During the first 13 weeks of the television season, the Saturday evening 8:00 p.m. to 9:00 p.m. audience proportions were recorded as ABC 30%, CBS 27%, NBC 26%, and independents 17%. A sample of 300 homes two weeks after a Saturday night schedule revision yielded the following viewing audience data: ABC 96 homes, CBS 69 homes, NBC 90 homes, and independents 45 homes.Test with α = 0.05 to determine whether the viewing audience proportions changed.State the null and alternative hypotheses.H0: pABC ≠ 0.30, pCBS ≠ 0.27, pNBC ≠ 0.26, pIND ≠ 0.17Ha: pABC = 0.30, pCBS = 0.27, pNBC = 0.26, pIND = 0.17 H0: pABC = 0.30, pCBS = 0.27, pNBC = 0.26, pIND = 0.17Ha: pABC ≠ 0.30, pCBS ≠ 0.27, pNBC ≠ 0.26, pIND ≠ 0.17 H0: The proportions are not pABC = 0.30, pCBS = 0.27, pNBC = 0.26, pIND = 0.17.Ha: pABC = 0.30, pCBS = 0.27, pNBC = 0.26, pIND = 0.17 H0: pABC = 0.30, pCBS = 0.27, pNBC = 0.26, pIND = 0.17Ha: The proportions are not pABC = 0.30, pCBS = 0.27, pNBC = 0.26, pIND = 0.17.Find the value of the test statistic. (Round your answer to three decimal places.)Find the p-value. (Round your answer to four decimal places.)p-value =State your conclusion.Reject H0. There has been a significant change in the viewing audience proportions. Reject H0. There has not been a significant
change in the viewing audience proportions. Do not reject H0. There has been a significant change in the viewing audience proportions. Do not reject H0. There has not been a significant change in the viewing audience proportions.

Answers

Answer 1

Part 1: Do not reject H0. There has not been a significant change in the viewing audience proportions.(The above conclusion holds as the p-value is greater than the significance level of 0.05)

Part 2:

H0:  

Ha:  

Part 3: The test statistic is given as 3.0081.

Part 4: The p-value is given as  0.39037

Step-by-step explanation:

As per the data

Part 2

H0:  

Ha:  

Part 3

As per the sample is of 300 homes, the expected values are given as

ABC=p(ABC)*300=0.30*300=90

CBS=p(CBS)*300=0.27*300=81

NBC=p(NBC)*300=0.26*300=78

IND=p(IND)*300=0.17*300=51

Now the values actually are given as

ABC=94

CBS=71

NBC=88

IND=47

So the test static is given as

So the test statistic is given as 3.0081.

Part 4

Now the degree of freedoms are given as 4-1=3

and chi square  is given as 3.0081 so for α = 0.05 , the p-value is given as  0.39037

Part 1.

As the value of p in part 4 is greater than the value of α = 0.05, thus Do not reject H0. There has not been a significant change in the viewing audience proportions.(The above conclusion holds as the p-value is greater than the significance level of 0.05)


Related Questions

HELP ME CANT FAIL!! Which parent function is represented by the graph?

A) An exponential parent function
B) Liner parent function
C)Absolute value parent function
D)Quadratic parent function

Answers

The answer is b

Explanation:

Un recipiente cilíndrico tiene un diámetro de 160cm. y la misma altura. ¿Cuánto litros de agua puede caber?

Answers

Respuesta:

3215360 cm³

Explicación paso a paso:

Dado que :

Radio = 160/2 = 80 cm

Altura, h = 160 cm

Volumen de un cilindro = πr²h

Volumen del cilindro = π * 80² * 160

Volumen = 3215360 cm³

how do I solve this equation?
[tex]x + 8y = 20 \\ 2x + 4y = 4[/tex]

Answers

Answer:

Subtract x x from both sides of the equation. 8y=20−x 8 y = 20 - x. Divide each term by 8 8 and simplify.

Solve for x 2x-4y=4. 2x−4y=4 2 x - 4 y = 4. Add 4y 4 y to both sides of the equation. 2x=4+4y 2 x = 4 + 4 y. Divide each term by 2 2 and simplify.

