Compute the MIRR statistic for project I if the appropriate cost of capital is 11 percent.
Cash flow -12,000, 5830, 4680, 2,500

The acceleration of the particle is 1 foot per second square

From the question, we have the following parameters that can be used in our computation:

Velocity function v(t) = −t2 + 5t − 3

Express properly

So, we have

v(t) = -t² + 5t − 3

At time t = 3 seconds, we have

v(3) = -(3)² + 5(3) − 3

Evaluate

v(3) = 3

So, we have

Acceleration = v(3)/3

This gives

Acceleration = 3/3

Evaluate

Acceleration = 1 foot per second square

Hence, the acceleration is 1 foot per second square

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The area is 8.84 sq. units

Area is defined as the total space taken up by a flat (2-D) surface or shape of an object.

To find the area we will find the product of 3.4 x 2.6, we can break each length into its base-ten units,

3.4 = 3+0.4

2.6 = 2+0.6

We can rewrite the product and solve it,

= (3+0.4) × (2+0.6)

= (3+0.4) × 2 + (3+0.4) × 0.6

= 3 × 2 + 0.4 × 2 + 3 × 0.6 + 0.4 × 0.6

This expression represents the partial product, each of the expression gives the area of sub rectangles (A, B, C and D). the sum of the partial product will give the area of the main rectangle.

Therefore,

3 × 2 + 0.4 × 2 + 3 × 0.6 + 0.4 × 0.6

= 6+0.8+1.8+0.24

= 8.84

Hence, the required area is 8.84 sq. units.

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The graph in the question is a parabola that opens downwards.

A function is a block of organized, reusable code that is used to perform a single, related action. Functions provide better modularity for your application and a high degree of code reusing. As you already know, Python gives you many built-in functions like print(), etc. but you can also create your own functions. These functions are called user-defined functions.

This means that the range of the function is all real numbers less than or equal to the y-intercept of the parabola, which is 0 in this case. Therefore, the range of the function is all real numbers less than or equal to 0.

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Initial value C is 1.9, Decay factor =0.41 and Growth factor = 0.59 when the function f(x)=1.9(0.41)ˣ.

Given that,

The equation f(x)=1.9(0.41)ˣ.

We have to state the initial value C, the growth or decay factor a, and percent change R for each unit increase in x.

We know that,

In order to translate their graphs over the 2D coordinate plane, I will offer the vertex form of an exponential equation for both the growth and decay functions.

In the case of growth, f(x) = a(1+r[tex])^{x-h}[/tex]+k, where b = 1+r

Decay is defined as f(x)=a(1-r)(x-h[tex])^{x-h}[/tex]+k, where b=1-r.

Consider the function  f(x)=1.9(0.41)ˣ.

We write as

f(x)=1.9(1-0.59)ˣ

So, initial value C is 1.9

Decay factor =0.41

Growth factor = 0.59

Therefore, Initial value C is 1.9, Decay factor =0.41 and Growth factor = 0.59 when the function f(x)=1.9(0.41)ˣ.

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The value of x on the line segment and the triangle is 17.3 units

From the question, we have the following parameters that can be used in our computation:

A triangle (see attachment for the triangle)

Also from the question, we understand that:

BD bisects ∠ABC

Using the bisector theorem, we have

x/13 = 20/15

Multiply both sides of the equation by 13

So, we have the following representation

13 * x/13 = 20/15 * 13

Evaluate the products

So, we have the following representation

x = 20/15 * 13

Evaluate the other products

So, we have the following representation

x = 52/3

This gives

x = 17.3

Hence, the length x is 17.3 units

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Raffles are chance-based contests in which participants compete to win exciting prizes.

To participate, all you need is a ticket with a number on it. Following the sale of all tickets, a drawing is conducted during which a random selection of tickets is made. If you chance to have the winning ticket, congratulations! a lot of engagement.

Raffles elicit a great deal of interest and support because people enjoy playing games of chance, especially when they have the possibility to win a significant prize.

high income. Your organisation has a strong possibility of making some big money from ticket sales if engagement is high!

low price. A virtual free raffle can be found online! A virtual raffle is the most cost-effective type of fundraising because you won't need to print actual tickets, reserve a location for the drawing, or buy refreshments.

