Cari owns a horse farm and a horse trailer that can
transport up to 8, 000 pounds of livestock and tack. She
travels with 5 horses whose combined weight is 6, 240
pounds. Let t represent the average weight of tack per
horse. Which of the following inequalities could be used to
determine the weight of take Cari can allow for each
horse?
O 6240 +t≤ 8000
O 8000 6240t
O 6240 + 5t ≤ 8000
O 8000 +6240 < 5t
O 8000 6240 > 5t
what would the answer be, it’s multiply chose

Answer:

80%

Step-by-step explanation:

each side of a square is 30 cm.

decreased by 20%.

find the percentage decrease in the area of the square.

20%x4side= 80%

cos(2a + B) is approximately equal to -0.2948.

why it is?

To find cos(2a + B), we can use the double angle formula for cosine:

cos(2a + B) = cos(2a)cos(B) - sin(2a)sin(B)

We already know the values of a and B, so we can substitute them into the formula and simplify using the trigonometric identities:

a = sin²-1(4/5) = 53.13° (rounded to two decimal places)

B = tan²-1(12/5) = 67.38° (rounded to two decimal places)

cos(2a) = cos²2(a) - sin²2(a) = (cos(a))²2 - (1 - (cos(a))²2) = 2(cos(a))²2 - 1

cos(2a) = 2(sin²-1(4/5))²2 - 1 = 2(0.8)²2 - 1 = 0.32

sin(2a) = 2sin(a)cos(a)

sin(2a) = 2(sin(sin²-1(4/5)))cos(sin²-1(4/5)) = 2(4/5)(3/5) = 0.96

cos(B) = 1/sqrt(1 + tan²2(B)) = 1/sqrt(1 + (12/5)²2) = 5/13

sin(B) = tan(B)cos(B) = (12/5)(5/13) = 0.48

Substituting these values into the formula for cos(2a + B) gives:

cos(2a + B) = cos(2a)cos(B) - sin(2a)sin(B)

cos(2a + B) = (0.32)(5/13) - (0.96)(0.48)

cos(2a + B) = 0.166 - 0.4608

cos(2a + B) = -0.2948

Therefore, cos(2a + B) is approximately equal to -0.2948.

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Step-by-step explanation:

[tex] \frac{1 - \ { \sin(t) }^{2} } { { \sin(t) }^{2} } = \frac{1} { { \sin(t) }^{2} } - \frac{{ \sin(t) }^{2}}{{ \sin(t) }^{2}} \: = \frac{1} { { \sin(t) }^{2} } - 1[/tex]

[tex] = { \sin(t) }^{ - 2} - 1[/tex]

hope this helps

A catapult, seatbelt, parachute, safety net, or unbalanced force can be used to stop moving objects.

When a seatbelt is fastened during sudden braking or a crash, it exerts pressure on the passenger's body and prevents them from moving forward.

Similar to this, when a parachute is opened, a significant amount of air resistance force is generated, slowing the wearer's descent.

A safety net exerts force on an object that is falling on it as well, absorbing the kinetic energy and stopping it.

A catapult can apply a significant unbalanced force that can halt an object in motion by quickly transferring energy from its springs or elastic materials to the target.

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The answer of  the given question based on finding each measure of a circle the answer is , (a)  m(MNP) = 12.5° degrees , (b) m(KL) = 102.5° degrees , (c)  m(KJ) = 52.5° degrees , (d)  m(JN) = 102.5° degrees , (e)  m(JLM) =  12.5° degrees.

In geometry,  arc is a portion of  curved line that can be thought of as  segment of  circle. It is defined by two endpoints on  circle and the arc itself is the part of  circle between those two points. An arc can be measured in degrees, and its measure is equal to  central angle subtended by  arc. The length of  arc can also be calculated using the formula L = rθ, where L is  length of  arc, r is radius of  circle, and θ is  angle (in radians) subtended by  arc at center of circle.

Using the properties of angles and arcs in circles:

a. Angle MNP is inscribed in arc MP, so m(MNP) = 1/2m(MP) = 1/2(25) = 12.5° degrees.

