Examples of Newton's three law of motion.
First law of motion: A rocket being launched up in the atmosphere.
Second law of motion:while riding a bicycle, a bicycle acts as a mass and our legs pushing on the pedals of the bicycle is the force.
Third law of motion:when we jump off from the boat,the boat moves backward.
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ifif it takes 1-minute for 45 c of charge to pass a point in an electric circuit what is the current through the circuit?
Answer:
45C in a minute is
45/60 C in a second
.75 C in a second is 3/4 of an ampere.
Explanation:
The current through a circuit when it takes one minute for 45C of charge to pass to a point in an electric circuit is 0.75 Ampere.
What is an electric circuit?
The electric circuit: a way for current to travel. A battery or generator is a device that provides energy to the charged particles that make up the current, a device that uses current, such as a lamp, an electric motor, or a computer, and the connecting wires or transmission lines to make up an electric circuit. Ohm's law and Kirchhoff's rules are two fundamental laws that quantitatively define how electric circuits function.
Given information,
The charge, q = 45 coulombs,
the time, t =1 minute
t = 60 sec
A minute at 45C is, In one second, 45/60 C,3/4 of an ampere is equal to 0.75 C per second.
Therefore, the current through a circuit when it takes one minute for 45C of charge to pass to a point in an electric circuit is 0.75 Ampere.
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A stone is thrown vertically upwards with an initial velocity 20m/s. Find the maximum height it reaches and the time taken by it to reach the height.
(g= 10m/s)
who gives answer with explanation i will make him braillint
Answer:
The maximum height it reaches will be 20 m.
The time taken by it to reach the height will be: t = 2 seconds.
Explanation:
We know the equation of the motion under gravity
v² - u² = 2gs
u = initial velocity = 20 m/s
v = final velocity = 0 m/s
[tex]s\:=\:h_{max}[/tex]
so
[tex]v^{2} \:-\:u^{2} \:=\:2gs[/tex]
substituting u = 20 m/s, v = 0 m/s, g = -10 and [tex]s\:=\:h_{max}[/tex]
[tex]\left(0\right)^2-\:\left(20\right)^2=\:2\left(-10\right)\times h_{max}[/tex]
[tex]2\left(-10\right)\times h_{max}=-400[/tex]
[tex]\frac{2\left(-10\right)h_{max}}{-20}=\frac{-400}{-20}[/tex]
[tex]\:h_{max}=20[/tex] m
Therefore, the maximum height it reaches will be 20 m.
We know the equation
u = gt
substitute u = 20, g = 10
20 = 10 × t
t = 20/10
t = 2 seconds
Therefore, the time taken by it to reach the height will be: t = 2 seconds.
A stone is thrown vertically upwards with an initial velocity 20m/s. Find the maximum height it reaches and the time taken by it to reach the height.
(g= 10m/s)
who gives answer with explanation i will make him braillint
Answer:
20metere
Y=VOYYT-1/2gt^2H=20m/s*2s-1/2*10m/s^2(2s)^H=40m-1/2*10 4s^240m-20H=20mHow much force would be needed to
push a 22 kg box across the floor with
an acceleration of 1.9 m/s^2? Assume
that there is a coefficient of friction of.
17 between the box and the floor.
Help me with this!!!!!!!it’s due in 10 minutes
There would be two forces acting on the box parallel to the floor, with a net force of
∑ F = p - f = m a
where p = magnitude of the push, f = mag. of friction, m = mass of the box, and a = acceleration. To find p, we first need f .
There are also only two forces acting on the box perpendicular to the floor, with net force
∑ F = n - w = 0
where n = mag. of normal force of the floor on the box and w = weight of the box. The net force is 0 because the box is only accelerating parallel to the floor.
w = m g, where g = 9.8 m/s² is the mag. of the acceleration due to gravity, so we can solve for n :
n = w = m g
n = (22 kg) (9.8 m/s²)
n = 215.6 N
The kinetic friction is proportional to the normal force by a factor of the given coefficient of friction, µ = 0.17, such that
f = µ n
f = 0.17 (215.6 N)
f = 36.652 N
Now solve for the required pushing force:
p - 36.652 N = (22 kg) (1.9 m/s²)
p ≈ 78 N
Answer:
0
Explanation:
define vector quantity giving examples
Answer:
Quantity with direction and magnitude
Displacement
Explanation:
Compare the rate of heat transfer by radiation for two objects, the first one has the temperature Ts1= 25 degree Celsius and the second is kept at temperature Ts2 = 40 degree Celsius. Suppose they are made of identical material (e1=e2) and have the same area participating in radiation (Ar1=Ar2). The Surrounding temperature Tr= 25 degree Celsius.
Answer:
The rate of heat transfer of the second object is greater than the first object.
