Answer:
In conduction, faster-moving molecules contact slower-moving molecules and transfer energy to them. During conduction the slower-moving molecules speed up and the faster-moving molecules slow down.
Explanation:
Question 17 of 20
The reactants of a chemical equation have 1 Satom and 40 atoms. Which
set of atoms must also be found in the equation's products so that the
equation models the law of conservation of mass?
A. 4 S and 40
B. 1 S and 40
C. 1 S and 10
O D. 4 S and 10
Answer:
B) 1S and 40
hope it helps
Answer:
b is ur answer
Explanation:
1S and 4O
A 20.0 L container at 303 K holds a mixture of two gases with a total pressure of 5.00 atm. If there are 2.00 mol of Gas A in the mixture, how many moles of Gas B are present?
The number of moles of Gas B in the gas mixture is equal to 2.00 mol.
What is the ideal gas equation?The ideal gas equation can be explained as an equation that describes the state of an ideal gas. This equation gives the product of the volume and pressure of ideal gas equal to the multiplication of the universal gas constant, absolute temperature, and moles of gas.
The mathematical form of the ideal gas equation mentioned below:
PV = nRT
Where P is the pressure, V is the volume, n is the moles, and R is the gas constant.
Given, the volume of the gas mixture, V = 500 ml = 0.5 L
The temperature of the gas mixture, T = 303 K
The pressure of the gas mixture = 5 atm
The value of gas constant, R =0.082 atmL/K mol
Substituting the values R, V, P, and T in the ideal gas law, we get:
The number of moles of the gas mixture, n = PV/RT
n = 5 ×20/(0.082 × 303)
n = 4.00 mol
The total number of moles of gas mixture = 4.00 mol
The moles of Gas A = 2.00 mol
The moles of Gas B = 4 - 2 = 2.00 mol
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Help please it is due soon
Answer:
it's the amount of energy released by an earthquake
What tides are at the points on Earth indicated by the letters?
A. high tide (A,C)
B. high tide (B,D)
C. Low tide (B,C)
D. Low tide (A,C)
Answer:
it is A tide (A,C)
Explanation:
i just took the test and tried c and it was a plzzzzz put a btw it was my test lol
Please help me as soon as possible!!! How many grams of H3PO4 are in a 4 L sample of a 17 M solution?
Answer:
about 6664 grams of hydro phosphoric acid are in a sample of 4 L of 17 M solution
Explanation:
grams of H3PO4 = 4 L | 17 mol | 98 grams H3PO4
| 1 L | 1 mol
1,3,5,7-Cyclooctatetraene, C8H8, is an unusual hydrocarbon in that it reacts with exactly 2 equivalents of potassium to give A, C8H8K2, which can be isolated as a white solid. A exhibits a single proton NMR signal. Draw the structure of A
Answer:
Explanation:
The main assignment here is to provide the structure of A. But before that, let us explain briefly some certain things:
The proton NMR (1H) gives data about the quantity of non-identical protons present in the structure. The resonance frequency is seen regarding the standard compound (0 ppm), which is addressed as a chemical shift. The same protons have equal value of chemical shift.
The protons that are available in a similar environment are addressed as comparable protons and the protons with various conditions are called non-identical protons.
However, from the image below, we can see the reaction of the compound 1,3,5,7-cyclooctatetraene resulting in 2 equivalents of potassium forming an aromatic dianion.
How many grams of CaCl 2 are in .48 moles ?
Answer:
We assume you are converting between moles CaCl2 and gram. You can view more details on each measurement unit: molecular weight of CaCl2 or grams This compound is also known as Calcium Chloride. The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles CaCl2, or 110.984 grams.
The mass of calcium chloride is 53.27 grams.
Given:
Moles of CaCl₂ = 0.48 moles
Molar mass of CaCl₂ = 110.98 g/mol
To find:
Mass of CaCl₂ = ?
Number of moles:It is defined as given mass over molar mass.
Number of moles = Mass / Molar mass
Mass = Number of moles * Molar mass
Mass = 0.48 moles * 110.98 g/mol
Mass = 53.27 grams
Thus, the mass of calcium chloride is 53.27 grams.
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A sample of calcium fluoride was decomposed into the constituent elements. If the sample produced 294 mg of calcium, how many g of fluorine were formed?
Answer:
Approximately [tex]279\; \rm mg[/tex] of fluorine would be produced.
Explanation:
Look up the relative atomic mass of these calcium and fluorine on a modern periodic table:
[tex]\rm Ca[/tex]: [tex]40.078[/tex].[tex]\rm F[/tex]: [tex]18.998[/tex].In other words, the mass of each mole of calcium atoms is (approximately) [tex]40.078\; \rm g[/tex]. Similarly, the mass of each mole of fluorine atoms is (approximately) [tex]18.998\; \rm g[/tex].
