Define kinetic energy and write a statement about how kinetic energy is affected as velocity increases.

Answers

Answer 1

Answer: Kinetic energy is the energy of mass in motion. Because kinetic energy is proportional to the velocity squared, increases in velocity will have an exponentially greater effect on translational kinetic energy.

Explanation: Google

Answer 2

A moving object's kinetic energy is directly proportional to both its mass and the square of its velocity.

How does kinetic energy gets changed ?

An object with twice as much mass and the same speed will have twice as much kinetic energy, whereas an object with twice as much mass and the same speed will have four times as much kinetic energy.Kinetic energy is the kind of energy an object or particle has because it moves. When a net force is applied to an object, which is work that transfers energy, the object accelerates and gains kinetic energy. A moving object or particle's kinetic energy is a property that is affected by its mass as well as its motion. Translation (movement along a path from one location to another), rotation about an axis, vibration, or any combination of these motions can be the type of motion.In the meter-kilogram-second system, the joule is the energy unit. The kinetic energy of a two-kilogram mass traveling at a speed of one meter per second, which is slightly more than two miles per hour, is one joule, or something like 4.4 pounds on Earth. The unit of energy in the centimeter-gram-second system is the erg, or 10^7 joules, which is the same as the kinetic energy of a mosquito in flight. On the atomic and subatomic scale, smaller units of energy, such as the electron volt, are also utilized in specific contexts.

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Related Questions

the filament of an electric lamp, which draws a current of 0.5 a is used for 2 hours. calculate the amount of charge flowing through the circuit

Answers

Answer:

I = 0.25  AND  T= 4 HOURS, Q = ??  

 multiply  both min  and sec , 240 and 60

we get 1400 sec  

the formula for current is   I = Q/T

substitute the given data in the formula  and simplify it

so , Q = 3600C  

You walk out to the edge of a 2,384 m. cliff and you toss a rock down to watch it drop. What is the rocks acceleration?

Answers

Answer:

9.8m/s

Explanation:

Wherever you're on the earth's surface, gravitational force remains the same and it does not matter either its a rock that's being tossed or a sheet of paper, the acceleration remains 9.8m/s only. *Condition applied=air resistance neglected

the diagram below shows the movement of matter in a portion of the water cycle.

what does p most likely represent

rivers
lakes
infiltration
precipitation

Answers

Answer:

Infilteration

Pls help me

What is the acceleration of a 10 kg mass pushed by a 5 N force? ​

Answers

Answer:

The answer is 0.5m/s²

Explanation:

Acceleration=Force ÷mass

= 5÷10=0.5m/s²

If a person weighs 692 N on earth and 5320 N on the surface of a nearby planet, what is the acceleration due to gravity on that planet?

Answers

Answer:

Approximately [tex]75.3\; \rm m \cdot s^{-2}[/tex]. (Approximately [tex]7.69\, g[/tex], where [tex]g[/tex] denotes the acceleration due to gravity on the surface of the earth.)

Explanation:

The weight of an object is the size of the overall gravitational pull on that object. If the mass of this person is [tex]m[/tex], the weight of this person at a point with gravitational acceleration [tex]g[/tex] would be [tex]m \cdot g[/tex].

Let [tex]g_{0}[/tex] denote the gravitational acceleration on the surface of the earth. The weight of this person on the surface of the earth would be [tex]m \cdot g_0[/tex].

Let [tex]g_1[/tex] denote the gravitational acceleration on the surface of that "nearby planet". The weight of this person on the surface of that planet would be [tex]m \cdot g_1[/tex].

According to the question:

Weight of this person on the surface of the earth: [tex]692\; \rm N[/tex]. Therefore, [tex]m \cdot g_0 = 692\; \rm N[/tex].Weight of this person on the surface of that nearby planet: [tex]5320\; \rm N[/tex]. Therefore: [tex]m \cdot g_1 = 5320\; \rm N[/tex].

Take the quotient of these two equations:

[tex]\displaystyle \frac{m\cdot g_1}{m \cdot g_0} = \frac{5320 \; \rm N}{692\; \rm N}[/tex].

[tex]\displaystyle \frac{g_1}{g_0} \approx 7.6879[/tex].

[tex]g_1 \approx 7.6879 \, g_0[/tex].

