Condition when an organ is impaired sickness

Answers

Answer 1

Answer:

As traditionally used, impairment refers to a problem with a structure or organ of the body; disability is a functional limitation with regard to a particular activity; and handicap refers to a disadvantage in filling a role in life relative to a peer group.

Explanation:

Hope this helps u

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Related Questions

A motorcycle travels a distance of 420 miles in 8.5 hours. Give the average speed of the motorcycle

Answers

Answer:

As per Provided Information

Distance travelled by motorcycle is 420 miles

Time taken by motorcycle is 8.5 hours

we have been asked to determine the average speed of the motorcycle .

[tex] \bf \: Speed_{(Average)} = \cfrac{total \: distance \: travelled}{time \: taken} [/tex]

Now let's put the given value to find the average speed of motorcycle

[tex] \longrightarrow \sf \: Speed_{(Average)} \: = \cfrac{420}{8.5} \\ \\ \\ \longrightarrow \sf \: Speed_{(Average)} \: = \cfrac{4200}{85} \\ \\ \\ \longrightarrow \sf \: Speed_{(Average)} \: = \cancel\cfrac{4200}{85} \\ \\ \\ \longrightarrow \sf \: Speed_{(Average)} \: = 49.41 \: miles \: per \: hour[/tex]

Therefore,

Average speed of the motorcycle is 49.41 miles per hour .

does a radio wave have a high or low frequency

Answers

Answer:

Low

Explanation:

Radio waves have photons with the lowest energies.

What does the atomic number of an atom tell us?

Answers

Answer:

The atomic number uniquely identifies a chemical element. It is identical to the charge number of the nucleus. In an uncharged atom, the atomic number is also equal to the number of electrons. The sum of the atomic number Z and the number of neutrons N gives the mass number A of an atom.

Explanation:

Answer:

I believe that the atomic number of an atom represents the number of protons in one atom of an element. It also tells you the number of electrons in a neutral atom of that element

Explanation:I hope that this is helpful.

a person drops two objects from the same height one object weighs 15n and the other weighs 10 n how does the mass of the object relate to the force of gravity on them​

Answers

Answer:

Since the gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force. So as the mass of either object increases, the force of gravitational attraction between them also increases.

Explanation:

sorry if this is wrong or is incorrect... but at least I tried right.

Their weights are in the ratio 3:2 so their mass is in the same ratio. They would both fall to the ground at the same time.

A boy pulls a wagon with an applied force of 40 N on frictionless surface. If the mass of the wagon is 13kg, what is the acceleration of the wagon?​

Answers

Answer:

3.1 m/s²

Explanation:

Apply Newton's second law:

∑F = ma

40 N = (13 kg) a

a ≈ 3.1 m/s²

Please help!!!!!!!

A tennis racket hits a tennis ball forward by exerting a force of 55 N on the ball.
What force does the ball exert on the tennis racket during the hit?

A. The ball exerts an equal backward force on the racket.

B. The ball is light, so it exerts almost no force on the racket.

C. The ball causes drag on the racket with a small forward force as it flies away.

D. The ball exerts a smaller force that alternates forward and backward to vibrate the racket.

Answers

The answer is A. The ball exerts an equal backward force on the racket. Newton’s 3rd Law: to every action there is an equal and opposite reaction.

A ball is thrown upward and let fall down a building. Another identical ball was dropped straight down the building at the same time with the same initial speed as the first ball. How will the velocities of these two balls compare when they each hit the ground? Justify your response.

Answers

Answer:

same velocity

Explanation:

energy is conserved-

KE=PE

As a hiker in Glacier National Park, you are looking for a way to keep the bears from getting at your supply of food. You find a campground that is near an outcropping of ice from one of the glaciers. Part of the ice outcropping forms a slope of angle θup to a vertical cliff. You decide that this is an ideal place to hang your food supply, as the cliff is too tall for a bear to reach it. You put all of your food into a burlap sack, tie an unstretchable rope to the sack, and tie another bag full of rocks to the other end of the rope to act as an anchor. The mass of rocks that you put into the anchor bag is equal to the mass of food in the other bag.What will be the acceleration aof the food bag when you let go of the anchor bag? Assume that the weight of the rope is negligible, and that the ice can be considered frictionless.Express the resulting acceleration aof the food bag in terms of θ and g, the acceleration due to gravity. Let the positive direction for this bag be downwards.