Since angles NPM and MPK are vertical angles, we have m(MPK) = m(NPM) = m(MNP) = 12.5° degrees. Then, m(MN) = m(MPK) + m(KPM) = 12.5 + 40 = 52.5° degrees.

b. Angle LKP is inscribed in arc LP, so m(LKP) = 1/2m(LP) = 1/2(25) = 12.5° degrees.

Since angles PKL and LKN are vertical angles, we have m(PKL) = m(LKN) = m(LKP) = 12.5° degrees. Then, m(KL) = m(PKL) + m(PKC) = 12.5 + 90 = 102.5° degrees.

c. Angle PKJ is inscribed in arc PJ, so m(PKJ) = 1/2m(PJ) = 1/2(25) = 12.5° degrees.

Since angles LPK and LPJ are vertical angles, we have m(LPK) = m(LPJ) = m(PKJ) = 12.5° degrees. Then, m(KJ) = m(LPK) + m(LPJ) = 12.5 + 40 = 52.5° degrees.

d. Angle JNM is inscribed in arc JM, so m(JNM) = 1/2m(JM) = 1/2(25) = 12.5° degrees.

Since angles KJM and KJN are vertical angles, we have m(KJM) = m(KJN) = m(JNM) = 12.5° degrees. Then, m(JN) = m(KJM) + m(MJN) = 12.5 + 90 = 102.5° degrees.

e. Angle JLM is an inscribed angle that intercepts arc JM, so m(JLM) = 1/2m(JM) = 1/2(25) = 12.5° degrees.

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Answer:

1

Step-by-step explanation:

[tex]\frac{4}{12}[/tex]  x 3 = 12/12 = 1

Answer: a

Step-by-step explanation: because a is my name

Answer:

Independent Variable: Smoking

Quasi-Independent Variable: Parents to Children (Assuming that the researcher purposely manipulated it, otherwise there is none.)

Dependent Variable: Children's attitudes toward smoking behavior

[tex](\stackrel{x_1}{-6}~,~\stackrel{y_1}{-3})\qquad (\stackrel{x_2}{-8}~,~\stackrel{y_2}{-4}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{-4}-\stackrel{y1}{(-3)}}}{\underset{\textit{\large run}} {\underset{x_2}{-8}-\underset{x_1}{(-6)}}} \implies \cfrac{-4 +3}{-8 +6} \implies \cfrac{ -1 }{ -2 } \implies \cfrac{ 1 }{ 2 }[/tex]

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{ \cfrac{ 1 }{ 2 }}(x-\stackrel{x_1}{(-6)}) \implies y +3 = \cfrac{ 1 }{ 2 } ( x +6) \\\\\\ y+3=\cfrac{ 1 }{ 2 }x+3\implies {\Large \begin{array}{llll} y=\cfrac{ 1 }{ 2 }x \end{array}}[/tex]

Answer:

m = 6

Step-by-step explanation:

Slope = rise/run or (y2 - y1) / (x2 - x1)

Pick 2 points on the table (4,6) (5,12)

We see the y increase by 6 and the x increase by 1, so the slope is

m = 6

So, the slope is 6

Answer:

18.67

Step-by-step explanation:

my calculate ratio results

Answer: The probability of drawing a vowel from a deck of 12 cards is 5/12, since there are 5 vowels (A, E, I, O, U) and 12 cards in total.

Since Brandi returns the first card drawn to the deck before drawing the second card, the outcome of the first draw does not affect the outcome of the second draw. Therefore, we can treat the two draws as independent events.

The probability of drawing a vowel on the first draw is 5/12, and the probability of drawing a vowel on the second draw is also 5/12. Since we want to find the probability of both events happening (drawing a vowel both times), we can multiply the probabilities:

P(vowel on both draws) = P(vowel on first draw) * P(vowel on second draw)

= (5/12) * (5/12)

= 25/144

Therefore, the theoretical probability that Brandi draws a card with a vowel both times is 25/144, which is approximately 0.1736 or 17.36%.

So the closest answer choice is B) 2.08%.

