can someone please answer both

Can Someone Please Answer Both

Answers

Answer 1

Answer:

2.16•x is up ur function

21. 6 feet in 10 minutes

Step-by-step explanation:

when u multiply by ten u move the decimal to the right one place

Answer 2

Answer:

this is what u need .........

Can Someone Please Answer Both

Related Questions

consider this algebraic expression:

5 + 3x – 1 + 4x

Use the algebra tiles to collect like terms.

What is the simplified expression?

Answers

Answer:

7x+4

Step-by-step explanation:

mark me brainliest pls

PLEASE HELP(I’ll mark your answer as the Brainiest! & 11points) can someone please do numbers 1-3 Find the angle measure. Tell which postulate or theorem you use, thank you in advance!❤️

Answers

Answer:

1. m<5 = 114

2. m<6 = 68

3. m<2 = 64

Step-by-step explanation:

Question 1:

<1 = <4 because of Vertical Angles Theorem

< 4 = <5 because of Alternate Interior Angles Theorem

Hence, <1 = <5

Since m<1 = 114: m<5 = 114.

Question 2:

<3 = <6 because of Alternate Interior Angles Theorem

Since m<3 = 68: m<6 = 68

Question 3:

<2 = <7 because of Alternate Exterior Angles Theorem

Since m<7 = 64: m <2 = 64

Hope this helped! If not, let me know! <3

Turn 2 1/8 into an improper fraction. Explain your steps

Answers

Answer:

17/8

Step-by-step explanation:

2 1/8    multiply 2 times 8 and 1 which equals to 17/8. The whole number times the denominator plus the numerator basically.

Answer:

17/8

Step-by-step explanation:

8 x 2 = 16

16 + 1 = 17

How many solutions does the equation have?
3(d+11) = 6(d +33)
O 0
O 1
O infinitely many

Answers

9514 1404 393

Answer:

  1 solution

Step-by-step explanation:

The coefficients of d are different on the two sides of the equation (3d vs 6d), so the equation has one solution.

__

Dividing by 3 gives ...

  d +11 = 2(d +33)

  d + 11 = 2d + 66

Adding -d-66 to both sides gives ...

  -55 = d . . . . . . the one solution

Answer:

The answer is B

Step-by-step explanation:

i took the test and 1 was correct so.

what value is equivalent to 13 - 2(1 - 15) divided by 14

Answers

Answer:

15

Step-by-step explanation:

Following PEMDAS you would do the equation in the parentheses first.

1 - 15 = -14

13 - 2  ⋅ (-14) divided by 14

-2 ⋅ (-14) = 28

13 + 28 divided by 14

28 divided by 14 = 2

13 + 2 = 15

Your answer is 15

Hope I helped :)

Please consider Brainliest :)

pls help with number 7. and 8.

Answers

Answer:

One pair of gloves cost $5.89

Step-by-step explanation:

You just have to divide 29.45 by 5 and that gives you how much one pair of gloves cost

Factorise fully
-x - 8


please do quick! will mark brainiest!​

Answers

Answer:

-(x+8)

Step-by-step explanation:

-x - 8

-1 *x -1 * 8

Factor out a -1

-1(x+8)

-(x+8)

Answer:

-1(x+8)1(-x -8)

Step-by-step explanation:

[tex] - x - 8[/tex]

Factor out common term : -1

[tex] - 1(x + 8)[/tex]

How is 5 represented in 6.75

Answers

Answer:

5 is in the hundreths place :))

Step-by-step explanation:

Answer:

0.05

Step-by-step explanation:

since the place value of the five is beyond the decimal point, and it is the second number beyond the decimal point, so it is in the hundredths place.

Plz help me it’s geometry

Answers

I can’t see the picture

Solve problem:
8-6•4+10/2

Answers

Answer:

[tex]8 - 6 \times 4 + \frac{10}{2} \\ = 8 - 6 \times 4 + 5 \\ = 8 - 24 + 5 \\ = 8 + 5 - 24 \\ = 13 - 24 \\ = - 11[/tex]

it is 200% correct answer..

