Answer:
x = 13.2
Step-by-step explanation:
We know that
sin theta = opp / hyp
sin 27 = y/x
sin 27 = 6/x
x sin 27 =6
x = 6/sin 27
x=13.21613559
Rounding to 1 decimal place
x = 13.2
Flying against the wind, an airplane travels 3800 kilometers in 4 hours. Flying with the wind, the same plane travels 3750 kilometers in 3 hours. What is the rate of the plane in still air and what is the rate of the wind?
Answer:
[tex]V_w =1100[/tex] ---- velocity of wind
[tex]V_a = 150[/tex] --- velocity of airplane
Step-by-step explanation:
Given
[tex]V_a \to[/tex] velocity of airplane
[tex]V_w \to[/tex] velocity of wind
Flying with the wind, the distance (d) is:
[tex]d = (V_w + V_a) * t[/tex]
Where d and t are distance travel and time spent with the wind
So:
[tex]3750 = (V_w + V_a) * 3[/tex]
Divide by 3
[tex]1250 = (V_w + V_a)[/tex]
Flying against the wind, the distance (d) is:
[tex]d = (V_w - V_a) * t[/tex]
Where d and t are distance travel and time against with the wind
So:
[tex]3800 = (V_w - V_a) * 4[/tex]
Divide by 4
[tex]950 = (V_w - V_a)[/tex]
Make [tex]V_w[/tex] the subject
[tex]V_w= 950 + V_a[/tex]
Substitute: [tex]V_w= 950 + V_a[/tex] in [tex]1250 = (V_w + V_a)[/tex]
[tex]1250 = 950 + V_a + V_a[/tex]
[tex]1250 = 950 + 2V_a[/tex]
Collect like terms
[tex]2V_a = 1250 -950[/tex]
[tex]2V_a = 300[/tex]
Divide by 2
[tex]V_a = 150[/tex]
Substitute [tex]V_a = 150[/tex] in [tex]V_w= 950 + V_a[/tex]
[tex]V_w =950 +150[/tex]
[tex]V_w =1100[/tex]
Bari Jay, a gown manufacturer, received an order for prom dresses from China. Her cost is $32 a gown. If her markup based on selling price is 76%, what is the selling price of each gown? (Round your answer to the nearest cent.)
Answer:
$56.32
Step-by-step explanation:
Find the selling price by multiplying the original cost by 1.76:
32(1.76)
= 56.32
So, the selling price is $56.32
Josie is purchasing a $75 appliance for her kitchen. She has three coupons to the store that she can choose from. Which is a true statement about Josie’s options?
Answer:
where are the answer choices?
Step-by-step explanation:
The radius of a cylinder of volume 2970cm³ is 30mm. Find the volume of a similar cylinder of radius 40mm.
34.3 cm3
if you use formula
30mm 2970cm3
x-x un^3
What is the value of [tex]\frac{81^4}{3^5}[/tex]? (Express your answer in exponential form.)
Answer:[tex]3^1^1\\[/tex]
Step-by-step explanation:
[tex]\frac{81^4}{3^5}[/tex]
[tex]\frac{3^1^6}{3^5}[/tex]
The base is same power can be add or subtract
[tex]3^1^6^-^5[/tex]
[tex]3^1^1[/tex]
Geometric stuff and please explain
Perimeter = Sum of the sides measures
Perimeter = | AB | + | AT | + | BT |
Perimeter = ( x + 3 ) + ( 4x ) + ( 2x + 2 )
40 = x + 4x + 2x + 3 + 2
Colect like terms
40 = ( 1 + 4 + 2 )x + ( 3 + 2 )
40 = 7x + 5
Subtract both sides - 5
40 - 5 = 7x + 5 - 5
35 = 7x
Switch sides
7x = 35
Divide both sides by 7
7x ÷ 7 = 35 ÷ 7
x = 5
_____________________________
AB = x + 3 = 5 + 3 ======》 AB = 8
AT = 4x = 4 × 5 =========》 AT = 20
BT = 2x + 2 = 2(5) + 2 ===》 BT = 12
According to the law of inequality in a triangle, the sum of any two random sides must be greater than the size of the other side which means :
AB + AT > BT
&
AB + BT > AT
&
AT + BT > AB
If the sides is true in the above inequalities, then those sides are able to form a triangle ;
But if even one of the above inequalities is violated, those sides will not be able to form a triangle.
8 + 20 > 12 ( Check )
8 + 12 > 20 ( Nope this inequlity violated )
Thus the measures of the sides can not represent the measures of the sides of a triangle .
And we're done ...
What is the value of 2 + (-2/3) ^2 ÷1/3 ?
16
3
-2
0
.
Answer:
Doing the test rn got 3 1/3 i dont know if u should trust me but just try
Step-by-step explanation:
Find the distance between the points (-6, -8) and (6, -3).