Step-by-step explanation:

Answer:

19

Step-by-step explanation:

We are given the following two functions of s

[tex]p(s) = s^3 + 10s\\f(s) = 6s - 3\\\\\text{To find p(2) substitute 2 for s in p(s)}\\p(2) = (2)^3 + 10(2) = 8 + 20 = 28\\\\[/tex]

[tex]\text{To find f(2) substitute 2 for s in f(s)}\\f(2) = 6(2) - 3= 12 - 3= 9\\[/tex]

[tex]p(2) - f(2) = 28 - 9 = 19[/tex]

Answer:

Step-by-step explanation:

D

Answer:

4 pens.

Step-by-step explanation:

Now he has 2 pens.

Then his friend gives him two more.

As a sum, that's:

2 + 2 = 4 pens.

Answer:

He has 4 pens now.

Step-by-step explanation:

2+2=4

Answer: 14.5

Step-by-step explanation:

When there is a decimal point, you start counting from the left any number that is not zero. If the zero is at the end, then you count it.

For example, if the answer is 0.000145 then the number of significant figures is still three because you start counting from the first nonzero number from the left.

If the answer is 14.50, then the number of significant figures is four because you start counting from the first nonzero number from the left.

14.53 is the answer to the equation but because you want to correct it to 3 significant figures, you round down because 3 is less than 5 and 14.5 ends up being the final answer.

With four decimal places added, we have P(2.04 Z 3.04) 0.0189.

To round a decimal value to two decimal places, use the hundredths place, which is the second place to the right of the decimal point.

Subtracting the area to the left of 1.25 from the area to the left of 2.15 will give us the standard normal area between 1.25 and 2.15.

The area to the left of 1.25 is 0.8944, and the area to the left of 2.15 is 0.9842, according to a conventional normal distribution table or calculator.

So, the standard normal area between 1.25 and 2.15 is:

P(1.25 < Z < 2.15) = 0.9842 - 0.8944 = 0.0898

Rounding to four decimal places, we get:

P(1.25 < Z < 2.15) ≈ 0.0898

We follow the same procedure as before to determine the standard normal region between 2.04 and 3.04:

P(2.04 < Z < 3.04) = P(Z < 3.04) - P(Z < 2.04)\

The area to the left of 2.04 is 0.9798, and the area to the left of 3.04 is 0.9987, according to a conventional normal distribution table or calculator.

So, the standard normal area between 2.04 and 3.04 is:

P(2.04 < Z < 3.04) = 0.9987 - 0.9798 = 0.0189

Rounding to four decimal places, we get:

P(2.04 < Z < 3.04) ≈ 0.0189

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The derivative of the function g(t) =  -2tsint - sint + 2tcost.

In mathematics, the derivative of a function of a real variable measures the sensitivity of the function's value (the output value) to changes in its independent variable (the input value). Derivatives are a fundamental tool of calculus. The process of finding derivatives is called differentiation. The reverse process is called retro differentiation.

The fundamental theorem of calculus associates inverse differentiation with integration. Differentiation and integration form the two basic operations in univariate calculus.

Given that:

g(t) = tan(ln(t)) g'(t)

Now, Differentiating for the first time:

  (t²+1) d/dt (sin t) + Sin t d/dt (t²+1)

= (t²+1) cos t + sint (2t)

Now,

h'(t) = t²cos t + cost + 2tsint

Differentiating again:

h''(t) = d/dt (t²cos t) + d/dt (cost) + d/dt (2tsint)

      = -2tsint - sint + 2tcost

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Answer:5

Step-by-step explanation:5555555

Answer: Below.

Step-by-step explanation:

To find each we must use the left side to put the first letter. The top for the right letter.

First row - AA

Second row - CB

Third row - CD

Fourth row - BD

Step 1: Arrange the arrays so that A and B are in the same order: A = [ 1 2 4 0 5 6 ], B = [ 7 3 2 5 1 9]

Step 2: To find C = A+B, add each element of A and B together.

C = [1+7, 2+3, 4+2, 0+5, 5+1, 6+9]

C = [8, 5, 6, 5, 6, 15]

Step 3: To find D = A-B, subtract each element of B from A.

D = [1-7, 2-3, 4-2, 0-5, 5-1, 6-9]

D = [-6, -1, 2, -5, 4, -3]

Answer: 62°

Step-by-step explanation:

All angles of a triangle add up to 180°.

So, add up all the other angles.

