Answers
Answer:
The value of [tex]\theta=63.43^0[/tex]
Explanation:
Range of projectile [tex]\mathrm{R}=\frac{\mathrm{u}^{2} \cdot \sin 2 \theta}{\mathrm{g}}[/tex]
Height of projectile [tex]\mathrm{h}=\frac{\mathrm{u}^{2} \cdot \sin ^{2} \theta}{2 \cdot \mathrm{g}}[/tex]
Here we have
[tex]R=2h\\\\\frac{\mathrm{u}^{2} \cdot \sin 2 \theta}{\mathrm{g}}=2\frac{\mathrm{u}^{2} \cdot \sin ^{2} \theta}{2 \cdot \mathrm{g}}\\\\\sin 2 \theta=\sin ^{2} \theta\\\\2\sin \theta\cos \theta=\sin ^{2} \theta\\\\\tan \theta=2\\\\\theta=63.43^0[/tex]
Range be R and height be h
[tex]\boxed{\sf R=\dfrac{u^2sin2\theta}{g}}[/tex]
[tex]\boxed{\sf h=\dfrac{u^2sin^2\theta}{2g}}[/tex]
u=initial velocitytheta is angle of projection.g=acceleration due to gravityATQ
[tex]\\ \sf\longmapsto R=2h[/tex]
[tex]\\ \sf\longmapsto \dfrac{u^2sin2\theta}{g}=\dfrac{2u^2sin^2\theta}{2g}[/tex]
Cancelling required ones[tex]\\ \sf\longmapsto sin^2\theta=sin2\theta[/tex]
sin2O=2sinOcosO[tex]\\ \sf\longmapsto sin^2\theta=2sin\theta cos\theta [/tex]
[tex]\\ \sf\longmapsto \dfrac{sin^2\theta}{sin\theta cos\theta=2[/tex]
[tex]\\ \sf\longmapsto \dfrac{sin\theta}{cos\theta}=2[/tex]
[tex]\\ \sf\longmapsto tan\theta=2[/tex]
[tex]\\ \sf\longmapsto \theta=tan^{-1}(2)[/tex]
[tex]\\ \sf\longmapsto \theta=63.4°[/tex]
Related Questions
A crate slides down a ramp that makes a 20∘ angle with the ground. To keep the crate moving at a steady speed, Paige pushes back on it with a 68 N horizontal force.
Part A
How much work does Paige do on the crate as it slides 3.0 m down the ramp?
Answers
Answer:
the answer is 69.7687j
Explanation:
W =F sin Φ
Which metals can be extracted from following ores (i) Argentite (ii) Haematite (iii) Chalcopyrite (iv) Bauxite
Answers
I hope it's helpful for you ☺️
1) iron
2) aluminium
3) silver
4) copper
Read the excerpt from The Building of Manhattan.
A temporary, small narrow-gauge track system was installed on each floor as it was needed. This enabled the material to be moved from the truck at ground level onto dump carts, raised by elevator to the designated floor, wheeled onto the track, and moved quickly to the exact spot needed. Turntables built into the track allowed the carts to be shifted about in any direction.
Which question can be answered only if an illustration accompanies the text?
What did turntables built into the track allow?
How were dump carts raised to designated floors?
When was a track system installed on a floor?
What does a turntable built into a track loo
Answers
Answer: this would be D.) What does a turntable built into a track look like
Explanation:
A wave has wavelength of 10 m and a speed of 340 m/s. What is the frequency of the wave?
I need the Formula,Known,Substitute & Solve Answer with Units
Answers
Answer:
This is the answer that I got.
Explanation:
Hope it is right.
Question 17 (Essay Worth 5 points)
(02.06 HC)
Choose two spheres of Earth which interact when hot springs are formed. Use complete sentences to explain how they interact during this process
X2
= 12 Source
ус
cM
В І
U S XX T
.
Styles
Format
Font
Size
A- A -
Increase Indent
Answers
Answer:
geosphere and hydrosphere
Explanation:
A 1000 kg car and a 1500 kg car are driving in opposite directions at 20 m/s and 10 m/s respectively. If the cars collide head-on and stick together, determine their combined speed after the collision.
Answers
Hi there!
Recall the conservation of momentum for an inelastic collision:
[tex]\large\boxed{m_1v_1 + m_2v_2 = (m_1 + m_2)v_f}}[/tex]
Remember, velocity is a VECTOR and direction must be accounted for. Let the 1000 kg car have a positive velocity and the 1500 kg car have a negative velocity (opposite direction).
Plug in the given values:
[tex](1000)(20) + (1500)(-10) = (1000 + 1500)v_f}}[/tex]
Solve:
[tex]20000 -15000 = 2500v_f}}\\\\5000 = 2500v_f\\\\v_f =\boxed{ 2 m/s}[/tex]
The mass of a car is 2000 lbs, and is traveling 100 mi/hr on the freeway, what is its momentum?
