Answer:
True Just took the test
Explanation:
Answer:
the answer is T or TRUE
Explanation:
In a system where Round Robin is used for CPU scheduling, the following is TRUE when a process cannot finish its computation during its current time quantum? The process will terminate itself. The process will be terminated by the operating system. The process's state will be changed from running to blocked. None of the mentioned.
Answer:
B. The process will be terminated by the operating system.
Explanation:
When Round Robin is used for CPU scheduling, a time scheduler which is a component of the operating system is used in regulating the operation. A time limit is set for each of the processes to be run.
So, when a process fails to complete running before its time elapses, the time scheduler would log it off and return it to the queue. This queue is in a circular form and gives each of the processes a chance to run its course.
Based on the information given regarding CPU scheduling, the correct option is C. The process's state will be changed from running to blocked.
It should be noted that in a system where Round Robin is used for CPU scheduling, when a process cannot finish its computation during its current time quantum, the process's state will be changed from running to blocked.
It should be noted that a prices transition to a blocked state occurs when it's waiting for some events like a particular resource becoming available.
Learn more about CPU scheduling on:
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Technician A says that the last step in the diagnostic process is to verify the problem. Technician B says that the second step is to perform a thorough visual inspection. Who is correct
Answer:
The answer to this question is given below in the explanation section. However, the correct option is Technician B.
Explanation:
There are eight steps procedures to diagnose the engine.
Step 1 Verify the Problem
Step 2 Perform a Thorough Visual Inspection and Basic Tests
Step 3 Retrieve the Diagnostic Trouble Codes (DTCs)
Step 4 Check for Technical Service Bulletins (TSBs)
Step 5 Look Carefully at Scan Tool Data
Step 6 Narrow the Problem to a System or Cylinder
Step 7 Repair the Problem and Determine the Root Cause
Step 8 Verify the Repair and Clear Any Stored DTCs
So the correct technician is Technician B that says that the second step is to perform a thorough visual inspection.
Which of the following is NOT solely an Internet-based company?
Netflix®
Amazon®
Pandora®
CNN®
Answer:
I think it's Pandora, though I am familiar with others
Answer:
CNN
Explanation:
Which of the following domestic appliances does not use a magnet?
A. Fridge
B. Pressing iron
C. Radio
D. Fan
Plz answer me will mark as brainliest
Answer:
True
Operating System
Booting
What is the maximum number of VLANs that can be configured on a switch supporting the 802.1Q protocol? Why?
Answer:
4096 VLANs
Explanation:
A VLAN (virtual LAN) is a group of devices on one or more LAN connected to each other without physical connections. VLANs help reduce collisions.
An 802.1Q Ethernet frame header has VLAN ID of 12 bit VLAN field. Hence the maximum number of possible VLAN ID is 4096 (2¹²). This means that a switch supporting the 802.1Q protocol can have a maximum of 4096 VLANs
A lot of VLANs ID are supported by a switch. The maximum number of VLANs that can be configured on a switch supporting the 802.1Q protocol is 4,094 VLANS.
All the VLAN needs an ID that is given by the VID field as stated in the IEEE 802.1Q specification. The VID field is known to be of 12 bits giving a total of 4,096 combinations.But that of 0x000 and 0xFFF are set apart. This therefore makes or leaves it as 4,094 possible VLANS limits. Under IEEE 802.1Q, the maximum number of VLANs that is found on an Ethernet network is 4,094.
Learn more about VLANs from
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Return to the Product Mix worksheet. Benicio wants to provide a visual way to compare the scenarios. Use the Scenario Manager as follows to create a PivotTable that compares the profit per unit in each scenario as follows:
a. Create a Scenario PivotTable report using the profit per unit sold (range B17:F17) as the result cells.
b. Remove the Filter field from the PivotTable.
c. Change the number format of the value fields to Currency with 2 decimal places and the $ symbol.
Answer:
To create a pivot table, select the columns to pivot and click on the insert option, click on the pivot table option and select the data columns for the pivot, verify the table range, select the location for the pivot and click ok. To format a column, select the columns and click the number option on the home tab, select the currency option and click on the number of decimal places
Explanation:
Microsoft Excel is a great tool for data analysis and visualization. It has several mathematical, engineering, statistical, and graphical tools for working with data.
A pivot-table is an essential tool for describing and comparing data of different types.