15 + 25 + 39 = 79

180 - 79 = 101

Then, to find x, subtract 39 from 101, to get 62!

There are 4 terms in the series.

what is an arithmetic sequence?

An arithmetic sequence is a sequence of numbers where each term is equal to the previous term plus a fixed constant difference, called the common difference.

The given series is an arithmetic sequence with a common difference of 16. We can find the first term by plugging in n=1 into the sequence:

a1 = -4 + 16(-1)^1 = -4 + 16 = 12

Using the formula for the sum of an arithmetic sequence, we have:

Sn = n/2(2a1 + (n-1)d)

where n is the number of terms, a1 is the first term, and d is the common difference. Plugging in the given values, we have:

3276 = n/2(2(12) + (n-1)(16))

Simplifying this equation, we get:

3276 = n/2(28 + 16n - 16)

3276 = n/2(12 + 16n)

Multiplying both sides by 2 and rearranging, we get:

6544 = n(6 + 8n)

Dividing both sides by 2, we get:

3272 = n(3 + 4n)

We can see that n must be an even number, since the left side is even. We can also see that n cannot be too large, since the right side increases much faster than the left side. Trying some even values of n, we find that:

n=8 -> 3272 = 8(3 + 4(8)) is false

n=6 -> 3272 = 6(3 + 4(6)) is false

n=4 -> 3272 = 4(3 + 4(4)) is true

Therefore, there are 4 terms in the series.

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there is a 20% chance that the point chosen at random will lie on bg.

To find the probability that a point chosen at random will be on the line segment bg, we need to consider the length of bg in relation to the length of the entire line segment ak.

Let us assume that ak is a straight line segment, and bg is a smaller segment that lies entirely within it. To find the probability, we need to divide the length of bg by the length of ak.

Let the length of bg be x and the length of ak be y. Then the probability that a point chosen at random will be on bg is:

Probability = Length of bg / Length of ak

Probability = x / y

However, we need to be careful here. If we choose a point anywhere on ak, it may not necessarily lie on bg. There are an infinite number of points on ak, but only one segment bg. Therefore, the probability we are looking for is actually the ratio of the lengths of bg to ak.

So, if we know the lengths of bg and ak, we can find the probability by dividing them. For example, if bg is 2 units long and ak is 10 units long, the probability of choosing a point on bg is:

Probability = 2 / 10

Probability = 0.2 or 20%

In this case, there is a 20% chance that the point chosen at random will lie on bg.

In conclusion, the probability of a point chosen at random on ak being on bg is directly proportional to the length of bg in relation to the length of ak. Therefore, we need to find the ratio of the lengths of the two line segments to determine the probability.

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what is the probability  a point is chosen at random on ak and then the point will be on bg. dont forget to reduce the products?

The factorization of the polynomial x³ + 9x² + 3x + 27 by grouping is:

x³ + 9x² + 3x + 27 = (x + 9)(x² + 3)

In algebra, "grouping" refers to a method of factoring polynomials that involves grouping together pairs of terms within the polynomial, in order to factor out a common factor.

In mathematics, a polynomial is a mathematical expression consisting of variables (also called indeterminates) and coefficients, that involves only the operations of addition, subtraction, multiplication, and non-negative integer exponents of variables.

In the given question,

To factor the four-term polynomial by grouping, we can follow these steps:

Step 1: Group the first two terms and the last two terms together.

x³ + 9x² + 3x + 27

= (x³ + 9x²) + (3x + 27)

Step 2: Factor out the common factor from each group.

= x²(x + 9) + 3(x + 9)

Step 3: Notice that the expression (x + 9) is a common factor of both terms, and factor it out.

= (x + 9)(x² + 3)

Therefore, the factorization of the polynomial x³ + 9x² + 3x + 27 by grouping is:

x³ + 9x² + 3x + 27 = (x + 9)(x² + 3).

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The number of 5 fluid ounce portions needed in 20 gallons is a total of 512 portions

To solve this problem, we first need to convert the volume of the soup recipe from gallons to fluid ounces, and then divide by the size of each portion to find the total number of portions.

