Criteria and constraints help determine which solutions will be applied when extracting materials from pomace in which way
might a specific criterion be applied to this situation? (1 point)
The use of pomace for pharmaceuticals might be chosen if a food company does not have access to a
production plant for extracting chemicals
The use of pomace for pharmaceuticals might be chosen if minimizing production costs is desired
a
The use of pomace for animal feed might be chosen if a food company does not have access to a
production plant for extracting chemicals
The use of pomace for animal feed might be chosen if minimizing production costs is desired.

Answer:

The answer is the Sodium Chloride.

Explanation:

A solute is the minor component in a solution, dissolved in the solvent, and the sodium is being dissolved in water ( or the solvent).

A chemist adds 36.0 g of sodium chloride to 200 g of water at STP and all of the sodium chloride dissolves, in this scenario sodium chloride is solute.

Those substance which are present in the solution relatively in less amount is known as solute.

In the question given that 36 grams of sodium chloride is added in the 200 grams of water. From this it is clear that sodium chloride is a solute and water is a solvent, which additionally makes a solution.

Hence, sodium chloride is a solute.

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Answer:

Growing population

The worlds developing regions will see 1.2 billion people added, a 20.7% increase; while the population of developed countries will increase a mere 3.3% adding 41 million to the current 1.3 billion people.

The volume of the 1.75 M H₃PO₄ solution required to neutralize 50 ml of 3.5 M Ca(OH)₂ solution is 66.67 mL

2H₃PO₄ + 3Ca(OH)₂ —> Ca₃(PO₄)₂ + 6H₂O

From the balanced equation above,

MaVa / MbVb = nA / nB

(1.75 × Va) / (3.5 × 50) = 2/3

(1.75 × Va) / 175= 2/3

Cross multiply

1.75 × 3 × Va  = 175 × 2

5.25 × Va = 350

Divide both side by 5.25

Va = 350 / 5.25

Va = 66.67 mL

Thus, the volume of the H₃PO₄ solution needed is 66.67 mL

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Answer:

Calculate the pOH for a solution with a hydroxide ion, (OH-) of concentration of 6.49 X 10-11 M.

Calculate the pH.

Note: the answers should have three significant figures

The pOH is: Blank 1

The pH is: Blank 2

Explanation:

Answer:

Explanation:

This is not my photo. I got it from this website.

https://pubchem.ncbi.nlm.nih.gov/compound/Chlorocyclohexane#section=2D-Structure

For a 35.83 g sample of potassium chlorate,  the mass of potassium chloride is mathematically given as

M Kcl=21.62g

Generally, the equation for the Chemical Reaction  is mathematically given as

2KClO_3----->2KCl+2O_2

Therefore

[tex]Mole of KCl=\frac{35.57}{122.55}[/tex]

Mole of KCl=0.29mol

Mass of Kcl=0.29*74.55

Mass of Kcl=21.62g

In conclusion, Mass of Kcl

M Kcl=21.62g

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When the zinc plate in one of Edison's coulometers increased in mass by 7.85 g, the amount of charge that had passed through it is 23,173 C.

The zinc metal will ionize as shown below;

Zn²₊ + 2e⁻ → Zn

The molar mass of zinc metal is given as 65.38 g/mol

Amount of charge that will deposite the given mass of zinc is calculated as follows;

e⁻ = 96500 C

2e⁻ = 2 x 96500 C = 193,000 C

65.38 g -------> 193,000 C

7.85 g -----------> ?

= (7.85 x 193,000)/(65.38)

= 23,173 C

Thus, when the zinc plate in one of Edison's coulometers increased in mass by 7.85 g, the amount of charge that had passed through it is 23,173 C.

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Answer:

20 atm

Explanation:

Use the equation P1 x V1 = P2 x V2.

1) Rearrange the equation with algebra to solve for P2.

P2 = (P1 x V1)/ V2

2) Plug in to the equation where V1 = 25L, P1 = 0.80 atm, and, V2 = 1 L

P2 = (25L x 0.80 atm)/ 1L

3) Solve: P2 = 20 atm

The pressure required to reduce the oxygen's volume to 1 L would be 20 atm.