In other words, the gravitational acceleration on the surface of that nearby planet is approximately [tex]7.6879[/tex] times the gravitational acceleration on the surface of the earth.

The gravitational acceleration on the surface of the earth is approximately [tex]g \approx 9.8\; \rm m \cdot s^{-2}[/tex]. Therefore, the gravitational acceleration on the surface of that planet would be approximately [tex]7.6879\, g \approx 7.8679 \times 9.8\; \rm m \cdot s^{-2} \approx 75.3\; \rm m \cdot s^{-2}[/tex].

The kinetic energy k of an object in joules is given by the formula k= 1 over 2mv^2 where m is the object’s mass in kilograms and v is it’s velocity in meters per second. An object’s velocity in meters per second, and it’s kinetic energy is 48,000 joules..If it speeds up to 40 meters per second, what is its new kinetic energy

Answers

Answer:

Ek = 192000 [J]

Explanation:

Originally missing speed data to solve this problem, we must assume that the original speed is 20 [m/s]. In this way, we can calculate the mass of the object.

48000 = (1/2)*m*(20)^2

m = 240 [kg]

The mass is conserved since it does not change only changes the speed of the body so we can calculate a new kinetic energy.

Ek = (1/2)*240*(40)^2

Ek = 192000 [J]

1-1 A carpet is to be installed in a room whose length is measured to be 12.71 m and whose width is measured to be 5.46 m. Find the area and error in the area of the room. (∆L=0.01)

Answers

Answer:

Explanation:

Area of the room = Length × Width

Given

Length = 12.71m

Width = 5.46m

Area of the room = 12.71m×5.46m

Area of the room = 69.3966m²

To get the area of the error, we will use the relationship;

∆A/A = {∆L/L + ∆W/W}

∆A/A = {0.01/12.71 + 0.01/5.46}

∆A/A = {0.0007868+ 0.001832}

∆A/A = 0.0026182

∆A = 0.0026182A

Since Area A = 69.3966m²

∆A = 0.0026182(69.3966)

∆A ≈ 0.1817m²

Hence error in the area of the room is 0.1817m²

Which one these statements describes how to typically tell the difference
between a synthesis (S) reaction and a decomposition (D) reaction?
Tap to select or deselect answer.
An S reaction has one product and two or more reactants and a D reaction
has one reactant and two or more products.
An Sreaction has one reactant and two or more products and a D reaction
has one product and two or more Reactants.
An S reaction has oxygen as a reactant and a Dreaction has oxygen as a
product
An S reaction has oxygen as a product and a D reaction has oxygen as a
reactant

Answers

Answer: An S reaction has one product and two or more reactants and a D reaction has one reactant and two or more products.

Explanation:

In a synthesis reaction, two or more simple molecules or substances interact to form a more sophisticated product. (General equation: A + B → AB)

When one reactant decomposes into two or more products, this is known to as a decomposition reaction. (General equation: AB → A + B)

A 30 kg child is in a school play. She is standing on the ground at rest but she is attached to a rope with a 5 kg mass attached. A 45 kg child takes off the 5 kg mass and jumps from a height in order to hoist the 30 kg child off the ground. What is the acceleration that both children have together?

:)

Answers

20kg because a child takes off 5K mass jumps meaning it possible be 15K

If a system does 63.0 kJ of work on its surroundings and releases 105 kJ of heat, what is the change in the internal energy of the system, in kJ

Answers

Answer:

-42 kJ

Explanation:

Q = ΔE + W

W = -63.0 kJ

Q = -105 J

so -105 = ΔE + (-63)

ΔE = 63 - 105 = -42 kJ

A system does the work of 63 kJ and releases 105 kJ of heat, then the change in internal energy will be -42 kJ.

What is heat?

When a thermodynamic system's boundary is crossed by a form of energy due to a temperature differential, that form of energy is referred to as heat. Heat is not present in thermodynamic systems.

In the right-hand image, a metal bar is "conducting heat" from its hot end to its cold end. However, if the metal bar is thought of as a thermodynamic system, then the energy moving within the metal bar is what is being described as "conducting heat" instead is called internal energy.

