The rider will be in danger when the people below are removed, because they initially helped to maintain equilibrium.
A system subjected to different forces is said to be in equilibrium when all the forces applied to the system are equal.
For a system subject to two opposite forces, the following exists;
If the upward force and the downward forces are equal, the system will remain in equilibrium positionIf the upward or downward force is greater than the other, the system will move in the direction of the greater force.Thus, we can conclude that the rider will be in danger when the people below are removed, because they initially helped to maintain equilibrium. Once these people are removed, the rider tends to move at a greater speed and possibly fall from the initial position.
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Why is it important that we learn about our solar system, the sun, and planets in our solar system other than Earth?
Answer:
To understand all the different kind of elements and how they work. Nature is a beautiful thing and it is important we understand how they survive and how we can help. The solar system is a mandatory nature. Learning about other planets also helps us feel safe and more knowledgable.
According to Hebrews 11, what did Abraham believe God would do if Isaac was slain as a sacrifice?
Answer:
That he would be happy,for he had ordered him to be sacrificed
A garden hose shoots water horizontally from the top of a tall building toward the wall of a second building 20 meters away. If the speed with which the water leaves the hose is 5 m/sec, how long does it take the water to reach the second building, and what distance does the water fall in this time?
Answer:
Explanation:
If air resistance is ignored, the water travels for a time of
t = d/v = 20 m / 5 m/s = 4 s
falling from vertical rest, the water strikes the wall a distance below the hose
d = ½gt² = ½(10)4² = 80 m
Yeah, I think ignoring air resistance is wishful thinking considering the time and distances involved.
Someone please help with this question. From my knowledge the answer I believe to be correct is 4Em but I’m still not so sure. Please explain!
Answer choices:
1/2 Em
Em
2Em
4Em
Answer:
Explanation:
For an ideal spring over a frictionless horizontal surface, stored energy is only a function of the spring constant k and the distance of compression. The mass of the block doing the compressing is irrelevant
Energy stored in the first example is
Em = ½kd²
Energy stored in the second example is
E₂m = ½k(2d)² = 4(½kd²) = 4Em
So the second situation has four times as much stored spring potential energy as the first situation
4 Em is correct
Good job!
what forces would a person inside an elevator feel when it is going up?
Where is a divergent boundary most likely to be found?
Answer:
mid-ocean oceanic ridges
Explanation:
Answer:
mid-ocean oceanic ridges
Explanation:
Divergent boundaries are most likely to be found at mid-oceean oceanic ridges.
what is the speed of a boy moving around a circular park of radius 6m if he goes around the park in 20s
Answer:
1.884 meters per second
Explanation:
s = d/t
d = C = 2πr = 2π(6) = 37.68 m
t = 20 s
s = (37.68 m)/(20 s)
s = 1.884 m/s
The speed of the boy is 1.88 m/s while he is moving around a circular park of radius 6m and taking time 20 seconds.
What is speed?Speed can be defined as a measurement of how quickly the distance an object traveled changes with time. Speed is a scalar quantity as it has magnitude but no direction as a unit of measurement.
An object that moves quickly and with high speed, traveling a lot of ground in a lesser time.
Given, the radius of the circular park, r = 6m,
The time taken to cover one round of the park, t = 20 s
The total distance traveled by the boy is equal to the circumference of the circular park, so
Circumference of park, C = d = 2πr = 2× 3.14 × 6 =37.68 m
The speed of the boy, S = d/t
S = 37.68 /20
S = 1.88 m/s
Therefore, the speed of the boy is equal to 1.88 m/s.
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a rectangular block has the density of 350g/cm3 the dimensions are 3.5 6.cm 2.5
cm calculate the mass of the bock
Answer:
18375g
Explanation:
[tex]\boxed{density = \frac{mass}{volume} }[/tex]
[tex]∴ mass = density \times volume[/tex]
Let's find the volume of the rectangular block.
Volume
= length ×breadth ×height
= 3.5 ×6 ×2.5
= 52.5cm³
Mass of the block
= 350(52.5)
= 18375g
C. Answer the following questions.
1. Define Earthquake. Write any 3 precautions during earthquake
Answer:
1. An earthquake is a sudden violent shaking of the ground, typically causing great destruction, as a result of movements within the earth's crust or volcanic action. 2. (3 precautions during an earthquake are)... If you are indoors take cover under a desk, Stay away for glass doors, windows or outside doors and finally drop down or hold on to something until the shaking stops.
Hope that helped?
Explanation:
What is the unit of pressure
is it P=F/A?
Answer:
Units of pressure include: Pa, bar, at, atm, torr, lbf/in^2
Explanation:
P = F/A is a formula for pressure not a unit.
