Evaluate the expression y2-y1/x2-x1 for the pairs (-7,-8) and (-5,2).

Algebra

Answer:

  20

Step-by-step explanation:

T19 = 97

T20 = 102

The 20th term is the first term more than 100.

__

You can find the value of n from ...

  2 +5n > 100

  5n > 98

  n > 19.6

The 20th term is the first term more than 100.

Answer:

£0.60

Step-by-step explanation:

If each pack costs £1.59 and Nadia orders 15 packs,

then the total order before discount = 1.59 x 15 = £23.85

From the table given, we can see that for an order of £23.85 a 2.5% discount will be applied.

Divide £23.85 by 100 to get 1%:  £23.85 ÷ 100 = £0.2385

Now multiply by 2.5 to get 2.5%:  £0.2385 × 2.5 = £0.59625 = £0.60

Alternatively, the calculation in one expression is:

(1.59 × 15) × 0.025 = 0.59625

Answer:

?

Step-by-step explanation:

Answer:

p<6

Step-by-step explanation:

this basically means she can buy 6 pounds or less

Answer:

p<7

Step-by-step explanation:

Answer:

28.26

Step-by-step explanation:

[tex]3.14\times9[/tex]

Calculate the product or quotient
[tex]28.26[/tex]

I hope this helps you

:)

Answer:

-1/4x+3/4

or

-0.25x+0.75

Step-by-step explanation:

g(x) = mx + b

m = slope

b = initial value

m = -1/4

b = 3/4

g(x) = -1/4x+3/4

Hope this helped, let me know if you need more help!

Answer:1244

Step-by-step explanation:

Answer:

Step-by-step explanation:

Use the formula for calculating compound interest PN=P0(1+rk)Nk where N is the unknown, PN=2250, k=1, N=15, and r=0.028. Substitute the values into the formula and simplify.

2250=P(1+0.0281)1⋅15

2250=P(1.028)15

2250=P(1.5132...)

1486.91=P

Rounded to the nearest dollar, Lucy's initial deposit was $1487.

Answer:

ta side from one base to next has  length of x. so we know each side has length x and  the shape they make is a square. This means we are only searching for the diagonal of a square. remember that a diagonal forms and isoscoles right triangle with the 2 sides being equal and the diagonal as the hypotenuse. Using  pythagoream theorem we can say

a^2 + b^2 = c^2 all side lengths are x so we can put x in for a and b  to get

x^2 + x^2 = c^2

2x^2 = c^2

c = x * squareroot(2)

so if the length between bases is 90 ft

c = 90 ft * squareroot(2)

c = 127.28 ft

Step-by-step explanation:

Answer: C 16,200 squared

Step-by-step explanation:

Answer:

[tex]\sf x= 14.04^{\circ \:}[/tex]

using tan rule:

[tex]\sf tan(x)= \dfrac{opposite}{adjacent}[/tex]

solve:

[tex]\rightarrow \sf tan(x)= \dfrac{5}{20}[/tex]

[tex]\rightarrow \sf x= tan^{-1}(\dfrac{5}{20})[/tex]

[tex]\rightarrow \sf x= 14.04^{\circ \:}[/tex]

Answer:

x = 14.04° (nearest hundredth)

Step-by-step explanation:

Use the tan trig ratio:

[tex]\mathsf{\tan(\theta)=\dfrac{O}{A}}[/tex]

where:

Given:

[tex]\implies \mathsf{\tan(x)=\dfrac{5}{20}}[/tex]

[tex]\implies \mathsf{x=\arctan\left(\dfrac{5}{20}\right)}[/tex]

[tex]\implies \mathsf{x=14.04\textdegree \ (nearest \ hundredth)}[/tex]

Answer:

a reflection over the vertical axis, the coordinates would be (-2,5) the first number being the horizontal, second vertical

Answer:

-x^2 +10x + 7

[tex]-x^2 +10x + 7[/tex]

Step-by-step explanation:

its the gray shaded area [(x+1)*(x+7)] minus the white area [(x-1)*(2x)]

AKA: [(x+1)*(x+7)] - [(x-1)*(2x)]

so first you foil to get both areas

gray region: (x+1)*(x+7) = x^2 + 8x + 7

white region: (x-1)*(2x) = 2x^2 - 2x

and then you subtract the white from the gray

[tex](x^2 + 8x + 7) - (2x^2 - 2x)[/tex]