The steps to follow in order to produce a Pivot table would be as mentioned below:
Opting the columns for a pivot table. Now, make a click on the insert option. This click is followed by opting for the pivot table and the data columns that are available in it.After this, the verification of the range of the table is made and then, the location for the pivot table has opted. After this, the column is formatted and the number option is selected followed by the currency option, and the quantity of decimal places. A Pivot table allows one to establish a comparison between data of distinct categories(graphic, statistical, mathematical) and elaborate them.Learn more about 'Pivot Table' here:
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Which function is used to display a string value to the screen?
main[]
print()
run=
SHOW!
Answer:
The correct answer to this question is given below in the explanation section.
Explanation:
in most programming languages, the print() function is used to display a string value to the screen. Because, the print function prints all the string given in it as a parameter.
for example: to print hello world.
we use the function to print hello world as print("hello world").
However, it noted that other options are not correct because the main() function is an entry point of a program and it does not print string value to the screen. while run and show function do not print string value of screen also.
Answer:
in python print()
Which of the following tabs in the PowerPoint Ribbon is unique to PowerPoint,
not found in other Microsoft Office applications?
a.
b.
Home
Animations
Insert
View
Answer:
The answer to this question is given below in the explanation section
Explanation:
The correct option for this question is Animation tab.
Animation tab in PowerPoint ribbon is a unique tab that is not found in other office applications such as in word, excel, outlook, publisher etc.
Because in PowerPoint you can use animation to make your slides animated and all animation can be managed and animation-related settings, you can find in the animation tab.
However, other tabs such as Home, Insert, and View are common in all office applications.
If the propagation delay through a full-adder (FA) is 150 nsec, what is the total propagation delay in nsec of an 8-bit ripple-carry adder
Answer:
270 nsec
Explanation:
Ripple-carry adder is a combination of multiple full-adders. It is relatively slow as each full-adder waits for the output of a previous full-adder for its input.
Formula to calculate the delay of a ripple-carry adder is;
= 2( n + 1 ) x D
delay in a full-adder = 150 nsec.
number of full-adders = number of ripple-carry bits = 8
= 2 ( 8 + 1 ) x 150
= 18 x 150
= 270 nsec
def build_dictionary(string):
d = dict()
for x in string:
if not d.get(x):
d[x] = 1
else:
d[x] += 1
return d
Part 2:
Create a function named build_word_counter that has the same signature as build_dictionary. This function also returns a dictionary, however, it normalizes each word such that the case of the word is ignored (i.e. case insensitive). So the words LIKE, Like, like should be considered the same word (much like a regular dictionary would). You must use the same function add_item again (so don't make any modifications to it) Normalize words by using the lower case version of the word.
Part 3:
Create a function named build_letter_distribution that has the same signature as build_dictionary. This function returns a dictionary; however, each key will be a letter and the value will be the count that represents how many times that letter was found. Essentially you will have a letter distribution over a sentence (which is a list of words). The letters should be case insensitive.
Answer:
Follows are the code to this question:
def build_word_counter(string):#defining a method build_word_counter that accepts string as a parameter
d = dict()#defining d variable as a dictionary
for x in string:#defining for loop that use string
x = x.lower()#Use lower method
if not d.get(x):#defining if block that holds value in d variable
d[x] = 1#use dictionary to hold value in 1
else:#defining else block
d[x] += 1#use dictionary to increment value by 1
return d#return dictionary
print(build_word_counter(["Like","like","LIKE"]))#use print method to call method
def build_letter_distribution(string):#defining a method build_letter_distribution that accepts string variable
d = dict()#defining d variable as a dictionary
for i in string:#defining for loop to count string value
for j in i:#defining for loop to hold string as number
if not d.get(j):#defining if block that doesn't get value in dictionary
d[j] = 1#hold value in dictionary
else:#defining else block
d[j] += 1#use dictionary to increment the dictionary value
return d#return dictionary
print(build_letter_distribution(["Like","test","abcdEFG"]))#use print method to return its value
Output:
please find the attached file.
Explanation:
In the first program a method, "build_word_counter" is defined that accepts a string variable in its parameter, and inside the method, a dictionary variable "d" is defined that uses the for loop to hold string value and convert all value into lower case.
In the next step, a conditional statement is used that holds value in the dictionary and count its word value.
In the second program a method, "build_letter_distribution" is defined that holds string variable in its parameter, and inside the method, a dictionary variable "d" is defined that uses the two for loop and in if the block, it holds value in the dictionary and returns its value, and use print method to print its return its value.