Calculate the number of moles of calcium atom that were produced:
[tex]\begin{aligned} &n({\rm Ca}) \\ &= \frac{m({\rm Ca})}{M({\rm Ca})} \\ &= \frac{294\; \rm mg}{40.078\; \rm g \cdot mol^{-1}} \\ &= \frac{0.294\; \rm mg}{40.08 \; \rm g \cdot mol^{-1}}\\ & \approx 7.3357 \times 10^{-3}\; \rm mol\end{aligned}[/tex].
Every formula unit of calcium fluoride, [tex]\rm CaF_2[/tex], contains twice as many fluorine atoms as calcium atoms.
Hence, if the sample contained approximately [tex]7.33570 \times 10^{-3}\; \rm mol[/tex] calcium atoms, it would contain twice as many fluorine atoms:
[tex]\begin{aligned}n({\rm F}) &= 2\, n({\rm Ca}) \\ &\approx 2 \times 7.33570\times 10^{-3}\; \rm mol \\ &\approx 1.4671 \times 10^{-2}\; \rm mol\end{aligned}[/tex].
Calculate the mass of that many fluorine atoms:
[tex]\begin{aligned}& m({\rm F}) \\ &= n({\rm F}) \cdot M({\rm F}) \\ &\approx 1.4671 \times 10^{-2}\; \rm mol \times 18.998\; \rm g \cdot mol^{-1} \\ &\approx 278.72 \times 10^{-3}\; \rm g \\&\approx 279\; \rm mg\end{aligned}[/tex].
279 mg of Fluorine was formed in the decomposition reaction
The equation of the reaction is;
CaF2 -----> Ca + 2F
Mass of calcium formed = 294 mg
Number of moles of Ca in 294 mg = 294 × [tex]10^-3[/tex] g/40 g/mol = 0.00735 moles
From the equation, the products are in ration 1 : 2
Since 1 mole of Ca is to 2 moles of F
0.00735 moles of Ca is to 0.00735 moles × 2 moles/1 mole
= 0.0147 moles of F
Mass of F = 0.0147 moles × 19 g/mol
= 0.279g or 279 mg of F
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This timeline woulchre useful to someone who was writing a report titled
What happens to the pH when alkali is added to the distilled water?
Adding water to an acid or base will change its pH. ... The acid is becoming less acidic. Similarly, when an alkali is diluted with water the concentration of OH - ions decreases. This causes the pH of the alkali to fall towards 7, making the solution less alkaline as more water is added
Alkali is a chemical that is characterized by reacting with acids to produce salts. When alkali or base are added to the distilled water then pH increases.
What is pH?
The pH has been defined as the concentration of the hyronium or the hydrogen ions that releases when dissolved in water. The concentration of the hydroxide and the hydrogen are the determining factor of the acidic and basic nature.
The acids are characterized by the low pH (below 7) whereas, the basic compounds are characterized by the high pH (above 7). The pH scale is used to measure the pH of the solution.
When an alkali is added to the distilld water then hydroxide ions are relesed resulting in an increase in the basicity of the water sample. The pH range depends on the strong and weak base.
Therefore, the pH increases after ading alkaline solution.
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If 5.00 g of O2 gas has a volume of 7.20 L at a certain temperature and pressure, what volume does 15.0 g of O2 have under the same conditions?
The volume 15.0 g of O₂ has at a certain temperature and pressure is 2.16 L.
What is volume?Volume is the space occupied by a three-dimensional object.
By the law of dilution
M₁/V₁ = M₂/V₂
Mass 1 is 5.00
Volume 1 is 7.20 L
Mass 2 15.0 g
Volume 2 is to find
Putting the value in the equation
5.00/ 7.20 = 15.0 / V₂
V₂ = 7.20 × 15.00/ 5.00 = 21.6
Thus, the volume will be 21.6 L.
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Rank the following compounds in order of increasing solubility in water. Items (4 items) (Drag and drop into the appropriate area) No more items Items in order most soluble CaO BaO KCI KI
I have tried CaO> BaO > KCl > KI, this is incorrect.
Answer:
CaO < BaO < KCl <KI
Explanation:
Let us remember that the solubility of an ionic substance in water depends on the magnitude of the lattice energy and the hydration energy. If the hydration energy is equal to or is greater than the lattice energy, the substance dissolves in water.
However, the lattice energy depends on the size of the ions. The smaller the ions in the ionic compound, the higher the lattice energy and the lesser the solubility of the ionic compound.
KI has the least lattice energy and the highest solubility in water while CaO has the highest lattice energy and the least solubility in water.
The ratio of ducks to chickens in our backyard is 2:3. The total number of ducks and chickens together is 30. If mother gave away 3 chickens to our neighbor, what is the new ratio of ducks to chickens now?