The benzene molecule is flat and planar. As a result of this planarity, the substituent is also in the plane of molecule and do not show any directionality.

The benzene molecule is a flat and planar molecule owing to the fact that all the bond lengths and bond angles in the molecules are the same. This results from resonance in the molecule.

Hence, owing to the planarity of the molecule, the substituent is also in the plane of molecule and do not show any directionality.

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Answer:

option B

cementation and compaction

Answer:

Your answer would be:
0.98atm.

Explanation:

The pressure of a gas can be calculated by using the following expression:

PV = nRT

P = pressure

V = volume
-----------------------------------

n = number of moles

R = gas law constant

T = temperature

P × 5 = 0.2 × 0.0821 × 298

5P = 4.893

P = 4.893 ÷ 5 = 0.98atm

P = 0.98atm

In conclusion, the pressure of a 5.00 L flask at 25 degrees C. that contains 0.200 mol of Cl2 is 0.98atm.

Have a great rest of your day
#TheWizzer

Answer:

Hello, senzawahl SORRY IF I SPELLED YOUR NAME INCORRECT
Prime here ready to solve your question :)


so your correct answer is 0.98atm.

Explanation:

Stay safe


-prime

When an electron moves from n = 2 to n = 1, it emits a photon of ultraviolet light.

During transition from n=2 to n=1 in a hydrogen atom, the electron emits energy in the form of photon. We know that when electron absorb energy, it moves from lower level to higher level and vice versa.

So we can conclude that when an electron moves from n = 2 to n = 1, it emits a photon of ultraviolet light.

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Answer:

S orbital

Explanation:

no explanation, just a name you memorize

Answer:

It is Se.

hope this helps.

Answer:

A.

Explanation:

Answer:

d=3.95 g/l

Explanation:

1) Ideal gas equation:

pV = nRT

2) Transform the equation to compute density, d = m / V

n = mass in grams / molar mass = m / MM

pV = (m/MM) RT

=> pV = mRT/MM

=> m/V = pMM / (RT)

d = pMM / (RT)

p = 1.21 atm

MM = 83.80 g/mol (this is the atomic mass of krypton element)

T = 50 + 273.15 K = 323.15K

3) Compute:

d = (1.25 atm * 83.80 g/mol) / (0.0821 atm*liter /K*mol * 323.15K)

For 3.50 grams of an unknown metal was placed in a graduate cylinder containing 50.0mL water initially,  the density of this unknown meta  is mathematically given as

D= 0.23 g/ml

Generally, the equation for the Volume of water  is mathematically given as

Vw= Volume of water after metal addition - Volume of water initial

Therefore

Vw = 65 ml - 50 ml

Vw= 15 ml

In conclusion,

D= Mass of metal / Volume

D= 3.5 / 15

D= 0.23 g/ml

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Answer:

the enthalpy change of this is 5.02mol

For a buffer that was prepared contain 0.50 M formic acid (HCOOH) and 0.50 M sodium formate (NaCOOH). the pH is mathematically given as

pH=3.95

Generally, the equation for the Hendersons equation   is mathematically given as

pH=pKa+log(SALT)/(ACID)

Where

moles of  (NaCOOH)=100*0.05/1000

moles of  (NaCOOH)=0.05moles

and  formic acid

moles of formic acid=100*0.05/1000

moles of  formic acid=0.05moles

Therefore

pKa=-logka

pKa=1.4*10*3.77

pH=3.77+log{0.06/0.04}

pH=3.95

In conclusion, the pH is

pH=3.95

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In the galvanic or voltaic cell, the standard cell potential is 1.67 V. The standard potential is the difference between the reduction potential of cathode and anode.

An electrochemical cell produces energy by a sponteanous chemical process. A galvanic or voltaic cell produces energy by a sponteanous chemical reaction.

