Determine if the graph is symmetric about the x-axis, the y-axis, or the origin.

r = 4 cos 5θ

Answer:

[tex]\frac{7}{4.1}[/tex]

Step-by-step explanation:

the word ''to'' means over

Answer:

40

Step-by-step explanation:

A +  B=75

A + C = 61

B = 5/3 *C

A+C * 5/3 = 75 then we got the answer

Answer:

A = 40

Step-by-step explanation:

A+B = 75

A+C = 61

Subtract

A+B = 75

-A-C = -61

----------------------

B-C = 14

B:C

5:3

for every 5B there are 3C

Replace B with 5/3 C

5/3C-C = 14

2/3C = 14

C = 21

A+C = 61

A +21 = 61

A = 40

Answer:

I think it's D

Answer:

its D

Step-by-step explanation:

Answer:

[tex]18 + 18 + 18 = 18 \times 3 = 54[/tex]

Step-by-step explanation:

I ain't sure but it might help you out:D

Answer:

140.3 cm²

Step-by-step explanation:

area of an equilateral triangle

[tex] = \frac{\sqrt{3} }{4} {a}^{2} [/tex]

where a is the side of the triangle

[tex] = \frac{ \sqrt{3} }{4} \times {18}^{2} \\ = 140.3 \: cm {}^{2} [/tex]

Answer:

DCE is similar to AED

EBA is similar to AED

AFE is similar to AED

EFD is similar to AED

Step-by-step explanation:

Triangle AED:

D=53(alternate interior angle)

A=180-90-53=37 (angle of triangle)

AA similarity criterion

DCE is similar to AED

angle BEA=180-90-53=37=angle A of AED

Thus: AA similarity criterion:

EBA is similar to AED

The diagonal of parallelogram(here:rectangle) cut it into 2 congruent triangles

Thus:

EBA is congruent to AFE

EBA is congruent to AFEDCE is congruent to EFD

Congruent triangles are similar

Conclusion:

DCE is similar to AED

EBA is similar to AED

AFE is similar to AED

EFD is similar to AED

Please give brainliest if it helps

The triangles are similar to triangles AED are DCE is similar to AED, EBA is similar to AED, AFE is similar to AED, EFD is similar to AED.

What triangles are similar to triangle AED?

Alternate interior angles are formed when a transversal passes through two lines.

The angles that are formed on opposite sides of the transversal and inside the two lines are alternate interior angles.

In the triangle AED:

The angle is equal to 53.

Then,

A=180-90-53=37

DCE is similar to AED.

Here EBA, DCE, EF, D, and AFE bc it doesn’t matter about the size it matters about the angle whether it stays the same and you can clearly see that angle b, and f, angle, c, and angle e are all 90 degrees making the triangles I listed similar to triangle AED.

Hence, The triangles are similar to triangles AED are DCE is similar to AED, EBA is similar to AED, AFE is similar to AED, EFD is similar to AED.

To know more about Triangle click the link given below.

https://brainly.com/question/23919428

Answer:

TV = 18

Step-by-step explanation:

First, we can visualize rotating the triangle ΔTUV 180 degrees to line it up with ΔTRS, as shown in the picture. This makes it easier to visualize which sides correspond to each other. Because UT is parallel to RT, and UV is still parallel to RS (rotating the triangle 180 or 360 degrees does not change this), we know UT is similar to RT and so on.

As the ratio of similar sides are equal in similar shapes, we can say that

RT/UT = TS/TV = RS/UV

One thing to note is that all sides of TRS are on top, while all sides of TUV are on the bottom. Make sure that for all your sides, that the same triangle's sides stay on either the top or bottom.

Given this, and that we want to find TV, we can say that

TS / TV = RS / UV (I didn't use RT/UT because we don't know UT)

27 / TV = 24 / 16

Multiply both sides by 16 to eliminate a denominator

27 * 16 / TV = 24

Multiply both sides by TV to eliminate all denominators

27 * 16 = 24 * TV

Divide both sides by 24 to isolate TV

27 * 16 / 24 = TV

TV = 18

Answer:

[tex] \sqrt[5]{96x {}^{7} y {}^{11} } = 2xy {}^{2} \sqrt[5]{3x {}^{2}y } [/tex]

Answer:

y = 2*(x - 3)^2 - 2

Step-by-step explanation:

Remember that a quadratic equation of vertex (h, k) is written as:

y = a*(x - h)^2 + k

Where a is the leading coefficient.

