Does the Sun actually turn dark during a total solar eclipse? Why or why not?

Answers

Answer 1

Answer:

No

Explanation:

The moon is just casting a shadow on the earth

Answer 2

Answer:

The sun does not turn dark during a solar eclipse because during a solar eclipse the moon covers the sun.

Explanation:


Related Questions

ELE Review questions
POSSIBLE POINTS: 3
Match the energy transformation sequence with the device it describes:
A hair dryer plugged into the wall
a
A hand crank generator emergency radio
A battery operated fan
11 CE to ELE
+ ELE to KE
:: KE to ELE
h
1
2
A Review

Answers

Answer:

1. ELE to KE = Electrical energy conversion to kinetic energy.

2. KE to ELE = kinetic energy conversion to electrical energy.

3. CE to ELE = chemical energy conversion to electrical energy.

Explanation:

The Law of Conservation of Energy states that energy cannot be destroyed but can only be transformed or converted from one form to another.

Some examples of energy are chemical energy, electrical energy, kinetic energy, sound energy, potential energy, light energy, etc.

The transformation of energy from one form to another are described below;

1. A hair dryer plugged into the wall: it involves the conversion of electrical energy to kinetic energy. The energy type present in the wall socket is electrical energy which powers the hair dryer to have kinetic energy i.e the energy possessed due to motion of hair dryer.

2. A hand crank generator emergency radio: it illustrates the conversion of kinetic energy to electrical energy. The hand crank generator possess kinetic energy as it is being wounded before it is then converted into electrical energy which powers the radio.

3. A battery operated fan: it illustrates the conversion of chemical energy to electrical energy. The cells present in battery possess chemical energy that is being converted into electrical energy to power the fan.

How much time will it take for a bug to travel 2 meters across the floor if it is traveling at 0.5 m/s?

Answers

Answer:

it will take 4 seconds to travel 2 meters.

Observer A, who is at rest in the laboratory, is studing a particle that is moving through the laboratory at a speed of 0.624c and determines its lifetime to be 159ns a) Obsever A places markers in the laboratory at the locations where the particle is produced and where it decays. How far apart are those markers in the laboratory? b) Obsever B, who observes the particle to be at rest and measures its lifetime to be 124ns. According to B, how far apart are the two markers in the laboratory?

Answers

Answer:

a) the markers are 29.76 m far apart in the laboratory

b) According to B, the markers are 23.21 m far apart in the laboratory

Explanation:

Given that;

speed of particle = 0.624c = (0.624 × 3×10⁸m/s)

{ where c is the speed of light}    

lifetime of the particle t = 159ns  = 1.59 × 10⁻⁷

a) Observer A places markers in the laboratory at the locations where the particle is produced and where it decays. How far apart are those markers in the laboratory

lets apply the formula distance = velocity × time

lets substitute

distance = (0.624×3×10⁸ m/s)  × (1.59 × 10⁻⁷ s)

distance = 29.76 m

Therefore, the markers are 29.76 m far apart in the laboratory

b) Observer B, who observes the particle to be at rest and measures its lifetime to be 124ns. According to B, how far apart are the two markers in the laboratory?

lifetime of the particle t = 124ns  = 1.24 × 10⁻⁷

distance = (0.624×3×10⁸ m/s)  × (1.24 × 10⁻⁷ s)

distance = 23.21 m

Therefore,  According to B, the markers are 23.21 m far apart in the laboratory

Help me guys please

Answers

Answer:

The answer is B

Explanation:

keep it up

The answer to this question is B

James makes a treasure map to locate a secret item on McEachern Campus. He uses the
following displacement vectors to locate the treasure
A student wants to simplify this information
5 m East
7 m North
5 m South
7 m East
3 m South
2 m West
A. Determine the Displacement Vector Components. (x componenty component)
Show all work. 2 pts
B. Use the Pythagorean Theorem to calculate the resultant vector. Show all work. 2 pts
Answer format:
a. work & answer...
b. work and answer...
(4 Points)

Answers

Answer:

south

Explanation:

A long, thin metal tube of cross-sectional area 1.60 cm2 is sealed into the top of a hollow cube of edge length 0.150 m. Water fills the cube and extends upward a distance h into the tube. Find h if the water exerts a force of 1.00 103 N on the base of the cube. What is the weight of the water?

