jump discontinuities x= DNE
removable discontinuities x= DNE
infinite discontinuities x= -2, 2
other discontinuities x= DNE
The function has an infinite discontinuity at x=-2 and x=2 because the denominator of the fraction, x^2 + 4, approaches 0 as x approaches -2 or 2.
A box was made in the form of a cube. If a second cubical box has inside dimensions four times those of the first box, how many times as much does it contain?
(A) 4
(B) 8
(C) 16
(D) 64
(E) none of these
Answer:
Since the second box has inside dimensions four times those of the first box, its volume is $(4a)^3 = 64a^3$ times as much as the volume of the first box, whose volume is $a^3$. Therefore, the answer is (D) 64.
Amanda bought a reusable water bottle that cost $23.94 including tax. After buying the water bottle, Amanda had $12.75 left in her wallet. Let m represent how much money Amanda had to start. Which equation models the problem? Solve this equation to find how much money Amanda had to start.
The equation which models the problem is m - $23.94 = $12.75 and the value of m is $36.69.
What is an Equation?A mathematical statement containing two algebraic expressions on two sides of an equal to sign is defined as an equation.
Given,
Cost of a reusable water bottle that Amanda bought = $23.94
Money remaining after buying the bottle = $12.75
Let m represent how much money Amanda had to start.
Then the equation can be written as,
m - $23.94 = $12.75
We have to solve the equation.
Adding $23.94 on both sides,
m = $12.75 + $23.94
m = $36.69
Hence the money at the start is $36.69.
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these are 3 different questions but the 3rd one is asking which function for question 1 and 2 has a greater rate .
Answer: Function A is greater.
Step-by-step explanation:
just find the slope...
Slope for Function C = [tex]\frac{1}{3}[/tex] = [tex]0.33333[/tex] repeat...
and for Function A = [tex]\frac{5}{2}[/tex] = [tex]2.5[/tex]
to find the slope we use; [tex]s=[/tex] [tex]\frac{y}{x}[/tex].
A car drove at 65 miles per hour 7 hours. How many miles are left if the entire trip is 540 miles ?
Answer: 85 miles left
Step-by-step explanation:
65 miles x 7 hours = 455 miles
540 miles - 455 miles = 85 miles
If f(x)=x²-1, and
g(x) = x + 2, then
f(g(x)) = [? ]x² +[ ]x+[ ]
Enter
Answer:
Step-by-step explanation:
g(f(x)) = x2 -1 + 2 = x2 + 1
In a running competition, a bronze, silver and gold medal must be given to the top three girls and top three boys. If 4 boys and 14 girls are competing, how many different ways could the six medals possibly be given out?
Answer:
there are 1456 different ways that the six medals can possibly be given out.
Step-by-step explanation:
There are different ways to approach this problem, but one common method is to use combinations.
First, we need to determine how many ways we can choose three girls out of 14, and three boys out of 4. This can be calculated using combinations:
Number of ways to choose 3 girls out of 14: C(14,3) = 364
Number of ways to choose 3 boys out of 4: C(4,3) = 4
Now, we can use the multiplication principle to determine the total number of ways to give out the six medals:
Total number of ways = number of ways to choose 3 girls * number of ways to choose 3 boys = 364 * 4 = 1456
Therefore, there are 1456 different ways that the six medals can possibly be given out.
Please help me and explain how to do this
The scale factor of figure A to figure B is 5/3.
What is Triangle?A triangle is a three-sided polygon that consists of three edges and three vertices.
Two triangles are said to be similar if their corresponding angles are congruent and the corresponding sides are in proportion .
A and B are similar triangles.
We need to find the scale factor.
The ratio between the scale of a given original object and a new object
Scale factor is 15/9=35/21=40/24
5/3=5/3=5/3
Hence, 5/3 is the scale factor of figure A to figure B.
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a learning experiment requires a rat to run a maze (a network of pathways) until it locates one of three possible exits. exit 1 presents a reward of food, but exits 2 and 3 do not. (if the rat eventually selects exit 1 almost every time, learning may have taken place.) let yi denote the number of times exit i is chosen in successive runnings. for the following, assume that the rat chooses an exit at random on each run. (a) find the probability that n
The probability that when n=6, [tex]Y_{1}[/tex] =3, [tex]Y_{2}[/tex]=1, [tex]Y_{2}[/tex]=2 is 0.0822.