Given that

1 gallon = 128 fluid ounces

Therefore, the recipe yields:

20 gallons x 128 fluid ounces per gallon = 2560 fluid ounces

Now, we can find the number of 5-fluid ounce portions by dividing the total volume by the portion size:

2560 fluid ounces / 5 fluid ounces per portion = 512 portions

Therefore, the soup recipe yields 512 portions of 5 fluid ounces each.

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The coordinates of p so that p partitions segment ab in the part-to-whole ratio of 1 to 5 with a(-9, 3) and b(1, 8) is (-44/6, 23/6).

To find the coordinates of point P, we can use the following formula:

P = ( (5 x Ax + 1 x Bx) / 6 , (5 x Ay + 1 x By) / 6 )

Here, Ax and Ay are the x and y coordinates of point A, and Bx and By are the x and y coordinates of point B. By plugging in the values we have, we get:

P = ( (5 x (-9) + 1 x 1) / 6 , (5 x 3 + 1 x 8) / 6 )

P = ( (-45 + 1) / 6 , (15 + 8) / 6 )

P = ( -44/6 , 23/6 )

So the coordinates of point P are (-44/6, 23/6).

To check if we got the right answer, we can measure the distance between A and P and the distance between P and B, and make sure that the ratio is indeed 1 to 5. We can use the distance formula for this:

Distance between A and P:

√( (-9 - (-44/6))² + (3 - 23/6)² )

= √( (35/6)² + (5/6)² )

= √( 1225/36 + 25/36 )

= √( 1250/36 )

= 5/6 x √(50)

Distance between P and B:

√( (1 - (-44/6))² + (8 - 23/6)² )

= √( (55/6)² + (41/6)² )

= √( 3025/36 + 1681/36 )

= √( 4706/36 )

= 5/6 x √(94)

The ratio of the distance between A and P to the distance between P and B is:

(5/6 x √(50)) / (5/6 x √(94)) = √(50/94)

Simplifying this gives us:

√(50/94) = √(25/47)

The ratio of the distances is indeed 1 to 5, which confirms that our answer for the coordinates of P is correct.

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The two triangles are related by SAS criteria, so the triangles are congruent.

Congruent triangles are triangles that are precisely the same size and form. When the three sides and three angles of one triangle match the same dimensions as the three sides and three angles of another triangle, two triangles are said to be congruent. Corresponding portions are those areas of the two triangles that share the same dimensions (are congruent). This indicates that corresponding triangle parts are congruent (CPCTC).

From the given figure we observe for that the two triangles two sides and the corresponding angle of 90 degree is similar.

Thus, using the SAS criteria we see that the two triangles are equal.

Hence, the two triangles are related by SAS criteria, so the triangles are congruent.

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The distance  from Link to the Octorok  is 10.63 units.

We know that the distance between two points (x₁, y₁) and (x₂, y₂) is given by the formula below:

distance = √( (x₂ - x₁)² + (y₂ - y₁)²)

Here we want to find the distance from Link to the Octorok so Link can attack, so we need to get the distance between the points (-4, -5) and (3, 3).

The distance will be:

distance = √( (3 + 4)² + (3 + 5)²)

distance = √( (7)² + (8)²)

distance = √113

distance = 10.63

The distance is 10.63 units.

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The value of x is 5

Triangles with the same shape but different sizes are said to be similar triangles. To be more specific, two triangles are comparable if their respective sides are proportionate and their corresponding angles are congruent.

Two triangles are similar if corresponding angles are congruent and corresponding sides are proportional.

from the below figure, both the triangles are similar, ∆ABC ≈ ∆EFB

By using Thales's theorem, the ratio of the sides of triangles are;

BE/EA = BF/FC

15/30 = x/10    

x = 5

Therefore the value of x is 5

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The ratio of triangle sides can be calculated using Thales' theory, and it is the value of x is 5

Similar triangles are those with the same shape but varying sizes. To be more precise, two triangles are comparable if their matching angles and respective sides are congruent.

If matching sides are proportional and corresponding angles are congruent, two triangles are similar.

Both triangles in the following figure are comparable ∆ABC ≈ ∆EFB

The ratio of triangle sides can be calculated using Thales' theory, and it is;

BE/EA = BF/FC

15/30 = x/10    

x = 5

Therefore the value of x is 5

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