So, if we know that the vertex is at (3, - 2)

we have:

y = a*(x - 3)^2 + (-2)

And we want the y-intercept to be (0, 16)

This means that, when we take x = 0, we must have y = 16

if we replace these in the above equation we get:

16 = a*(0 - 3)^2 - 2

now we can solve this for a

16 = a*(-3)^2 - 2

16 = a*9 - 2

16 + 2 = a*9

18 = a*9

18/9 = a

2 = a

Then the quadratic equation is:

y = 2*(x - 3)^2 - 2

Answer:

Step-by-step explanation:

cos(c)= x/ac

ac = cos32/9.4

ac =11.08

Answer:

Step-by-step explanation:

sin(58/9.4 = sin(90)/AC

AC= 11.08

Answer:

Here,

CD + DE = CD

x+10 + x+4 = 8

2x + 14 = 8

2x= -6

x= -3

Answer:

(a - b)^2 = 49 - 4b^2 +2ab

Step-by-step explanation:

Given: a^2 + b^2 = 7b (assuming A is really “a”)

b^2 + (2b - a)^2 = 7^2

Find; (a - b)^2

Plan: Use Algebraic Manipulation

Start with b^2 + (2b - a)^2 = 7^2 =>

b^2 + 4b^2 - 4ab + a^2 = 49 by expanding the binomial.

a^2 + b^2 + 4b^2 - 4ab = 49 rearranging terms

a^2 + b^2 -2ab - 2ab + 4b^2 = 49 =>

a^2 - 2ab + b^2 = 49 - 4b^2 +2ab rearranging and subtracting 4b^2 and adding 2ab to both sides of the equation and by factoring a^2 - 2ab + b^2

(a - b)^2 = 49 - 4b^2 +2ab

Double Check: recalculated ✅ ✅

(a - b)^2 = 49 - 4b^2 +2ab

Answer:

Para el CO₂ sabemos que:

densidad = 0,001976 g/cm³

Sabemos que:

densidad = masa/volumen

Entonces, si tenemos una masa de 28 g, podemos escribir:

volumen = masa/densidad

volumen = (28g)/(0,001976 g/cm³) = 14,170 cm^3

Para obtener la masa molar (es decir, la masa de un mol de esta sustancia) simplemente sumamos la masa de un mol de cada componente.

Carbono: tiene una masa molar de 12 g/mol

Oxígeno: tiene una masa molar de 16 g/mol (y tenemos dos oxígenos)

entonces la masa molar va a ser:

masa molar = 12g/mol + 2*16g/mol = 44 g/mol

Es decir, un mol de CO₂, pesa 44 gramos.

do you have a clearer picture please? I can help :))

Answer:

1/11

Step-by-step explanation

There are 12 marbles in the bag. When we first pick we have 4 blue marbles. So 4 blue marbles/12 random marbles. When we pick blue and noted, there are 3 marbles in the bag because of we didn't put it back. So when we choose again there are 11 marbles and 3 blue marbles in the bag. Choosing a blue one case is 3/11.

The last part of this case is happening as a chain. So we need to multiply our two answers.

=4/12*3/11

=1/3*3/11

=1/11

f(x)/g(x) = (x2-16)/(x+4)

The domain is all real numbers except x = -4 (because the denominator is zero at x = -4 and division by zero is undefined.)

We can simplify by factoring the numerator:

(x2-16)/(x+4) = (x-4)(x+4)/(x+4) = (x-4)

The domain is the same as the original expression: all real numbers except x = -4

Answer:

Step-by-step explanation:

Hi, to answer this question we have to write a system of equations:

3 T + 4 B =425

T + B = 125

Where T is the number of tacos sold, and B is the number of burritos sold.

Multiplying the second equation by 3, and subtracting it to the first equation:

3 T + 4 B =425

3T + 3B = 375

___________

B =50

Replacing B in any equation:

T + B = 125

T +50 =125

T =125-50

T = 75

Feel free to ask for more if needed or if you did not understand something.

Answer:

correct bayan HAHAHAHAHAHA

Answer:

x = + 5/4 or x = - 5/4

Step-by-step explanation:

[tex]4 x^2 = 6\frac{1}{4}\\\\4 x^2 = \frac{25}{4}\\\\x^2 =\frac{25}{16}\\\\x = \pm \frac{5}{4}[/tex]

Answer:

[tex]Area = 52\sqrt3 \ ft^2[/tex]

Step-by-step explanation:

Area of trapezoid

                         [tex](\frac{a+ b}{2}) \times h[/tex]      -----------( 1 )

We will split the trapezoid into Triangle and rectangle. To find the height and full length of base.

[tex]sin 60 = \frac{opposite}{hypotenuse}[/tex]   [tex][ opposite \ in \ the \ equation \ \ is \ the \ height \ of \ the \ trapezoid ][/tex]

[tex]\frac{\sqrt3}{2} = \frac{opposite }{ 8}\\\\\frac{\sqrt3}{2} \times 8 = opposite\\\\4\sqrt3 = opposite[/tex]

Therefore, h = 4√3 ft

[tex]cos 60 = \frac{adjacent}{hypotenuse}[/tex]    [tex]adjacent \ in \ the\ equation \ is \ the\ base \ of \ the \ triangle ][/tex]

[tex]\frac{1}{2} = \frac{adjacent}{hypotenuse}\\\\\frac{1}{2} \times 8 = adjacent\\\\4 = adjacent[/tex]

Therefore, a = 11 feet, b = 11 + 4 = 15 feet

Substitute the values in the Area equation :

                                                [tex]Area = \frac{11 + 15}{2} \times 4 \sqrt3 = \frac{26}{2} \times 4\sqrt3 = 13 \times 4\sqrt3=52\sqrt3 \ ft^2[/tex]