We have to find the probability that n=6, [tex]Y_{1}[/tex] =3, [tex]Y_{2}[/tex]=1, [tex]Y_{2}[/tex]=2
A rat has three possible exits to come out from the maze
The pmf of multinomial distribution is
P[tex](y_{1}, y_{2}, y_{3}......, y_{k} ) = \frac{n!}{{y_{1!} }y_{2}!....y_{k}! } p^y_1 1p^y_2 2......p^y_k k[/tex]
The probability of choosing one of the ways is 1/3
Then [tex]p_{1}[/tex]= 1 / 3,[tex]q_{1}[/tex] = 1-(1/3) = 2/3
[tex]p_{2} = 1/3, q_{2} = 2/3\\ p_{3} = 1/3, q_{3} = 2/3[/tex]
[tex]P(y_{1}, y_{2}, y_{3} ) = P(1,2,3)\\ = \frac{6!}{3! 2! 1!} (\frac{1}{3} )3(\frac{1}{3} )2(\frac{1}{3} )1[/tex]
=60(0.00137)
=0.0822
Hence, the probability that when n=6, [tex]Y_{1}[/tex] =3, [tex]Y_{2}[/tex]=1, [tex]Y_{2}[/tex]=2 is 0.0822.
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The correct question is:
A learning experiment requires a rat to run a maze (a network of pathways) until it locates one of three possible exits. Exit 1 presents a reward of food, but exits 2 and 3 do not. (If the rat eventually selects exit 1 almost every time, learning may have taken place.) Let [tex]Y_{i}[/tex] denote the number of times exit i is chosen in successive runnings. For the following, assume that the rat chooses an exit at random on each run.
a Find the probability that n = 6 runs result in [tex]Y_{1} = 3, Y_{2} = 1, and Y_{3} = 2.[/tex]
The average income, I, in dollars, of a lawyer with an age of x years is modeled with the following function:
I=-425x^(2) + 45,500x-650,000
What is the youngest age for which the average income of a lawyer is $275,000
The youngest age for which the average income of a lawyer is $275,000 is 27.91 year.
Quadratic Equation helps solve quadratic equations. First, put the equation into the form ax²+bx+c=0. where a, b, and c are the coefficients. Then plug these coefficients into the equation.
(-b±√(b²-4ac))/(2a) . See examples of solving various equations using formulas
The average annual income, I, in dollars, of a lawyer with an age of x years is modeled with with the following function:
I = - 425x² + 45500x - 650000 .......... (1)
If the average annual income of the lawyer at the age of x years is $275000, then from the equation (1) we can write
- 425x² + 45500x - 650000 = 250000
I=-425x^(2) + 45,500x-650,000
275000 = -425x^(2) + 45,500x-650,000
-425x^(2) + 45,500x -650000-275000=0
425x^(2) -45,500x +925000=0
x = 900/17 ± 10√(1810)/17
= 77.96 and 27.91
here we are not accepting the ans 77.96 because we have already less value which is 27.91 so final ans will be 27.91
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2 2/13 of 52 is _____
how to solve this...
The measure of the angle that defines the orange arc is 144°.
How to find the measure of the angle?We know that if we have a circle of radius R, and there is an arc defined by an angle θ, then the area of that arc is given by:
A = (θ/360°)*pi*R^2
Where pi = 3.14
Here we know that the diameter is 10 miles, then the radius is:
R = 10mi/2 = 5mi
We can see that the shaded area is a = 10*pi mi²
Then we can write the equation:
(θ/360°)*pi*(5mi)^2 = 10*pi mi²
We can divide both sides by pi to get:
(θ/360°)*(5mi)^2 = 10 mi²
We can solve this for θ.