Answers

Answer: the acceleration is (g( 1 - sinθ)) / 2

Explanation:

the tension in one bag is expressed as;

T = ma + mg sin θ ........................lets say equ 1

now the tension in another bag is expressed as;

T = -ma + mg..................lets say equ 2

so equate both equations

ma + mg sinθ = -ma + mg

2ma =  mg ( 1 - sinθ)

a = (g( 1 - sinθ)) / 2

therefore the acceleration is (g( 1 - sinθ)) / 2

please help in 5 mintues

Which component uses the core muscles of your stomach?

a. Muscular endurance
b. Flexibility
c. BMI
d. Abdominal endurance

Answers

Answer:

a. Muscular endurance

is correct answer

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the speed of sound in air at a temperature of -40c° ?​

Answers

Answer:

304.87 m/s

Explanation:

v2 = v1 × √T2÷√T2

v2 = 330 × √233÷√273

v2 = 304.87 m/s

Which event causes the formation of trenches in Earth’s crust?

magma rising
mantle emerging
volcanoes erupting
lithosphere colliding

Answers

Answer:

D lithosphere colliding

Reason:

Image result for what causes the formation of trenches in Earth’s crust

Trenches are formed by subduction, a geophysical process in which two or more of Earth's tectonic plates converge and the older, denser plate is pushed beneath the lighter plate and deep into the mantle, causing the seafloor and outermost crust (the lithosphere) to bend and form a steep, V-shaped depression.

The formation of trenches in Earth's crust is caused by the collision of lithospheric plates, so the correct answer is "lithosphere colliding."

What are trenches in Earth's crust?

Trenches are long, narrow depressions or canyons in the Earth's crust that form at subduction zones, where one lithospheric plate is forced beneath another plate into the Earth's mantle. Trenches are primarily found on the ocean floor, where they can be several kilometers deep and hundreds of kilometers long.

Trenches are formed by the process of subduction, which occurs when one tectonic plate moves beneath another plate. As the denser plate sinks into the mantle, it creates a deep trench in the ocean floor. This process is associated with volcanic activity, as the sinking plate often triggers the melting of rock in the mantle, which can then rise to the surface and form volcanic islands or arcs.

Trenches are important features of the Earth's crust because they provide evidence for the movement and interaction of tectonic plates over time. Additionally, they are often associated with earthquakes and can serve as warning signs of potential seismic hazards in the surrounding region.

Therefore, lithosphere colliding causes the formation of trenches in Earth’s crust.

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According to The first law thermodynamics Energy can be created and destroyed, True or False? 

Answers

Answer:

False

Explanation:

energy in terms I've heard at least energy cannot be created or destroyed

state and explain parallelogram Law of vector addiction​

Answers

Answer:

Parallelogram law of vector addition states that. if two vectors are considered to be the adjacent sides of a parallelogram, then the resultant of the two vectors is given by the vector that is diagonal passing through the point of contact of two vectors.

At constant mass, the __________________ of an object varies (directly, inversely) with the net external force applied. That is to say, that an object’s acceleration increases as the force applied is (decreased, increased), but its acceleration decreases if the force applied is (decreased, increased).

At constant force, acceleration varies (directly, inversely) with mass. When subjected to the same amount of net external force, a heavier object will experience (less, greater) acceleration than a lighter one.

Answers

Chemistry of an object

An ideal fluid is moving at 3.0 m/s in a section of a pipe of radius 0.20 m. If the radius in another section is 0.35 m, what is the flow speed there

Answers

The flow speed of the fluid in the second section of the pipe is 0.98 m/s

What is flow speed?

Flow speed is the rate at which the distance of a fluid changes with respect to time as it moves in a pipe.

To calculate the flow speed in the second section, we use the formula below.

Formula:

AV = A'V'............ Equation 1

Where:

A = Cross-sectional area of the first  section of the pipeV = Velocity of fluid in the first  section of the pipeA' = cross-sectional area in the second  section of the pipeV' = Velocity of fluid in the second section of the pipe.

Make V' the subject of the equation

V' = AV/A'......... Equation 2

From the question,

Given:

A = πR² = 0.04π m²V = 3 m/sA' = πr² = (0.35²×π) = 0.1225π m²

Substitute these values into equation 2

V' = 3(0.04π)/(0.1225π)V' = 0.98 m/s

Hence, The flow speed of the fluid in the second section of the pipe is 0.98 m/s

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A rope is wrapped three and a half times around a cylinder. Determine the range of force T exerted on the free end of the rope for maintaining equilibrium that is required to just support a 5 kN weight. The coefficient of friction between the rope and the cylinder is 0.2

Answers

The range of force exerted at the end of the rope is 285.7 N to 1,000 N.

Net horizontal force of the cylinder

The net horizontal force of the cylinder when it is at equilibrium position is determined by applying Newton's second law of motion.