Pa = Pascal
Bar = Bar
at = Technical Atmosphere
Torr = Torr
lbf/in^2 = pounds per square inch
A train travels at 40m/s. Calculate the time it takes to travel:
A) 30,000 m
B) 50 km
Answer:
a is 750 second
b is 2 hour
The time it takes for the train to travel 30,000m and 50,000m is 750seconds and 1250 seconds, respectively.
What is speed?The speed is the distance covered by an object at a particular time. Therefore, it is the ratio of distance and time.
[tex]\rm{Speed = \dfrac{Distance}{Time}[/tex]
A train travels at 40m/s. Now, the time it takes to travel the given distance is,
A.) 30,000m
Speed = Distance / Time
Time = Distance / Speed
Time = 30,000m / 40m/s
Time = 750 seconds
B.) 50 km
1 km = 1000m
50 km = 50 × 1000m = 50,000 m
Speed = Distance / Time
Time = Distance / Speed
Time = 50,000m / 40m/s
Time = 1250 seconds
Hence, the time it takes for the train to travel 30,000m and 50,000m is 750seconds and 1250 seconds, respectively.
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What is force? And tell it's unit
Answer:
force is simply a push or a pull in a particular direction. The unit is N (newton)
Explanation:
hope this helped
Answer:
In physics force is an influence which changes the motion of an object which has mass
Its unit is N or kgms/2
Question: Self-test 3.12 Calculate the change in G for ice at -10°C, with density 917 kg mº, when the pressure is increased from 1.0 bar to 2.0 bar.
The change in the Gibb's free energy per mole (G) is 1.96 J.
The given parameters:
Density of the ice, ρ = 917 kg/m³Initial pressure, P₁ = 1.0 barFinal pressure, P₂ = 2.0 barTemperature, T = - 10 CMass of water = 18 gThe change in the Gibb's free energy per mole (G) is calculated as follows;
[tex]\Delta G = V(P_2-P_1) \\\\[/tex]
where;
V is the volume of the ice
[tex]Density = \frac{Mass}{Volume} \\\\Volume = \frac{Mass}{Density} \\\\Volume = \frac{18 \times 10^{-3} \ kg}{917 \ m^3} \\\\Volume = 1.96 \times 10^{-5} \ m^3\\\\Volume = 1.96 \times 10^{-5} \ m^3 \times \frac{1000 \ L}{m^3} \\\\Volume = 0.0196 \ L[/tex]
Change in pressure;
[tex]P_2 - P_1 = 2.0 \ bar \ - \ 1.0 \ bar = 1.0 \ bar = 0.987 \ atm[/tex]
The change in the Gibb's free energy per mole (G);
[tex]\Delta G= V(P_2-P_1)\\\\\Delta G = 0.0196\ L \times 0.987\ atm \\\\\Delta G = 0.0193 \ L.atm\\\\1 \ L.atm = 101.325 \ J\\\\\Delta G = 0.0193 \ L.atm \times \frac{101.325 \ J}{1 \ L.atm} \\\\\Delta G = 1.96 \ J[/tex]
Thus, the change in the Gibb's free energy per mole (G) is 1.96 J.
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Two satellites are in orbit around a planet. Satellite 1 has a mass of mm and an orbital radius of 2r2r. Satellite has a mass of 2m2m and an orbital radius of rr. If the magnitude of the gravitational force the planet exerts on Satellite 1 is FF, the magnitude of the gravitational force the planet exerts on Satellite 2 is
a) F
b) 1/2F
c) 2F
d) 1/4F
The magnitude of the gravitational force the planet exerts on Satellite 2 is 1/2F.
We recall that from Newton's law of universal gravitation, the gravitational force is given by;
F =G m1m2/r^2
m1 and m2 are the respective masses
r is the distance of separation.
Let the mass of the planet be M and the mass of the satellite be m. The distance of separation is r.
For satellite 1;
F = GmM/(2r)^2
F = GmM/4r^2
For satellite 2;
F2= G2mM/r^2
Hence, the magnitude of the gravitational force the planet exerts on Satellite 2 is 1/2F.
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Need quite a bit of help
When the cart was at Table
Normal reaction (N)=mgNow acceleration due to gravity acting on the gravity.
When the air comes out of straw it tries to take the cart upwards.But the force is equal to that of acceleration due to gravity but in opposite direction.Hence.
[tex]\\ \sf\Rrightarrow F_{net}=0N[/tex]
So the cart doesn't movethe book has a mass of 2.5 kg. What net force must act on the book to mak it accelerate to the left at a rate of 7.0m/s2?