(θ/360°)*(5mi)^2 = 10 mi²
(θ/360°)25 mi² = 10 mi²
(θ/360°) = (10/25)
θ = (10/25)*360° = 144°
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A stemplot titled speed limit. The values are 10, 45, 45, 45, 45, 50, 50, 55, 55, 55, 55, 55, 60, 60, 60, 65, 65, 65, 65, 65, 65, 70, 70. The stemplot shows the speed limit on different signs. Which statement is true about the data shown in the stemplot?
The statement that is true about the data shown in the stemplot is that the most common speed limit is 55.
What is stemplot ?
A stemplot, also known as a stem-and-leaf plot, is a type of chart used to display data. It shows the distribution of a set of values by separating each value into a stem and a leaf.
Given by the question:
Based on the values given, the stemplot titled "speed limit" could be constructed as follows:
1 | 0
4 | 5 5 5 5
5 | 0 5 5 5 5 5
6 | 0 0 0 5 5 5 5
7 | 0 0
The stem represents the tens digit of each value, and the leaves represent the ones digit. For example, the first value of 10 has a stem of 1 and a leaf of 0.
Based on the stemplot, we can make the following observations:
The speed limits range from 10 to 70.There are no speed limits between 11 and 44.The most common speed limit is 55, which appears 5 times.There are four speed limits of 45 and two speed limits of 50 and 60.There are a total of 23 speed limits.Therefore, the statement that is true about the data shown in the stemplot is that the most common speed limit is 55.
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Find the effective rate corresponding to the following nominal rate.5% compounded continuously.
The effective rate for a nominal rate of 5% compounded continuously over a time period of 1 year is 5.13%.
To find the effective rate corresponding to a nominal rate compounded continuously, we use the formula:
r_effective = [tex]e^{(r\_nominal * t)} - 1[/tex]
where r_nominal is the nominal rate, and t is the time period.
For a nominal rate of 5% compounded continuously, the effective rate can be calculated as follows:
r_effective = [tex]e^{(0.05*t)}-1[/tex]
Note that the time period t is usually expressed in years. For example, if we want to find the effective rate for a time period of 1 year, we have:
r_effective = [tex]e^{(0.05*t)}-1[/tex]
= 1.051296 - 1
= 0.051296 or 5.13%
So, the effective rate for a nominal rate of 5% compounded continuously over a time period of 1 year is 5.13%.
It's important to understand the difference between nominal and effective rates. The nominal rate is the rate that is advertised or quoted, while the effective rate takes into account the frequency of compounding. The effective rate is a more accurate representation of the true interest rate because it shows the actual amount of interest earned over a given time period.
Continuous compounding means that interest is calculated and added to the principal continuously, rather than at regular intervals. This results in a higher effective rate compared to the same nominal rate compounded at regular intervals.
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Determine whether each statement is always, sometimes, or never true.
a. The difference of a binomial and a binomial is a binomial.
Answer Choices:
Always
Sometimes
Never
Question 2
b. When a 6th-degree polynomial with 5 terms is written in standard form, the second term has a degree of 5.
Answer Choices:
Always
Sometimes
Never
Question 3
c. The sum of a 4th-degree polynomial and a 2nd-degree polynomial is a 2nd-degree polynomial.
Answer Choices:
-Always
-Sometimes
-Never
Answer:
a. Never
b. Never
c. Sometimes
Step-by-step explanation:
a. The difference of a binomial and a binomial is never a binomial, as the result will always be another type of expression.
b. When a 6th-degree polynomial with 5 terms is written in standard form, the second term will always have a degree that is less than the 6th degree, since there are only 5 terms and the degree of each term decreases as its position increases.
c. The sum of a 4th-degree polynomial and a 2nd-degree polynomial is sometimes a 2nd-degree polynomial, depending on the coefficients of the terms. It is possible for the degree of the sum to be lower than the degree of both individual polynomials if the coefficients of the higher degree terms cancel out.
The difference of a binomial and a binomial always yields a binomial. A 6th-degree polynomial with 5 terms in standard form always has a degree of 5 for the second term. The sum of a 4th-degree polynomial and a 2nd-degree polynomial never results in a 2nd-degree polynomial.
Explanation:1. For the operation a. The difference of a binomial and a binomial is a binomial.