∑F = 0

F - μFn = 0

F - 0.2(5,000) = 0

F - 1,000 = 0

F = 1,000 N

The strength of the applied force increases as the number of turns of the rope increases.

minimum force = total force/number of turns of rope

minimum force = 1,000/3.5

minimum force = 285.7 N

Thus, the range of force exerted at the end of the rope is 285.7 N to 1,000 N.

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If 2 J of wok is done in raising a 180 g red delicious apple to bring it to your mouth to take a bite of the apple, how far is it lifted?

Answers

Answer:

Most likely 2ft

Explanation:

Your arm aint that long

We can talk about the amountofpotential energy per unit chargeas a function of locationâwe use the term voltageto describe this.A voltage difference between two locations results from the presence of an electric field. The more work the field can do in moving thecharge from point A to point B, the higher the voltageof point A is relative to point B.

Required:
a. Describe and draw the electric field between two large, oppositely charged plates.
b. Electric potentialis completely analogous to an object being dropped off of a building. The higher the building, the more potential energy the object has. Make a sketch of the ground and a building anddraw lines that indicate constantpotential energyof an object.
c. On your sketch for part a, draw lines of constant potential (these are called equipotentiallines). It may help to imagine placing a positive charge between the plates. It will accelerate toward the negative plate and run into it. Regardless of where you place the charge on an equipotential line, itâll hit the negative plate with the same speed.

Answers

Answer:

potential lines that are perpendicular to the electric field, they must be parallel to the plates

Explanation:

A and C) for this drawing, as the electric field lines go from the positive plate to the negative plate and are horizontal to the potential lines that are perpendicular to the field, they must be parallel to the plates, see attached part a

B) in this case the ground has an energy of zero and the lines are parallel to the ground, see attached part b

An object started moving with an initial velocity of 10m/s after travelling a distance of 5m gets a velocity of 20m/s find its: (a)acceleration
(b)time taken

Answers

Answer: a = 30 m/s^2

t = .33 s

Explanation:

(v final)^2 = (v initial)^2 + 2*a*d → 20^2 = 10^2 + (2)(a)(5) → a = 30 m/s^2

Acceleration = change in velocity / time → 30 = (20 - 10) / t → t = .33 s :)

Calculate the current in a circuit if 500 C of charge passes through it in 10 minutes. *
(1 Point)
a) 0.83A
b) 0.083A
c) 8.3A
d) 83A

Answers

Answer:

Choice a. Approximately [tex]0.83\; \rm A[/tex] on average.

Explanation:

The electric current through a wire is the rate at which electric charge flows through a cross-section of this wire.

Assume that electric charge of size [tex]Q[/tex] flowed through a wire cross-section over a period of time [tex]t[/tex]. The average current in that wire would be:

[tex]\displaystyle I = \frac{Q}{t}[/tex].

For this question:

[tex]Q = 500\; \rm C[/tex], whereas[tex]t = 10\; \rm \text{minutes}[/tex].

Therefore, the average current in this circuit would be:

[tex]\displaystyle I = \frac{Q}{t} = \frac{500\; \rm C}{10\; \text{minutes}} = 50\; \rm C /\text{minute}[/tex].

However, the units in the choices are all in [tex]\rm A[/tex] (for Amperes.) One Ampere is equal to one [tex]\rm C / \text{second}[/tex]. It will take some unit conversations to change the unit of [tex]I = 50\; \rm C/ \text{minute}[/tex] (coulombs-per-minute) to coulombs-per-second.

[tex]\begin{aligned}I &= 50\; \rm C/ \text{minute} \\ &= \frac{50\; \rm C}{1\; \rm \text{minute}} \times \frac{1 \; \text{minute}}{60\; \rm \text{seconds}} \approx 0.83\; \rm C/ \text{second} = 0.83 \; \rm A\end{aligned}[/tex].

Hence, the most accurate choice here would be choice a.

Describe Health and Exercise

Answers

Answer:

plenty of exercise

Explanation:

If you are unhealthy or not happy with yourself. try this. Do a 30 minute walk everyday and eat normal amounts of food portions a human should have an in a day. Make sure you drink plenty of water. If that doesn't work maybe taking to someone about it and see what information they have for you. These things do work because i was over weight and lost 73 pound just by doing those few things.

What is the average kinetic energy of a molecule of an ideal gas at temperatures of 27°c? what is the total random kinetic energy of the molecule in 1 mole of this gas .what is the RMS of speed of oxygen molecule .​

Answers

(a) The average kinetic energy of a molecule of an ideal gas is 6.21 x 10⁻²¹ J.

(b) The total random kinetic energy of the molecule in 1 mole of this gas is 3,741.3 J.

