China is selling school supplies in the United States for very low prices, even lower than the
preventing prices in China, and thus making it extremely difficult for American manufacturers to
compete. This is referred to as

Answer:

Throughout the interpretation section elsewhere here, the explanation of the problem is summarized.

Explanation:

Answer:

Here is the Python program:

d = {5:3, 4:1, 12:2}

val_of_max = d[max(d.keys())]

print(val_of_max)

Explanation:

The program works as follows:

So we have a dictionary named d which is not empty and has the following key-value pairs:

5:3

4:1

12:2

where 5 , 4 and 12 are the keys and 3, 1 and 2 are the values

As we can see that the largest key is 12. So in order to find the largest key we use max() method which returns the largest key in the dictionary and we also use keys() which returns a view object i.e. the key of dictionary. So

max(d.keys()) as a whole gives 12

Next d[max(d.keys())]  returns the corresponding value of this largest key. The corresponding value is 2 so this entire statement gives 2.

val_of_max = d[max(d.keys())] Thus this complete statement gives 2 and assigns to the val_of_max variable.

Next print(val_of_max) displays 2 on the output screen.

The screenshot of program along with its output is attached.

Answer:

WHAT DO YOU MEAN

Explanation:

THIS IS FOR QUESTIONS ONLY !!!!

Answer:

a. I think the Aluminum will conduct heat better.

b. I think the Fiberglass will insulate heat better.

Fiberglass is used to insulate most everyday items, so I can be sure that fiberglass can be the best insulator, as for aluminum it conducts heat like you wouldn't believe.

Note: Your answer doesn't have to be right, they just want you to make a prediction about your answer, that means it's alright to guess, also know I didn't guess I am just telling you that you didn't have to ask this question. <3

In python:

for i in range(56, 71):

   print(i, end=" ")

Answer:

for n in range(56,71):

   print(n, end=" ")

Explanation:

Answer:

The equivalent if statements is:

ranforce = randi([0, 12]);

if (ranforce == 0)

     disp('There is no wind')

else  if(ranforce>0 && ranforce <7)

     disp('There is a breeze')

else  if(ranforce>6 && ranforce <10)

     disp('This is a gale')

else  if(ranforce>9 && ranforce <12)

     disp('It is a storm')

else  if(ranforce==12)

     disp('Hello, Hurricane!')

end

Explanation:

The solution is straight forward.

All you need to do is to replace the case statements with corresponding if or else if statements as shown in the answer section

Answer:

false

Explanation:

1 MB = 0.001 GB

Answer:

Open your python console and execute the following .py code

Explanation:

Code bellow:

#include <iostream>

#include <iomanip>

#include <string>

using namespace std;

void inputInfo(string*, int*, int);

double mathAvr(int*, int);

void printInfo(string*, int*, int, double);

int main()

{

   double avg;  

   int n;  

   string *names;  

   int *scores;  

   char ch;

   do

   {

       cout << "\n contestants quantity: ";

       cin >> n;

       names = new string[n];

       scores = new int[n];

       inputInfo(names, scores, n);

       avg = mathAvr(scores, n);

       printInfo(names, scores, n, avg);

       delete [] names;

       delete [] scores;

       cout << "\n again? (Y/N): ";

       cin >> ch;

   }while(ch=='Y' || ch=='y');

   cout << "\n\n";

   return 0;

}

void inputInfo(string *names, int *scores, int n)

{

   int i;

   for(i=0; i<n; i++)

   {

       cout << "\n\n Name of the participant: ";

       cin >> *(names+i);

       do

       {

           cout << "\n score " << *(names+i) << " (0-100): ";

           cin >> *(scores+i);

       }while(*(scores+i) < 0 || *(scores+i) > 100);

   }

}

double mathAvr(int *scores, int n)

{

   int i, sum=0;

   double avg;

   for(i=0; i<n; i++)

   {

       sum += *(scores+i);

   }

   avg = sum / (double)n;

   return avg;

}

void printInfo(string *names, int *scores, int n, double avg)

{

   int i;

   cout << "\n\n " << left << setw(20) << "Participant name" << left << setw(6) << "Score" << " \n";

   for(i=0; i<n; i++)

   {

       cout << "\n " << left << setw(20) << *(names+i) << left << setw(6) << *(scores+i);

   }

   cout << fixed << setprecision(2);

   cout << "\n\n Average: " << avg << " \n\n";

}

Answer:

Ill do this in C# and Java

Explanation:

C#:

public static void Main(string[] args)

       {

           string input = Console.ReadLine();

               switch (input)

               {

                   case "A1":

                       Console.WriteLine("Footwear:");

                       Console.WriteLine("Shoes");

                       break;

                   case "B1":

                       Console.WriteLine("Tops:");

                       Console.WriteLine("Jackets");

                       break;

                   case "C1":

                       Console.WriteLine("Pants:");

                       Console.WriteLine("Trousers");

                       break;

                   case "A2":

                       Console.WriteLine("Footwear:");

                       Console.WriteLine("Trainers");

                       break;

                   case "B2":

                       Console.WriteLine("Tops:");

                       Console.WriteLine("TShirts");

                       break;

                   case "C2":

                       Console.WriteLine("Pants:");

                       Console.WriteLine("Shorts");

                       break;

                   default:

                       Console.WriteLine("Incorrect Input");

                       break;

               }

       }

Java:

public static void main(String[] args)

   {

       Scanner myObj = new Scanner(System.in);  // Create a Scanner object

       String input = myObj.nextLine();

       {

           switch (input)

               {

                   case "A1":

                       System.out.println("Footwear:");

                       System.out.println("Shoes");

                       break;

                   case "B1":

                       System.out.println("Tops:");

                       System.out.println("Jackets");

                       break;

                   case "C1":

                       System.out.println("Pants:");

                       System.out.println("Trousers");

                       break;

                   case "A2":

                       System.out.println("Footwear:");

                       System.out.println("Trainers");

                       break;

                   case "B2":

                       System.out.println("Tops:");

                       System.out.println("TShirts");

                       break;

                   case "C2":

                       System.out.println("Pants:");

                       System.out.println("Shorts");

                       break;

                   default:

                       System.out.println("Incorrect Input");

                       break;

               }

       }

Answer:

import java.util.Scanner;

public class Main

{

public static void main(String[] args) {

              //print the header

              System.out.println("**************************************");

              System.out.println("*                                    *");

              System.out.println("*                                    *");

              System.out.println("*   Gas-N-Clean Service Station      *");

              System.out.println("*                                    *");

              System.out.println("*   March 2, 2004                    *");

              System.out.println("*                                    *");

              System.out.println("**************************************");

               //set the constant values for gasoline

               final double REGULAR_GASOLINE = 2.89;

               final double PLUS_GASOLINE = 3.09;

               final double SUPER_GASOLINE = 3.39;

              // initialize the variables as 0

              double gasolinePrice = 0, gasolineCost = 0, carWashCost = 0, totalCost = 0;

               Scanner input = new Scanner(System.in);

               //ask the user to enter the gallons, gas type and car wash choice

               System.out.print("Enter number of gallons ");

               double gasolinePurchase = input.nextDouble();

               System.out.print("Enter gas type (R, P, S, or N) ");

               char gasType = input.next().charAt(0);

               System.out.print("Enter Y or N for car wash ");

               char carWashChoice = input.next().charAt(0);

               //check the gas type. Depending on the choice set the gasolinePrice from the corresponding constant value

              if(gasType == 'R')

                  gasolinePrice = REGULAR_GASOLINE;

              else if(gasType == 'P')

                  gasolinePrice = PLUS_GASOLINE;

              else if(gasType == 'S')

                  gasolinePrice = SUPER_GASOLINE;

                //calculate the gasolineCost

                gasolineCost = gasolinePurchase * gasolinePrice;

               //check the carWashChoice. If it is yes and gasolineCost is greater than 10, set the carWashCost as 1.25. Otherwise, set the carWashCost as 3.00

               if(carWashChoice == 'Y'){    

                   if(gasolineCost >= 10)

                       carWashCost = 1.25;

                   else

                       carWashCost = 3.00;

               }

              //calculate the total cost, add gasolineCost and carWashCost

              totalCost = gasolineCost + carWashCost;

               //print the values in required format

              System.out.println("Amount Gasoline purchases " + gasolinePurchase);

              System.out.println("Gallons Price per gallons $ " + gasolinePrice);

              System.out.printf("Total gasoline cost $ %.2f\n", gasolineCost);

              System.out.println("Car wash cost $ " + carWashCost);

              System.out.printf("Total due $ %.2f\n", totalCost);

               System.out.println("Thank you for stopping\nPlease come again \nRemember to buckle up and drive safely");

}  

}

Explanation:

*The code is in Java.