Answer: Always
Reason: This is true because when you subtract a binomial from another, the result is always a binomial as well. For instance, (x+y)-(x-y) would result in 2y, a binomial.
2. For the operation b. When a 6th-degree polynomial with 5 terms is written in standard form, the second term has a degree of 5.
Answer: Always
Reason: This is always the case because in ordered or standard form, the terms decrease by degree in sequence
3. For the operation c. The sum of a 4th-degree polynomial and a 2nd-degree polynomial is a 2nd-degree polynomial.
Answer: Never
Reason: The highest degree of the sum of two polynomials is the higher degree of the individual polynomials, in this case, it would be a 4th degree polynomial.
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In ΔUVW, w = 7.2 cm, v = 6.2 cm and ∠V=8°.
Find all possible values of ∠W, to the nearest
10th of a degree.
We can use the Law of Sines to find the measure of angle W:
sin(W)/w = sin(V)/v
sin(W) = w*sin(V)/v
sin(W) = 7.2*sin(8°)/6.2
sin(W) ≈ 0.1001
Taking the inverse sine of both sides, we get:
W ≈ 5.78° or W ≈ 174.22°
Since W is an angle in a triangle, it must be between 0° and 180°. Therefore, the only possible value for ∠W is:
W ≈ 5.78° (to the nearest tenth of a degree).
Find an estimate of the total distance traveled in the first 6 hours of travel for a particle whose velocity is given by
v(t)=−t^2 +4t+6
where v is in MPH and t is in hours.
Estimate of the total distance traveled in the first 6 hours of travel for a particle v(t)=−t^2 +4t+6 is 36m.
We have v(t)=−t² +4t+6
For finding the distance we have to find the integration of the given equation:
s = ∫ -t² +4t+6
= -t³/3 + 4t²/2 + 6t
= -t³/3 + 2t²/ + 6t
For the value of t = 6 hours
= -6³/3 + 2(6)² + 6(6)
= -72 + 72 + 36
= 36
Estimate of the total distance traveled in the first 6 hours is 36 m.
When a moving object has a positive velocity, its position is constantly rising. (We focus on the case when velocity is always positive; we will soon explore cases where velocity is negative.) We have shown that the area under the velocity curve represents the precise distance travelled whenever is constant on an interval. Finding the areas of rectangles that closely resemble the area under the velocity curve allows us to calculate the total distance travelled when is not constant.
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Greg's age is 6 less than 5 times Rachel's age. In four years the sum of their ages will be 20. How old is each person now?
Answer:
Rachels age = 3 years
Greg's age = 9 years
Step-by-step explanation:
Framing algebraic equations and solving:Present age:
Let Rachels age = x years
5 time of Rachel's age = 5*x = 5x
6 less than 5x = 5x - 6
Greg's age = (5x - 6) years
Age after four years:
Rachel's age = (x + 4) years
Greg's age = 5x - 6 + 4
= ( 5x - 2) years
Sum of their ages = 20
x + 4 + 5x - 2 = 20
x + 5x + 4 - 2 = 20
Combine like terms,
6x + 2 = 20
Subtract 2 from both sides,
6x = 20 - 2
6x = 18
Divide both sides by 6,
x = 18 ÷ 6
x = 3
Rachel's age = 3 years
Greg's age = 5*3 - 6
= 15 - 6
= 9 years
Under her cell phone plan, Paisley pays a flat cost of $60 per month and $3 per gigabyte. She wants to keep her bill under $75 per month. Write and solve an inequality which can be used to determine g g, the number of gigabytes Paisley can use while staying within her budget.
Answer:
Step-by-step explanation:
The inequality to determine the number of gigabytes Paisley can use while staying within her budget can be written as:
60 + 3g < 75
Solving for g:
60 + 3g < 75
-60 -60
0 + 3g < 15
/3 /3
g < 5
So Paisley can use up to 5 gigabytes while staying within her budget.
Harper is going to create a graph of the
equation y = -0.5x + 12. Which of the following
will be true about the graph
The graph of the equation y = -0.5x + 12 will be a straight line
How to determine the true statement about the graphThe equation y = -0.5x + 12 represents a linear function
The slope of the line is -0.5The y-intercept (the value of y when x = 0) is 12Based on the slope -0.5 this means that as the value of x increases, the value of y will decrease.