It helps you ☺️

Thank you ☺️

The Fashion Store has $6000 available each month for advertising. Newspaper ads cost $200 apiece and no more than 20 can be run per month. Radio ads cost $100 each and no more than 30 can run per month. TV ads cost $800 a piece, with a maximum of 7 available each month. Approximately 1000 women will see each newspaper ad, 800 will hear each radio ad, and 14,000 will see each TV ad. How much of each type of advertising should be used if the store wants to maximize exposure?

Answers

9514 1404 393

Answer:

7 TV ads4 radio ads

Step-by-step explanation:

The audience per dollar is ...

  Newspaper: 1000/$200 = 5/$

  Radio: 800/$100 = 8/$

  TV: 14000/$800 = 17.5/$

So, TV gives the greatest exposure. As much of the budget as possible should be spent on TV ads. That amount is the lesser of $6000 and ...

  (7 ads)($800/ad) = $5600

With $5600 spent on TV ads, the remaining advertising budget is ...

  $6000 -5600 = $400

The next most cost-effective medium is radio. The remaining $400 budget allows for ...

  $400/($100/ad) = 4 ads

__

To maximize exposure, the advertising budget should be spent this way:

TV: 7 ads for $5600, exposure of 98000Radio: 4 ads for $400, exposure of 3200

find the values of the six trigonometric functions for angle theta in standard position if a point with the coordinates (1, -8) lies on its terminal side

Answers

Answer:

cosФ = [tex]\frac{1}{\sqrt{65}}[/tex] , sinФ = [tex]-\frac{8}{\sqrt{65}}[/tex] , tanФ = -8, secФ = [tex]\sqrt{65}[/tex] , cscФ = [tex]-\frac{\sqrt{65}}{8}[/tex] , cotФ = [tex]-\frac{1}{8}[/tex]

Step-by-step explanation:

If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:

cosФ = [tex]\frac{x}{r}[/tex]sinФ = [tex]\frac{y}{r}[/tex]tanФ = [tex]\frac{y}{x}[/tex]secФ = [tex]\frac{r}{x}[/tex]cscФ = [tex]\frac{r}{y}[/tex]cotФ = [tex]\frac{x}{y}[/tex]Where r = [tex]\sqrt{x^{2}+y^{2} }[/tex] (the length of the terminal side from the origin to point (x, y)You should find the quadrant of (x, y) to adjust the sign of each function

∵ Point (1, -8) lies on the terminal side of angle Ф in standard position

∵ x is positive and y is negative

→ That means the point lies on the 4th quadrant

∴ Angle Ф is on the 4th quadrant

∵ In the 4th quadrant cosФ and secФ only have positive values

∴ sinФ, secФ, tanФ, and cotФ have negative values

→ let us find r

∵ r = [tex]\sqrt{x^{2}+y^{2} }[/tex]

∵ x = 1 and y = -8

∴ r = [tex]\sqrt{x} \sqrt{(1)^{2}+(-8)^{2}}=\sqrt{1+64}=\sqrt{65}[/tex]

→ Use the rules above to find the six trigonometric functions of Ф

∵ cosФ = [tex]\frac{x}{r}[/tex]

∴ cosФ = [tex]\frac{1}{\sqrt{65}}[/tex]

∵ sinФ = [tex]\frac{y}{r}[/tex]

∴ sinФ = [tex]-\frac{8}{\sqrt{65}}[/tex]

∵ tanФ = [tex]\frac{y}{x}[/tex]

∴ tanФ = [tex]-\frac{8}{1}[/tex] = -8

∵ secФ = [tex]\frac{r}{x}[/tex]

∴ secФ = [tex]\frac{\sqrt{65}}{1}[/tex] = [tex]\sqrt{65}[/tex]

∵ cscФ = [tex]\frac{r}{y}[/tex]

∴ cscФ = [tex]-\frac{\sqrt{65}}{8}[/tex]

∵ cotФ = [tex]\frac{x}{y}[/tex]

∴ cotФ = [tex]-\frac{1}{8}[/tex]    

This table gives a few (x, y) pairs of a line in the coordinate plane. What is the x-intercept of the line?

Answers

Answer:

(22,0)

Step-by-step explanation:

22 0

35 -15

48 -30

61 -45

74 -60

what is the best classification for angle 1 and angle 3?