Answers
Answer:
momentum= 145999324.8(kg(m/s))
Explanation:
formula for momentum: p=mv
where p= momentum, m=mass, and v=velocity.
p=2000lbs(100mi/hr)
The standard unit for mass is kg
2000lbs=907.2kg
standard unit for velocity is meters/sec
100mi=160934meters.
907.2kg(160934m/s)=145999324.8
Name the force used in removing iron scrap from a heap of mixed scrap. (a) Magnetic Force (b) Electrostatic force (c) Gravitational force (d) Friction Force
Answers
Answer:
magnetic force
Explanation:
because iron is magnetic so magnet is able to attract iton
if A and B are non zero vectors, is it possible for vector A×vector B and vector A.vector B both to be zero? Justify your answer
Answers
Answer:
not able to understand the question
define one kilogram mass
Answers
Answer:
kg - one thousand grams; the basic unit of mass adopted under the Systeme International d'Unites; "a kilogram is approximately 2.2 pounds"
Explanation:
HELPPP PLEASE
1) if the distance between two masses are 15 meters and the masses are 350kg and 492 kg
respectively; what is the magnitude of gravitational force?
Answers
Answer:
-8
5.092×10
Explanation:
given,
distance (d) =15m
mass (M1) =350kg
mass(M2) = 492kg
Gravitational constant (G)=6.67×10^-11
we know,
gravitational force=(Gm1m2)÷d^2
=(6.67×10^-11×350×492)÷15^2
= (1.14857×10^-5)÷225
= 5.092×10^-8
PLEASE HELP also i know this isnt physics but there was no HOPE/Gym subject for me to choose.
Answers
Answer:
Plan B.
Because flexibility is best improved by stretching.
Explanation:
Improving and increasing flexibility is done by having stretching sessions daily which maintains and widens the range of motion in the joints and stretches muscles.
A 2,000 kg car, initially traveling at a speed of 15 m/s, is accelerated by a constant force of 10,000 N for 3 seconds. The new speed of the car is
Answers
Answer:
The new speed of the car is 30 m/s.
Hope you could get an idea from here.
Doubt clarification - use comment section.
A 1,500 kg car is traveling at 25 m/s. The driver suddenly applies the brakes causing the car to skids to a stop. If the average braking force between the tires and the road is 7,100 N, how far does the car slide before it comes to rest?
Answers
By Newton's second law, the car slows down with an average acceleration a such that
-7100 N = (1500 kg) a ⇒ a ≈ -4.7 m/s²
If we treat the car as accelerating uniformly with this magnitude, then the car slides a distance ∆x such that
0² - (25 m/s)² = 2a ∆x ⇒ ∆x ≈ 66 m
The car slide before it comes to rest will be 66 m. Newton's second equation of motion is applied in this problem.
What is force?Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body.
Force is defined as the product of mass and acceleration. Its unit is Newton.
The acceleration is found as;
F=ma
-7100 N = (1500 kg) a
a= -4.7 m/s²
If we assume that the automobile accelerates uniformly with this magnitude, the car slides x distance. From the Newton's second equation of motion;
v²=u²+2as
v²-u²=2as
0² - (25 m/s)² =2×(-4.7) s
s=66 m
Hence,the car slide before it comes to rest will be 66 m.
To learn more about the force, refer to the link;
https://brainly.com/question/26115859
#SPJ2
what planets experience an eclipse from the sun
Answers
Answer:
Earth
Explanation:
The sun and the moon come together and they seem like one bonded.
is atom on the offficial repository of ubuntu ?
Answers
Answer:
Atom, the cross-platform, open source code editor developed by Github, has become quite popular thanks to its plug-ins and embedded Git Control. ... There are, however, official Atom repositories for some Linux distributions, like Ubuntu, Debian, Fedora, Red Hat, CentOS, and open.
if a 5kg ball is traveling at 20 m/s and it’s stopped in 4s, what’s the impulse on the ball?
Answers
F(4)=(5)(20)
F= 100/4
F= 25 N
An experiment is conducted such that an applied force is exerted on a 5kg object as it travels across a horizontal surface in which frictional forces are NOT considered to be negligible. A graph of the net force exerted on the object as a function of the object’s distance traveled is shown. How could a student use the graph to determine the net work done on the object?
Answers
If an experiment is conducted such that an applied force is exerted on an object, a student could use the graph to determine the net work done on the object.
The graph of the net force exerted on the object as a function of the object’s distance traveled is attached below.
A student could use the graph to determine the net work done on the object by Calculating the area bound by the line of best fit and the horizontal axis from 0m to 5mFor more information on work done, visit
https://brainly.com/subject/physics
Answer:
D. There is not enough information that is known or can be obtained from the graph to determine the net work done on the object.
Explanation:
it’s the answer For Ap classroom
Can someone help with 25 to 28 it’s multiple-choice!