X = -8y + 20
2(-8y + 20) +4y = 4
-16y + 40 + 4y = 4
-12y +40=4
Subtract 40 from each side
-12y= -36
Divide both by -12
y = 3
Plug Y=3 in to find x
X + 8(3) = 20
X + 24 = 20
Subtract 24
x = -4

Calculate the unit price. Round to the nearest cent, if necessary.

0.75 lb of salami for $2.65

$4.64 per lb of salami
$2.65 per lb of salami
$3.53 per lb of salami
$1.99 lb of salami
per

Answers

Answer:

$3.53 per lb of salami

Step-by-step explanation:

0.75 lb of salami for $2.65

The price per of salami will be :

0.75 lb = $2.65

1 lb = x

Using cross multiplication :

0.75 * x = $2.65 * 1

0.75x = $2.65

Divide both sides by 0.75

0.75x / 0.75 = $2.65 / 0.75

x = $3.533

This means that :

The price per unit of salami is $3.53

Answer:

0.75 lb of salami for $2.65 is $3.53 per lb of salami.

A sample of 16 ATM transactions shows a mean transaction time of 67 seconds with a standard deviation of 12 seconds. Find the test statistic to decide whether the mean transaction time exceeds 60 seconds.
a. 1.457
b. 2.333
c. 1.848
d. 2.037

Answers

Answer:

b. 2.333

Step-by-step explanation:

Test if the mean transaction time exceeds 60 seconds.

At the null hypothesis, we test if the mean transaction time is of 60 seconds, that is:

[tex]H_0: \mu = 60[/tex]

At the alternate hypothesis, we test if it exceeds, that is:

[tex]H_1: \mu > 60[/tex]

The test statistic is:

[tex]t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, s is the standard deviation of the sample and n is the size of the sample.

60 is tested at the null hypothesis:

This means that [tex]\mu = 60[/tex]

A sample of 16 ATM transactions shows a mean transaction time of 67 seconds with a standard deviation of 12 seconds.

This means that [tex]n = 16, X = 67, s = 12[/tex]

Value of the test statistic:

[tex]t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}[/tex]

[tex]t = \frac{67 - 60}{\frac{12}{\sqrt{16}}}[/tex]

[tex]t = \frac{7}{3}[/tex]

[tex]t = 2.333[/tex]

Thus, the correct answer is given by option b.

Select all the expressions that are equivalent to 13 - x *

Answers

You gave no options but the simplest way to solve this is to set it equal to all of the answers to see if it is correct.

HELP ANYONE OUT THERE WITH MY MATH

Answers

Answer:

x is 37.,.,.,.,.,.,.,.,.,.,.,.,.,.,.,.

Answer:

x = 37

Step-by-step explanation:

Interior angles of a square is 90 each.

∠JKL = 90°

Given ∠JKL = 3x - 21

Therefore, 3x - 21 = 90

                    3x = 90 + 21

                    3x = 111

                      x =  37

22 hours. A
Silas ran 100 m race at a speed of 8 m/s. How long did it take him to com-
plete the race?​

Answers

Answer:

100/8 = 12.5 (s)

Step-by-step explanation:

hmm bro

Answer:

[tex]{ \boxed{ \tt{formular : { \bf{ \green{time = \frac{distance}{speed} }}}}}} \\ time = \frac{100}{8} \\ { \boxed{time = 12.5 \: seconds}} \\ \\ { \underline{ \blue{ \tt{becker \: jnr}}}}[/tex]

Illustrative Example 1:
The grades in Statistics of 10 students are 87, 84, 85, 85, 86, 90, 79, 82, 78, 76.
What is the mode?​

Answers

Given:

The data set is:

87, 84, 85, 85, 86, 90, 79, 82, 78, 76

To find:

The mode of the given data set.

Solution:

We have,

87, 84, 85, 85, 86, 90, 79, 82, 78, 76

Arrange the data values in the ascending order.

76, 78, 79, 82, 84, 85, 85, 86, 87, 90

We know that the mode of date set is the most frequency value of the data set.

From the above data set it is clear that the number 85 has the highest frequency 2.

Therefore, the mode of the data set is 85.