Write your answer as a whole number or a fully simplified radical expression. Do not round.
units
Answer:
[tex]\displaystyle d = 13[/tex]
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra I
Coordinates (x, y)Algebra II
Distance Formula: [tex]\displaystyle d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}[/tex]Step-by-step explanation:
Step 1: Define
Identify
Point (-6, -8)
Point (6, -3)
Step 2: Find distance d
Simply plug in the 2 coordinates into the distance formula to find distance d
Substitute in points [Distance Formula]: [tex]\displaystyle d = \sqrt{(6- -6)^2+(-3- -8)^2}[/tex][√Radical] (Parenthesis) Subtract: [tex]\displaystyle d = \sqrt{12^2+5^2}[/tex][√Radical] Evaluate exponents: [tex]\displaystyle d = \sqrt{144+25}[/tex][√Radical] Add: [tex]\displaystyle d = \sqrt{169}[/tex][√Radical] Evaluate: [tex]\displaystyle d = 13[/tex]What is the value of U
I don't have a value... jk jk :)
Answer: 40°
Explanation... since U is on a straight line and since GS is 140
180 - 140 = 40
Hope it helps...
A youth club has 150 members. 60 of the members are girls. What percentage of the club members are girls?
Answer:
40 %
Step-by-step explanation:
no of members in youth club = 150
no of girls = 60
girls percentage = ?
girls percentage = no of girls / total members * 100%
= 60 / 150 *100%
=6000 / 150
=40 %
Express 60g as a percentage of 3kg?
Answer:
2%
60/3000g= ?/100
60×100/3000=2
help please asap just the answers
a = 2 ; b = −1 and c = −3
The values are :
[tex]a = 2[/tex][tex]b = - 1[/tex][tex]c = - 3[/tex]let's plug the values :
[tex] {c}^{2} + 5ab[/tex][tex]( - 3) {}^{2} + (5 \times 2 \times - 1)[/tex][tex]9 - 10[/tex][tex]-1[/tex]Therfore, correct answer is :
[tex] \large - 1[/tex][tex]\mathfrak{good \: \: luck \: \: for \: \: your \: \: assignment}[/tex]
[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }[/tex]
[tex] \huge\underline{\sf{\red{Problem:}}}[/tex]
9.) Detemine the value of [tex] \sf{ {c}^{2} + 5ab.}[/tex][tex] \huge\underline{\sf{\red{Given:}}}[/tex]
[tex]\quad\quad\quad\quad\sf{a = 2}[/tex]
[tex]\quad\quad\quad\quad\sf{b = - 1}[/tex]
[tex]\quad\quad\quad\quad\sf{c = - 3}[/tex]
[tex] \huge\underline{\sf{\red{Solution:}}}[/tex]
[tex]\quad\quad\quad\quad\sf{⟶{c}^{2} + 5ab}[/tex]
[tex]\quad \quad \quad \quad \sf{⟶{( - 3)}^{2} + 5( 2)( - 1)}[/tex]
[tex]\quad \quad \quad \quad \sf{⟶9+ 5( 2)( - 1)}[/tex]
[tex]\quad \quad \quad \quad \sf{⟶9+ 10( - 1)}[/tex]
[tex]\quad \quad \quad \quad \sf{⟶9 - 10 }[/tex]
[tex]\quad \quad \quad \quad ⟶ \boxed{ \sf{ -1}}[/tex]
[tex]\huge\underline{\sf{\red{Answer:}}}[/tex]
[tex]\huge\quad \quad \underline{ \boxed{ \sf{ \red{-1}}}}[/tex]
[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }[/tex]
#CarryOnLearning
[tex]\sf{\red{✍︎ C.Rose❀}}[/tex]
You kick a 3.2 kg ball with a Force of 61 N. Find the acceleration of the
ball in m/s2. Round your answer to 1 decimal place.
Answer:
[tex]19.4 ms^{-2}[/tex]
Step-by-step explanation:
Newton second law: [tex]\vec F= m\vec a[/tex] We know the force, we know the mass, we can substitute and find the acceleration, which is [tex]61/3.2 = 19.4 ms^{-2}[/tex]
If k = 23 and m
-14, what is ✓k + m?
Submit
Answer:
3
Step-by-step explanation:
Evaluate:
Sqrt of k = 32 + m = -14
Sqrt of 32-14 = 9
Sqrt of 9 = 3
Therefore, our answer is 3!
Btw sqrt means: square root
Hope this helps! Have a good day!
32% of the days in a year the wind blows south.About how many days does the wind blows south?
Answer:
116 days because 32 percent of 365 is 116
Please help I’ll give brainliest
Answer:
The answer for this question is 3
Answer:
i believe its 2 but i could be wrong
Step-by-step explanation:
im sorry if i am
Find a third-degree polynomial equation with rational coefficients that has roots –5 and 6 + i.
The coefficients of the polynomial are rational, which means that any non-real roots occur alongside their complex conjugates. In this case, 6+i is a root, so 6-i is also a root.
So the simplest polynomial you can build with these roots is
(x - (-5)) (x - (6 + i )) (x - (6 - i )) = x ^3 - 7x ^2 - 23x + 185
(first choice)
b(1)=−7
b(n)=b(n−1)+12
Find the 4th term in the sequence.