Answers
Answer:
25:speed
26:acceleration
27:scalar
28:kinetic
1)A chocolate bar measures 10 cm long by 2 cm wide and is 2 cm thick
a)Calculate the volume of one bar.
b)How many bars each 2 cm long, 2 cm wide and 2cm thick have the same total volume?
c)A pendulum makes 10 complete oscillations in 8 seconds. Calculate the time period of the pendulum
Answers
Answer:
40cm³
Explanation:
I only have an answer to 1a
Volume = Length X breadth X height
where;
length = 10cm
breadth = 2cm and;
width = 2cm
*Find*
V = ?
V = L X B X H
V = 10 X 2 X 2
= 40cm³✓
A 600g toy train completes 10 laps of its circular track in 1 min 20s. If the radius of the track is 1.2 m, Find the speed of the train in m/s.
Answers
Answer:
0.236 m/s² (rounded)
Explanation:
Anyone please help thank you
Answers
Answer:
A) earth
B) live
C) live
D) earth
Explanation:
hope i help
A 0.24 kg mass with a speed of 0.60 m/s has a head-on collision with a 0.26 kg mass that is traveling in the opposite direction at a speed of 0.20 m/s. Assuming that the collision is perfectly inelastic, what is the final speed of the combined masses?
Answers
The final speed of the combined masses is 0.186m/s
According to the law of collision, the sum of the momentum of the bodies before the collision is equal to the momentum after the collision.
Mathematically;
m1u1 - m2u2 = (m1+m1)v
v is the final speed of the combined masses.Substituting the given parameters;
0.24(0.6) - 0.26(0.2) = (0.24+0.26)v
0.144 - 0.052 = 0.5v
0.092 = 0.5v
v = 0.092/0.5
v = 0.184m/s
Hence the final speed of the combined masses is 0.186m/s
Learn more on collision here: https://brainly.com/question/7538238
Describe the relative energies of particles in the
different States of matter.
Answers
Answer:
MATTER
ARE
OF
THREE
TYPES
SOLID
LIQUID
GAS
how is one kg mass defined in SI system
Answers
Answer:
It is originally defined as the mass of one liter (10-3 cubic meter) of pure water.
me (5) A taxi is travelling at 15. m/s. Its driver accelerates with acceleration 3 m/s for 4 s. What is its new velocity? A car accelerates from 20 m/s to 30 m/s in 10 (a) Calculate the car's acceleration using v=utat. (b) Draw a velocity-time graph to show the car's motion. Find the distance it travels by calculating the area under the graph. (c) Check your answer by using the equation s = ut + hat Grade 9
Answers
Answer:
5)
Solution
initial velocity = 15 m/s
acceleration = 3m/s^2
time = 4 s
final velocity = 15+3×4
=15+12
=27m/s
A car accelerates from 20m/s to 30m/s in 10 second
T9 be honest I think some part of the second question is missing
Select the correct answer. What are the directions of an object's velocity and acceleration vectors when the object moves in a circular path with a constant speed? A. The question is meaningless, since the acceleration is zero.
B. The vectors point in opposite directions.
C. Both vectors point in the same direction.
D. The vectors are perpendicular.
Answers
The centripetal acceleration which always act toward the center of the circle. The vectors are perpendicular. The correct answer for this question, is option D
The speed of an object is always constant in a circular motion while the object keeps changing direction regularly. The velocity will keep changing because of the change in direction.
Whenever there is a change in velocity, there must be acceleration.
When the object is moving in a circular path with a constant speed, the directions of an object's velocity and acceleration vectors will be perpendicular to each other
The reason is because acceleration is centripetal acceleration which always act toward the center of the circle.
Therefore, the correct answer for this question, is option D
Learn more about circular motion here: https://brainly.com/question/10493657
two forces of magnitude 12 n and 24 n act at the same point. which force cannot be the resultant of these forces?
Answers
The force that cannot be the resultant of these forces is 10N since it is less than both given forces
Given the forces with a magnitude of 12N and 24N, the resultant of these forces must not be less than any of the two forces.
From the given options, the only force that is less than both 12N and 24 N is 10N. Hence the force that cannot be the resultant of these forces is 10N since it is less than both given forcesLearn more on resultant force here: https://brainly.com/question/14626208
0. Kedija walked 300m from A to B and returned back and walked 200m and then stopped at 'C', what
is her change in position from A to in the figure below
300m
200m
A
С
B
C/-500m
D 100m
B/ -100m
A Soom
Answers
Answer:
100
Explanation:
Displacement is the shortest line between the starting point and the ending point
so , the starting point is "A"
,the ending point is "C"
so "AC" = AB - CB = 300 - 200 = "100"
A cheetah runs at an average speed of 60mph. find the distance it runs in 30 s
Answers
Answer:60mph means it runs every minute.
Explanation: because it makes sense.
Answer:
2640 ft, or 1/2 mile
Explanation:
Recognizing that 30 s = 0.5 min, we can convert the units like this.
distance = speed × time
distance = (60 mi/h) × (1 h/(60 min)) ×(0.5 min) = 0.5 mi
In feet, that is ...
(5280 ft/mi)(0.5 mi) = 2640 ft
A cheetah runs 1/2 mile, or 2640 feet in 30 s.