(c) The RMS speed of the oxygen molecule is 215.25 m/s.

Average kinetic energy of ideal gas

The average kinetic energy of a molecule of an ideal gas is calculated as follows;

[tex]K .E = \frac{3}{2} K T[/tex]

Where;

K is Boltzmann constant = 1.38066 x 10⁻²³ J/KT is temperature in Kelvin, = 27°c  + 273 = 300 K

[tex]K.E = \frac{3}{2} \times (1.38 066 \times 10^{-23}) \times 300\\\\K.E = 6.21 \times 10^{-21} \ J[/tex]

Total random kinetic energy

The total random kinetic energy of the molecule in 1 mole of this gas is calculated as follows;

[tex]K.E = \frac{3}{2} nRT\\\\K.E = \frac{3}{2} (1) (8.314)(300)\\\\K.E = 3,741.3 \ J[/tex]

RMS of speed of oxygen molecule

The RMS speed of the oxygen molecule is calculated as follows;

[tex]K.E = \frac{1}{2} mV_{rms}^2\\\\V_{rms}^2 = \frac{2K.E}{m} \\\\V_{rms} = \sqrt{\frac{2 K.E}{m} }[/tex]

one mole of oxygen gas = 32 g = 0.032 kg

[tex]V_{rms} = \sqrt{\frac{2 \times 741.3 }{0.032} }\\\\V_{rms} = 215.25 \ m/s[/tex]

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A lightbulb uses 98 J of electrical energy every second to produce 10 J of light energy in the same time frame. What is the percent efficiency of the lightbulb in converting electricity into light?

Answers

Answer:

10.2 % efficiency.

Explanation:

Percent efficiency formula: (output / input) * 100%

The output energy (in Joules) is how much was used eventually. - It is 10 J

The input energy (in Joules) is how much energy was put into the lightbulb initially. It is 98 J

(10 J / 98 J) * 100% = 10.2 % efficiency.

What is the value of 4p − 2, when p = 8? 16 24 30 34

Answers

Answer:

30

Explanation:

Plug in p to get 4(8) - 2

32 - 2 = 30

This problem it has to be 30.

A bus run at 100 km/hr top speed. It can carry a maximum of 6 persons. If speed of bus decreases in fixed proportion with increase in number of person, find speed when three person are traveling in bus.​

Answers

Answer:

150 km/h

Explanation:

It is given that,

Speed of a bus is 100 km/h and it can carry a maximum of 6 persons.

If speed of bus decreases in fixed proportion with increase in number of person, then we need to find the speed when 3 person are traveling in bus.​

6 person = 100 km/h

1 person = (100/6) km/h

Ans

3 person = [tex]\dfrac{100}{6}\times 3=50\ km/h[/tex]

Net speed = 100 km/h + 50 km/h = 150 km/h

Hence, if the required speed is 150 km/h.

A container is filled to a depth of 154.7 cm with water. On top of the water floats a 124.5 cm thick layer of oil with specific gravity 0.754. What is the absolute pressure at the bottom of the container

Answers

the pressure is 4502.23 reacurring.

1.99 m/s^2 for the first 60.0 m, then decelerates at -0.266 m/s^2 for the final 40.0 m. How much time did the race take?

Answers

Time required to complete 60m:-

[tex]\\ \rm\longmapsto s=1/2at^2[/tex]

[tex]\\ \rm\longmapsto 60=1.99/2t^2[/tex]

[tex]\\ \rm\longmapsto 120=1.99t^2[/tex]

[tex]\\ \rm\longmapsto t^2=60.3[/tex]

[tex]\\ \rm\longmapsto t\approx 7.7s[/tex]

Time taken to complete last 40m

[tex]\\ \rm\longmapsto 80=-0.266t^2[/tex]

[tex]\\ \rm\longmapsto t^2=300.75[/tex]

[tex]\\ \rm\longmapsto t\approx 17.3s[/tex]

Total time:-

7.7+17.3=25s(Approx)

Answer:

Explanation:

Two kinematics equation

v = u + at

and

s = ut + 1/2(at^2)

where u is initial velocity, v is final velocity, a is acceleration, t is time and s is displacement.

For the first 60m, initial velocity is 0 and acceleration is 1.99.

60 = 0 + 1/2(1.99)t^2

t^2 = 120/1.99

t = 7.765s

Velocity at 60m = 0 + 1.99(7.765) = 15.453 m/s

For the final 40m, initial velocity = 15.453, acceleration is -0.266.