B1:B4 is a search table or a lookup value
Answer:
lookup value
Explanation:
1. When you write HTML code, you use ______ to describe the structure of information on a webpage. a. a web address b. tags c. styles d. links
Answer:
b. tags
Explanation:
When you write HTML code, you use tags to describe the structure of information on a webpage. These tags are represented by the following symbols <>. All of HTML is written using different types of tags such as <body>, <main>, <div>, <nav>, etc. Each of these serves a different purpose but are all used for structuring the specific information on a website so that the information is well organized and is not all on top of each other. This also allows for specific sections to be easily targeted and styles separately from the other sections.
The code below is supposed to display the name and score for the student with the highest score one time before the program ends. It is displaying Jim as the student with the highest score. It is displaying the highest score of 95. Unfortunately, Jim does not have a score of 95. Correct the following code:
Declare String students[SIZES] = {"Jen", "Jon", "Jan", "Joe", "Jim"}
Declare Integer scores[SIZES] = 70, 85, 72, 95, 90
Declare Integer index Declare Integer highest = scores[0]
Declare Integer highest Name = " " For index = 0
To SIZES //Assume that this translates to For (index = 0; index <= SIZES, index ++)
If scores[index] > highest then highest = scores[index]
End Of highestName = students[index]
End For Display "
The name of the student with the highest score is ", highest Name Display "The highest score is ", highest
Answer:
Modify
If scores[index] > highest then highest = scores[index]
End Of highest
Name = students[index]
End For Display
to
If scores[index] > highest then highest = scores[index]
Name = students[index]
End Of highest
End For Display
Explanation:
In the code, you posted the code segment that gets the name of the student with the highest score is outside the if condition that determines the highest.
To make correction, we only need to bring this code segment into the loop.
See Answer
A CPU with a quad-core microprocessor runs _____ times as fast as a computer with a single-core processor.
two
three
four
eight
Answer:
four
Explanation:
quad means four so it runs four times faster
7. While an adjacency matrix is typically easier to code than an adjacency list, it is not always a better solution. Explain when an adjacency list is a clear winner in the efficiency of your algorithm
Answer:
The answer is below
Explanation:
Adjacency list is a technique in a computer science that is used for representing graph. It deals with a gathering of unorganized lists utilized to illustrate a limited graph. In this method, each list depicts the group of data of a peak in the graph
Adjacency List are most preferred to Adjacency Matrix in some cases which are:
1. When the graph to is required to be sparsely.
2. For iterability, Adjacent List is more preferable
We define the following terms:
Lexicographical Order, also known as alphabetic or dictionary order, orders characters as follows:
For example, ball < cat, dog < dorm, Happy < happy, Zoo < ball.
A substring of a string is a contiguous block of characters in the string. For example, the substrings of abc are a, b, c, ab, bc, and abc.
Given a string, , and an integer, , complete the function so that it finds the lexicographically smallest and largest substrings of length .
Input Format
The first line contains a string denoting .
The second line contains an integer denoting .
Constraints
consists of English alphabetic letters only (i.e., [a-zA-Z]).
Output Format
Return the respective lexicographically smallest and largest substrings as a single newline-separated string.
Sample Input 0
welcometojava
3
Sample Output 0
ava
wel
Explanation 0
String has the following lexicographically-ordered substrings of length :
We then return the first (lexicographically smallest) substring and the last (lexicographically largest) substring as two newline-separated values (i.e., ava\nwel).
The stub code in the editor then prints ava as our first line of output and wel as our second line of output.