Q = Δ E + W

W = -63.0 kJ

Q = -105 J

Then,

-105 = Δ E + (-63)

ΔE = 63 - 105 = -42 kJ

Therefore, the change in internal energy will be -42 kJ.

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In which soil layer do plant seeds germinate and plant roots thrive?
subsoil
organic
bedrock
topsoil

Answers

Answer: Topsoil

Explanation:

Bio

Answer:

topsoil

Explanation:

A student is investigating magnetic fields. The student places four different objects near identical magnets and observes what happens. The student records her observations in the table below. Using data from the table, which argument can the student make about magnetic fields?
a. The effect that a magnetic field has on an object depends on the mass of the object.
b. The effect that a magnetic field has on an object depends on the material of the object.
c. The effect that a magnetic field has on an object depends on the type of magnet used.
d. The effect that a magnetic field has on an object depends on the distance to the object.

Answers

Answer:

B. The effect that a magnetic field has on an object depends on the material of the object.

Explanation:

Just makes sense

Based on the data given in the table, the best argument the student can make about magnetic fields is that b. The effect that a magnetic field has on an object depends on the material of the object.

Why can this argument be made?

Certain objects have properties that make them easier to be magnetizable than other materials. Crayons and wooden toothpicks for instance, are not magnetizable.

The conclusion that can be made therefore is that the effect of a magnet on an object depends on the material of the object.

In conclusion, option B is correct.

Find out more on magnetic fields at https://brainly.com/question/14411049.

If a satellite is launched to a distance of 1000000m above the earth’s surface, what is the gravitational field strength on the satellite from the earth?

Answers

Explanation:

A 620 kg satellite above the earth's surface experiences a gravitational field strength of 4.5 N/kg.

Knowing the gravitational field strength at Earth’s sur-

face and Earth’s radius, how far above Earth’s surface

is the satellite? (Use ratio and proportion.)

The less energy a wave has, the ________

Answers

Answer:

The less energy a wave has, the smaller the amplitude

Explanation:

Hope this helps!!!

A disc of radius wich uniform distribution of mass rotates about on axis perpendicular to it's plane at the rim with angular speed, the moment of inertia of the disc about the axis through the centre is 1/2MR*R, what's the kinetic energy of the disc?​

Answers

Answer:

Explanation:

M3U1 Pre-Assessment

Reflection Journal - Thursday

100 POINTS QUESTION. PLEASE PROVIDE EXPLANATION

Answers

Answer:

t = 0, p = 12.0, v = 6.00

t = 20, p = 112, v = 56.0

t = 25, p = 62.0, v = 31.0

Explanation:

Impulse = change in momentum

J = Δp

FΔt = mΔv

The impulse equals the area under the F vs t graph.

At t = 0 s, the initial velocity is 6.00 m/s, so the momentum is:

p = (2.00 kg) (6.00 m/s)

p = 12.0 kg m/s

From t=0 s to t=20 s, the impulse is:

J = (20 N) (5 s) + ½ (20 N) (5 s) + ½ (-10 N) (10 s)

J = 100 Ns

So the new momentum is:

p = 12.0 kg m/s + 100 kg m/s

p = 112 kg m/s

And the new velocity is:

v = (112 kg m/s) / (2.00 kg)

v = 56.0 m/s

From t=20 s to t=25 s, the impulse is:

J = (-10 N) (5 s)

J = -50 Ns

So the new momentum is:

p = 112 kg m/s − 50 kg m/s

p = 62.0 kg m/s

And the new velocity is:

v = (62.0 kg m/s) / (2.00 kg)

v = 31.0 m/s

long narrow uniform stick of length ! and mass m lies motionless on ice (assume the ice provides a frictionless surface). The center of mass of the stick is the same as the geometric center (at the midpoint of the stick). The moment of inertia of the stick about its center of mass is lcm . A puck (with putty on one side) has same mass m as the stick. The puck slides without spinning on the ice with a speed of v0 towards the stick, hits one end of the stick, and attaches to it. You may assume that the radius of the puck is much less than the length of the stick so that moment of inertia of the puck about its center of mass is negligible compared to Icm . (a) How far from the midpoint of the stick is the center of mass of the stick-puck combination after the collision?