40 = 15.453t' + 1/2(-0.266)t'^2

0.133t'^2 - 15.453t' + 40 = 0

Using the quadratic formula, t' = 2.649s or 113.54s

The solution of 113.54s represents someone running pass the finish line and continuing the deceleration until one runs backwards to the finish line again. So that solution should be rejected.

The total time taken = 7.765 + 2.649

= 10.414s

What effect does the finite of the black paper have on the field?

Answers

The effect of black papper on the field is that the black paper have a form of chimney effect. Thid is because the black paper heat up the space between the field and the body in order to allow an upward air current like a chimney. This air current adds to the cooling of the field.

Black paper absorb heat from the surrounding and generate it to current flow in the field.

What is a Field?

A field refer to a egion in which each point has a physical quantity like time or gravitational or space which are connected and associated with the region.

Therefore, the black paper allow air current flow.

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Suppose that a car starts from rest at t = 0. The car moves with an acceleration of 1.5 m/s2. How far will the car travel in 3.0 s?

Answers

Answer:

6.75m

Explanation:

To calculate the distance in this question, we can use the formula:

S = ut + 1/2at^2

Where; S = distance

u = initial velocity = 0m/s

t = 3s

a = 1.5m/s^2

Hence:

S = (0 × 3) + 1/2 (1.5 × 3 × 3)

S = 0 + 1/2 (13.5)

S = 13.5/2

S = 6.75

Therefore, the car will travel 6.75m in 3seconds.

To find the distance traveled by the car in 3 seconds is equal to 6.75 meters.

Given the following data:

Initial velocity = 0 m/s (since it starts from rest).Acceleration = 1.5 [tex]m/s^2[/tex]Time = 3 seconds.

To find the distance traveled by the car in 3 seconds, we would apply the second equation of motion:

The second equation of motion.

Mathematically, the second equation of motion is given by the formula;

[tex]S=ut +\frac{1}{2} at^2[/tex]

Where:

S is the distance traveled.u is the initial velocity.a is the acceleration.t is the time measured in seconds.

Substituting the given parameters into the formula, we have;

[tex]S=0(3) +\frac{1}{2} \times 1.5 \times 3^2\\\\S=\frac{1}{2} \times 1.5 \times 9\\\\S = 1.5 \times 4.5[/tex]

Distance, S = 6.75 meters.

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A 7.50 kg bowling ball moving
6.42 m/s strikes a 1.60 kg bowling
pin at rest. After, the ball moves
5.43 m/s at a 12.0° angle. What is
the x-component and y-component of the pin's final
velocity?

Answers

Answer:

Explanation:

To solve this problem we need to know the direction in which the ball was moving to start with.

The answer will be different depending n the original angle of the ball's movement.

It might be reasonable to assume that the ball is meant to approach along the x-axis,

but if so, the initial speed of 6.42m/s would be irrelevant to the answer.

So I will solve the problem for the general case of two objects colliding at arbitrary angles, and

tell you how to specialize it for any assumption about the initial conditions.

Let

m1 = 7.5 kg be the mass of the ball,

m2 = 1.6 kg be the mass of the pin,

v1 = 6.42 m/s be the velocity of the ball before the strike,

v2 = 0 m/s be the velocity of the pin before the strike,

α1 be the angle of v1,

α2 be the angle of v2,

w1 be the velocity of the ball after the strike,

w2 = 14.8 m/s be the velocity of the pin after the strike,

β1 be the angle of w1,

β2 = -47° be the angle of w2.

By conservation of momentum:

m1v1 + m2v2 = m1w1 + m2w2

Since the velocities are vectors, the addition is vector addition, and the equality is vector equality.

"Vector equality" means that the x-coordinates are equal and the y-coordinates are equal.

The problem cares only about y-coordinates, specifically the y-coordinate of w1, which is w1sin(β1).

(In general, the y-coordinate of any vector is obtained by multiplying the vector's norm by the sine of its angle.)

Conservation of momentum in the y-coordinate is then

m1v1sin(α1) + m2v2sin(α2) = m1w1sin(β1) + m2w2sin(β2)

Expressing the sought quantity

w1sin(β1) = (m1v1sin(α1) + m2v2sin(α2) - m2w2sin(β2))/m1

Substituting known quantities:

w1sin(β1) = (7.5×6.42×sin(α1) + 1.6×0×sin(α2) - 1.6×14.8×sin(-47°))/7.5

= (48.15×sin(α1) + 17.3)/7.5

In the above expression we do not know α1.

If we assume that the ball is approaching along the x-axis then α1 = 0, and

w1sin(β1) = 17.3/7.5 = 2.3

Under that assumption the y-component of the ball's final velocity is 2.3 m/s;

being positive, it is opposite the direction of the pin.

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