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Answer:

17.5 miles

Step-by-step explanation:

right!!

Answer:

60cm

Step-by-step explanation:

given:

focal length (f) = 20cm

image height (v) = ½u

object height (u) = ?

(1÷v) + (1÷u) = (1÷20)

(1÷(½u)) + (1÷u) = (1÷20)

(2÷u) + (1÷u) = (1÷20)

(3÷u) = (1÷20)

u = 20 × 3

u = 60cm

The two scenarios that can be represented by a ratio 4:5 are

1. The ratio of fiction books to the non fiction books, if there are 4 fiction books to 5 non fiction books

2. The ratio of marker to crayon , if there are 4 markers and 5 crayons. ( option A and D)

A ratio is an ordered pair of numbers a and b, written a / b where b does not equal 0. A proportion is an equation in which two ratios are set equal to each other. For example, if there is 1 boy and 3 girls you could write the ratio as: 1 : 3 (for every one boy there are 3 girls) 1 / 4 are boys and 3 / 4 are girls.

For a scenario that will give ratio of 4:5, it means the first entity will be 4 and the second entity will be 5.

Therefore the two statements that obey this in the option are

1. The ratio of fiction books to the non fiction books, if there are 4 fiction books to 5 non fiction books

2. The ratio of marker to crayon , if there are 4 markers and 5 crayons.

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The 5 life examples are:

In all these life examples that are listed above, the number 100 is divided by 20 giving 5 as the result. which is said to be:

100/20

= 5.

Therefore, reason behind this is that the number 20, in these life examples, is a representative of a whole value and the number 5 represents the number of parts it is being divided into, so when you multiply 20 by 5, you get 100, which represents the total of these five parts. So, 100 is related to 20 in this context as the multiple of 20 and 5.

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Greatest common factor (GCF) of 50 and 65 is 5.

We will first find the prime factorization of 50 and 65. After we will calculate the factors of 50 and 65 and find the biggest common factor number .

Step-1: Prime Factorization of 50

Prime factors of 50 are 2, 5. Prime factorization of 50 in exponential form is:

50 = 21 × 52

Step-2: Prime Factorization of 65

Prime factors of 65 are 5, 13. Prime factorization of 65 in exponential form is:

65 = 51 × 131

Step-3: Factors of 50

1, 2, 5, 10, 25

Final Step: Biggest Common Factor Number

We found the factors and prime factorization of 50 and 65. The biggest common factor number is the GCF number.

So the greatest common factor 50 and 65 is 5.

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The blanket that they should choose is the one for which the multiplication of dimensions result in the largest value.

The area of a rectangle of dimensions length and width is given by the multiplication of these dimensions, as follows:

Area = length x width.

Then, to obtain the area for each blanket, their dimensions must be multiplied.

Then the blankest with the greatest area is the one for which the multiplication of the dimensions will result in the largest value.

(applying the formula for the area of the rectangle).

The problem is incomplete, as the dimensions were not given, hence the answer is given in general terms.

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it is found that 29 are taking algebra, 14 are taking physics, and 5 are enrolled in both using principle of inclusion-exclusion we can say 38 students are enrolled in either algebra or physics.

To find how many students are enrolled in either algebra or physics, you can use the principle of inclusion-exclusion, which states that the total number of elements in two sets can be found by adding the number of elements in each set and then subtracting the number of elements that are in both sets.

So, the number of students enrolled in either algebra or physics is:

29 (students enrolled in algebra) + 14 (students enrolled in physics) - 5 (students enrolled in both) = 38

So, 38 students are enrolled in either algebra or physics.

It is important to notice that in the table you provided is a two-way frequency table also known as a contingency table, it shows the relationship between two variables, in this case, Algebra and Physics and the frequencies of each combination.

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The value of the expression 8x² + 6x - 8 below when x=2 is 36.

The expression can be evaluated by following the steps below:

8x² + 6x - 8 in x = 2 means that the variable x will be replaced by the given number which is 2.