Please see the comments in the code for explanation

Answer:

B

Explanation:

you can post blog updates in real time as things happen

Answer: Stock market values and news updates

Explanation: These are things that you can follow in real time and that happen in real time (think of something like a livestream)

PLATO/EDMENTUM

Corrected Question

Write a program that reads in 15 numbers in sorted order from the user (i.e. the user enters them in order) and stores them in a 1D array of size 15. Next, prompt the user for a number to search for in the array (i.e. the "target"). Then, print the array. Next, search the array using a linear search – find the target element and printing out the target and its index as well as the entire array

Answer:

The solution is given in the explanation section

See detailed explanation of each step given as comments

Explanation:

import java.util.*;

class Main {

 public static void main(String[] args) {

   //Create the array of 15 elements

   int [] array = new int [15];

   //Create an object of the scanner class to receive user input

   Scanner in = new Scanner(System.in);

   //Prompt user to enter the values in sorted order

   //Using a for loop

   for (int i =0; i<array.length; i++){

         System.out.println("Enter the next element: In SORTED order please!");

         array[i] = in.nextInt();

   }

   System.out.println("All Fifteen element have been entered");

   // Ask the user for an element to be searched for

   //A target element

   System.out.println("Which element do you want to search for in the array");

   //Create the target element

   int target = in.nextInt();

   //Use a for loop to sequentially check each element in the array

   for(int i = 0; i<array.length; i++){

     if(array[i]==target){

       System.out.println(target+" is found at index "+i +" of the array");

     }

   }

       // Printout the entire array

   System.out.println(Arrays.toString(array));

 }

}

Answer:

human performance plan

Explanation:

(for odyssey users)

Answer:

a pop-up box

Explanation:

A voice command, mouse clicks, or keyboard strokes is the user doing something. But a pop-up box is not. I realize that a popup box could contain a user input, but the box itself is not any sort of user input. It's the opposite.

Answer:A 404 error is often returned when pages have been moved or deleted. ... 404 errors should not be confused with DNS errors, which appear when the given URL refers to a server name that does not exist. A 404 error indicates that the server itself was found, but that the server was not able to retrieve the requested page.

Explanation: Hope this helps

Answer:

The solution is provided in the explanation section.

Detailed explanation is provided using comments within the code

Explanation:

import java.util.*;

public class Main {

//The Bubble sort method

public static void bb_Sort(int[] arr) {  

   int n = 10; //Length of array  

   int temp = 0; // create a temporal variable  

   for(int i=0; i < n; i++){  

         for(int j=1; j < (n-i); j++){  

           if(arr[j-1] > arr[j]){  

               // The bubble sort algorithm swaps elements  

               temp = arr[j-1];  

               arr[j-1] = arr[j];  

               arr[j] = temp;  

             }  

         }            

         }  

        }

 public static void main(String[] args) {

   //declaring the array of integers

   int [] array = new int[10];

   //Prompt user to add elements into the array

   Scanner in = new Scanner(System.in);

   //Use for loop to receive all 10 elements

   for(int i = 0; i<array.length; i++){

     System.out.println("Enter the next array Element");

     array[i] = in.nextInt();

   }

   //Print the array elements before bubble sort

   System.out.println("The Array before bubble sort");

   System.out.println(Arrays.toString(array));

   //Call bubble sort method

   bb_Sort(array);  

   System.out.println("Array After Bubble Sort");  

   System.out.println(Arrays.toString(array));

 }

}

Answer:

Sentence: Jack or Peggy Zale must fix quickly the fax.

Correct: Either Jack or Peggy Zale must quickly fix the fax.

There are 2 errors in these sentence construction. In stating two persons as an option we must use the word "either" to indicate that you only have two choose from the two of them. The word "

Explanation:

The correct sentence would be "either Jake or Peggy Zale must quickly fix the fax".

In the question construction, there is a conjunction and misarrangement error.

In conclusion, the word " "either Jake or Peggy Zale must quickly fix the fax" is correct

Read more about conjunction

brainly.com/question/8094735

Answer:

True.

Explanation:

An indicator is a comprehensive analysis of critical information by an adversary normally providing the whole picture of an agency's capabilities.

Hope this helps!

An indicator is a comprehensive analysis of critical information by an adversary normally providing the whole picture of an agency's capabilities is true.

Thus, Information that is critical is integrity class-2 information. Samples 1 through 3 are given. according to 3 papers Make a copy Critical information is defined as information that must be shared from shift to shift in order to ensure the health, safety, and welfare of the people served.