Additionally, since the y-intercept is 12, the line will cross the y-axis at the point (0, 12).
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In a small town, there are two discount stores ABC and XYZ. They are the only
stores that handle the festival goods. The total number of customers is equally divided
between the two because the price and quality of goods sold are equal. Both stores
have good reputations in the community, and they render equally good customer
services. Assume that a gain of customer by ABC is a loss to XYZ and vice versa.
Both stores plan to run annual pre-Christmas sale during the first week of December.
Sales are advertised through the local newspaper, radio and television media. With the
aid of advertising the payoff for ABC store is constructed and given below.
XYZ store
News paper
radio
Television
News paper
30
40
-80
ABC radio
0
15
-20
Television
90
20
50
Find optimal strategies for both stores and the value of the game.
The value of the game is equal to -20 and is the least loss for ABC (which is the maximum gain for XYZ).
How did we come to our conclusion?The Minimax theorem, which states that in a two-person zero-sum game, each player minimizes the maximum loss conceivable, can be used to determine the best course of action for both stores.
ABC retailer:
If XYZ decides to use newspaper advertising, ABC could see a maximum loss of -80.
If XYZ chooses radio advertising, ABC might lose as much as -20.
If XYZ chooses television advertising, ABC will ultimately lose 50.
As a result, selecting the advertising medium that results in the lowest possible loss, which is radio advertising with a loss of -20.
XYZ retailer:
If ABC chooses newspaper advertising, XYZ might earn up to 40.
If ABC chooses radio advertising, XYZ might earn a maximum of 15.
If ABC chooses television advertising, XYZ might earn up to $20.
Therefore, by selecting the advertising medium that offers the highest possible gain, which is newspaper advertising with a gain of 40, XYZ optimizes the greatest gain.
Therefore, the value of the game is equal to -20 and is the least loss for ABC (which is the maximum gain for XYZ).
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Correct question:
In a small town, there are two discount stores ABC and XYZ. They are the only
stores that handle the festival goods. The total number of customers is equally divided
between the two because the price and quality of goods sold are equal. Both stores
have good reputations in the community, and they render equally good customer
services. Assume that a gain of customer by ABC is a loss to XYZ and vice versa.
Both stores plan to run annual pre-Christmas sale during the first week of December.
Sales are advertised through the local newspaper, radio and television media. With the
aid of advertising the payoff for ABC store is constructed and given below.
XYZ store
News paper radio Television
News paper 30 40 -80
ABC radio 0 15 -20
Television 90 20 50
Find optimal strategies for both stores and the value of the game.
On average, ABC can expect to earn 15 more customers than XYZ during the pre-Christmas sale.
What do you mean by graph?In mathematics and computer science, a graph is a collection of points (called vertices or nodes) that are connected by lines or curves (called edges). Graphs can be used to represent many different types of relationships or structures, including social networks, transportation networks, electrical circuits, and mathematical functions.
A graph is usually represented visually as a set of points on a plane or in space, with lines or curves connecting them. The points can represent any type of object or entity, such as cities, people, or data points, while the edges represent the connections or relationships between them. Edges can be directed (with arrows indicating a one-way relationship) or undirected (with no preferred direction).
To find the optimal strategies for both stores and the value of the game, we can use the graphical method of solving 2-player zero-sum games.
First, we can create a payoff matrix using the given information:
markdown
Copy code
| Newspaper | Radio | Television |
--------------------------------------------
ABC | 30 | 15 | 20 |
XYZ | 40 | -15 | 50 |
Note that the payoff for XYZ in the radio column is negative, indicating a loss.
Next, we can plot the payoffs on a graph, with ABC's strategies on the x-axis and XYZ's strategies on the y-axis. We can also draw a line at the minimum value of each column (the "minimax" line) and a line at the maximum value of each row (the "maximin" line).
