Explanation:
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1. A 10 kg rocket blast off the ground with an applied force of 150 N, calculate the net force
of your rocket
The net force on the rocket at the given applied force is 52 N.
The given parameters:
Mass of the rocket, m = 10 kgApplied force, F = 150 NThe net force on the rocket is calculated by applying Newton's second law of motion as follows;
F(net) = F(up) - F(down)
F(net) = 150 - mg
F(net) = 150 - (10 x 9.8)
F(net) = 150 - 98
F(net) = 52 N
Thus, the net force on the rocket at the given applied force is 52 N.
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2. What is the oxidation number of oxygen in most compounds?
A. 6
B.-2
C. 8
D.O
Answer:i am pro
kExplanation:
g A 24-gg bullet strikes and becomes embedded in a 1.50-kgkg block of wood placed on a horizontal surface just in front of the gun. Part A If the coefficient of kinetic friction between the block and the surface is 0.23, and the impact drives the block a distance of 9.5 mm before it comes to rest, what was the muzzle speed of the bullet
The muzzle speed of the bullet before the collision is 415.3 m/s.
The given parameters:
Mass of the bullet, m₁ = 24 gMass of the wood, m₂ = 1.5 kgCoefficient of kinetic friction, μk = 0.23Distance traveled by the block before stopping, d = 9.5 mApply the principle of work-energy theorem to determine the final velocity of the block-bullet system;
[tex]F_f \times d = \frac{1}{2} mv^2\\\\\mu_k F_n \times d = \frac{1}{2} mv^2\\\\\mu_ k (m_1 + m_2)g \times d = \frac{1}{2} (m_1 + m_2)v^2\\\\\mu_k g \times d= \frac{1}{2} v^2\\\\2\mu _k gd = v^2\\\\v= \sqrt{2\mu _k gd } \\\\v = \sqrt{2 \times 0.23 \times 9.8 \times 9.5} \\\\v = 6.54 \ m/s[/tex]
Apply the principle of conservation of linear momentum to determine the muzzle speed of the bullet;
[tex]m_1 u_1 \ + \ m_2u_2 = v(m_1 + m_2)\\\\0.024(u_1) \ + \ 1.5(0) = 6.54(0.024 + 1.5)\\\\0.024u_1 = 9.967\\\\u_1 = \frac{9.967}{0.024} \\\\u_1 = 415.3 \ m/s[/tex]
Thus, the muzzle speed of the bullet before the collision is 415.3 m/s.
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Which of the following is damaging electromagnetic radiation?
a. Gamma Ray c. Ultraviolet
b. Visible Light d. X-rays
Explanation:
Which of the following electromagnetic waves is used in medicine to destroy cancer cells?
A. IR rays
B. Visible rays
C. Gamma rays
D. Ultraviolet rays
Answer
VerifiedVerified
105.9k+ views
Hint: Electromagnetic rays that have a high frequency and highest-energy photons such that their energy is enough to penetrate several centimetres of lead is used to destroy cancer cells.
Complete step by step answer:
Electromagnetic waves with wavelengths shorter than about 100-trillionths of a meter are called gamma rays. They are used in a technique called radiation therapy to kill diseased cells in the human body. A beam of gamma rays can damage the biological molecules in living cells, causing both healthy and diseased cells to die. By carefully controlling the amount of gamma ray radiation and focusing it on the diseased area, the damage to healthy cells can be reduced during treatment.
So, the correct answer is “Option C”.
Additional Information: A. Infrared rays are used to form images of objects. Remote control and CD-drives also used infrared waves.
B. Visible light is the light that we can detect with our eyes. The spectrum of visible light shows all colours of light from long wavelength red to short wavelength violet.
D. Ultraviolet rays provide vitamin D for the body. They are also used to disinfect food, water and medical supplies. If Ultraviolet rays enter a cell, they can damage the DNA.
Note: Apart from Gamma rays, X-rays are also used in radiation therapy to kill diseased cells in the human body. X-rays are also used to form images of bones and teeth and in airport screening devices to examine contents of luggage.
hope this passage helps I don't know Its correct answer ..... its from my school PDF
Answer:
Gamma rays
Explanation:
NOTE: The higher the frequency of the radiation, the more damage it is likely to cause to the body: infrared radiation is felt as heat and causes skin to burn.