Differentiate the function. y = (2x - 5)^2 (5 - x)?​

Answers

Answer:

[tex]\displaystyle y' = -(2x - 5)(6x - 25)[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Distributive Property

Algebra I

Terms/CoefficientsFactoring

Calculus

Derivatives

Derivative Notation

Derivative of a constant is 0

Basic Power Rule:

f(x) = cxⁿ f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]:                                                                                    [tex]\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)[/tex]

Derivative Rule [Chain Rule]:                                                                                       [tex]\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]

Step-by-step explanation:

Step 1: Define

Identify

y = (2x - 5)²(5 - x)

Step 2: Differentiate

Derivative Rule [Product Rule]:                                                                        [tex]\displaystyle y' = \frac{d}{dx}[(2x - 5)^2](5 - x) + (2x - 5)^2\frac{d}{dx}[(5 - x)][/tex]Chain Rule [Basic Power Rule]:                                                                        [tex]\displaystyle y' = [2(2x - 5)^{2 - 1} \cdot \frac{d}{dx}[2x]](5 - x) + (2x - 5)^2\frac{d}{dx}[(5 - x)][/tex]Simplify:                                                                                                             [tex]\displaystyle y' = [2(2x - 5) \cdot \frac{d}{dx}[2x]](5 - x) + (2x - 5)^2\frac{d}{dx}[(5 - x)][/tex]Basic Power Rule:                                                                                             [tex]\displaystyle y' = [2(2x - 5) \cdot 1 \cdot 2x^{1 - 1}](5 - x) + (2x - 5)^2(1 \cdot -x^{1 - 1})][/tex]Simplify:                                                                                                             [tex]\displaystyle y' = [2(2x - 5) \cdot 2](5 - x) + (2x - 5)^2(-1)[/tex]Multiply:                                                                                                             [tex]\displaystyle y' = 4(2x - 5)(5 - x) - (2x - 5)^2[/tex]Factor:                                                                                                               [tex]\displaystyle y' = (2x - 5)[4(5 - x) - (2x - 5)][/tex][Distributive Property] Distribute 4:                                                                 [tex]\displaystyle y' = (2x - 5)[20 - 4x - (2x - 5)][/tex][Distributive Property] Distribute negative:                                                    [tex]\displaystyle y' = (2x - 5)[20 - 4x - 2x + 5][/tex][Subtraction] Combine like terms (x):                                                              [tex]\displaystyle y' = (2x - 5)[20 - 6x + 5][/tex][Addition] Combine like terms:                                                                        [tex]\displaystyle y' = (2x - 5)(25 - 6x)[/tex]Factor:                                                                                                               [tex]\displaystyle y' = -(2x - 5)(6x - 25)[/tex]

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

Will mark Brainlest hellpppp​

Answers

[tex]h(-3) - h( - 2) = - \frac{5}{ 8} \\ \\ [/tex]

Step-by-step explanation:

[tex]\boxed{h(x) = \frac{2 {x}^{2} - x + 1}{3x - 2}}[/tex]

[tex]h(2) = \frac{2 {(2)}^{2} - (2) + 1}{3(2) - 2} [/tex]

[tex]h(2) = \frac{2 {(4)} - 2 + 1}{6 - 2} [/tex]

[tex]h(2) = \frac{ 8 - 1}{4} [/tex]

[tex]h(2) = \frac{7}{4}[/tex]

[tex]h( - 3) = \frac{2 {( - 3)}^{2} - ( - 3) + 1}{3( - 3) - 2} \\ h( - 3) = \frac{2 (9) + 3 + 1}{ - 9- 2} \\ h( - 3) = \frac{18 + 4}{ - 11} \\ h( - 3) = \frac{22}{ - 11} \\ h(-3) = -2[/tex]

[tex]h( - 2) = \frac{2 {( - 2)}^{2} - ( - 2) + 1}{3( - 2) - 2} \\ h( - 2) = \frac{2 (4) + 2+ 1}{- 6 - 2} \\ h( - 2) = \frac{8 + 3}{- 8} \\ h( - 2) = \frac{11}{- 8} [/tex]

[tex]h(3) - h( - 2) = -2 - \frac{11}{- 8} \\ h(3) - h( - 2) =-2 + \frac{11}{ 8} \\ h(3) - h( - 2) = \frac{-2}{1}+ \frac{11}{ 8} \\ h(3) - h( - 2) = \frac{-16}{8} + \frac{11}{ 8} \\ h(3) - h( - 2) = \frac{-16+11}{8} \\ h(3) - h( - 2) = \frac{-5}{8} \\ - \frac{5}{ 8} [/tex]

Please help

A. B.C. D

Answers

Its d I took that test

mary is 1 m 15 cm tall. her friend larry is 1 m 30 cm tall. who is taller and by how much?