Answer:
4:5
Explanation:
No. of chickens before giving away 3 chickens = 30 x 3/5 = 18
No. of ducks before giving away 3 chickens = 30 - 18 = 12
After giving away 3 chickens,
No. of chickens = 15
No. of ducks = 12
New ratio = 12:15 = 4:5
Convert 2.024 kilocalories to calories I need to know ASAP
Explanation:
kcal = 1000 cal
2.024 Kcal to cal
= 2.024 × 1000
= 2024 cal
#CMIIWBased on the graph, which statement about human use of natural resources is most likely false?
Hey love! <3
Answer:
C. Resource use by humans has gone up and down over the years is a false statement
Explanation:
In the graph you can make an observation on how the increase of human population is directly positive.
The resource use either has a positive or negative correlation, making it impossible for the usage to fluctuate over the years.
Hope this brightens up your day a little! ❀‿❀ Sincerely, Kelsey from Brainly.
~ #LearnWithBrainly ~
phenol used in DNA extractiom
Answer:
This is thought to aid in the extraction, as this dissolved phenol helps denature proteins while they are still in the aqueous solution. ... Phenol/Chloroform – This is a mixture of buffer-saturated phenol and chloroform, usually close to 1:1 for DNA purification with other ratios sometimes used for RNA purification
Explanation:
Hope it helps!
If you dont mind can you please mark me as brainlest?
Answer:
This is thought to aid in the extraction, as this dissolved phenol helps denature proteins while they are still in the aqueous solution. ... Phenol/Chloroform – This is a mixture of buffer-saturated phenol and chloroform, usually close to 1:1 for DNA purification with other ratios sometimes used for RNA purification
The diagrams below show the alignment of the Sun, the Moon, and Earth.
Answer:A
Explanation: I learned it from a gizmo
HELP FAST 75 PTS Calculate the amount of heat needed to melt 35.0 g of ice at 0 ºC. must show work
Answer:
It takes 12,000 Joules of energy to melt 35 grams of ice at 0 °C
Explanation:
Good Luck!
Which superpower would you have for the rest of your life?
The ability to fly
Teleportation
Super speed
Super strength
Invisibility
Time travel
Or be normal and have nothing special
time travel is the best option
Give the reason for the following; 1. Iodimetric titrations are usually performed in neutral or mildly alkaline (pH 8) to weakly acid solution. 2. Iodine solutions are prepared by dissolving I2 in a concentrated solution of potassium iodide. 3. Iodimetric determination of vitamin C is performed rapidly after preparing vitamin C solution
Answer:
Explanation:
blach bal
Chlorine and hydrogen gas react to form hydrogen chloride as shown in the following reaction Cl 2 ( g)+H 2 (g)--->2HCl (g) Given a 7.10 g sample of chlorine (MM =71.0 g/mol) , how many grams of hydrogen chloride (MM =36.5 g/mol) is produced, assuming the reaction goes to completion? a. 7.10 g 6.3.65 9 c. 5,68 g d 7.300
Answer:
it should be 7.300 sorry if I am wrong
Answer:
The answer is 115
Explanation:
Teacher walked me through it.
Predict the products of the electrolysis of molten nickel(II) iodide. Write an ionic half-equation for the formation of one of these products. products:
ionic half-equation:
Answer:
See explanation
Explanation:
The electrolysis of nickel(II) iodide yields nickel solid and iodine gas.
In the oxidation half equation;
2I^-(aq)-------> I2(g) + 2e
In the reduction half equation;
Ni^2+(aq) + 2e -----> Ni(s)
These are the half equations of the process;
The overall equation is;
Ni^2+(aq) + 2I^-(aq)-------> NiI2
Choose the best answer
1. Gas A diffuses twice as fast as another gas B. If the density of the gas A is 2, the molecular mass of
(a)2
(b) 4
(c) 8
(d) 16
i think it is
(b) 4
:) hope its correct :)
Practice: A gas reaction is allowed to take place in a canister while submerged in water at a temperature of 25oC. The gas expands and does P-V work on the surroundings equal to 385 J. At the same time, the temperature of the water decreases to 20oC as the energy in the gas reaction reaches 364 J. What is the change in energy of the system
Answer:
change in energy of the system = - 21 J
Explanation:
Δu = q + w
q = 364 J
w = - 385
Temperature of system drops from 25°c to 20°c
hence
Δu ( change in energy ) = q - w
= 364 - 385
= -21 J
Which of these 2A elements has the largest atomic radius?
A.beryllium
B.magnesium
C.calcium
D.barium
E.radium
Answer:
E. radium
E. radium
E. radium
Answer:
magnesium is the elwment which has the largest atomic number
In general, what is the effect of increased temperature on the solubility of a gas?
A. It is uniform
B.The solubility increases.