-x^2 +10x + 7

Answer: I'd go with C

Step-by-step explanation:

Answer:

y = 90[tex]\sqrt{2}[/tex]

Step-by-step explanation:

using the sine ratio in the right triangle and the exact value

sin45° = [tex]\frac{1}{\sqrt{2} }[/tex] , then using the 45° angle on the lower left

sin45° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{90}{y}[/tex] = [tex]\frac{1}{\sqrt{2} }[/tex] ( cross- multiply )

y = 90[tex]\sqrt{2}[/tex]

Answer:

1

Step-by-step explanation:

Anything to the exponent of 0 is 1.

Step-by-step explanation:

A Scatter Analysis is used when you need to compare two data sets against each other to see if there is a relationship. Scatter plots are a way of visualizing the relationship; by plotting the data points you get a scattering of points on a graph.

Answer:

2/5x6/7 = 12/35

Step-by-step explanation:

when we multiply fractions we multiply the denominators together and the numerators as well, so 2 x 6 = 12. and  5 x 7 =35

12/35

Answer:48 mm

Step-by-step explanation:

6 x 2 x 4= 48mm

As rest angles have sum 150°

Using angle sum property

Now

Complementary angles have sum 90°

So the complementary angle is 90-30=60°

Option B

Answer:

i think its a

Step-by-step explanation:

Answer: 21.9

Step-by-step explanation:

-Use Pythagoras theorem-

To find hypotenuse: square root 15 squared plus 16 squared

= 21.9

Answer:

<aob=1/2(can + ab)

<aob=1/2(25+46)

<aob=1/2(71)

<aob=35.5

Complete options are;

a. The approximation requires np > 10 and n(1 - p) > 10.

b. The sample size here is too small to use the Normal approximation to the binomial.

c. The approximation requires np > 30.

d. The Normal approximation works better if the success probability p is close to p = 0.5.

Answer:

Option C is false

Step-by-step explanation:

Looking at the options,

In normal approximation to the binomial,

n is the sample size,

p is the given probability.

q = 1 - p

Now, one of the conditions for using normal approximation to the binomial is that; np and nq or n(1 - p) must be greater than 10.

This means that option A is true because we require np or n(1 - p) to be greater than 10.

From Central limit theorem, the sample size needs to be more than 30 for us to use normal approximation. Our sample is 10. Thus, option B is true.

The approximation doesn't require np > 30. Rather it's the sample size that needs to be more than 30. Thus, option C is false.

Generally, when the value of p in a binomial is close to 0.5, the normal approximations will work better than when the value of p is closer to either 0 or 1. The reason is that: for p = 0.5, the binomial distribution will be symmetrical. Thus, option D is correct.

Given parameters:

 Find the slope of the line;

                         -5x + 4y  =  -16

To find the slope of this line, we must express it in linear form according to the equation below;

                        y  = mx + c

Where x and y are the coordinates

                m is the slope

                c is the intercept

 Now let us write the given equation in this form;

                      -5x + 4y  =  -16

                    Take add +5x to both sides;

                    -5x + 4y + 5x  = 5x - 16

                              4y  = 5x - 16

  Now, divide through by 4;

                         [tex]\frac{4y}{4}[/tex]   = [tex]\frac{5x}{4}[/tex]  - [tex]\frac{16}{4}[/tex]

                        y  = [tex]\frac{5x}{4} - 4[/tex]

So the slope of the line is [tex]\frac{5}{4}[/tex]

f(z-5)=z-5-2

f(z-5)=z-9

Answer:

77

Step-by-step explanation:

<DBE and <ABE are supplementary angles so their sum is equal to 180

<DBE is given as 103

103 + <ABE = 180 subtract 103 from both sides

<ABE = 77

First look for the fundamental solutions by solving the homogeneous version of the ODE:

[tex]y''+3y'=0[/tex]

The characteristic equation is

[tex]r^2+3r=r(r+3)=0[/tex]

with roots [tex]r=0[/tex] and [tex]r=-3[/tex], giving the two solutions [tex]C_1[/tex] and [tex]C_2e^{-3t}[/tex].

For the non-homogeneous version, you can exploit the superposition principle and consider one term from the right side at a time.