Answers

Answer:

Mary's friend Larry is taller by 15cm.

Step-by-step explanation:

First look for the bigger number.

Then subtract the smaller number from the bigger number.

How do you work out the total surface area of a cuboid (equation)

Answers

Answer:

A cuboid has a total of 6 rectangular sides. If you calculate the area of each of the 6 rectangular sides and add them up, you will get the surface area of the cuboid.

Surface Area of a Rectangle = Width x Height

9x5
pls help meeeeeeeeee

Answers

Answer:

45

hope this helps

Answer:

45

Step-by-step explanation:

9x5=45

Nine subtracted from four times a number is -21 what is the number?

Answers

Answer:

-3

Step-by-step explanation:

My knowledge ;D

In function notation, f(x) is another way of saying ______.
1.)y
2.)x
3.)or none of the above

Answers

Answer:

y

Step-by-step explanation:

In function notation, f(x) is another way of saying y. Then the correct option is A.

What is a function?

A function is an assertion, concept, or principle that establishes an association between two variables. Functions may be found throughout mathematics and are essential for the development of significant links.

Tables, symbols, and graphs can all be used to represent functions. Every one of these interpretations has benefits. Tables provide the functional values of certain inputs in an explicit manner. How to compute direct proportionality is succinctly stated in symbolic representation.

The function is represented as,

y = f(x)

In function notation, f(x) is another way of saying y. Then the correct option is A.

More about the function link is given below.

https://brainly.com/question/5245372

#SPJ2

Dertemine a área total at

Answers

Rectangle: A=width•length
Square: A = a^2

ASAP PLEASE!!The table and the relative frequency histogram show the distribution of the number of tails and three coins are tossed. Find the probability P(T=1). write your answer as a fraction.

Answers

Answer:  3/8

Explanation:

P(T = 1) is the notation that means "The probability of getting exactly one tail". The table shows 3/8 in the bottom row, under the "1" in the top row. So that's why P(T = 1) = 3/8

Or it might make more sense to say P(one tail) = 3/8 so we don't have too many equal signs going on.

Peggy constructed the 95 percent confidence interval (4.8,5.2) to estimate the slope of a regression model for a set of bivariate data with 24 data values. Peggy claims that the width of the confidence interval will increase if a sample size of 30 is used, all other things remaining the same. Quincy claims that the width of the confidence interval will decrease if a sample size of 30 is used. Which statement is true about the claims made by Peggy and Quincy?
А. Peggy's claim is correct.
B. Quincy's claim is correct.
C. Both Peggy's claim and Quincy's claim are correct
D. Neither Peggy's claim nor Quincy's claim is correct.
E. There is not enough information to determine whether the claims are correct.

Answers

Answer:

B. Quincy's claim is correct.

Step-by-step explanation:

Margin of error of a confidence interval:

The margin of error of a confidence interval has the following format:

[tex]M = z\frac{s}{\sqrt{n}}[/tex]

In which z is related to the confidence level, s is the standard error and n is the size of the sample.

From this interval, we have that the margin of error and the sample size are inversely proportional, that is, if we increase the sample size, the margin of error decreases, and so does the width of the confidence interval.

Peggy claims that the width of the confidence interval will increase if a sample size of 30 is used, all other things remaining the same.

Peggy is wrong, as the increase of the sample size results on the decrease of the margin of error, and a decrease of the width.

Quincy claims that the width of the confidence interval will decrease if a sample size of 30 is used.

Margin of error decreases, and so does the width of the interval, thus, Quincy's claim is correct, and the correct answer is given by option b.

