\\\NH_4Cl\;Molarity=\dfrac{50\;g}{53.491\;g/mol\;\times\;1\;L} \\\\NH_4Cl\;Molarity=0.935\;M[/tex]
The ammonia in the solution contributes to the pH from the ammonium chloride salt. The pH can be given as:
[tex]\rm pH=pKa+log\dfrac{acid}{salt}[/tex]
The pKa of ammonia is 9.25. The concentration of ammonia is given as 0.75 M.
The pH of the solution can be given as:
[tex]\rm pH=9.25+log\dfrac{0.75\;M}{0.935}\\ pH=9.25+(-0.09)\\pH=9.16[/tex]
The pH of the solution is 9.16.
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What tides are at the points on Earth indicated by the letters?
A. high tide (A,C)
B. high tide (B,D)
C. Low tide (B,C)
D. Low tide (A,C)
Answer:
it is A tide (A,C)
Explanation:
i just took the test and tried c and it was a plzzzzz put a btw it was my test lol
ASAP pleas
Which of the following pair of elements are found as diatomic gaseous molecules in nature?
a)carbon and chlorine
b) sulfur and oxygen
c) oxygen and hydrogen
d) Nitrogen and Neon
what is heterogenous mixture
Answer:
heterogeneous mixture is a mixture that is non-uniform and contains smaller component parts.
Answer:
heterogenous mixture is type of mixture
Explanation:
it is one type of mixture involve in the mixture of different or hetro substance and can also easely separated or seen by naked eye example mixture of water and sand
4.50 g of Nacl react with 10.00 g of Agno3 to produce 7.93 g of Agcl.if the theroretical amount of agcl that can be formed is 8.43 g what is the percent yield
The second law of thermodynamics can be worded in different ways, such as a.) heat can flow spontaneously from a hot object to a cold object, or b.) the total entropy of any system plus that of the environment increases as a result of natural processes. Why are these statements equivalent
Answer:
Explanation:
The principal reason why these statements are equivalent and identical is that there can be a progressional flow of heat from a hot object item to a cold object because of this entropy is increasing and expanding Δg < 0 but stream flow from cold to hot is nonspontaneous as Δg > 0.
e.g [tex]dS = \dfrac{\delta Q}{T}[/tex]
As found in heat engines and refrigerators.
Help please it is due soon
Answer:
it's the amount of energy released by an earthquake
Precipitation that falls to earth sometimes soaks into the soul and becomes____.
Answer:
not sure but i think the answer is A
Which of the following phase changes is exothermic?
gas to solid
solid to liquid
solid to gas
liquid to gas