Hence, given the standard reduction potentials;

Sn4+ + 2e- ==> Sn2+  Eº = 0.15 V (anode)

Co3+ + 2e- ==> Co2+  Eº = 1.82 V (cathode)

Eºcell = 1.82 V - 0.15 V = 1.67 V

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337.92 moles of Ozone will be produced

1 Oxygen atom is 8 g

1 mole of ozone, O3 = 8 * 3 = 24 g

7.92 * 1024 = 8110.08 g

1 mole = 24 g

? moles = 8110.08 g

? = 337.92 moles

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Hope it helps

Ozone has a molecular formula of O3. If 7.92*1024 atoms of oxygen react to form ozone, then 337.92 moles of ozone will produce.

Molecular formula is defined as an expression that defines a number of atoms of each element in one molecule of a compound.

It can also be defined as a chemical formula that gives the total number of atoms of each elements in each molecules of a substance.

Ozone is defined as a highly reactive gas composed of three oxygen atoms and form a layer above the earth surface called as ozone layer.

1 oxygen atom = 8 g

1 mole of ozone = 8 x 3 = 24 g

7.92 x 10²⁴ = 8110.08 g

24 g = 1 mole

So, 8110.08 g = 337.92 moles

Thus, Ozone has a molecular formula of O3. If 7.92*1024 atoms of oxygen react to form ozone, then 337.92 moles of ozone will produce.

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#SPJ2

Answer:

2AgNO³(l) → 2Ag(s) + O²(g) + 2NO²(g)

Explanation:

I used powers ³,²,²

So change them to be down

Answer:

c

Explanation:

mass is like matter it cant be created or destroyed so mass stays the same.

Answer:

C) It is equal to the total mass of the products.

Explanation:

The law of conservation of mass states that in a chemical reaction, the total mass of reactants is equal to the total mass of products.

- profparis

Answer: True

Explanation:

[tex]\mathrm{The\ balanced \ chemical \ equation\ is\ :}\\$2 \mathrm{Na}{(s)}+\mathrm{Cl}_{2}(g) \rightarrow 2 \mathrm{NaCl}(s)[/tex]

For Na

[tex]\\$Given mass $=20.4 \mathrm{~g}$ \ \ Molecular mass $=23 \mathrm{~g}\ \ $Number of moles $=\frac{\text { Given mass }}{\text { Molecular mass }}$$$\begin{aligned}&=\frac{20.4}{23} \\&=0.887 \text { moles }\end{aligned}$$Stoichiometric ratio of $\mathrm{Na}$ is same as that of $\mathrm{NaCl}$ i.e., $1: 1$.$\therefore$ Moles of $\mathrm{NaCl}=0.887$ motes[/tex]

For NaCl

[tex]$$\\\begin{aligned}\text { Molecular mass } &=23+35.5 \\&=58.5 \mathrm{~g}\end{aligned}$$[/tex]

[tex]\begin{aligned}\\& $\therefore$ Mass of $\mathrm{NaCl}$ produced will be=\text { No.of moles } \times \text { Molecular mass } \\&=0.887 \times 58.5 \\&=51.9 \\&\simeq 52 \mathrm{~g} \quad\end{aligned}$$[/tex]

Therefore, it is true that when 20.4g of sodium metal are mixed with chlorine gas, 52.0 g of sodium chloride is produced

Explanation:

The answer: True

I explained the answer to your question in the submitted photo

Answer: The gas from an erupting volcano had the following composition: 494 torr CO₂, 0.054 atm HCI, 0.028 atm HF, 0.017 atm 50₂. 0.76 mmHg H₂5, and H₂. If the total pressure is 1.00 atm, what is the partial pressure of H₂?

Explanation:

Answer:

ΔU = Q − W

Explanation:

the branch of physical science that deals with the relations between heat and other forms of energy (such as mechanical, electrical, or chemical energy), and, by extension, of the relationships between all forms of energy.

ΔU is the change in internal energy U of the system. Q is the net heat transferred into the system—that is, Q is the sum of all heat transfer into and out of the system.

Apply thermodynamics

[tex]\\ \rm\rightarrowtail Q=mc\delta T[/tex]

[tex]\\ \rm\rightarrowtail Q=1500(4.184)(27)[/tex]

[tex]\\ \rm\rightarrowtail Q=169452J[/tex]