Answer:
17.5 N
Explanation:
Given :Mass (m) = 2.5 kgAcceleration (a) = 7.0 m/s²To calculate :Force exerted (F)Calculation :• F = ma→ F = (2.5 × 7.0) N
→ F = 25/10 × 7 N
→ F = 5/2 × 7 N
→ F = (5 × 7)/2 N
→ F = 35/2 N
→ F = 17.5 N towards left
Hence, 17.5 N of net force must act on the book to make it accelerate to the left.
i need some help getting started on an essay for physics. i decided on the topic of roller costers and dont know how to start it. see the image on my requirements.
Explanation:
force , motion , electric current
3 materials that are denser than water and 3 that arent denser than water
Answer:
denser than water:
1. clay
2. coins
3. rock
aren't denser than water
1. wood
2. sponge
3. apple
The 0.01 kg marble is dropped from rest at A through the smooth glass tube and accumulate in the basket at C as shown in Figure Q2(b). Determine: i) the velocity of the marble at B ii) the horizontal distance R of the basket from the end of the tube, and iii) the speed at which the marble falls into the basket.
Crazy Wally Ok Ok ok hhahahaha
25.Figure 22.22 shows a plot
of potential versus position
along the x-axis. Make a plot
of the x-component of the
electric field for this situation.
The relationship between the potential and the electric field allows to find the results for the value of the electric field as a function of the distance is:
In the attachment we see the graph of the electric field as a function of distance.
Electric potential is defined by the change in potential energy of a test charge between two points, between the value of the test charge.
dV = - E . ds
E = [tex]- \frac{dV}{ds} \ \hat s[/tex]
Where the bold letters indicate vectors, V is the potential difference, E the electric field and s the path.
Let's apply this expression for each section of the given graph:
1) section from x₀ = 0 to x_f = 2 m, the potential is V₀ = 2 V is constant.
The derivative of a constant is zero.
E = 0
2) Section between x₀ = 2 and x_f = 4 m, the potential varies linearly from V₀ = 2 v to V_f = -2 V.
We look for the equation of the line.
V-V₀ = m (x- x₀)
We carry out the derivative.
E = - m i ^
The slope (m) is:
[tex]m= \frac{V_f - V_o}{x_f- x_o}[/tex]
Let's calculate.
[tex]m= \frac{-2 -2}{4-2} = \ -2 \ V/m[/tex]
Let's substitute.
E = [tex]2 \hat i \ V/m[/tex]
3) From x₀ = 4 to x_f = 4.5 m, the potential varies from V₀ = -2 to V_f = 0.
We look for the equation of the line and we derive.
E = - m i ^
Let's substitute.
[tex]m = \frac{0-(-2)}{4.5-4} = \ 4 V/m[/tex]
E = - 4 [tex]\hat i[/tex] V / m
4) From x₀ = 4.5 m to x_f = 6m. The potential is constant and the derivative of a constant is zero.
E = 0
5) From x₀ = 6m to x_f = 8 m, the potential changes linearly from v₀ = 0 to V_f = 1 V
We look for the equation of the line and we derive.
E = - m i ^
[tex]m = \frac{1-0}{8-6} = \ 0.5 \ V/m[/tex]
E = - 0.5 [tex]\hat i[/tex] V/m
6) From x₀ = 8m to x_f = 9m, the potential changes linearly from V₀ = 1 V to V_f = -1.
We look for the equation of the line and we derive.
E = - m i ^
[tex]m = \frac{-1-1}{9-8} = \ -2 \ V/m[/tex]
Let's substitute.
E = 2 [tex]\hat i[/tex] V/m
7) From x₀ = 9m to x_f = 10 m, the potential changes linearly from V₀ = -1 V to V_f = -2 V
We look for the equation of the line and we derive.
E = - m i ^
[tex]m = \frac{-2+1}{10-9} = \ -1 \ V/m[/tex]
Let's substitute.
E = 1 [tex]\hat i[/tex] V/m
In the attachment we can see these Electric fields as a function of distance.
In conclusion, the relationship between the potential and the electric field we can find the results for the value of the electric field as a function of the distance is:
In the attachment we see the graph of the electric field as a function of distance.
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stuck with this one.
Who actually asked Abraham to sacrifice his son?
I think god did ??? I searched it up okay
God asked him to scarface his sons life
A converging-diverging nozzle has a throat area of 10 cm2 and an exit area of 28.96 cm2 . A normal shock stands in the exit when the back pressure is sea-level standard. If the upstream tank temperature is 400 K, estimate (a) the tank pressure and (b) the mass fl ow
The tank pressure is 5.08 kPa and the mass flow rate is 2.6 kg/s.