Answers

Answer:

Explanation:

Given that:

The area of the metal tube = 1.60 cm² = 1.60 × 10⁻⁴ m²

Length of cube L = 0.150 m

The exerted force by water = 1.00 × 10³ N

At the top of the cube;

The force on water is F = pgL

F = 9.8 m/s² × (1000 kg/m³) (0.150 m)(0.150 m)²

F = 33.075 N

[tex]pgh = \dfrac{F}{A}[/tex]

[tex]h = \dfrac{F}{Apg}[/tex]

[tex]h = \dfrac{33.075}{(1.60 \times 10^{-4} \ m^2) \times (1000 \ kg/m^3)(9.8)}[/tex]

h = 21.09 m

The volume of the water V = L³

V = (0.150 m)³

V = 0.003375 m³

weight of the water w = p(V + Ah)

w = 1000 (0.003375 + (1.60 × 10⁻⁴ × 21.09))

w = 6.75 kg

Using a simple model of an electromagnet, describe the factors that increase the magnetic field strength of an electromagnet.(2 points)

Answers

Answer:

Factors Affecting the Strength of the Magnetic Field of an Electromagnet: Factors that affect the strength of electromagnets are the nature of the core material, strength of the current passing through the core, the number of turns of wire on the core and the shape and size of the core

Explanation:

Follow me for more

The following factors affect the strength of an electromagnet; number of turns, wire size, current and the presence of iron core.

What is electromagnet?

This is a type of magnet  in which the magnetic field is produced by an electric current.

Factor affecting electromagnet

The following factors affect the strength of an electromagnet;

Number of turnsWire sizeCurrentPresence of iron core.

Learn more about electromagnet here: https://brainly.com/question/12555869

Review. As it passes over Grand Bahama Island, the eye of a hurricane is moving in a direction 60.08 north of west with a speed of 41.0 km/h. (a) What is the unit-vector expression for the velocity of the hurricane

Answers

Answer:

Velocity = -20.45 i + 35.54 j km/h

Explanation:

given data

speed v = 41.0 km/h

direction = 60.08 north of west

solution

first we get here Speed in west direction that is express as

Speed in west direction = v × cos(60.08)     ..........................1

Speed in west direction = 41 × cos(60.08)

Speed in west direction = 20.45 km/h

now we get Speed in north direction that is

Speed in north direction = v × sin(60.08)        ............................2

Speed in north direction = 41 × sin(60.08)

Speed in north direction = 35.54 km/h

so Velocity will be here

Velocity = -20.45 i + 35.54 j km/h

Friction produces heat because it causes molecules to move faster and
have more energy.
True or false.

Answers

Answer:

True

Explanation:

Friction occurs because no surface is perfectly smooth. Even surfaces that look smooth to the unaided eye make look rough or bumpy when viewed under a microscope. You know that friction produces heat. That’s why rubbing your hands together makes them warmer. But do you know why? Friction causes the molecules on rubbing surfaces to move faster, so they have more energy. This gives them a higher temperature, and they feel warmer. Heat from friction can be useful. It not only warms your hands.

Calculate the amount of potential difference in a capacitor of 0.9 MF , If the amount of charge is 1.4x10^-4 C .(Show all the work)

Answers

Answer:

Potential difference [tex]V=1.6\times 10^{-10}\ V[/tex]

Explanation:

Capacitance of capacitor, C = 0.9 MF

Charge, [tex]Q=1.4\times 10^{-4}\ C[/tex]

We need to find the amount of potential difference. We know that,

[tex]Q=CV[/tex]

V is potential difference

So,

[tex]V=\dfrac{Q}{C}\\\\V=\dfrac{1.4\times 10^{-4}}{0.9\times 10^6}\\\\V=1.6\times 10^{-10}\ V[/tex]

So, the required potential difference is [tex]1.6\times 10^{-10}\ V[/tex].

Could a sea breeze occur at night? Explain why or why not.

Answers

No sea breeze can not occur at night because while sea breezes occur during the day, land breezes occur at night. Despite the difference in times at which the land breezes and sea breezes occur, the reason for the land breeze's formation is basically the same as the sea breeze, but the role of the ocean and land is reversed.
Hope this helps ✌️

se the following graph describing a motorcycle's motion to answer the question below.