Explanation:
[tex]\varepsilon[/tex] = Emissivity of the object
[tex]\sigma[/tex] = Stefan-Boltzmann constant = [tex]5.67\times 10^{-8}\ \text{W/m}^2/\text{K}^4[/tex]
[tex]T_1[/tex] = Temperature of surface 1 = [tex]25^{\circ}\text{C}+273.15=298.15\ \text{K}[/tex]
[tex]T_2[/tex] = Temperature of surface 2 = [tex]40^{\circ}\text{C}+273.15=313.15\ \text{K}[/tex]
[tex]T_0[/tex] = Surrounding temperature = [tex]25^{\circ}\text{C}+273.15=298.15\ \text{K}[/tex]
Rate of heat transfer is given by
[tex]P_1=\varepsilon \sigma (T_1^4-T_0^4)\\\Rightarrow P_1=\varepsilon \sigma A_1(298.15^4-298.15^4)\\\Rightarrow P_1=0\ \text{W}[/tex]
[tex]P_2=\varepsilon \sigma (T_2^4-T_0^4)\\\Rightarrow P_2=\varepsilon 5.67\times10^{-8} A_2(313.15^4-298.15^4)\\\Rightarrow P_2=\varepsilon A_297.2[/tex]
[tex]\varepsilon A_297.2>0[/tex]
So, [tex]P_2>P_1[/tex]
Hence, the rate of heat transfer of the second object is greater than the first object.
write any one advantage and disadvantage of eddy current
Explanation:
[tex]advantage[/tex]
It is Sensitivity to surface defects. ...
[tex]disadvantage[/tex]
There is a major heat loss during cycling eddy currents due to friction in the magnetic circuit, especially where the core is saturated
Please mark as brainliest answer
What did James Hutson do
Answer:
Dr Hutson is the author of several books among them: John Adams and the Diplomacy of the American Revolution (1980); winner of the Gilbert Chinard Prize, 1981; To Make All Laws: The Congress of the United States, 1789-1989 (Washington and Boston, 1989-90; 4th edition, Washington, 1990); The Sister Republics
Answer:
Dr Hutson is the author of several books among them: John Adams and the Diplomacy of the American Revolution (1980); winner of the Gilbert Chinard Prize, 1981; To Make All Laws: The Congress of the United States, 1789-1989 (Washington and Boston, 1989-90; 4th edition, Washington, 1990); The Sister Republics: ... Explanation: HOPE I HELPED!!!!!
The vertical force f acts downward at A on the two membered frames. Determine the magnitude of the two components of F directed along axes of AB and AC. Set F=500N
Answer:
The magnitude will be "353.5 N". A further solution is given below.
Explanation:
The given values is:
F = 500 N
According to the question,
In ΔABC,
⇒ [tex]\angle BCA = (90-30)[/tex]
⇒ [tex]=60^{\circ}[/tex]
then,
⇒ [tex]\angle BAC=(180-45-60)[/tex]
⇒ [tex]=75^{\circ}[/tex]
Now,
The corresponding angle will be:
⇒ [tex]\angle FAC=60^{\circ}[/tex]
⇒ [tex]\angle FAB=70+60[/tex]
⇒ [tex]=135^{\circ}[/tex]
Aspect of F across the AC arm will be:
= [tex]F\times cos(60)[/tex]
On putting the values of F, we get
= [tex]500\times (.5)[/tex]
= [tex]200 \ Newton[/tex]
Component F along the AC (in magnitude) will be:
= [tex]F\times cos(135)[/tex]
= [tex]500\times (-.707)[/tex]
= [tex]-353.5 \ N \[/tex]
what is the difference between beat and beat frequency.
Explanation:
The beat is a word used for sound waves. The beat frequency is the difference in frequency of two waves. ... In sound, we hear said beat frequency as the rate at which the loudness of the sound varies whereas we hear the ordinary frequency of the waves as the pitch of the sound.
Explanation:
Beats :--
A wave not only travels in space but it also propagates through time, so if the two waves can produce interference by overlapping in space they should also produce an interference pattern when they overlap in time, this phenomenon is called beats.
Beat Frequency :--
The beat frequency is when two sound waves with different frequencies come across each other, then their amplitude gets added and subtracted alternatively for a given time period. This leads to the growth of the sound to louder and softer.
A tank holding 70 liters of water is heated by a 18000W electric immersion heater. If the specific heat capacity of water is 4200 J/(kg .℃), Calculate the time to change the temperature from 20 Degree Celsius to 100 degree Celsius.
Answer:
1306.67 s
Explanation:
From the question given above, the following data were obtained:
Volume of water = 70 L
Power (W) = 18000 w
Specific heat capacity (C) = 4200 J/g℃
Initial temperature (T1) = 20 ℃
Final temperature (T2) = 100 ℃
Time (t) =?
