Determine the percent yield for the reaction between 46.5 g of
ZnS and 13.3 g of oxygen if 18.l4 g of ZnO is recovered along with an unknown quantity of sulfur
dioxide.
please show work thank you
Answers
The percentage yield of the reaction has been 46.74%.
Percentage yield can be given as the ratio of the actual yield to the theoretical yield.
For the theoretical yield, the balanced equation will be:
[tex]\rm 2\;ZnS\;+\;3\;O_2\;\rightarrow\;2\;ZnO\;+\;2\;SO_2[/tex]
Thus, 2 moles of ZnS will give 2 moles of ZnO.
The moles of 46.5 g ZnS:
Moles = [tex]\rm \dfrac{weight}{molecular\;weight}[/tex]
ZnS = [tex]\rm \dfrac{46.5}{97.474}[/tex]
ZnS = 0.477 mol
The moles of 13.3 grams Oxygen:
Oxygen = [tex]\rm \dfrac{13.3}{32}[/tex]
Oxygen = 0.415 mol.
The moles of 18.14 grams ZnO:
ZnO = [tex]\rm \dfrac{18.14}{81.38}[/tex]
ZnO = 0.222 mol
According to the balanced chemical equation,
2 moles ZnO = 2 moles ZnS
0.222 mol ZnO = 0.222 mol ZnS
2 moles ZnO = 3 moles Oxygen
0.222 mol ZnO = 0.334 mol of Oxygen
Since, both the reactants are in enough concentration,
The theoretical yield can be calculated with any of the reactants. The theoretical yield of ZnO from 46.5 grams of ZnS can be given as:
1 mole ZnS = 1 mol ZnO
0.477 mol of ZnS = 0.477 mol of ZnO.
The mass of 0.477 mol of ZnO:
Mass = moles [tex]\times[/tex] molecular weight
Mass of ZnO = 0.477 [tex]\times[/tex] 81.38
Mass of ZnO = 38.818 grams.
The theoretical yield of ZnO = 38.818 g.
The actual yield of ZnO = 18.14 g.
Percentage yield = [tex]\rm \dfrac{18.14}{38.81}\;\times\;100[/tex]
Percentage yield = 46.74 %
The percentage yield of the reaction has been 46.74%.
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A. hiding
B. protective resemblance
C. mimicry
D. protective coloration
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Answer:
The answer to your question is A.
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²⁴³₉₅Am --> ²³⁹₉₃Np + ⁴₂He
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M
a
V
a
=
M
b
V
b
M
a
= 6.77M - the initial molarity (concentration)
V
a
= 15.00 mL - the initial volume
M
b
= 1.50 M - the desired molarity (concentration)
V
b
= (15.00 + x mL) - the volume of the desired solution
(6.77 M) (15.00 mL) = (1.50 M)(15.00 mL + x )
101.55 M mL= 22.5 M mL + 1.50x M
101.55 M mL - 22.5 M mL = 1.50x M
79.05 M mL = 1.50 M
79.05 M mL / 1.50 M = x
52.7 mL = x
59.7 mL needs to be added to the original 15.00 mL solution in order to dilute it from 6.77 M to 1.50 M.
I hope this was helpful.
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Question 2 options:
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more oxygen gas became present in the atmosphere
Answers
In a chemical reaction
1 point
The atoms of the reactants unbond, rearrange and then rebond to form the products
Some atoms disappear while others multiply to form the products
The atoms of the reactants always stay together to form the products
New atoms are formed which combine to make the products
Answers
Answer:
A) The atoms of the reactants unbond, rearrange and then rebond to form the products
Explanation:
Using method of elimination:
A) The atoms of the reactants unbond, rearrange and then rebond to form the products
This is the correct option. Chemical reactions involves breaking and forming of new bonds.
B) Some atoms disappear while others multiply to form the products
This option is incorrect. Atoms do not disappear
C) The atoms of the reactants always stay together to form the products
This option is incorrect. The bonds between the atoms in the reactants must first be broken before products can be formed.
D) New atoms are formed which combine to make the products
This option is incorrect. Atoms do not just form out of nowhere.
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Explanation:
Good Luck!
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Answers
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Determine the percent yield for the reaction between 98.7 g of
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Answers
Convert mols Sb2S3 to mols Sb4O6 using the coefficients in the balanced equation.
Convert mols Sb4O6 to grams Sb4O6. (This is the theoretical yield.)
Convert grams Sb4O6 to percent Sb4O6.
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So basically your answer is 85.5%
The percent yield of the reaction would be 85.64%
Percent YieldFrom the balanced equation of the reaction:
[tex]9 O_2 + 2 Sb_2S_3 ---> 6 SO_2 + Sb_4O_6[/tex]
Mole ratio of Sb2S3 to Sb4O6 is 2:1
Mole of 98.7g Sb2S3 = 98.7/339.7
= 0.29 moles
Equivalent mole of Sb4O6 = 0.29/2
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In a chemical reaction*
1 point
The atoms of the reactants unbond, rearrange, and then rebond to form the products
Some atoms disappear while others multiply to form the products
The atoms of the reactants always stay together to form the products
New atoms are formed which combine to make the products
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1st one is correct
The atom of the reactants unbound , rearrange, and then rebond to form the product
hope it helps
In a chemical reaction, the atoms of the reactants unbond, rearrange, and then rebond to form the products. Therefore, option A is correct.
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Combustion reaction, decomposition reaction, neutralization reaction, redox reaction, precipitation or double-displacement reaction, and synthesis reaction are some of the numerous types of reactions.
In a chemical reaction, bonds between molecules of the reactant are broken and new bonds between molecules of the product are established to create a new substance.
A chemical equation is nothing more than a mathematical statement that represents how reactants form products.
Thus, option A is correct.
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Answers
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Answers
Answer:
Area of rectangular poster = [tex]\frac{3}{16}[/tex] yard²
Explanation:
P.S - The exact question is -
Given - A rectangular poster is [tex]\frac{1}{4}[/tex] yard wide and [tex]\frac{3}{4}[/tex] yard tall.
To find - What is its area ?
Proof -
We know that ,
The area of rectangle = Length × Breadth
Here,
Given that,
Length of rectangle = [tex]\frac{3}{4}[/tex] yard
Breadth of rectangle = [tex]\frac{1}{4}[/tex] yard
∴ we get
Area of rectangular poster = [tex]\frac{3}{4}[/tex] × [tex]\frac{1}{4}[/tex] yard²
= [tex]\frac{3}{16}[/tex] yard²
⇒Area of rectangular poster = [tex]\frac{3}{16}[/tex] yard²
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Answers
Answer:
The answers are 1:3:13
Explanation:
when I had to do these types of equations just search them up on you-tube lol theres this guy called Wayne Breslyn that does a really good job of explaining and has like the answers for any and everyy balancing equation