Helpppppppp thank u so much

Answers

Answer:

acute triangle

Step-by-step explanation:

First find the other angle

The sum of the angles is 180

x+65+60  = 180

x + 125 = 180

x = 180-125

x = 55

All three angles are different so all three side lengths are different

All the angles are less than 90 so all the angles are acute

This is an acute scalene triangle

Answer:

im is 55 so the only correct option is c

Step-by-step explanation:

hope this helps! have a great day!!

If x = 82°, find the measures of angles 1, 2, and 3

Answers

Answer:

98

Step-by-step explanation:

x(o) + 1(o)  = 180(o)

∠2° = ∠x°

∠1° = ∠3°

Answer:

angle 2 is 82 also and angle 3 and 4 is 180 - 82 = 98

please answer i will mark brainliest :)

Answers

Answer:

c I think that's the right answer

..........................................................

Answers

make ur pizza- and then reply with what u put so iv u need help with finding a profit

Right triangle ABC is shown.

Triangle A B C is shown. Angle A C B is a right angle and angle C B A is 50 degrees. The length of A C is 3 meters, the length of C B is a, and the length of hypotenuse A B is c.

Which equation can be used to solve for c?

sin(50o) = StartFraction 3 Over c EndFraction
sin(50o) = StartFraction c Over 3 EndFraction
cos(50o) = StartFraction c Over 3 EndFraction
cos(50o) =

Answers

Answer:

A and A.

Step-by-step explanation:

Got it correct on edge 2022.

Somebody help me with this

Answers

Answer: 3x4 +x3+ 15x2+30x-14

Multiply(distribute) (x2-x+7) with (3x2+4x-2) and combine like terms.

Answer:

3x4 +x3+ 15x2+30x-14

Step-by-step explanation:

25. Approximate the sample variance and standard deviation given the following frequency distribution: Class Frequency 0–9 13 10–19 7 20–29 10 30–39 9 40–49 11

Answers

Answer:

Sample variance = 228.408

Standard deviation = 15.113

Step-by-step explanation:

The well formatted frequency table has been attached to this response.

To calculate the sample variance and standard deviation of the given grouped data, follow these steps:

i. Find the midpoint (m) of the class interval.

This is done by adding the lower bounds and upper bounds of the class intervals and dividing the result by 2. i.e

For class 0 - 9, we have

m = (0 + 9) / 2 = 4.5

For class 10 - 19, we have

m = (10 + 19) / 2 = 14.5

For class 20 - 29, we have

m = (20 + 29) / 2 = 24.5

For class 30 - 39, we have

m = (30 + 39) / 2 = 34.5

For class 40 - 49, we have

m = (40 + 49) / 2 = 44.5

This is shown in the third column of the attached table.

ii. Find the product of each of the frequencies of the class intervals and their corresponding midpoints. i.e

For class 0 - 9, we have

frequency (f) = 13

midpoint (m) = 4.5

=> f x m = 13 x 4.5 = 58.5

For class 10 - 19, we have

frequency (f) = 7

midpoint (m) = 14.5

=> f x m = 7 x 14.5 = 101.5

For class 20 - 29, we have

frequency (f) = 10

midpoint (m) = 24.5

=> f x m = 10 x 24.5 = 245

For class 30 - 39, we have

frequency (f) = 9

midpoint (m) = 34.5

=> f x m = 9 x 34.5 = 310.5

For class 40 - 49, we have

frequency (f) = 11

midpoint (m) = 44.5

=> f x m = 11 x 44.5 = 489.5

This is shown in the fourth column of the attached table.

iii. Calculate the mean (x) of the distribution i.e

This is done by finding the sum of all the results in (ii) above and dividing the outcome by the sum of the frequencies. i.e

x = ∑(f x m) ÷ ∑f

Where;

∑(f x m) = 58.5 + 101.5 + 245 + 310.5 + 489.5 = 1205

∑f = 13 + 7 + 10 + 9 + 11 = 50

=> x = 1205 ÷ 50

=> x = 24.1

Therefore, the mean is 24.1

This is shown on the fifth column of the attached table.

iv. Calculate the deviation of the midpoints from the mean.