The graph should look like this:
lua
Copy code
-15 15 20
|-------|--------|
30 | 30 | 15 |
| | |
|-------|--------|
50 | 40 | -15 |
| | |
|-------|--------|
40 50
To find the optimal strategies, we need to find the intersection of the minimax and maximin lines. In this case, the intersection is at the point (Radio, Television) = (15, 50), so the optimal strategies are for ABC to advertise on the radio and XYZ to advertise on television.
The value of the game is the payoff at the intersection of the minimax and maximin lines, which is 15. This means that on average, ABC can expect to earn 15 more customers than XYZ during the pre-Christmas sale.
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Tracked Emails. According to a 2017 Wired magazine article, 40% of emails that are received are tracked using software that can tell the email sender when, where, and on what type of device the email was opened (Wired magazine website). Suppose we randomly select 50 received emails. a. What is the expected number of these emails that are tracked? b. What are the variance and standard deviation for the number of these emails that are tracked? 11. Mailing Machine Malfunctions. A technician services mailing machines at companies in the Phoenix area. Depending on the type of malfunction, the service call can take 1, 2, 3, or 4 hours. The different types of malfunctions occur at about the same frequency. a. Develop a probability distribution for the duration of a service call. b. Draw a graph of the probability distribution. c. Show that your probability distribution satisfies the conditions required for a discrete probability function. d. What is the probability a service call will take three hours? e. A service call has just come in, but the type of malfunction is unknown. It is 3:00 P.M. and service technicians usually get off at 5:00 P.M. What is the probability the service technician will have to work overtime to fix the machine today?
Using standard deviation, the probability that the service technician will have to work overtime to fix the machine today is 0.5.
What does standard deviation mean?The degree of variance or dispersion in a set of data values is measured by standard deviation. It gauges how far the data values depart from the data set's mean (average).
The mean of the data set is first determined, then the standard deviation. The difference between each data point and the mean is then squared for each data point. After dividing the total number of data points by the sum of these squared differences, minus one, the standard deviation is calculated by taking the square root of this result.
a. The expected number of emails that are tracked can be found by multiplying the total number of emails by the probability that an email is tracked:
Expected number of tracked emails = 50 x 0.4 = 20
Therefore, we can expect that 20 out of 50 received emails will be tracked.
b. To find the variance and standard deviation for the number of tracked emails, we can use the formula:
Variance = np(1-p)
Standard deviation = sqrt(np(1-p))
where n is the number of trials (in this case, 50) and p is the probability of success (0.4).
Variance = 50 x 0.4 x (1 - 0.4) = 12
Standard deviation = sqrt(50 x 0.4 x (1 - 0.4)) ≈ 3.46
Therefore, the variance for the number of tracked emails is 12 and the standard deviation is approximately 3.46.
c. The probability distribution for the duration of a service call is:
Duration (hours) Probability
1 0.25
2 0.25
3 0.25
4 0.25
d. The probability that a service call will take three hours is 0.25, as shown in the probability distribution table.
e. To find the probability that the service technician will have to work overtime, we need to calculate the probability that a service call will take longer than two hours, since the technicians usually get off at 5:00 P.M. and it is currently 3:00 P.M.
The probability that a service call will take longer than two hours is:
P(call takes 3 hours or 4 hours) = P(call takes 3 hours) + P(call takes 4 hours) = 0.25 + 0.25 = 0.5
Therefore, the probability that the service technician will have to work overtime to fix the machine today is 0.5.
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The median a data set with nine data values is 36. A tenth value was added to the set, and the median is still 36. If the new value is greater than 36, why did the median not change?
The median did not change because the 5th and 6th term of data is same.
What are mean and median?The mean is the average value which can be calculated by dividing the sum of observations by the number of observations
Mean = Sum of observations/the number of observations
Median represents the middle value of the given data when arranged in a particular order.
Given that;
The median of data set with nine numbers= 36
After the addition of tenth value median= 36
Now,
Median is the middle term of data
Here, the middle value and 6th term must be same.
So, 5th term= 6th term= 36
Therefore, the median of the given data set is same.
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If [tex]f(x)=\frac{5x^{4}}{1-x}[/tex] then [tex]f^{4} (x)[/tex]
Note: There is a way of doing this problem without using the quotient rule 4 times.