8*2² + 6*2 - 8

8*4 + 12 - 8

32 + 16 - 8 = 36

This therefore means that when x= 2 in 8x² + 6x - 8 , the value gotten will be 36.

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On solving the value of provided question we can say that - the value of the slope intercept y = -3.

The point on the y-axis where the slope of the line passes is known as the intersection point in mathematics. the location on a line or curve where the y-axis crosses that point. This is demonstrated by putting y = mx+c as the equation for the straight line, where m denotes the slope and c the y-intercept. In the intercept form of the equation, the slope (m) and y-intercept (b) of the line are highlighted. The slope is m, and the y-intercept is b for equations in the intercept form (y=mx+b). Additionally, certain equations may be recast to seem like slope intercepts. For instance, if y=x is rewritten as y=1x+0, the slope becomes 1 and the y-intercept becomes 0.

as we can see from graph that,

line passes through origin, so x= 0

the, y = -5x - 3

y = -3

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Answer:

3.5m(3m + 1.8)

10.5m^2+6.3m

Step-by-step explanation:

So on solving the provided question, we can say that the function g(x) is equal to g(x) = [tex]\sqrt{2x}[/tex]

The mathematical procedure known as "function composition" takes two functions, f and g, and creates a function, h = g f, such that h(x) = g. This process involves applying the function g to the outcome of applying the function f to x. When the result of one function is utilized as the input for another, this is known as a composite function. The function f g (x) fg(x) fg(x) fg(x), also known as "f of g of x" or "f g fg fg of x," is the composition of the two functions if we have a function f and another function g.

f(f(x)) = [tex]\frac{x}{\sqrt{6} }[/tex]

f(x) = 3x^2

g(f(x)) = [tex]\frac{3x^2}{\sqrt{6} }[/tex]

g(x) = [tex]\sqrt{2x}[/tex]

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The graph of the linear equation is attached below. After 11 months, the total savings will be $237.50.

What is a saving account?

An account in a retail bank is a savings account. Common characteristics include having a finite number of withdrawals allowed, not having check or connected debit card facilities, having few transfer choices, and not being able to become overdrawn.

Given equation is

y = 12.5x + 100

To find points on the linear equation, putting x = 0, 1 and 2 in the given equation:

y(0) = (12.5 × 0) + 100

y(0) = 100

y(1) = (12.5 × (1)) + 100

y(1) = 12.5 + 100

y(1) = 112.5

y(2) = (12.5 × 2) + 100

y(2) = 25 + 100

y(2) = 125.

The points on the linear equation are (0,100), (1, 112.5), (2,125).

Plot the points and join the points to draw the line to get graph the linear equation.

Putting y = 237.50 in the given equation y = 12.5x + 100:

237.50 = 12.5x + 100

Subtract 100 from both sides:

237.50 - 100 = 12.5x + 100 - 100

137.50 = 12.5x

Divide both sides by 12.5:

x = 137.50/12.5

x = 11

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Answer:

x=4 and y=2

Step-by-step explanation:

You should use graph, point of intersection(for example point M(4,2) ) is solution

And we can conclude that x=4 and y=2

Answer: The matching jacket requires 1/6 yards less fabric than the dress, which is 3 1/4 - 1/6 = 3 1/4 - 2/12 = 3 1/4 - 1/6 = 3 1/4 - 1/6 = 3 1/4 - 1/6 = 3 3/12 yards of fabric.

To add these two amounts of fabric together, you need to add the yards and the inches separately.

For the dress: 3 1/4 yards = 3 + 1/4 = 3 + 0.25 = 3.25

For the jacket: 3 3/12 yards = 3 + 3/12 = 3 + 0.25 = 3.25

So, for both pieces, the required fabric is 3.25 + 3.25 = 6.5 yards

Step-by-step explanation:

Answer:

A.  x ≥ 21[tex]\frac{2}{3}[/tex]

Step-by-step explanation:

81 - 1[tex]\frac{1}{5}[/tex] x ≤ 55

-1[tex]\frac{1}{5}[/tex] x ≤ 55-81

-[tex]\frac{6}{5 }[/tex] x ≤ -26

x ≥ -26(-[tex]\frac{5}{6}[/tex])       **flip the inequality when you divide by a negative number

x ≥ 21[tex]\frac{2}{3}[/tex]

Answer:

  3.58

Step-by-step explanation:

You want to know the weekly growth factor if the daily growth factor is 1.2.