Solution:-
import java.util.Scanner;
public class Solution {
public static String getSmallestAndLargest(String s, int k) {
String smallest = "";
String largest = "";
smallest = largest = s.substring(0, k);
for (int i=1; i
String substr = s.substring(i, i+k);
if (smallest.compareTo(substr) > 0)
smallest = substr;
if (largest.compareTo(substr) < 0)
largest = substr;
}
return smallest + "\n" + largest;
}
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
String s = scan.next();
int k = scan.nextInt();
scan.close();
System.out.println(getSmallestAndLargest(s, k));
}
}
Answer:
Here is the JAVA program:
import java.util.*;
public class Solution { // class name
public static String getSmallestAndLargest(String s, int k) { //method that takes a string s and and integer k and returns lexicographically smallest and largest substrings
String smallest = ""; //stores the smallest substring
String largest = ""; //stores the largest substring
smallest = largest = s.substring(0, k); //sets the smallest and largest to substring from 0-th start index and k-th end index of string s
for(int i = 0;i<=s.length()-k;i++){ //iterates through the string s till length()-k
String subString = s.substring(i,i+k); //stores the substring of string s from ith index to i+k th index
if(i == 0){ //if i is equal to 0
smallest = subString; } //assigns subString to smallest
if(subString.compareTo(largest)>0){ //checks if the subString is lexicographically greater than largest
largest = subString; //sets subString to largest
}else if(subString.compareTo(smallest)<0) //checks if the subString is lexicographically less than smallest
smallest = subString; } //sets subString to smallest
return smallest + "\n" + largest; } //returns the lexicographically smallest and largest substrings
public static void main(String[] args) { //start of main method
Scanner scan = new Scanner(System.in); //creates Scanner object
String s = scan.next(); //scans and reads input string from user
int k = scan.nextInt(); //scans and reads integer k from user
scan.close();
System.out.println(getSmallestAndLargest(s, k)); } } //calls method by passing string s and integer k to it to display lexicographically smallest and lexicographically largest substring
Explanation:
The program takes a string s and an integer k and passes them to function getSmallestAndLargest that returns the lexicographically smallest and lexicographically largest substring. The method works as follows:
Lets say s = helloworld and k = 3
smallest = largest = s.substring(0, k);
s.substring(0, k); is returns the substring from 0th index to k-th index so it gives substring hel
for(int i = 0;i<=s.length()-k;i++) This loop iterates through the string s till s.length()-k times
s.length()-k is equal to 7 in this example
At first iteration:
i = 0
i<=s.length()-k is true so program enters the body of loop
String subString = s.substring(i,i+k); this becomes:
subString = s.substring(0,3);
subString = "hel"
if(i == 0) this is true so:
smallest = subString;
smallest = "hel"
At second iteration:
i = 1
i<=s.length()-k is true so program enters the body of loop
String subString = s.substring(i,i+k); this becomes:
subString = s.substring(1,4);
subString = "ell"
if(subString.compareTo(smallest)<0) this condition is true because the subString ell is compared to smallest hel and it is lexographically less than smallest so :
smallest = subString;
smallest = "ell"
So at each iteration 3 characters of string s are taken and if and else if condition checks if these characters are lexicographically equal, smaller or larger and the values of largest and smallest change accordingly
After the loop ends the statement return smallest + "\n" + largest; executes which returns the smallest and largest substrings. So the output of the entire program with given example is:
ell wor
Here ell is the lexicographically smallest substring and wor is lexicographically largest substring in the string helloworld
The screenshot of the program along with its output is attached.
Roger's camera battery had a short circuit, which caused a fire at his home. What could he have done to prevent this from happening? A left batteries in camera when not in use B. stored batteries with other metal objects c. kept batteries near a magnetic field D. removed the batteries from the camera
Answer: D
Explanation: Because if he took the battery out it would not have short circuited.
My Mac is stuck on this screen? How to fix?
Answer:
Press and hold the power button for up to 10 seconds, until your Mac turns off. If that doesn't work, try using a cellular device to contact Apple Support.
Explanation:
If that also doesn't work try click the following keys altogether:
(press Command-Control-Eject on your keyboard)
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
This makes the laptop (macOS) instruct to restart immediately.
Hopefully this helps! If you need any additional help, feel free and don't hesitate to comment here or private message me!. Have a nice day/night! :))))
Another Tip:
(Press the shift, control, and option keys at the same time. While you are pressing those keys, also hold the power button along with that.)
(For at least 10 seconds)
Which feature of a database allows a user to locate a specific record using keywords?
Chart
Filter
Search
Sort
Answer:
Search
Explanation:
Because you are searching up a specific recording using keywords.
I hope this helps
Answer:
Filter
Explanation:
I got it correct for a quiz.
What is a small device that connects to a computer and acts as a modem
Answer:
Dongle
Explanation:
a small device that connects to a computer and acts as a modem. broadband. internet connection with fast data-transfer speeds and an always-on connection. cable internet service.
Which type of chart or graph uses vertical bars to compare data?
Column chart
Line graph
Pie chart
Scatter chart
Answer:
Colunm Chart
Explanation:
Trust me
Online Privacy
1.)Explain why is online privacy a controversial topic?
2.)Explain why this issue is applicable to you and your peers.
3.)Explain why this issue is a federal issue and not a state or local issue.
Answer:
Yes
Explanation:
Online privacy is a controversial topic due to the fact that it's a very hard thing to navigate. Some websites use cookies that are used to store your data so in a way there taking your privacy away which is controversial because of the way they use the information. Some websites store it for use of ads while others sell it. This issue is applicable to me and my peers because of the way we use technology. It can be used to steal my information about where I live and what I look up online. Also, the information stored could have my credit or debit card credentials. This issue should be a federal and nationwide issue because this is an everyday occurrence and leaves tons of people in crushing debt every year.