The given parameters:
Throat area of the nozzle, [tex]A^*[/tex] = 10 cm² = 0.001 m²The exit area of the nozzle, A = 28.96 cm² = 0.002896 m²Air pressure at sea level = 101.325 kPaThe ratio of the areas of the converging-diverging nozzle is calculated as follows;
[tex]= \frac{A}{A^*} \\\\= \frac{0.002896}{0.001} \\\\= 2.896[/tex]
From supersonic isentropic table, at [tex]\frac{A}{A^*} = 2.896[/tex], we can determine the following;
[tex]M_e = 2.6 \ kg/s\\\\\frac{P_o}{P_e} = 19.954[/tex]
The tank pressure is calculated as follows;
[tex]\frac{P_o}{P_e} = 19.954 \\\\P_e = \frac{P_o}{19.954} \\\\P_e = \frac{101.325 \ kPa}{19.954} \\\\P_e = 5.08 \ kPa[/tex]
Thus, the tank pressure is 5.08 kPa and the mass flow rate is 2.6 kg/s.
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I'm reasking this because I keep getting links not a real answer and I need a proper answer soon please
Answer:
Adding salt to the water increases the density of the solution because the salt increases the mass without changing the volume very much.
Explanation: the explanation is in a file
8th grade science !
can someone help me with trying to understand this question for my homework especially how to understand the graph and use that for my evidence and help me give an idea of how should I write the evidence and reasoning?
Answer:
for reasoning you could put -> the line is at the top at the left handed sided of the chart (also the beginning) slopes down towards the very bottom right handed side of the chart, symbolising less force as distance goes.
Define the following units used for measuring distances in space.
a. Arcsecond
b. Astronomical unit
c. Parsec
d. Light year
Answer:
The astronomical unit is used primarily for measuring distances within the Solar System or around other stars.
7. Which of the following explains how radiometric dating is used to estimate absolute
age.
a. By comparing how deep in the curst the radioactive material in a sample of rock
is, scientists can calculate the length of time since the rock formed.
b. By comparing the amount of organic material in a sample of rock, to the known
rate of decay of the parent rock, scientists can calculate the length of time since
the rock formed.
C. By comparing the amount of radioactive material in a sample of rock, to the
surrounding rocks, scientists can calculate the length of time since the rock
formed.
d. By comparing the amount of a radioactive material in a sample of rock, to the
know rate of decay of the parent rock, scientists can calculate the length of time
since the rock formed.
Answer:
d.
Explanation:
Radiometric dating is a method of dating geological/ archaeological specimens by determining the relative proportions of particular radioactive isotopes present in a sample. Carbon dating is a form of radiometric dating, but, in choice b, you're not comparing the carbon to the rock. One would compare ¹⁴C levels within the organic compound, just as one would compare radioactive isotope levels in a rock.
Why is visual constancy important?
A.
It gives people the ability to see things both close up and far away.
B.
It lets people of all ages see the edges of cliffs so they don’t fall over.
C.
It allows perceptions to remain the same even as images change.
D.
It offers the chance to use one retina at a time to interpret an image.
Reset
Answer:
C.
Explanation:
Visual constancy is a key mechanism that allows the perception to remain.the same even as images change
#CARRYONLEARNING
Visual constancy is important because it allows perceptions to remain the same even as images change.
What is Constancy phenomenon?Constancy phenomenon describes how people and animals tend to perceive familiar objects as having a constant shape, size, colour, or location regardless of adjustments to distance, illumination, or perspective. Instead of responding to the real stimulus, the impression has a tendency to adapt to the object as it is or is imagined to be.
The ability to recognise things in a variety of situations, which appear to be "taken into account" throughout a process of mental rebuilding of the known image, is a result of perceptual constancy. For instance, snow appears white in both the dim moonlight and the 800,000-fold brighter day. Reduced contextual cues that help with object identification and limited experience with the object both affect perceptual constancy.
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what are the applications of triangle law of forces
Answer:
The triangle law of forces can also be stated as. if a body is in equilibrium under the action of three forces acting at a point, then the three forces can be completely represented by the three sides of a triangle taken in order. A body might be subjected to further than one force at a similar time.
Explanation:
Hope it's help
i need help with the problem below
Answer:
Explanation:
a) F = ma
a = F/m
a = 9(800) / 1 x 10⁹ = 7.2 x 10⁻⁶ m/s
b) t = v/a
t = 200 / 7.2 x 10⁻⁶
t = 2.8 x 10⁷ s about 10½ months
c) v² = u² + 2as
s = (v² - u²) / 2a
s = (200² - 0²) / (2( 7.2 x 10⁻⁶))
s = 2.8 x 10⁹ m nearly 7 times around the earth
And all this assumes NO FRICTION.