Can someone help answer this 6th grade question?

For the integral ∫asin(x)dx, use integration by parts ∫udv=uv−∫vdu.

Let u=asin(x) and dv=dx.

Then du=(asin(x))′dx=[tex]\rm \dfrac{dx}{ \sqrt{1 - {x}^{2} } } [/tex] and v=∫1dx=x

So,

[tex] \rm{\int{\operatorname{asin}{\left(x \right)} d x}}=\color{h}{\left(\operatorname{asin}{\left(x \right)} \cdot x-\int{x \cdot \frac{1}{\sqrt{1 - x^{2}}} d x}\right)}=\color{h}{\left(x \operatorname{asin}{\left(x \right)} - \int{\frac{x}{\sqrt{1 - x^{2}}} d x}\right)} \\ [/tex]

Let u=1−x2.

Then du=(1−x2)′dx=−2xdx and we have that xdx=−du/2.

The integral can be rewritten as

[tex] \rm x \operatorname{asin}{\left(x \right)} - \color{g}{\int{\frac{x}{\sqrt{1 - x^{2}}} d x}} = x \operatorname{asin}{\left(x \right)} - \color{j}{\int{\left(- \frac{1}{2 \sqrt{u}}\right)d u}} \\ [/tex]

Apply the constant multiple rule ∫cf(u)du=c∫f(u)du with c=-1/2 and f(u)=[tex] \frac{1}{ \sqrt{u} } [/tex]

[tex] \rm x \operatorname{asin}{\left(x \right)} - \color{h}{\int{\left(- \frac{1}{2 \sqrt{u}}\right)d u}} = x \operatorname{asin}{\left(x \right)} - \color{h}{\left(- \frac{\int{\frac{1}{\sqrt{u}} d u}}{2}\right)} \\ [/tex]

Apply the power rule

[tex] \rm\int u^{n}\, du = \frac{u^{n + 1}}{n + 1} \\ [/tex]

with n=−1/2

[tex] \rm x \operatorname{asin}{\left(x \right)} + \frac{\color{h}{\int{\frac{1}{\sqrt{u}} d u}}}{2}=x \operatorname{asin}{\left(x \right)} + \frac{\color{j}{\int{u^{- \frac{1}{2}} d u}}}{2}=x \operatorname{asin}{\left(x \right)} + \frac{\color{j}{\frac{u^{- \frac{1}{2} + 1}}{- \frac{1}{2} + 1}}}{2}=x \operatorname{asin}{\left(x \right)} + \frac{\color{j}{\left(2 u^{\frac{1}{2}}\right)}}{2}=x \operatorname{asin}{\left(x \right)} + \frac{\color{h}{\left(2 \sqrt{u}\right)}}{2} \\ [/tex]

[tex] \rm Recall \: that  \: u=1− {x}^{2} [/tex]

[tex] \rm x \operatorname{asin}{\left(x \right)} + \sqrt{\color{re}{u}} = x \operatorname{asin}{\left(x \right)} + \sqrt{\color{rd}{\left(1 - x^{2}\right)}} \\ [/tex]

Therefore,

[tex] \rm\int{\operatorname{asin}{\left(x \right)} d x} = x \operatorname{asin}{\left(x \right)} + \sqrt{1 - x^{2}}+C \\ [/tex]

Answer:

me sandip is a jokeerrrr..........

Step-by-step explanation:

no god sucks......... **** brainly

[tex]\bold{\huge{\underline{ Solution }}}[/tex]

Here,

The dimension of larger cuboid are

We know that,

Lateral surface area of cuboid

[tex]\bold{\red{ = 2( lb + bh + hl)}}[/tex]

Subsitute the required values,

[tex]\sf{ = 2[(7)(7) + (7)(12) +(7)(12) ]}[/tex]

[tex]\sf{ = 2[ 49 + 84 ]}[/tex]

[tex]\sf{ = 2[ 49 + 168 ]}[/tex]

[tex]\sf{ = 2[ 217 ]}[/tex]

[tex]\bold{ = 434 cm^{2}}[/tex]

We have to find the lateral surface area of smaller cuboid

Therefore,

Lateral surface area of smaller cuboid

[tex]\sf{ = 2[(2)(7) + (7)(2) +(2)(2) ]}[/tex]