If correct please give brainliest
Stay safe and healthy
Thank You
If the speed of the magnet is doubled, the induced voltage is ________ . twice as great four times as great half as great unchanged
If the speed of the magnet is doubled, the induced voltage is twice as great
Faraday's law of induction states that whenever relative motion exists between a coil and magnetic field, a voltage will induce in the circuit and this voltage is proportional to the rate of change of the flux. The expression for the motional emf is as follows:
ε=Blv
Here, ε is the motional emf, B is the magnetic field, l is the length of the conductor, and v is the velocity at which the magnetic field changes.
The induced voltage by the moving magnet is directly proportional to the speed of the magnet. Therefore, an increase in the speed of the magnet will increase the induced voltage.
If the speed of the magnet is doubled, the induced voltage is twice as great
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A model shows a machine that works using electric fields. What would this machine need for the electrical field to function properly
A physics professor leaves her house and walk along the sidewalk toward campus. After 5 min it starts to rain and she returns home. Her distance from her house as a function of time shown in figure: 1. At which of the labelled point is her velocity (a) zero? (b) Constant and positive? (c) constant and negative ? (d) Increasing in magnitude? (e) Decreasing in magnitude?
Answer: I think its zero-
I dont really know about this...
What is the significance of Isaac's name?
[tex] \large \bf{Answer:-}[/tex]
The name Isaac means “one who laughs” or “one who rejoices.” In the Old Testament of the Bible, Isaac is the firstborn son of Abraham. He is one of the three biblical patriarchs revered by Jews, Christians, and Muslims.
Blonde hair is produced by inheriting double recessive alleles (bb) from one’s parents. What is the probability of their offspring having blonde hair?
plz help
Answer:
25%
Explanation:
Please answer the question in the picture
What is the weight of a 5kg object at the surface of the earth?
A. 49N
B. 49kg
C. 5.0kg
D. 25N
Answer: The answer is A) 49 N(Newtons).
A 4.0 ohm resistor has a current of 3.0 A for 5.0 min. How many electrons pass through the resistor during this time interval?
a. 7.5 x 10^21
b. 3.8 x 10^21
c. 8.4 x 10^21
d. 2.1 x 10^21
e. 5.6 x 10^21
Answer:
e. 5.6 x 10^21 electrons.
Explanation:
In order to calculate the charge Q passing through the resistor for in a definite amount of time is
[tex]Q \ (\mathrm{coulombs}) \ = \ I \ (\mathrm{amperes}) \ \times \ t \ (\mathrm{seconds}) \\ \\ \-\hspace{2.22cm} = \ 3.0 \ \mathrm{A} \ \times \ 5.0 \ \mathrm{min} \ \times \ \displaystyle\frac{60 \ \mathrm{sec}}{1 \ \mathrm{min}} \\ \\ \-\hspace{2.22cm} = \ 900 \ \mathrm{C}[/tex]
Thus, using the law of quantization of electric charge, the number of electrons passing through the resistor during this time interval can be calculated.
[tex]Q \ = \ n \times e \\ \\ n \-\hspace{0.18cm} = \ \displaystyle\frac{Q}{e} \\ \\ n \-\hspace{0.18cm} = \displaystyle\frac{900 \ \mathrm{C}}{1.6 \times 10^{-19} \ \mathrm{C}} \\ \\ n \-\hspace{0.18cm} = 5.6 \times 10^{21} \ \ \mathrm{electrons}[/tex], where n denotes the number of electrons and e is the unit charge of an electron ([tex]1.6 \times 10^{-19} \ \mathrm{C}[/tex]).
a bicycle with tires 68 cm in diameter travels 9.2 km. how many revolutions do the wheels make
Answer:
Explanation:
Circumference in meters is
C = πD = 0.68π
9200 m / 0.68π m = 4,306.545518...
4,306.5 revolutions
A bicycle with tires 68 cm in diameter travels 9.2 km. the number of revolutions made by the wheel would be 4309
What is Velocity?The total displacement covered by any object per unit of time is known as velocity. It depends on the magnitude as well as the direction of the moving object. It can also be represented by the infinitesimal rate of change of displacement with respect to time. The unit of velocity is meter/second.