[tex]y''+3y'=2t^4[/tex]

Assume the ansatz solution,

[tex]{y_p}=at^5+bt^4+ct^3+dt^2+et[/tex]

[tex]\implies {y_p}'=5at^4+4bt^3+3ct^2+2dt+e[/tex]

[tex]\implies {y_p}''=20at^3+12bt^2+6ct+2d[/tex]

(You could include a constant term f here, but it would get absorbed by the first solution [tex]C_1[/tex] anyway.)

Substitute these into the ODE:

[tex](20at^3+12bt^2+6ct+2d)+3(5at^4+4bt^3+3ct^2+2dt+e)=2t^4[/tex]

[tex]15at^4+(20a+12b)t^3+(12b+9c)t^2+(6c+6d)t+(2d+e)=2t^4[/tex]

[tex]\implies\begin{cases}15a=2\\20a+12b=0\\12b+9c=0\\6c+6d=0\\2d+e=0\end{cases}\implies a=\dfrac2{15},b=-\dfrac29,c=\dfrac8{27},d=-\dfrac8{27},e=\dfrac{16}{81}[/tex]

[tex]y''+3y'=t^2e^{-3t}[/tex]

[tex]e^{-3t}[/tex] is already accounted for, so assume an ansatz of the form

[tex]y_p=(at^3+bt^2+ct)e^{-3t}[/tex]

[tex]\implies {y_p}'=(-3at^3+(3a-3b)t^2+(2b-3c)t+c)e^{-3t}[/tex]

[tex]\implies {y_p}''=(9at^3+(9b-18a)t^2+(9c-12b+6a)t+2b-6c)e^{-3t}[/tex]

Substitute into the ODE:

[tex](9at^3+(9b-18a)t^2+(9c-12b+6a)t+2b-6c)e^{-3t}+3(-3at^3+(3a-3b)t^2+(2b-3c)t+c)e^{-3t}=t^2e^{-3t}[/tex]

[tex]9at^3+(9b-18a)t^2+(9c-12b+6a)t+2b-6c-9at^3+(9a-9b)t^2+(6b-9c)t+3c=t^2[/tex]

[tex]-9at^2+(6a-6b)t+2b-3c=t^2[/tex]

[tex]\implies\begin{cases}-9a=1\\6a-6b=0\\2b-3c=0\end{cases}\implies a=-\dfrac19,b=-\dfrac19,c=-\dfrac2{27}[/tex]

[tex]y''+3y'=\sin(3t)[/tex]

Assume an ansatz solution

[tex]y_p=a\sin(3t)+b\cos(3t)[/tex]

[tex]\implies {y_p}'=3a\cos(3t)-3b\sin(3t)[/tex]

[tex]\implies {y_p}''=-9a\sin(3t)-9b\cos(3t)[/tex]

Substitute into the ODE:

[tex](-9a\sin(3t)-9b\cos(3t))+3(3a\cos(3t)-3b\sin(3t))=\sin(3t)[/tex]

[tex](-9a-9b)\sin(3t)+(9a-9b)\cos(3t)=\sin(3t)[/tex]

[tex]\implies\begin{cases}-9a-9b=1\\9a-9b=0\end{cases}\implies a=-\dfrac1{18},b=-\dfrac1{18}[/tex]

So, the general solution of the original ODE is

[tex]y(t)=\dfrac{54t^5 - 90t^4 + 120t^3 - 120t^2 + 80t}{405}\\\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,-\dfrac{3t^3+3t^2+2t}{27}e^{-3t}-\dfrac{\sin(3t)+\cos(3t)}{18}[/tex]

Step-by-step explanation:

Let an angle = x

x= 70+(90-x)

x= 160-x

2x=160

x=80

So angle is 80 and it's complementary angle would be 10

Answer:

55∘ and 125∘

Step-by-step explanation:

Supplementary angles sum to

180∘

let one angle be [tex]x[/tex]

then the other angle is [tex]x+70[/tex]

summing the 2 angles gives

[tex]x+x+7=180[/tex]

[tex]2x+70=180[/tex]

subtract 70 from both sides

[tex]2x=180 -70=110[/tex]

divide both sides by

[tex]2x=\frac{110}{2} =55[/tex]

thus the angles are

55∘ and  55 + 70= 125∘