Answers

I do not see a graph for it?

The specific heat of water is 4,186 J/kg.'C. Approximately how much heat must
be removed from 0.500 kg of water to change its temperature from 24.0°C to
5.00°C?

Answers

Explanation:

Q= mc∆T

∆T= 5-24=- 19

Q= 0.5*4186*-19

Q= -39767 J

negative sign show heat releases

Gamma rays are dangerous because they


a.can breakdown molecules and cells

b. fluoresce

c. cause food to spoil

d. cause sunburn

Answers

Answer:

A.

Explanation:

A large fraction of astronomical gamma rays are screened by Earth's atmosphere. Gamma rays are ionizing radiation and are thus biologically hazardous. Due to their high penetration power, they can damage bone marrow and internal organs.

The extremely high energy of gamma rays allows them to penetrate just about anything. They can even pass through bones and teeth. This makes gamma rays very dangerous. They can destroy living cells, produce gene mutations, and cause cancer.

Sound will travel fastest in air at _____.
-5°C
0°C
10°C
15°C
The following table lists the speed of sound in various materials. Use this table to answer the question.
Substance
Speed (m/s)
Glass
5,200
Aluminum
5,100
Iron
4,500
Copper
3,500
Salt water
1,530
Fresh water
1,500
Mercury
1,400
Hydrogen at 0°C
1,284
Ethyl Alcohol
1,125
Helium at 0°C
965
Air at 100°C
387
Air at 0°C
331
Oxygen at 0°C
316

Answers

Answer:

iron/copper

iron faster because it in the core so iron is the answer with would be 15C because its the hottest in the core and is very quick there to being moved by the core so iron being 15C is the answer.

Explanation:

Suppose a meteor of mass 2.50 x 1013 kg is moving at 33.0 km/s relative to the center of the Earth and strikes the Earth. Suppose the meteor creates the maximum possible decrease in the angular speed of the Earth by moving toward the west and striking a point on the equator tangentially. What is the change in the angular speed of the Earth due to this collision

Answers

Answer:

change is imperceptible

          w_f = 7.272  10⁻⁵ rad / s

Explanation:

For this exercise we can use the conservation of angular momentum.

Initial. Before the crash

        L₀ = I w₀

final. After the crash

         L_f = I w_f + p r

where the moment is

        p = mv

As the system is formed by the two bodies, the forces during the impact are internal, therefore the angular momentum is conserved

        L₀ = L_f

        I w₀ = I w_f + m v r

        w_f = w₀ - [tex]m \frac{ v \ r }{I}[/tex]

We can approximate the Earth to a sphere, so its angular momentum is

       I = 2/5 M r²

we substitute

         w_f = w₀ - [tex]\frac{5 \ m \ v}{2 \ M \ r}[/tex]

We can find the angular velocity of the Earth with the duration of a spin which is the period of one day

        w₀ = 2π / T

        T = 24 h (3600 s / 1h) = 86 400 s

         w₀ = 2π / 86400

         w₀ = 7.272 10⁻⁵ rad / s

let's calculate

         w_f = 7.27 10⁻⁵ - [tex]\frac{5 \ 250 \ 10^{13} \ 33.0 \ 10^{3} }{ 2 \ 5.98 \ 10^{24} \ 6.37 10^{6} }[/tex]

         w_f = 7.272 10⁻⁵ - 1.0829 10⁻¹³

         w_f = 7.27199999 10⁻⁵

this change is imperceptible

          w_f = 7.272  10⁻⁵ rad / s

What attitudes and actions can group leaders take in trying to establish trust within a group during the initial stage of group development? How is each attitude and action important in the process of initiating trust?​

Answers

Answer:

i dont know!

Explanation:

A volleyball player spiking is it kinetic or potential

Answers

Answer:

It is kinetic energy.

Explanation:

The kinetic energy of an object is the energy that it possesses due to its motion. It is defined as the work needed to accelerate the volleyball from rest to its stated velocity. Having gained this energy from the player spiking it during its acceleration, the body maintains this kinetic energy unless its speed changes.