[tex]\sf{ = 2[ 14 + 14 + 4 ]}[/tex]

[tex]\sf{ = 2[ 28 + 4 ]}[/tex]

[tex]\sf{ = 2[ 32]}[/tex]

[tex]\bold{ = 64 cm^{2}}[/tex]

The common base area of both the cuboids

[tex]\sf{ = lb }{\sf{ + lb}}[/tex]

[tex]\sf{ = 14 + }{\sf{ 14}}[/tex]

[tex]\bold{ = 28 cm^{2}}[/tex]

The total surface area of the given composite figure

= SA of larger cuboid + SA of smaller cuboid - common base area

Subsitute the required values,

[tex]\sf{ = 434 + 64 - 28 }[/tex]

[tex]\sf{ = 498 - 28 }[/tex]

[tex]\bold{ = 470cm^{2}}[/tex]

Hence, The surface area of composite figure is 470 cm² .

Answer:

470cm²

Step-by-step explanation:

SA= (12*7)*4+(7*7)*2+(2*2)*2+(7*2)*2

=336+98+8+28

= 470 cm²

Therefore, the surface ares is 470 cm².

~

[tex]~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$8911\\ r=rate\to 7.71\%\to \frac{7.71}{100}\dotfill &0.0771\\ t=years\dotfill &20 \end{cases} \\\\\\ A=8911e^{0.0771\cdot 20}\implies A=8911e^{1.542}\implies A\approx 41649.38[/tex]

Answer:

x=1/3

Step-by-step explanation:

Answer:

the slope is −12

Step-by-step explanation:

The equation of a perpendicular line to y=−x2+5 y = - x 2 + 5 must have a slope that is the negative reciprocal of the original slope.

-1/2

That would be the answer

Answer:

Step-by-step explanation:

The formula for calculating the volume of a right triangular prism is:

Let's use the formula to calculate the volume of the right triangular prism.

Answer: 0.29

Step-by-step explanation:

The probability of the first being blue is 6/17, the second is 5/16 and the third is 4/15.  Multiply these together to get the total probability:

6/17 x 5/16 x 4/15 = .029

Answer:

I don't know-how to answer that

Answer:

-1

Step-by-step explanation:

5-2=3

2-3=-1

Answer:

=−148

     3

(Decimal: -49.333333)

Step-by-step explanation:

−364

9

−(

−102

9

)−

182

9

Answer:

36 Minutes

Step-by-step explanation:

150/8=18.75

675/18.75=36

So hence, your answer is 36 Minutes

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Thanks!

Mark me brainliest!

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Answer:

40

Step-by-step explanation:

Angles opposite congruent sides in a triangle are congruent, so the other base angle is also 70 degrees.

This means that the interior angles are 70, 70, and x

Since the sum of the measures of the angles of a triangle is 180 degrees,

70+70+x=180

140+x=180

x=40

Answer:

none

Step-by-step explanation:

plug it in, it doesnt add up

Answer:

1110 g

Step-by-step explanation:

Here is the fastest way to solve this problem: (5 x 186) + (2.5 x 72)

However, if you want a step-by-step explanation, here it is:

The total mass of the coins in the bag is the mass of the nickels plus the mass of the pennies.

Let's start by finding the mass of the nickels in the bag.

We know that one nickel has a mass of 5 g, and that there are 186 nickels. So, the total mass of all the nickels in the bag will be 186 x 5 = 930 g.

Now, let's find the mass of the pennies in the bag.

We know that one penny has a mass of 2.5 g, and that there are 72 pennies in the bag. So, the total mass of all the pennies in the bag will be 2.5 x 72 = 180.

We now add these two masses (930 + 180) to get our final answer, 1110 g.

Answer:

I am pretty sure it is

y >_ 20(0.061)^t

t >_ 0

Step-by-step explanation:

Answer:

Probability of drawing a yellow candy: 10/36= 5/18

Something besides a yellow candy: for ecample: the red candies: 8/36= 2/9

Step-by-step explanation:

Probability of drawing yellow candies equals the sum of candies over yellow candies.