The weekly growth factor will be the growth factor over 7 days:

  (1.2)^7 ≈ 3.58

Every week, the number of locusts grows by a factor of 3.58.

__

Additional comment

The exponential model is ...

  number = (initial number)(growth factor)^t

The period of time associated with the growth factor is the units associated with t. Since 1 week = 7 days, the multiplier for 7 days is ...

  weekly growth factor = (daily growth factor)^7

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Answer:

−1 < y < 3

Step-by-step explanation:

Answer:

The tree is 44 feet

Step-by-step explanation:

[tex]\frac{8}{6}[/tex] is equivalent to [tex]\frac{4}{3}[/tex] (divide the numerator and denominator by 2)

[tex]\frac{4}{3}[/tex] = [tex]\frac{x}{33}[/tex]

3 x 1  = 33, so 4 x 11 = 44

Answer:

a = -20/13

Step-by-step explanation:

7 - 13a = 27

-13a = 20

a = -20/13

Let's check

7 - 13(-20/13) = 27

7 + 260/13 = 27

7 + 20 = 27

27 = 27

So, a = -20/13 is the correct answer!

The equations that are true for x = –2 and x = 2 are:

x^2-4=0 and 4x^2 = 16

We can determine the equations that are true for x = –2 and x = 2 by testing the given options:

After testing the options option  1 ; x^2-4=0 putting x = 2 or -2 into the equation will give zero.  

(2^)2-4=0

(-2)^2-4=0

Then option 4: 4x^2 = 16

4(2)^2 = 16

4(-2)^2 = 16

Therefore, option 1st and 4th are correct.

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You will be reported if you guess. The result is -1 if P=(4,7)on D2 (P). Consequently, P=(4,7) in D2 reports -1. (P).

Given p= (4,7)

The answer to  4 p+7 is 4(-2)+7=-8+7=-1

The value of the denominator (d2), a weighting factor, is depends on the control chart's subgroup size, n. Based on a subgroup size of 5, the value of d2 in the case is 2.326. Following is a brief list of the d2 values for other subgroup sizes.

The table of constants below contains the d2 value, which is determined by the subgroup size. The average moving range, or MR-bar, will be used if your subgroup size is one. Model No. The average range is 0.220, and the mean is 0.8057 (X-bar). The D2 function gives the sample range of n independent, normally distributed random variables with the same mean and a standard deviation of 1 the anticipated value.

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1)Triangle : s = 6cm ; P= 18 cm

2.) Square : s = 7 cm ; P = 28 cm

3.) Rectangle = W = 4cm , L = 8 cm ; P = 24cm

4.) Regular Heptagon : s = 3cm ; P = 21 cm

5.) Circle : r = 12cm ; C = 24∏ cm.

What is circumference?

The circumference of a circle or ellipse in geometry is its perimeter. That is, if the circle were opened up and straightened out to a line segment, the circumference would be the length of the arc. The curve length around any closed figure is more often referred to as the perimeter.

Given that the length of each side of a triangle is 6 cm.

The perimeter of an equilateral triangle is 3a, where a is the length of the side of the equilateral triangle.

The perimeter of the triangle is 3 × 6 = 18 cm

The length of side of a square is 7 cm.

The perimeter of a square is 4a, where a is the length of the side of the square.

The perimeter of the square is 4 × 7 = 28 cm.

The length and breadth of a rectangle is W = 4 cm and L = 8 cm.

The perimeter of a rectangle is 2(L+ W)

The perimeter of the rectangle is = 2(8 + 4) = 2 × 12 =24 cm

The perimeter of Regular Heptagon is 7a, where a is the length of the side of the Regular Heptagon.

The perimeter of a Regular Heptagon is (7  × 3) = 21 cm

The perimeter of a circle with a radius r is 2∏r.

The perimeter of the circle is 2∏ × 12 = 24∏ cm.

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