Answers

Answer:

the answer would be 0 as known to the length

Explanation:

0m x96 would put as an mass of 900 into 0 so there for your answer would be 0

Object A has a charge of -1 C. Object A has a charge of -1 C. At a given distance, the object with which
charge would be most strongly attracted by object A?*
+1 C
-1 C
+2 C
-2 C

Answers

The positive charge with the highest magnitude is +2 C and this charge would be most strongly attracted by object A.

Attraction of opposite charges

Opposite charges have the ability to attract each other while, similar charges repel each other.

The given charge of object A is negative, and it will be strongly attracted to a positive charge.

The greater the positive charge, the greater the force of attraction of object A.

From the given options, the positive charge with the highest magnitude is +2 C and this charge would be most strongly attracted by object A.

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An object is placed at 0 on a number line. It moves 3 units to the right, then 4 units to the left and then 6 units to the
right. What is the displacement of the object?
1
5
7
13

Answers

Answer:

5

Explanation:

when you move 3 unit to the right your object is at 3.then when you move 4 units to the left your object is at -1 because

a number line also has negative numbers.Then if you move 6 units your object is at 5

Please help 50 points: A ball is thrown straight up, from 3 m above the ground, with a velocity of 14m/s. When does it hit the ground? Use vertical motion formula.

Answers

Projectile Motion for an Object Launched at an Angle

When an object is projected from rest at an upward angle, its initial velocity can be resolved into two components. These two components operate independently of each other. The upward velocity undergoes constant downward acceleration which will result in it rising to a highest point and then falling backward to the ground. The horizontal motion is constant velocity motion and undergoes no changes due to gravity.The analysis of the motion involves dealing with the two motions independently.

Explanation:

and Thais

Projectile Motion for an Object Launched at an Angle

When an object is projected from rest at an upward angle, its initial velocity can be resolved into two components. These two components operate independently of each other. The upward velocity undergoes constant downward acceleration which will result in it rising to a highest point and then falling backward to the ground. The horizontal motion is constant velocity motion and undergoes no changes due to gravity.The analysis of the motion involves dealing with the two motions independently.

Projectile Motion for an Object Launched at an Angle

When an object is projected from rest at an upward angle, its initial velocity can be resolved into two components. These two components operate independently of each other. The upward velocity undergoes constant downward acceleration which will result in it rising to a highest point and then falling backward to the ground. The horizontal motion is constant velocity motion and undergoes no changes due to gravity.The analysis of the motion involves dealing with the two motions independently.

what is an electric current ?​

Answers

Answer:

An electric current is a stream of charged particles, such as electrons or ions, moving through an electrical conductor or space. It is measured as the net rate of flow of electric charge through a surface or into a control volume.

Explanation:

the force F is given in terms of time 'y'all and displacement 'X' by the equation F=AsinBx+CsinDt. what is the dimension of D/B?​

Answers

Answer:

D/B ahs units of  Length over Time

Explanation:

Notice that B is multiplying "x" (displacement) as argument of the sine function, therefore it has to have units of the reciprocal of Length.

Also the constant D is multiplying "t" as argument of the sine function, and as such, it must have units of the reciprocal of time.

Therefore, the quantity D/B must have units of Length over Time.

What are two differences and two similarities between applied force and tension force

Answers

Answer:

similarities: They are both members of an action reaction-pair and are produced by electromagnetic forces between the particles. In the case of tension a force is acting to separate the molecules from their equilibrium position, the tension is the resistance to this separatio; that is the electrical attraction among the charged particles that opposes the action of the applied force. In the case of the normal force when gravity pulls an object downward, the electrons of the two surfaces are pulled so close that they mutually reject each other. This rejection between the electrons of the 2 surfaces produces the normal force, acting in opposition to gravity.

Differences: The main difference between tension and force is the direction of force. ... Tension is a force pulling something apart, such as a force pulling apart on the ends of a rope. You often calculate tension in pulley problems. A force is a more general term applying to pushing or pulling on something.

Explanation:

i hope this helps you :)

list clown the advantages and disadvantages
of the micrometer screw guage
Caliper?
over Vernier

Answers

Answer:

Micrometers provide very accurate measurements

The micrometer is one of the most accurate types of measuring device.

Most micrometers can measure up to 0.001mm or 0.0001 inches.