Examples include, but are not limited to: irrational behavioral outbursts, sudden or unexplained mood swings in individuals, the administration of PRN medication, transportation issues, unanticipated trips to the doctor or hospital, routine doctor visits requiring follow-up, reportable and information.

All parties working on the Subcontract, including support staff, must be informed of critical information in order for it to be protected against unintentional release and to guarantee that all parties are aware of it.

Thus, An indicator is a comprehensive analysis of critical information by an adversary normally providing the whole picture of an agency's capabilities is true.

Learn more about Critical information, refer to the link:

https://brainly.com/question/32115676

#SPJ6

Answer: it’s E btw

Explanation:

Answer:

It is A and D

Explanation:

Hope this helps. :)

Answer:

To use cout statements, you must include the iostream file in your program.

Answer:

110101 = 53

Hope this helps :)

To help us solve this problem, I've created a simple python program.

print(int("110101", 2))

The program prints 53 to the console.

If you search python ide online and paste that code into the ide and then replace the binary in between the quotes, you can find the value of any binary number you want.

This is python code.

In python, you are supposed to put a colon at the end of while loops. This code does not have a colon after the while loop, therefore, you need to add a colon to the end of the statement.

The error to be fixed in the while loop is to add a colon at the end of the while statements.

x = 1

while (x<26)

     print(x)

     x = x + 1

This is the right code;

x = 1

while(x < 26):

   print(x)

   x = x + 1

The actual code , the while statement is missing a colon at the end of it.

The code is written in python. In python while or for loops statements always ends with a colon.

In the error code, there was no colon at the end of the while loop.

The right codes which I have written will print the value 1 to 25.

learn more on python loop here: https://brainly.com/question/19129298?referrer=searchResults

Answer:

4

Explanation:

Input/output, datapath, control, and memory

There wrong its C bold it.

:)))))

Answer:

729. is answer...........

Answer:

729

Explanation:

Answer:

success = -10 <= number <= 10

Explanation:

I check that -10 is less than or equal to number, and number is less than or equal to 10.

Answer:

def __str__(self):

       return ('Year: %d, VIN: %s' %(self.year_made, self.car_vin))

Explanation:

Here you go! This should do it.

The program gives an implementation of the car record class which displays the model year and registration number of a car. The program written in python 3 goes thus :

class CarRecord :

#initialize a class named carRecord

def __init__(self):

#define the init method of the class

self.year_made = 0

#year car was made is initialized to 0 (integer)

self.car_vin = ' '

#vehicle registration is an empty string

def __str__(self):

#define an str method

return f"Year:{self.year_made}, VIN:{self.car_vin}"

#returns formatted display of the year and VIN number

my_car = CarRecord()

#creates an instance of the carRecord class

my_car.year_made = int(input())

#prompts user for the model year of the car

my_car.car_vin = input()

#prompts user for the model Vin number

print(my_car)

# display the details

A sample run of the program is given

Learn more :https://brainly.com/question/20504501

Answer:

The answer is "The last memory addresses used by a specific program is 2CF0".

Explanation:

For this specific problem, we assume that only a memory storage allocation like Array data structure is needed, as well as any allocation only needs one memory cell since it focuses on the structure and type of data used.  

So, first, we will transform the provided memory address for better comprehension from Hexadecimal into decimal.  

[tex]\to \bold{(2C8D)_{16} = (11405)_{10}}[/tex]

Now 11405 is the first memory cell's address. With all of this number, it can add 99, resulting in the final decimal memory address.  

[tex]=11405 + 99\\\\= 11504[/tex]

[tex]\bold{(11504)_{10} = (2CF0)_{16}}.[/tex]

Answer:

when a file is double clicked it opens so you can see the file.

Explanation:

Answer:

I hope the above picture may help you.

Answer:

C. O(n).

Explanation:

for better understanding, the os is a program that helps in telling how much resources can be used and when processor can be accessed.

to each programme data structures would load and unload every time that a programme is to be run.

while a programme is being managed there would be extra overheads and based on whatever type of os or programme that this is, it may or may not have fixed overhead

from our question overhead is fixed at 100ms

we have,

net time as: 300-100, 510-100, 905-100, 1750-100, 3305-100,

which is, 200, 410, 805, 1650, 3205

when we double 2¹⁰ to 2¹¹ to 2¹² etc, the programme ran is also doubling

this says that run time is same as size of instance n

O(n)