C. The solubility decreases
D.The saturation increases
E. The effect cannot be determined
Answer:
C. The solubility decreases.
Explanation:
Took the plato test!
g You are given a 1.25 gram mixture of calcium nitrate and calcium chloride. You dissolve this mixture in 200.0 mL of water and add an excess of 0.300 M silver nitrate. You collect and dry the white precipitate which forms and find it has a mass of 0.535 grams. Calculate the percent calcium chloride by mass in the original mixture.
Answer:
16.51%
Explanation:
The reaction that takes place is
CaCl₂(aq) + 2AgNO₃(aq) → 2AgCl(s) + Ca(NO₃)₂(aq)Meaning that the white precipitate that formed is AgCl. Now we convert 0.535 g of AgCl into moles, using its molar mass:
0.535 g ÷ 143.43 g/mol = 0.00373 mol AgClThen we convert 0.00373 moles of AgCl into moles of CaCl₂, using the stoichiometric coefficients:
0.00373 mol AgCl * [tex]\frac{1molCaCl_2}{2molAgCl}[/tex] = 0.00186 mol CaCl₂We convert moles of CaCl₂ into grams, using its molar mass:
0.00186 mol CaCl₂ * 110.98 g/mol = 0.206 gFinally we calculate the percent of CaCl₂ by mass in the original mixture:
0.206 g / 1.25 g * 100% = 16.51%The percent calcium chloride by mass in the original mixture is 16.4%
The equation of the reaction between calcium nitrate and silver chloride is:
[tex]\mathbf{CaCl_2 + 2AgNO_3 \to 2 AgCl+Ca(NO_3)_2}[/tex]
Given that;
the weight mass of the white precipitate formed is = 0.535 gramsthe number of moles of the precipitated AgCl is:
= 0.535 g / 143.32 g/mol
= 0.0037 moles
From the above reaction, If 2 moles of AgCl are formed by 1 mole of CaCl2
Then, 0.0037 moles of AgCl will form (0.0037 × 1)/2 moles of CaCl2.
0.0037 moles of AgCl will form 0.00185 moles of CaCl2.
Now, we can say that the number of moles of CaCl2 present in the mixture is = 0.00185 moles
Mass amount of CaCl2 present = 0.00185 moles × 110.98 g/mol
Mass amount of CaCl2 present = 0.205 grams
Finally, the mass percentage [tex]\mathbf{=\dfrac{0.205}{1.25}\times 100\%}[/tex]
= 16.4%
Therefore, we can conclude that the percent calcium chloride by mass in the original mixture is 16.4%
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What is the atomic mass of hafnium if, out of every 100 atoms, 5 have a mass of 176, 19 have a mass of 177, 27 have a mass of 178, 14 have a mass of 179, and 35 have a mass of 180.0? Answer with 2 decimals
Answer:
178.36 a.m.u
Explanation:
5 have a mass of 176,
5/100 * 176 = 8.8
19 have a mass of 177
19 / 100 * 176 = 33.44
27 have a mass of 178
27 / 100 * 178 = 48.06
14 have a mass of 179
14 / 100 * 179 = 25.06
35 have a mass of 180.0
35 / 100 * 180 = 63
Atomic Mass = 8.8 + 33.44 + 48.06 + 25.06 + 63
Atomic Mass = 178.36 a.m.u
what is the molecular formula of a compound with the empirical SO and molecular weight 96.13?
Answer:
Explanation: A compound with the empirical formula SO has a molecular weight of 96.13
Which is a saturated solution?
A）40g NH4Cl in 100g water at 50°C
B）2g SOz in 100g water at 10°C
C）52g KCl in 100g water at 80°C
D）120g KI in 100g water at 20°C
Answer:
C）52g KCl in 100g water at 80°C
Explanation:
A saturated solution is one that contains as much solute as it can dissolve in the presence of excess solute at that particular temperature.
A solutibility curve is a graph that shows the variability with temperature of the solubility of a solute in a given solvent. A solutibility curve can provide information of whether a solution formed frommthe solute and solvent are saturated or not at a given temperature.
From the solubility curve in the attachment below:
A) A saturated solution of NH₄Cl will contain about 52 g solute per 100 g sat 50 °C. Thus, a solution of 40 g NH₄Cl in 100 g water at 50 °C is an unsaturated solution.
B) A saturated solution of SO₂ at 10°C will contain about 70 g of solute in 100 g of water. Thus a solution of 2g SO₂ in 100g water at 10°C is an unsaturated solution.
C) A saturated solution of KCl at 80 °C will contain about 52 g of solute in 100 g of water. Thus, a solution of 52g KCl in 100g water at 80°C is a saturated solution.
D) A saturated solution of Kl at 20 °C will contain about 145 g of solute in 100 g of water. Thus, a solution of 120g KI in 100g water at 20°C is an unsaturated solution.