The mathematical expression for velocity is given by
velocity= displacement / time taken
As given in the problem a bicycle with tires 68 cm in diameter travels 9.2 km
Diameter = 68 cm
radius = diameter /2
= 68/2
= 34 cm
The distance covered by the tire in one cycle would be
distance in one revolution = 2π×Radius
= 2×3.14× 34
= 213.52 cm
=2.13 m
The number of revolutions by wheel = total distance/distance in one revolution
number of revolutions = 9200/2.135
=4309 revolutions
Thus, the number of revolutions made by the wheel would be 4309
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I need help with parts a and B of this question
Answer:
Explanation:
Let x be the leaf spring compression distance
F = kx
5.20 x 10⁵ = (5.45 x 10⁵)x + (3.80 x 10⁵)(x - 0.500)
5.20 x 10⁵ = (5.45 x 10⁵)x + (3.80 x 10⁵)(x) - 1.90 x 10⁵
7.10 x 10⁵ = (9.25 x 10⁵)x
x = 0.76756...
x = 0.768 m
W = ½(5.45 x 10⁵)0.768² + ½(3.80 x 10⁵)(0.768 - 0.500)²
W = 174,148.648648...
W = 174 KJ
How many valence electrons do most stable atoms have?
A) one
B) two
C) four
D) eight
Answer:
D) 8
Explanation:
Due to the octet rule the most stable atoms will have 8 valence electrons.
Which degree would a person most likely pursue if they are interested in how
computers work to solve problems?
A. Business management
B. Mechanical engineering
C. Computer science
D. Education technology
SUBMIT
Answer:
Computer science
Explanation:
You would get everything you need to know about computers if you took computer science. I hope this helps
Answer:
Computer science
Explanation:
Identify the types of motion:-
the movement of the snail on the ground
the strings of the guitar
the whirling of stone tied with a thread
Answer:
the movement of snail on the ground is in random motion.
the strings of the guitar is in oscillatory motion.
the whirling of stone tied with a thread is in circular motion.
Select the correct answer. Chloe is playing the flute some distance away from a crowd. If the atmospheric temperature is 15°C, what is the speed of the sound traveling from the flute? A. 340 meters/second B. 330 meters/second C. 320 meters/second D. 310 meters/second E. 300 meters/second
Answer:
A. 340 meters/second
I think this is the right answer.
What is the significance of Isaac's name?
Answer:
ghgivjgifigo ra together aigig disgust u hoodie
A crate is released on a frictionless plank inclined at angle q with
respect to the horizontal. Which of the following relationships is true?
(Assume that the x-axis is parallel to the surface of the incline.)
a. Fy = Fg
c. Fy = Fx
b. Fx = 0
d. none of the above
None of the given options is correct based on the relationship for the components of the crate's weight.
The given parameter:
Angle of inclination, = qThe vertical component of the force on the crate is calculated as follows;
[tex]F_y = W \times cos(q)\\\\F_y = F_gcos(q)[/tex]
The horizontal component of the crate is calculated as follows;
[tex]F_x = F_g \times sin(q)\\\\F_x = F_g sin(q)[/tex]
Thus, we can conclude that none of the given options is correct based on the relationship for the components of the crate's weight.
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Lisa runs up 4 flights of stairs in 22 seconds. She weighs 510 Newtons. If each flight rises 310 cm: (a) What is her change in potential energy? (b) What average power (watts) was required during the 22 s?
The change in potential energy is 6324 Joules while the power is 263.5 Watts.
Potential energy is the amount of energy possessed by a body due to its position relative to another object.
a) Potential energy = weight * height = 510 N * 4 flight * 3.1 m per flight
Potential energy = 6324 Joules
b) Power = Energy / time = 6324 Joules / 22 seconds = 263.5 Watts
The change in potential energy is 6324 Joules while the power is 263.5 Watts.
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A book is at rest on a flat table. The book is pushed across the table, causing it to move
and eventually come to rest again. How does the potential and kinetic energy change
during this process? (1 point)
The potential and kinetic energy will stay the same unless the book speeds
up or slows down
The potential energy increases as the book is pushed across the table.
The kinetic energy stays the same.
The potential energy will stay the same as long as the book stays on the
table. The kinetic energy increases as the book is pushed across the table.
The potential and kinetic energy decreases as the book comes to rest
again
Answer:
Explanation:
As no altitude or mass changed, the potential energy remained constant.
The potential energy will stay the same as long as the book stays on the
table.
Kinetic energy went from zero at rest to a positive value while moving, and then returned to zero when the book was at rest again.
The kinetic energy increases as the book is pushed across the table.