Answer:
To find the fourth derivative of f(x), we can use the fact that f(x) can be expressed as:
f(x) = 5x^4 (1 - x)^-1
Then, using the product rule repeatedly, we can find the derivatives of f(x) up to the fourth order:
f'(x) = 20x^3 (1 - x)^-1 - 5x^4 (1 - x)^-2
f''(x) = 60x^2 (1 - x)^-1 + 40x^3 (1 - x)^-2 + 10x^4 (1 - x)^-3
f'''(x) = 120x (1 - x)^-1 + 180x^2 (1 - x)^-2 + 120x^3 (1 - x)^-3 + 20x^4 (1 - x)^-4
f^4(x) = 120 (1 - x)^-1 + 720x (1 - x)^-2 + 1080x^2 (1 - x)^-3 + 480x^3 (1 - x)^-4 + 60x^4 (1 - x)^-5
So, we have found the fourth derivative of f(x) without using the quotient rule four times.
The fourth derivative of the function f(x) = 5x⁴/(1 - x)⁻¹ is,
f''''(x) = 120/(1 - x)⁻¹ + 720x/(1 - x)⁻² + 1080x²/(1 - x)⁻³ + 480x³/(1 - x)⁻⁴
+ 60x⁴/(1 - x)⁻⁵.
What is differentiation?A technique for determining a function's derivative is differentiation. Mathematicians use a procedure called differentiation to determine a function's instantaneous rate of change based on one of its variables.
We have to find the fourth derivative of f(x), f(x) = 5x⁴/(1 - x)⁻¹
The derivatives of f(x) up to the fourth order can then be discovered by continually applying the product rule,
f'(x) = 20x³/(1 - x)⁻¹ - 5x⁴/(1 - x)⁻²
f''(x) = 60x²/(1 - x)⁻¹ + 40x³/(1 - x)⁻² + 10x⁴/(1 - x)⁻³
f'''(x) = 120x/(1 - x)⁻¹ + 180x²/(1 - x)⁻² + 120x³/(1 - x)⁻³ + 20x⁴/(1 - x)⁻⁴
f''''(x) = 120/(1 - x)⁻¹ + 720x/(1 - x)⁻² + 1080x²/(1 - x)⁻³ + 480x³/(1 - x)⁻⁴ +
60x⁴/(1 - x)⁻⁵.
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a battleship simultaneously fires two shells toward two identical enemy ships. one shell hits ship a, which is close by, and the other hits ship b, which is farther away. the two shells are fired at the same speed. assume that air resistance is negligible and that the magnitude of the acceleration due to gravity is g .
The magnitude of the acceleration due to gravity would decrease with increasing height.
If the two shells were fired simultaneously with the same speed, their initial velocity would be the same. However, the shell that hits ship A, which is closer, would take less time to reach its target compared to the shell that hits ship B.
Since the magnitude of the acceleration due to gravity is constant, the vertical motion of the shells would be described by the following equation:
h = vi * t + (1/2) * g * [tex]t^2[/tex]
where h is the height of the shell, vi is the initial velocity, t is the time, and g is the acceleration due to gravity.
The horizontal motion of the shells would be described by the following equation:
d = vi * t
where d is the horizontal distance travelled by the shell.
By solving the above equations, we can determine the time taken by each shell to reach its target and therefore, the time difference between the two shells.
Note that this analysis assumes that air resistance is negligible and that the magnitude of the acceleration due to gravity is constant. In reality, air resistance would play a role in the motion of the shells, and the magnitude of the acceleration due to gravity would decrease with increasing height.
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Ech of
avior?
now
u
4. A class plants a tree.
Sketch the graph of the
height of the tree
over time.
Year 0 3 feet
Year 3 7 feet
a. Identify the two variables.
b. How can you describe the relationship
between the two variables?
The relationship between the two variables is y=4/3 x+3.
What is the equation of a line?The general equation of a straight line is y=mx+c, where m is the gradient, and y = c is the value where the line cuts the y-axis. This number c is called the intercept on the y-axis.