Answers

I think it is B but I ain’t sure. Sorry

Answer:

C not adjacent because adjacent angles are right next to each other. And <1 and <3 are not right next to each other.

Step-by-step explanation:

They are not vertical angles this is what vertical angles look like ><

They are not adjacent or a linear pair.

So it is C.

m. 2.7(2x + 3) –4.6 n. 2 3 (12 + 15z) – 4 1 2 z o. 9 10 + 1 4 ( 2 3 v+ 2 5 )–1

Answers

Answer:

go on

Step-by-step explanation:

math,way, ., com

I don't understand calculus at all bruh :/. I figured out some of this but I don't know if the answer is 0 or 2. Whoever figures this, out also please explain how you got it.

Answers

Calculus isn’t that difficult. And that’s not to insult you or for me to brag. You just simply aren’t being taught correctly, assuming you’re trying.

The first step for ANY limit is to plug in. Always plug in first. You can take the odd root of a negative number because let’s say you have -1^3, you’re still gonna get -1. But if the power is even, you will always get a positive number. So plug in -32 to get the 5th root of -32. The answer would be -2 because -2^5 = -32

A factory that manufactures screws is performing a quality control experiment. Each object should have a length of no more than 19 centimeters. The factory believes that the length of the screws exceeds this value and measures the length of 65 screws. The sample mean screw length was 19.04 centimeters. The population standard deviation is known is known to be 0.19 centimeters. What is the null hypothesis and what is the alternative hypothesis?

Answers

Answer:

Step-by-step explanation:

Ok

Answer:

A factory that manufactures bolts is performing a quality control experiment. Each object should have a length of no more than  11 centimeters. The factory believes that the length of the bolts exceeds this value and measures the length of 76 bolts. The sample mean bolt length was 11.09 centimeters. The population standard deviation is known to be 0.29 centimeters.

What is the test statistic ?

What is the -value?

Does sufficient evidence exist that the length of bolts is actually greater than the mean value at a significance level of

Find the distance between each pair of points in the coordinate plane.
(3,-2) and (2,-1)​

Answers

Answer:

1.41

Step-by-step explanation:


Eight rolls of paper towels cost $4.80. At the same unit rate, how much will six rolls of paper towels cost?

Answers

Answer:

10

Step-by-step explanation:

A directed segment ST¯¯¯¯¯ is partitioned from S (−5,0) to T in a 32 ratio at point M (10, 15). What are the coordinates of point T? (20, 25) (15, 20) (7, 3) (5, 15

Answers

Answer:

[tex]T = (20,25)[/tex]

Step-by-step explanation:

Given

[tex]S = (-5,0)[/tex]

[tex]M = (10,15)[/tex]

[tex]Ratio = 3:2[/tex]

Required

Determine the coordinate of T

Line division by ratio is calculated using:

[tex]M(x,y) = (\frac{mx_2 + nx_1}{m+n},\frac{my_2 + ny_1}{m+n})[/tex]

Where:

[tex](x_1,y_1) = (-5,0)[/tex]

[tex](x,y) = (10,15)[/tex]

[tex]m:n = 3:2[/tex]

So, we have:

[tex](10,15) = (\frac{3 * x_2 + 2 * -5}{3+2},\frac{3 * y_2 + 2 * 0}{3+2})[/tex]

[tex](10,15) = (\frac{3x_2 -10}{5},\frac{3y_2}{5})[/tex]

Multiply through by 5

[tex]5 * (10,15) = (\frac{3x_2 -10}{5},\frac{3y_2}{5}) * 5[/tex]

[tex](50,75) = (3x_2 -10,3y_2)[/tex]

By comparison:

[tex]3x_2 - 10 = 50[/tex]

[tex]3y_2 = 75[/tex]

[tex]3x_2 - 10 = 50[/tex]

[tex]3x_2 = 50 + 10[/tex]

[tex]3x_2 = 60[/tex]  --- Divide through by 3

[tex]x_2 = 20[/tex]

[tex]3y_2 = 75[/tex]

[tex]y_2 =75/3[/tex] --- Divide through by 3

[tex]y_2 =25[/tex]

Hence:

The coordinates of T is

[tex]T = (20,25)[/tex]

simplify 3 · 32 + 8 ÷ 2 − (4 + 3)

Answers

Answer:

= 93

Step-by-step explanation:

Calculate within parentheses:

(4+3)

= 7

Simplify:

= 3 * 32 + 8 ÷ 2 - 7

Multiply and divide (left to right):

= 96 + 8 ÷ 2 - 7

Multiply and divide (left to right):

= 96 + 4 - 7

Add and subtract (left to right):

= 93

* Pending
This map shows the organization that was
association of nearly 30 countrior

Answers

Where’s the map?? Or is this a part 2 to a question?