Answer:
4th term = 29
to generate the terms, substitute n = 2, 3, 4 into the rule
noting that b(1) = - 7
b(2) = b(2 - 1) + 12 = b(1) + 12 = -7 + 12 = 5
b(3) = b(3 - 1) + 12 = b(2) + 12 = 5 + 12 = 17
b(4) = b(4 - 1) + 12 = b(3) + 12 = 17 + 12 = 29
how to solve 3^8 times 3^2
Answer:
3072 that what I known as a 10th grader
Equation of a line is y = 2x + 5
a) what is the gradient?
b)what is y- intercepted?
c) if the gradient is -3 and y-intercept is 1,then what is the equation of the line?
Answer:
Step-by-step explanation:
Generally, we have the equation of a straight line as;
y = mx + b
where m is the slope and g is y intercept
a) The gradient is the slope and we have the value as 2
b) The y-intercept here is 5
c) for slope -3 and intercept 1, the equation becomes
y = -3x + 1
What is the answer for this
Answer:
A
Step-by-step explanation:
The green is the starting place, when you move from a point on the green triangle to the blue one, you go 5 to the left and 3 down.
10 points!!!!! Do 14 and 15 only hurry please.
Answer:
8. x = 16
9. x = 10
14.
m ∠RSU = 130°
m ∠UST = 50°
15.
m ∠RSU = 124°
m ∠UST = 56°
Step-by-step explanation:
8.
Given ∠DEF is bisected by EG. That is , ∠DEG = ∠GEF
That is , (x + 15)° = 31°
x = 31 - 15 = 16
9.
Given ∠DEF is bisected by EG. That is , ∠DEG = ∠GEF
That is ,
(6x - 4)° = 56°
6x = 56 + 4
6x = 60
x = 10
14.
13x + 5x = 180° [straight line angles ]
18x = 180
x = 10
m ∠RSU = 130°
m ∠UST = 50°
15.
4x + 12 + 2x = 180° [ straight line angles]
6x = 180 - 12
6x = 168
x = 28
m ∠RSU = 4(28) + 12 = 112 + 12 = 124°
m ∠UST = 2(28) = 56°
Answer:
14. 13x+5x
=18x
180(angles on a st. line)= 18x
180/18
=10
RSU=13*10=130
UST=5*10=50
y is proportional
to x
y = 72 when x = 12
Write a direct
proportion
equation.
A. y = 12x
B. y = 6x
C. 72x = 12
D. 7 x 12 = y
Answer:
B :) (im sure btw)
Step-by-step explanation:
HELP I HAVE 10 MINS
If AB and CD have endpoints at A(- 1,3), B(6,8), C(4, 10) and D(9,3), are AB and CD parallel,
perpendicular, or neither? Explain.
Answer:
perpendicular
What is the product?
(-20d^2+s)(5d^2-6s)
Answer:
-100d⁴ + 125d²s - 6s²
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra I
Terms/CoefficientsExpand by FOILStep-by-step explanation:
Step 1: Define
Identify
(-20d² + s)(5d² - 6s)
Step 2: Expand
FOIL: -100d⁴ + 120d²s + 5d²s - 6s²[Addition] Combine like terms: -100d⁴ + 125d²s - 6s²Cameron drives a semi-truck for Haulin' Harry's Trucking Company. He earns $0.45 for every mile he drives. If Cameron drove 827.4 miles on his last route, how much money did he earn?
Answer:
$372.33
Step-by-step explanation:
For 1 mile= $0.45
For 827.4 miles = $0.45 x 827.4
= $372.33
Pls don’t have much time
Answer:
the answer is b
Step-by-step explanation:
35 occurs the most on the graph meaning that it's the mode
ASAP 30 POINTS BRAINLIEST IF RIGHT
Answer:
answer in the link below if you have any questions let me know
Answer:
≈ 0.14
Step-by-step explanation:
The average rate of change of f(x) in the closed interval [ a, b ] is
[tex]\frac{f(b)-f(a)}{b-a}[/tex]
Here [a, b ] = [ - 1, 3 ] , then
f(b) = f(3) = [tex]\sqrt[3]{3+3}[/tex] = [tex]\sqrt[3]{6}[/tex] ≈ 1.817
f(a) = f(- 1) = [tex]\sqrt[3]{-1+3}[/tex] = [tex]\sqrt[3]{2}[/tex] ≈ 1.260 , then
average rate of change = [tex]\frac{1.817-1.260}{3-(-1)}[/tex] = [tex]\frac{0.557}{4}[/tex] ≈ 0.14 ( to the nearest hundredth )
Solve for x.
3x +13
6x + 5
x = [?]
Answer:
nessa resposta da 10 beijos
Answer:
x = 18
Step-by-step explanation:
The given angles are same- side exterior angles and sum to 180°, that is
6x + 5 + 3x + 13 = 180
9x + 18 = 180 ( subtract 18 from both sides )
9x = 162 ( divide both sides by 9 )
x = 18
Graph a line with y- intercept of 5 and gradient of -10/3
Step-by-step explanation:
the equation is:
y= -10/3 x +5
the graph as attached