The coordinate points are (0, 3) and (3, 7)
Here, slope (m) = (7-3)/(3-0)
= 4/3
Substitute m=4/3 and (x, y)=(0, 3) in y=mx+c, we get
3=4/3(0)+c
c=3
So, the equation is y=4/3 x+3
Therefore, the relationship between the two variables is y=4/3 x+3.
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Complete the proof.
Statements
AB= 3, BC = 5, and CA = 3.5
LM=6.3, MN = 9, and NL = 5.4
NL 5.4
AB
MN
5.4
3
=
9
||
5
BC
LM 6.3
CA
3.5
9
Octo
=
= 1.8
= 1.8
5
6.3
3.5
N = MN = LM
AABC →ALNM
ZB ZN
= 1.8
Reasons
given
substitution property of equality
simplify
Corresponding angles of similar triangles are congruent.
The proof is completed as follows
Statement Reason
NL/AB = MN/BC = LM/CA ratios of side of similar triangles are equal
Δ ABC is similar to Δ LNM Definition of similar triangles
What are similar triangles?
Similar triangles are triangles that have the same shape but may differ in size. That is to say, they have the same angles but their sides may be scaled differently.
When two triangles are similar, their corresponding angles are congruent and the corresponding sides are in proportion to each other.
This means that if you know the lengths of any two sides of a similar triangle, you can use those ratios to find the lengths of the other sides.
In the proof, the equation NL/AB = MN/BC = LM/CA means that proportions are equal
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what is the least common denominator for these two fractions
Answer:
Least common denominator is 3.
Step-by-step explanation:
2/3 = 2/3 x 1/1 = 2/3
1/3 = 1/3 x 1/1 = 1/3
HELP NOW PLS!! 100 PTS!!!! BRAINLIEST ANSWER!!!!!!
Answer: 10
Step-by-step explanation: beacause you add both of the sides
LOTS OF POINTS IF U ANSWER RIGHT!!
Graph g(2) = 4 cos (2x) - 2.
Use 3.14 for pi.
Use the sine tool to graph the function. The first point must be on the midline and the second point must be a maximum or minimum value on the graph closest to the first point.
1. Find the 15th term in the sequence if a1= 3 and d= 4
2. Find Sn for the arithmetic series where a1= 5, an= 119, n= 20
3. Find Sn for the arithmetic series where a1= 12, d= 6, n= 15
4. Find the 6th term in the geometric sequence where a1= 2, a6= 64, r= 2
5. Find Sn for the geometric series where a1= 2 , r= 4, n= 6
an = 3 + (15 - 1) * 4 = 3 + 14 * 4
= 3 + 56
= 59
So, the 15th term in the sequence is 59.
2. To find the sum of an arithmetic series with first term a1, last term an, and number of terms n, we use the formula: Sn = n/2 * (a1 + an). Plugging in the values, we get:
Sn = 20/2 * (5 + 119)
= 20/2 * 124
= 620
So, the sum of the series is 620.
3. To find the sum of an arithmetic series with first term a1, common difference d, and number of terms n, we use the formula: Sn = n/2 * (2a1 + (n - 1)d). Plugging in the values, we get:
Sn = 15/2 * (2 * 12 + (15 - 1) * 6) = 15/2 * (24 + 84)
= 15/2 * 108
= 810
So, the sum of the series is 810.
4.To find the nth term in a geometric sequence with first term a1, common ratio r, and nth term an, we use the formula: an = a1 * r⁽ⁿ⁻¹⁾. Plugging in the values, we get:
64 = 2 * r⁽⁶⁻¹⁾
64 = 2 * r⁵
32 = r⁵
r = [tex]2^{(5^{(1/5)} )}[/tex]
So, the 6th term in the sequence is 64.
5. To find the sum of a finite geometric series with first term a1, common ratio r, and number of terms n, we use the formula: Sn = a1 * (1 - rⁿ) / (1 - r). Plugging in the values, we get:
Sn = 2 * (1 - 4⁶) / (1 - 4)
= 2 * (1 - 4096) / -3
= 2 * (-4095) / -3
= 2730
So, the sum of the series is 2730.
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