-------

Ratchet speeder helps to provide reliable measurements

The ratchet speeder/stop mechanism ensures that uniform pressure is applied to the thimble so that measurements are reliable and repeatable.

-------

Explanation:

A baseball is batted. It's a long fly ball. 4 seconds later the ball reaches the outfield 100 meters away and returns to the height from which it left the bat. Determine the horizontal component of the ball's initial velocity in magnitude, in m/s,

Answers

Answer:

25 m/s

Explanation:

First we should define the variables

T=4

Dx = 100

ay=-9.8

ax=0

We can use formula 1 from the BIG 5

x=(v+v0)t/2

By plugging in our variables we can get 100=4(v+v0)/2

Which is 50=v+v0

v=v0 since horizontal acceleration always equals zero

so 2v0 = 50

v0 = 25

PLEASE HELP AND I WILL GIVE U BRAINLY

a south african white rhinoceros weighs 22658 N and has a top speed of 14 m/s. a bullet from a barrett 0.50 caliber rifle has a weight of 0.4 N and travels with a velocity of 884 m/s. Which object has more momentum in its motion?

Answers

Answer:

it is the white rhinoceros because it weighs more then the bullet all though the bullet travels faster once the rhino gets running it is hard to stop because it weighs so much

I need to know the answer to this and I do not need an explanation

Answers

Answer:

3rd sentence

Explanation:

The average standard rectangular building brick has a mass of 3.10 kg and dimensions of 225 m x 112 m x 75 m. The gravitational field constant g = 9.8 N/kg. Calculate the maximum pressure created by brick

Answers

Answer:

[tex]P=3.61\times 10^{-3}\ Pa[/tex]

Explanation:

Given that,

Mass of a brick, m = 3.1 kg

The dimensions of the brick 225 m x 112 m x 75 m

We need to find the maximum pressure created by the brick. We know that, the force acting per unit area is called pressure exerted. It is given by the formula as follows :

[tex]P=\dfrac{F}{A}[/tex]

F = mg

A = area with minimum dimensions i.e. 112 m x 75 m

Pressure is maximum when the area is least.

So,

[tex]P=\dfrac{mg}{A}\\\\P=\dfrac{3.1\times 9.8}{112\times 75}\\\\P=3.61\times 10^{-3}\ Pa[/tex]

So, the maximum pressure created by brick is [tex]3.61\times 10^{-3}\ Pa[/tex].

What is the name of the area around a charged object where the object can exert a force on other charged objects?

A) electric field
B) electric charge
C) electric induction
D) electric force

Answers

I believe it’s the electric field.

The name of the area around a charged object where the object can exert a force on other charged objects will be the electric field. Option A is correct.

What is an electric field?

An electric field is an electric property that is connected with any location in space where a charge exists in any form. The electric force per unit charge is another term for an electric field.

The electric field formula is as follows:

E = F /Q

Where,

The electric field is denoted by the letter E.

F is the electric force

The charge is Q.

The name of the area around a charged object where the object can exert a force on other charged objects will be the electric field.

Hence option A is correct.

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A race starts and finishes a race that is 50,000m. (30miles). The time is 23 minutes. The final velocity is 67m/s. What is the average acceleration ?

Use acceleration formula

Answers

Answer:

a = 0.0505 [m/s^2]

Explanation:

In order to solve this formula we must use the following formula of kinematics.

[tex]x=(v_{o} *t)+(\frac{1}{2} )*a*t^{2}[/tex]

where:

x = distance = 50000 [m]

Vo = initial velocity = 0

a = acceleration [m/s^2]

t = time = 23 [min] = 1380 [s]

Note: the positive sign in the above equation shows that the car accelerates.

50000 = (0*1380) + (0.5*a*1380^2)

a = 0.0525 [m/s^2]

But we can calculate the acceleration using the following formula:

[tex]v_{f} =v_{o} +a*t[/tex]

where:

Vf = final velocity = 67 [m/s]

67 = 0 + (a*1380)

a = 0.0485 [m/s^2]

We can see that by means of kinematics and with the given values we can find two values of accelerations, however, we can determine the average acceleration, by means of the mathematical average.

a = (0.0485 + 0.0525) / 2

a = 0.0505 [m/s^2]

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