Answer:

For number question #8 its 8/3

Step-by-step explanation:

One way i do is multiply the denominator by the whole number and then add the numerator . For example 2 2/3

2x3=6     6+2=8

Do NOT change the numerator, it stays the same.

common denominator = 7x11 = 77

5/7 = (5x11) / (7x11) = 55/77

and

8/11 = (8x7) / (11x7) = 56/77

5/7 and 8/11 can be rewritten as 55/77 and 56/77, respectively, so that they have a common denominator of 77.

An element of a whole is a fraction. The number is represented mathematically as a quotient, where the numerator and denominator are split. Both are integers in a simple fraction. A fraction appears in the numerator or denominator of a complex fraction. The numerator of a proper fraction is less than the denominator.

To rewrite 5/7 and 8/11 with a common denominator:

We can find the least common multiple (LCM) of the denominators 7 and 11, which is 77.

Then, we can multiply each fraction by the appropriate form of 1 so that the denominators are equal to 77.

Here are the steps:

5/7 = (5/7) x (11/11) = 55/77 (multiply the numerator and denominator of the first fraction by 11)

8/11 = (8/11) x (7/7) = 56/77 (multiply the numerator and denominator of the second fraction by 7)

Therefore, 55/77 and 56/77 are the required fractions.

To learn more about fractions;

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Answer:

7.011%

Step-by-step explanation:

61/(300+100+7+61+402) = 0.07011

Multiply the result of that by 100 to get 7.011%.

Answer:

60

Step-by-step explanation:

east and north are two axis that are perpendicular to each other, so if we use Pythagorean rule, sqr60^2+20^2=20sqr10, approximately 63.24555

[tex]f(x) = \sqrt{7 + x} [/tex]

[tex]7 + x \geqslant 0[/tex]

[tex]x \geqslant - 7[/tex]

[tex]domain \: - 7 \leqslant x \leqslant \infty [/tex]

[tex]range \: \: 0 \leqslant f(x) \leqslant \infty [/tex]

Origin = [tex](0, 0)[/tex]

Point = [tex](-18, 24)[/tex]

Distance = [tex]\sqrt{(24 - 0)^2 + (-18 - 0)^2} = \sqrt{24^2 + (-18)^2} = \sqrt{576 + 324} = \sqrt{900} = 30[/tex]

The distance from the origin to the point (-18, 24) is 30 units.

To find the distance from the origin (0, 0) to the point (-18, 24), we can use the distance formula in two-dimensional Cartesian coordinates.

The distance formula between two points [tex](x_1, y_1) and\ (x_2, y_2)[/tex] is given by:

[tex]\[d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\][/tex]

In this case, the coordinates of the origin are (0, 0) and the coordinates of the point are (-18, 24). Plugging these values into the distance formula, we get:

[tex]\[d = \sqrt{(-18 - 0)^2 + (24 - 0)^2} = \sqrt{(-18)^2 + 24^2} = \sqrt{324 + 576} = \sqrt{900} = 30\][/tex]

So, the distance from the origin to the point (-18, 24) is 30 units.

To know more about distance, refer here:

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Answer:

1:4

Step-by-step explanation:

To represent 14:56 as a simplified ratio, we need to reduce it by finding the GCF (greatest common factor) and dividing it by both terms.

The GCF of 14 & 56 is 14.

14 / 14 = 1

56 / 14 = 4

Thus we are left with our new simplified ratio, 1:4.

The volume of the rectangular prism with the dimensions given are as follows:

v = 72 inches³

v = 36 inches³

v =  80 inches³

v = 54 inches³

where

l = length

w = width

h = height

Therefore,

a.  

b.

c.

d.

learn more on rectangular prism here: https://brainly.com/question/13512346

Answer:

$20

Step-by-step explanation:

The large ones cost $4 more so what you would do is to subtract that $4 from the $24.

24-4=20

Answer:

hello the data required is missing attached below is the missing data and solution

Answer : Fail to reject H[tex]_{0}[/tex] and conclude that the mean value of weight 1 is the same for Managers and supervisors in the population

Step-by-step explanation:

At 5% level of significance the conclusion of this test is  Fail to reject H[tex]_{0}[/tex] and conclude that the mean value of weight 1 is the same for Managers and supervisors in the population.

The value of the test statistic tcal = 0.7402 lies between the critical values

±[tex]t_{\frac{0.05}{2.2} }[/tex] = ±2.086

attached below is the detailed solution and missing part of the question