Question 6
2 pts
Jenny loves puffed rice cereal. As she is pouring the cereal, two little pieces of cereal each with
equal charges of 1.85 x10-18 coulombs fall into the bowl 0.025 meters apart. Use Coulomb's Law
to find the electrostatic force between them. (Remember, Coulomb's constant is 8.99 x10
N*m²/C2)
4.9 x 10-23 N
6.2 x 10-15 N
9.0 x 10-3N
2.5 x 10-23 N

Answers

Answer:

4.9 x 10-23 N

Explanation:

I took the test

A Drive to the BeachMary drove from her home to the beach that is 30 mi from her house. The first 15 mi she drove at 60 mph, and the next 15 mi she drove at 30 mph. Would the trip take more, less, or the same time if she traveled the entire 30 mi at a steady 45 mph

Answers

Answer:

Explanation:

Let us calculate the average velocity .

Average velocity = total distance / total time

Time taken to drive first 15 mi

= 15 / 60 = .25 h

Time taken to drive next 15 mi

= 15 / 30 = .5 h

Total time = .25 + .5 = .75 h

Total distance = 30 mi

average speed = 30 / .75

= 40 mi / h

So average speed is 40 mph which is less than given velocity of 45 mph .

Hence if she travels at 45 mph , she will take less time .

1. Calculate the electric field due to a single +1nC point charge at a distance of lm, 2m, and 3m

Answers

Answer:

Approximately [tex]9.0\; \rm N \cdot C^{-1}[/tex] at [tex]1\; \rm m[/tex] from this charge, pointing away from the point charge.Approximately [tex]2.2\; \rm N \cdot C^{-1}[/tex] at [tex]\rm 2\; \rm m[/tex] from this charge, pointing away from the point charge.Approximately [tex]1.0\; \rm N \cdot C^{-1}[/tex] at [tex]3\; \rm m[/tex] from this charge, pointing away from the point charge.

Assumption: there is no object between this point charge and the observer.

Explanation:

The electric field of a point charge is inversely proportional to the square of the distance from that point charge.

Let [tex]k[/tex] denote Coulomb's constant ([tex]k \approx 8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-1}[/tex].) Let the magnitude of that point charge be [tex]q[/tex]. At a distance of [tex]r[/tex] from this charge, the electric field due to this charge would be:

[tex]\displaystyle E = \frac{k \cdot q}{r^{2}}[/tex].

Convert the magnitude of the point charge in this question to standard units:

[tex]q = 1\; \rm nC = 10^{-9}\; \rm C[/tex].

Apply that equation to find the magnitude of the electric field due to this point charge:

[tex]r = 1\; \rm m[/tex]:

[tex]\begin{aligned} E &= \frac{k \cdot q}{r^{2}} \\ &= \frac{8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-2} \times 10^{-9}\; \rm C}{(1\; \rm m)^{2}} \\ &\approx 9.0\; \rm N \cdot C^{-1}\end{aligned}[/tex].

[tex]r = 2\; \rm m[/tex]:

[tex]\begin{aligned} E &= \frac{k \cdot q}{r^{2}} \\ &= \frac{8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-2} \times 10^{-9}\; \rm C}{(2\; \rm m)^{2}} \\ &\approx 2.2\; \rm N \cdot C^{-1}\end{aligned}[/tex].

[tex]r = 3\; \rm m[/tex]:

[tex]\begin{aligned} E &= \frac{k \cdot q}{r^{2}} \\ &= \frac{8.98755 \times 10^{-9}\; \rm N \cdot m^{2} \cdot C^{-2} \times 10^{-9}\; \rm C}{(3\; \rm m)^{2}} \\ &\approx 1.0\; \rm N \cdot C^{-1}\end{aligned}[/tex].

The direction of the electric field at a point is the same as the direction of a force from this field onto a positive point charge at this point.

Because the [tex](+1\; \rm nC)[/tex] point charge here is positive, the electric field of this charge would repel other positive point charges. Hence, the electric field around this [tex](+1\; \rm nC)\![/tex] point charge at any point in the field would point away from this charge.

A pendulum Bob released from some initial height such that the speed of the bob at the bottom of the swing is 1.9m/s. What is the initial height of the bob?