Answer:

1. x = -6, -8, -90

2. solutions for [tex]-2x\geq 10[/tex] include -5, while -5 is not a solution for [tex]-2x>10[/tex]

Step-by-step explanation:

Answer:

bjkfkvdvdejij

Step-by-step explanation:

22333444 ijdcijsivjdivdvndk snciscicicnlvjavjadvj

Step-by-step explanation:

answers I the above photo

some of the questions are not clear

Answer:

1. C(13inches)

2. A(40°)

3. B(126°)

4. C(50°)

5. 7cm

Step-by-step explanation:

According To the Question,

1. Given, The sum of all the sides of a STOP sign is 104 inches. A STOP sign is Octagon  with all sides equal.

Thus, Octagon has 8 equal side

So, Each Side Measure = 104/8 ⇔ 13inches

2. Given, In Triangle ABC, ∠A & ∠B each measure 70°

And, We Know Sum of all angles of a triangle is 180°.

Thus, ∠C = 180° - (∠A + ∠B)  ⇔  180°-140° ⇒ 40°

3. Given, The measures of the three angles of a quadrilateral are ∠A=49° ,∠B=58° & ∠C=127° .

And, We know sum of all angles of quadrilateral is 360°.

Thus, ∠D=360° - (∠A+∠B+∠C)  ⇔ 360°-234° ⇒ 126°

4. Given, The measure of all the Four angles of a quadrilateral are ∠A=(x+40)°, ∠B=130°, ∠C=x° & ∠D=(2x-10)° .

And, We know sum of all the angles of quadrilateral is 360°.

Thus, ∠A+∠B+∠C+∠D = 360°

Put all the Values, we get

x+40+130+x+2x-10 = 360

4x+160 = 360

4x = 200 ⇔ 200/4 ⇒ 50°

5. Given, the length of the two sides of an isosceles triangle are 3cm and 7cm .

Now, in order to form a triangle the sum of any two side of a triangle is always greater than the third side of a triangle.

So, We have an isosceles triangle in which two sides is always equal & we have given two sides of 3cm & 7cm .

Assume, if third side be 3cm (First Side+Third side > Second side)

3+3 ⇒6cm which is not greater than 7cm(thus, the Triangle not possible if we assume 3cm as triangle's third side)

Hence, The other Side of Triangle Surely be 7 cm.  

Consider that we need to find [tex](a+b)(x), (a-b)(x), (ab)(x),\left(\dfrac{a}{b}\right)(x)[/tex].

Given:

The functions are:

[tex]a(x)=4x+9[/tex]

[tex]b(x)=3x-5[/tex]

To find:

The function operations [tex](a+b)(x), (a-b)(x), (ab)(x),\left(\dfrac{a}{b}\right)(x)[/tex].

Solution:

We have,

[tex]a(x)=4x+9[/tex]

[tex]b(x)=3x-5[/tex]

Now,

[tex](a+b)(x)=a(x)+b(x)[/tex]

[tex](a+b)(x)=4x+9+3x-5[/tex]

[tex](a+b)(x)=7x+4[/tex]

Similarly,

[tex](a-b)(x)=a(x)-b(x)[/tex]

[tex](a-b)(x)=4x+9-(3x-5)[/tex]

[tex](a-b)(x)=4x+9-3x+5[/tex]

[tex](a-b)(x)=x+14[/tex]

And,

[tex](ab)(x)=a(x)b(x)[/tex]

[tex](ab)(x)=(4x+9)(3x-5)[/tex]

[tex](ab)(x)=12x^2-20x+27x-45[/tex]

[tex](ab)(x)=12x^2+7x-45[/tex]

And,

[tex]\left(\dfrac{a}{b}\right)(x)=\dfrac{a(x)}{b(x)}[/tex]

[tex]\left(\dfrac{a}{b}\right)(x)=\dfrac{4x+9}{3x-5}[/tex]

Therefore, the required functions are [tex](a+b)(x)=7x+4[/tex], [tex](a-b)(x)=x+14[/tex], [tex](ab)(x)=12x^2+7x-45[/tex] and [tex]\left(\dfrac{a}{b}\right)(x)=\dfrac{4x+9}{3x-5}[/tex].

Answer:

Measures of Variability: Range, Interquartile Range, Variance, and Standard Deviation. ... While a measure of central tendency describes the typical value, measures of variability define how far away the data points tend to fall from the center. We talk about variability in the context of a distribution of values.

Answer:

5 shirts

Step-by-step explanation:

Y=12x+3 equation 1

y=8x+23 equation 2

12x+3=8x+23 substituting y value will cause equations to equal

4x=20

x=5 shirts

check answer

y=12x+3

y=12(5)+3

y=60+3

y=63

y=8x+23

y=8(5)+23

y=40+23

y=63

Answer:

Equation: 4x+1+75=180

X= 26

105°

Step-by-step explanation:

When added, the two angles would create a flat angle of 180°, so just add the two angles:

4x+1+75=180

4x+76=180

   -76   -76

4x=104

x=26

Input the solved x value into the angle to get the angle measure

4(26)+1 = 105