Please help! Thank you

Answers

Answer:

-294

Step-by-step explanation:

32 students play basketball and 25 Students play
volleyball . It is found that 13 students play both
games. Find the number of students playing at least
one game
dotos numbers Sets
n
و​

Answers

No. of students playing at least one game = 44
Step-by-step explanation:
B = basketball; V = volleyball
n(B) = no of students playing only B
n(V) = no. of students playing only V
n(B∩V) = no. of students playing both B and V
Now:
32 students play basketball. Some of them could also be playing volleyball. Hence, the number of students playing only basketball will be 32 minus those that play both.
n(B) = 32 - 13 ............(Given that 13 play both games)
n(B) = 19
Similarly,
25 students play volleyball. Some of them could also be playing basketball. Hence, the number of students playing only volleyball will be 25 minus those that play both.
n(V) = 25 - 13
n(V) = 12
Thus, we have 19 students playing only B, 12 students playing only V and 13 students playing BOTH.
Clearly, the number of students that play at least one game is:
No. of students playing ONLY basketball +
No. of students playing ONLY volleyball +
No. of students playing BOTH
This can be given as:
n(B) + n(V) + n(B∩V)
= 19 + 12 + 13
= 44

Answer:

44 students

Step-by-step explanation:

Given parameters:

Number of students playing basketball = 32

Number of students playing volleyball = 25

Number of students playing both = 13

Unknown:

Number of students playing at least one game = ?

Solution:

Let us first find the number of students that play basketball only and volleyball only.

Number of students playing basketball only = 32  - 13  = 19

Number of students playing volleyball only = 25 - 13  = 12

So,

Least number of students that play at least one game  = number of students that plays basketball only + number of students that plays volleyball only + number of students that plays both;

     = 19 + 12 + 13  

      = 44 students

Name the slop and one point that is on the line represented by the equation: y + 3 = -1/2(x +7)

Answers

Answer:

The slope is -1/2 and a point on the line is ( -7,-3)

Step-by-step explanation:

y + 3 = -1/2(x +7)

This is in point slope form

y - y1 = m(x-x1) where m is the slope and ( x1,y1) is a point on the line

y - -3 = -1/2(x - -7)

The slope is -1/2 and a point on the line is ( -7,-3)

Find the quotient:

_________________
x - 4 ) x^3 + 2x^2 – 16x - 32

Answers

Step-by-step explanation:

x-4)x³+2x²-16x-32(x²+6x+8

x³-4x²

- +

____________

6x²-16x-32

6x²-24x

- +

_________

8x-32

8x-32

- +

_____

X X

______

Hence,

The quotient is x²+6x+8.

The following data represent the​ high-temperature distribution for a summer month in a city for some of the last 130 years. Treat the data as a population. Complete parts​ (a) through​ (c).

Temperature Lower Limit Upper Limit Days
50-59 50 59 2
60-69 60 69 313
70-79 70 79 1419
80-89 80 89 1503
90-99 90 99 319
100-109 100 109 9

Required:
Approximate the mean and standard deviation for temperature.

Answers

Answer:

The mean is  [tex]\= x  = 79.7 [/tex]

The standard deviation  [tex]\sigma =7.81[/tex]

Step-by-step explanation:

From the question we are told that

  The data given is  

Temperature                Lower Limit           Upper Limit               Days

50-59                               50                             59                          2

60-69                                 60                            69                        313

70-79                                  70                           79                          1419

80-89                                   80                          89                         1503

90-99                                   90                          99                          319

100-109                                100                         109                         9        

Generally the average of each limit is evaluated as

Temperature    Lower Limit   Upper Limit         Average[tex](x_i)[/tex]                    Days[tex](f_i)[/tex]