Answers

Answer:

h = 18.4 cm

Explanation:

Given that,

The speed of the bob at the bottom of the swing is 1.9m/s.

We need to find the initial height of the bob. Let it is h.

We can find it using the conservation of energy i.e.

[tex]mgh=\dfrac{1}{2}mv^2[/tex]

Where

v is speed of the bob

So,

[tex]h=\dfrac{v^2}{2g}\\\\h=\dfrac{(1.9)^2}{2\times 9.8}\\\\h= 0.184\ m[/tex]

or

h = 18.4 cm

So, the initial height of the bob is 18.4 cm.

The initial height of bob will be "18.4 cm".

Speed and height:

Speed would be the scalar quantity that describes "how quickly an attribute moves." This could sometimes be defined as this same rate whereby an object travels a given distance.

According to the question,

The speed of the bob = 1.9 m/s

Let,

The initial height be "h".

By using the conservation of energy, we get

→ mgh = [tex]\frac{1}{2}[/tex]mv²

or,

→      h = [tex]\frac{v^2}{2g}[/tex]

By substituting the values, we get

          = [tex]\frac{(1.9)^2}{2\times 9.8}[/tex]

          = 0.184 m or,

          = 18.4 cm

Thus the above answer is correct.

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https://brainly.com/question/13665920

A 20.0 newton force is used to push a 2.00 kilogram cart a distance of 5.00 meters how much work is done on the cart

Answers

Answer:

100

w=f*s

20*5=100....

100 Joules of work is done on the cart.

What is Work done?

Work done by a force is defined as the product of the displacement and the component of the applied force on the object in the direction of displacement. When we push a block with some force, the body moves with some acceleration, so it is called work done.

Work done is expressed as W=Fd and its unit is joules which can be defined as the amount of work done by a force in Newton is applied to an object, as a result of which it is displaced in meter.

For above given information,

Force= 20 N

Distance= 5 m

So, work done= 20*5= 100 Joules

Thus, 100 Joules of work is done on the cart.

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#SPJ2

Which activities demonstrate speed the most?

Answers

Answer:I think sprinting

Explanation:

Convert the arc length of 6.86 radians into cycles.
Plz convert this for me people have been putting random comments

Answers

Answer:

1.092 cycles

Explanation:

We need to convert the arc length of 6.86 radians into cycles.

We know that,

1 radian = 0.1592 cycles

To convert 6.86 radians to cycles, we use unitary method.

6.86 radian = (0.1592 × 6.86) cycles

= 1.092 cycles

Hence, there are 1.092 cycles in 6.86 radians. Hence, this is the required solution.


A stone is dropped off of a 123 meter cliff and falls to the ground below. How long does it take for the stone to hit the ground

Answers

25.10 or 24.6m/s both answers are correct

Explanation:

firstly , divide the multiply with 2 and divide the result by acceleration due to gravity which is 9.8m/s or 10m/s

123*2=246

246/9.8 or 10

= 25.10 or 24.6m/s

Convert the arc length of 3.05 degrees into meters.

Answers

That depends on the circle's radius, which you neglected to mention.

If the radius is 1 meter, then an arc of 3.05 degrees is 5.32 centimeters long.

If the radius is 1 kilometer, then an arc of 3.05 degrees is 53.2 meters long.

often occurs at subduction zones. Check all that apply:
O convergence
trench
upward convection currents in the mantle below it
Orifts
most volcanoes...Pacific Ring of Fire
continental plate subducts because it's less dense

Answers

Answer:

convergence and trench

Explanation:

LOL

Two carts collide and have a perfectly inelastic collision. Cart1 has a mass of 500 grams and
Cart2 has a mass of 600 grams. Cart1 has an initial westward velocity of 1.6 m/s and collides
with Cart2 which was initially at rest. What is was the final velocity of the two cart system (SI
units)?

Answers

Answer: look at the file

A copper wire of length L and cross-sectional area A has resistance R. A second copper wire at the same temperature has a length of 2L and a cross-sectional area of A. What is the resistance of the second copper wire?
A. 2R
B. 4R
C. R
D. 1/2 R

Answers

Answer: 4R

Explanation:R=pL/A

R second wire=p2L/1/2A

=4R

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