Plz answer me will mark as brainliest
Answer:
Application
Explanation:
Application software comes in many forms like apps, and even on computers. The software is most common on computers of all kinds while mobile applications are most common on cellular devices.
Explaim Why the shape of a cell is hexagonal
Create an interface called Runner. The interface has an abstract method called run() that displays a message describing the meaning of run to the class. Create classes called Machine, Athlete, and PoliticalCandidate that all implement Runner.
The run() should print the following in each class:
Machine - When a machine is running, it is operating.
Athlete - An athlete might run in a race, or in a game like soccer.
PoliticalCandidate - A political candidate runs for office.
----------------------------------------------------------------------------------------------------
public class Athlete implements Runner
{
public void run()
{
// write your code here
}
}
--------------------------------------------------------------------------------------
public class DemoRunners
{
public static void main(String[] args)
{
Machine runner1 = new Machine();
Athlete runner2 = new Athlete();
PoliticalCandidate runner3 = new PoliticalCandidate();
runner1.run();
runner2.run();
runner3.run();
}
}
------------------------------------------------------------------------------------------
public class Machine implements Runner
{
public void run()
{
// write your code here
}
}
----------------------------------------------------------------------------------------------------
public class PoliticalCandidate implements Runner
{
public void run()
{
// write your code here
}
}
----------------------------------------------------------------------------------------------------
public interface Runner
{
// write your code here
}
----------------------------------------------------------------------------------------------------
Answer:
Please find the code and its output in the attached file.
Explanation:
In the above-given code, an interface "Runner" is defined, inside the interface, an abstract method run is declared.
In the next step, three class "Athlete, Machine, and PoliticalCandidate" s defined that implements the run method, and use the print message that holds a given value as a message.
In the next step, a class "DemoRunners" is defined, and inside the main method, the three-class object is declared, which calls the run method.
explain how to use the information in an outline to start writing a business document
Answer: document
Explanation:
Find the maximum value and minimum value in milesTracker. Assign the maximum value to maxMiles, and the minimum value to minMiles. Sample output for the given program:
Min miles: -10
Max miles: 40
Here's what I have so far:
import java.util.Scanner;
public class ArraysKeyValue {
public static void main (String [] args) {
final int NUM_ROWS = 2;
final int NUM_COLS = 2;
int [][] milesTracker = new int[NUM_ROWS][NUM_COLS];
int i = 0;
int j = 0;
int maxMiles = 0; // Assign with first element in milesTracker before loop
int minMiles = 0; // Assign with first element in milesTracker before loop
milesTracker[0][0] = -10;
milesTracker[0][1] = 20;
milesTracker[1][0] = 30;
milesTracker[1][1] = 40;
//edit from here
for(i = 0; i < NUM_ROWS; ++i){
for(j = 0; j < NUM_COLS; ++j){
if(milesTracker[i][j] > maxMiles){
maxMiles = milesTracker[i][j];
}
}
}
for(i = 0; i < NUM_ROWS; ++i){
for(j = 0; j < NUM_COLS; ++j){
if(milesTracker[i][j] < minMiles){
minMiles = milesTracker[i][j];
}
}
}
//edit to here
System.out.println("Min miles: " + minMiles);
System.out.println("Max miles: " + maxMiles);
}
Answer:
See Explanation
Explanation:
Your program is correct and doesn't need an attachment.
However, there's a mismatch in placement of curly braces in your program
{
}
I've made corrections to that and I've added the corrected program as an attachment.
Aside that, there's no other thing to be corrected in your program.
Use another compiler to compile your program is you are not getting the required output.
A _____ is a smaller image of a slide.
template
toolbar
thumbnail
pane
802.11ac provides an advantage over 802.11n by incorporating increased channel bonding capabilities. What size bonded channels does 802.11ac support?
Answer:
The 802.11ac wireless standard takes channel bonding to a higher level because it can support 20MHz, 40MHz, and 80MHz channels, with an optional use of 160MHz channels.
Explanation:
The 802.11ac is a standardized wireless protocol established and accepted by the institute of electrical and electronics engineers (IEEE). 802.11ac as a wireless local area network (WLAN) protocol, has multiple amplitude and bandwidth, thus making it to be the first standard wireless protocol to have the ability to operate on a Gigabit (Gb) network.
Generally, the 802.11ac wireless standard provides an advantage over 802.11n by incorporating increased channel bonding capabilities. The 802.11ac wireless standard takes channel bonding to a higher level because it can support 20MHz, 40MHz, and 80MHz channels, with an optional use of 160MHz channels.
On the other hand, 802.11n is a standardized wireless protocol that can support either a 20MHz or 40MHz channel.