Use words in the box to complete the diagram, and the definitions below it. Some words will be used
more than once and some words may not be used at all
Hertz
period
metros
dip
seconds
peak
wavelength trough
crest
frequency
amplitudo
oscillation equilibrium line
- the top of a wave
the bottom of a wave
the level if the wave flattened out
a repeated action back and forth or up and down
the number of waves that pass every second (measured in
the time it takes for one complete wave to pass (measured in
Answer:
There ya go
Explanation:
The correct words to fill the given blanks would be as follows:
- Peak
- Trough
- Equilibrium Line
- Oscillation
- Frequency, Hertz
- Period, seconds
The "peak" is denoted as the highest or maximum point that the wave attains while 'Trough' is characterized as the base of the wave. The 'equilibrium line' is characterized as the extent to which the wave flattens or compresses.Oscillation is defined as the process in which an object moves in the "back and forth motion."Frequency is the amount of occurrences that waves travel in a second which is denoted in the terms of Hertz.Lastly, period is the duration required by wave to accomplish one motion is denoted in terms of seconds.Amplitude is the breadth or magnitude of the waves.Learn more about "Oscillation" here:
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What capacitance is needed to store 3μC of charge at a voltage of 120V?
Answer:
C = 0.025F
Explanation:
Charge =q=3×[tex]10^{-6}[/tex]C
Voltage=V=120V
Q=CV
C=Q/V
=3×[tex]10^{-6}[/tex]/120
=1/40×[tex]10^{-6}[/tex]
C = 0.025F
C=2.5 [tex]10^{-4}[/tex]C 0r 25 ×[tex]10^{-3}[/tex]F
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In introductory physics, a typical cavendish balance for measuring the gravitational constant G use metal masses 2.39kg and 16g whose center are separated by 6.81cm calculate the gravitation force between these forces, treating each as a point mass located at the center of the sphere.
gravitational constant =6.67259 × 10⁻¹¹N·m²/kg²
Answer:
Explanation:
F = GMm/d²
F = 6.67259 x 10⁻¹¹(2.39)(0.016) / 0.0681²
F = 5.5019685...x 10⁻¹⁰ N
round as appropriate, probably no more than 3 significant figures.
Value of G seems low, but well within the 3 significant figures of the other numerals. I typically see G = 6.674 x 10⁻¹¹
Identify the types of motion a) The movement of a snail on the ground b) The strings of the guitar c) The whirling of stone tied with a thread
Answer:
1. friction, gravity,
Explanation:
Specific heat capacity
of a solid
1. The acceleration equation of a certain particle is a=2t, after 4s, its velocity reaches 20m/s, then the initial velocity of the particle movement is ) ms B Sms 2.
Answer:
Change in velocity is the integral of all the differential accelerations acting over the period of acceleration.
[tex]20 = u + \int\limits^4_0 {2t} \, dt[/tex]
20 = u + t²[tex]\left \{ {{4} \atop {0}} \right.[/tex]
20 = u + 4² - 0²
20 = u + 16
u = 4 m/s
4. Trilobites are animals that lived during the Paleozoic era. They populated all parts of the
ocean showed consistent evolution over time and left behind fossils that are large
enough to be studied without a microscope. All of these characteristics make trilobites
the ideal
a. Trace fossil
b. Keystone species
c. Index fossil
d. Reference point
dnreserve the remains of dead
Answer:
c. index fossil
Explanation:
Trilobite fossils are found worldwide, with many thousands of known species. Because they evolved rapidly, and molted like other arthropods, trilobites serve as excellent index fossils. (Arthropods periodically shed their old exoskeletons, or molt.) An index fossil is one that is useful for dating and correlating the strata in which it is found.
A ball is kicked horizontally from a 60 meter tall cliff at 10 m/s. How far from
the base of the cliff does it land?
Hi there!
We can begin by deriving the equation for how long the ball takes to reach the bottom of the cliff.
[tex]\large\boxed{\Delta d = v_it+ \frac{1}{2}at^2}}[/tex]
There is NO initial vertical velocity, so:
[tex]\large\boxed{\Delta d= \frac{1}{2}at^2}}[/tex]
Rearrange to solve for time:
[tex]2\Delta d = at^2\\\\t = \sqrt{\frac{2\Delta d}{g}}[/tex]
Plug in the given height and acceleration due to gravity (g ≈ 9.8 m/s²)
[tex]t = \sqrt{\frac{2(60)}{(9.8)}} = 3.5 s[/tex]
Now, use the following for finding the HORIZONTAL distance using its horizontal velocity:
[tex]\large\boxed{d_x = vt}\\\\d_x = 10(3.5) = \karge\boxed{35 m}[/tex]