This is done by finding the difference between the midpoints and the mean. i.e m - x where x = mean = 24.1 and m = midpoint

For class 0 - 9, we have

midpoint (m) = 4.5

=> m - x = 4.5 - 24.1 = -19.6

For class 10 - 19, we have

midpoint (m) = 14.5

=> m - x = 14.5 - 24.1 = -9.6

For class 20 - 29, we have

midpoint (m) = 24.5

=> m - x = 24.5 - 24.1 = 0.4

For class 30 - 39, we have

midpoint (m) = 34.5

=> m - x = 34.5 - 24.1 = 10.4

For class 40 - 49, we have

midpoint (m) = 44.5

=> m - x = 44.5 - 24.1 = 20.4

This is shown on the sixth column of the attached table.

v. Find the square of each of the results in (iv) above.

This is done by finding (m-x)²

For class 0 - 9, we have

=> (m - x)² = (-19.6)² = 384.16

For class 10 - 19, we have

=> (m - x)² = (-9.6)² = 92.16

For class 20 - 29, we have

=> (m - x)² = (0.4)² = 0.16

For class 30 - 39, we have

=> (m - x)² = (10.4)² = 108.16

For class 40 - 49, we have

=> (m - x)² = (20.4)² = 416.16

This is shown on the seventh column of the attached table.

vi. Multiply each of the results in (v) above by their corresponding frequencies.

This is done by finding f(m-x)²

For class 0 - 9, we have

=> f(m - x)² = 13 x 384.16 =  4994.08

For class 10 - 19, we have

=> f(m - x)² = 7 x 92.16 = 645.12

For class 20 - 29, we have

=> f(m - x)² = 10 x 0.16 = 1.6

For class 30 - 39, we have

=> f(m - x)² = 9 x 108.16 = 973.44

For class 40 - 49, we have

=> f(m - x)² = 11 x 416.16 = 4577.76

This is shown on the eighth column of the attached table.

vi. Calculate the sample variance.

Variance σ², is calculated by using the following relation;

σ² = ∑f(m-x)² ÷ (∑f - 1)

This means the variance is found by finding the sum of the results in (vi) above and then dividing the result by one less than the sum of all the frequencies.

∑f(m-x)² = sum of the results in (vi)

∑f(m-x)² = 4994.08 + 645.12 + 1.6 + 973.44 + 4577.76 = 11192

∑f - 1 = 50 - 1 = 49         {Remember that ∑f was calculated in (iii) above}

∴ σ² = 11192 ÷ 49 = 228.408

Therefore, the variance is 228.408

vii. Calculate the standard deviation

Standard deviation σ, is calculated by using the following relation;

σ =√ [ ∑f(m-x)² ÷ (∑f - 1) ]

This is done by taking the square root of the variance calculated above.

σ = [tex]\sqrt{228.408}[/tex]

σ = 15.113

Therefore, the standard deviation is 15.113

i need the answer of this with steps and solutions fast plz​

Answers

Answer:

[tex] 1 \dfrac{13}{15} [/tex]

Step-by-step explanation:

[tex] 2 \dfrac{1}{5} - \dfrac{1}{3} = [/tex]

[tex] = \dfrac{11}{5} - \dfrac{1}{3} [/tex]

[tex] = \dfrac{33}{15} - \dfrac{5}{15} [/tex]

[tex] = \dfrac{28}{15} [/tex]

[tex] = 1 \dfrac{13}{15} [/tex]

find the value of tan 45° + sin 30°​

Answers

Answer:

I think it's approximately 44°

A company makes plastic baseballs. They put 6 baseballs nackage. Which teple shows the values for Op, the number of baseballs in p packages? Number of packages. P 7 Tamber of baseballs. 5p42 47 52 number of cackages out of basebis 50​

Answers

Answer:

Table C

Step-by-step explanation:

Given

[tex]1\ package = 6\ balls[/tex]

Required

Which table is correct

We have:

[tex]1\ package = 6\ balls[/tex]

For 7 packages, it will be:

[tex]7\ packages = 42\ balls[/tex] --- i.e. 6  * 7

For 8:

[tex]8\ packages = 48\ balls[/tex] --- i.e. 8 * 7

For p packages

[tex]f(p) = 6p[/tex]

Using the above formula, we can conclude that table (C) is correct

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