50-59                 50                   59              ( 50 + 59 )/2 =54.5                 2

60-69                 60                   69              (60+69)/2 = 64.5                    313

70-79                 70                    79               (70+79)/2 =74.5                    1419

80-89                 80                   89                (80+89)/2 =84.5                  1503

90-99                 90                   99                 (90+99)/2 = 94.5                319

100-109             100                  109                 (100+109)/2 = 104.5            9  

Generally the mean is  evaluated as

     [tex]\mu  =  \frac{\sum x_i f_i}{\sum f_i}[/tex]

=>  [tex]\mu  =  \frac{ (54.5 * 2) + (64.5 * 313) +\cdots +(104.5 *  9)}{2 + 313 +\cdots + 9}[/tex]

=> [tex]\= x  = 79.7 [/tex]

Generally the standard deviation  is  evaluated as

    [tex]\sigma = \sqrt{ \frac{\sum[ f_i * ( x_i^2 - \= x^2)] }{\sum f_i}}[/tex]

=>   [tex]\sigma =\sqrt{ \frac{[2 * [(54.5)^2) - 79.7^2 ]]+[313 *[ (64.5)^2)-79.7^2] +\cdots +[9 *[ (104.5)^2)- 79.7^2]  }{2 + 313 +\cdots + 9}}[/tex]

=>  [tex]\sigma =7.81[/tex]

   

The mean and Standard deviation for the given data would be as follows:

μ [tex]= 79.7[/tex]

б [tex]= 7.81[/tex]

Frequency Distribution

Given that,

Temperature       Lower Limit           Upper Limit             Days([tex]f_{i}[/tex])

50-59                       50                           59                          2

60-69                       60                           69                         313

70-79                         70                           79                          1419

80-89                        80                          89                          1503

90-99                        90                          99                           319

100-109                    100                         109                            9  

Average([tex]x_{i}[/tex])    

[tex]( 50 + 59 )/2 =54.5[/tex]

[tex](60+69)/2 = 64.5[/tex]

[tex](70+79)/2 =74.5[/tex]

[tex](80+89)/2 =84.5[/tex]

[tex](90+99)/2 = 94.5[/tex]

[tex](100+109)/2 = 104.5[/tex]

As we know,

Mean (μ) [tex]=[/tex] ∑[tex](x_{i} f_{i}) /[/tex]∑[tex]f_{i}[/tex]

[tex]= [(54.5[/tex] × [tex]2) + (64.5[/tex] ×[tex]313)+....(104.5[/tex]× [tex]9)][/tex][tex]/(2 + 313 + 1419 + ....9)[/tex]

∵ μ [tex]= 79.7[/tex]

As we know,

Standard Deviation:-

[tex]\sigma={\sqrt {\frac {\sum(x_{i}-{\mu})^{2}}{f_{i} }}}[/tex]

by putting the values, we get

∵ б [tex]= 7.81[/tex]

Thus, μ [tex]= 79.7[/tex] and б [tex]= 7.81[/tex] are the correct answers.

Learn more about "Temperature" here:

brainly.com/question/7510619

Help me plsss! I'll give u 10 points​

Answers

Answer:

1.02n

Step-by-step explanation:

We just have to simply the expression already given which will give you the equivalent expression.

n + 0.02n since these are like terms because of the variable "n", we can just add them together

n+0.02n

1.02n

How many solutions does this equation have

2x + 1 = 2x – 1

Answers

Wait by x do you mean times or? If you don’t mean times then it’s 4x

A manufacturer knows that their items have a lengths that are approximately normally distributed, with a mean of 9.8 inches, and standard deviation of 1.6 inches. If 48 items are chosen at random, what is the probability that their mean length is greater than 9.2 inches

Answers

Answer:

0.6462

Step-by-step explanation:

Given that

Mean (m) = 9.8

Standard deviation (s) = 1.6

Probability that mean length is greater than 9.2

Z = (x - m) / s

Z = (9.2 - 9.8) / 1.6

Z = - 0.6 / 1.6

Zscore = - 0.375 = - 0.375

P(Z >- 0.375) = 1 - P(Z < - 0.375) ;

P(Z < - 0.375) = 0.3538

1 - P(Z < - 0.38) = 1 - 0.3538 = 0.6462

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