Next, we shall determine the mass of the water. This can be obtained by converting 70 L to kg. This is illustrated below:
1 L = 1 kg
Therefore,
70 L = 70 Kg
Thus, the mass of the water is 70 kg.
Next, we shall determine the heat energy involved. This is can be obtained as follow:
Mass (M) of water = 70 Kg
Specific heat capacity (C) = 4200 J/g℃
Initial temperature (T1) = 20 ℃
Final temperature (T2) = 100 ℃
Heat Energy (Q) =?
Q = MC(T2 – T1)
Q = 70 × 4200 × (100 – 20)
Q = 294000 × 80
Q = 3520000 J
Thus, the heat energy involved is 3520000 J
Finally, we shall determine the time taken.
Power (W) = 18000 w
Heat Energy (Q) = 3520000 J
Time (t) =?
Power = energy / time
18000 = 3520000 / time
Cross multiply
18000 × time = 3520000
Divide both side by 18000
Time = 3520000 / 18000
Time = 1306.67 s
How does a decrease in thermal energy affect the kinetic energy of the particles in each state of matter?
Answer:
kinetic and potential energy). The opposite is true when you remove thermal energy: Particles move slower (less kinetic energy). Particles get closer together (less potential energy)
Answer:
Explanation:
kinetic and potential energy). The opposite is true when you remove thermal energy: Particles move slower (less kinetic energy). Particles get closer together (less potential energy).
Does this make sense??-
what is the correct answer?
Answer:
length=2
Explanation:
You simply find the zeros of the quartic polynomial
The factored form is (x+1)(x-5)(x-2)=0
The zeros become -1,5 and 2
Dimension 5 is already given and the question says length>width and 2>-1
Therefore length=2
What voltage is required to move 6A through 20?
Answer:
120V
Explanation:
Given parameters:
Current = 6A
Resistance = 20Ω
Unknown:
Voltage = ?
Solution:
According to ohms law;
V = IR
Where V is the voltage
I is the current
R is the resistance
Now, insert the parameters and solve;
V = 6 x 20 = 120V
2km south is a measure of what
The answer Is kilometers
Billy throws a peach vertically upward. It takes 3 seconds for the peach to land back in his hand. How fast did Billy throw the peach?
Answer:
48 ft/s
Explanation:
Acceleration due to gravity decreased the upward velocity to zero in 1.5 seconds (half the total time), so the initial velocity must have been ...
(32 ft/s^2)(1.5 s) = 48 ft/s
N in-ground swimming pool has the dimensions shown in the drawing. It is filled with water to a uniform depth of 3.00 m. The density of water = 1.00 × 103 kg/m3. What is the total pressure exerted on the bottom of the swimming pool? 1.97 × 105 Pa 2.49 × 105 Pa 2.94 × 104 Pa 1.80 × 105 Pa 1.31 × 105 Pa
Answer:
The pressure is [tex]P = 1.31*10^{5} \ Pa[/tex]
Explanation:
From the question we are told that
The depth of the swimming pool is [tex]d = 3.00 \ m[/tex]
The density of water is [tex]\rho = 1.00*10^{3} \ kg /m^3[/tex]
Generally the total pressure exerted on the bottom of the swimming pool is mathematically represented as
[tex]P = P_o + \rho * g * h[/tex]
Here [tex]P_o[/tex] is the atmospheric pressure with value
[tex]P_o = 101325 \ Pa[/tex]
So
[tex]P = 101325 + [1000 * 9.8 * 3][/tex]
=> [tex]P = 130725 \ Pa[/tex]
=> [tex]P = 1.31*10^{5} \ Pa[/tex]
WHICH ONE IS IT????
RINGS
POINT
GRAPH
READS
TALKS
Answer: c or b
Explanation:
A ball is launched with an initial horizontal velocity of 10.0 meters per second. It takes 500 milliseconds for the ball to reach its maximum height.
Determine the maximum horizontal distance that the ball will travel.
Calculate the initial vertical velocity of the ball.
Answer:
500ms times 2 would be when the ball reaches the max horizontal distance.
Then to find the angle, use the formula of time to reach max height t = u sin theta / g . With t being the max height time 500ms, u being 10m/s
For initial vertical velocity just use u sin theta.
The max horizontal height is "10 meters" and the initial vertical velocity is "4.9 m/s".
Given:
Horizontal velocity,
[tex]V_x = 10 \ m/s[/tex]Time,
t = 500 m/sAt max height,
[tex]V_{yf} = 0 \ m/s[/tex](a)
→ Time to flight (T) will be:
= [tex]2t[/tex]
= [tex]2\times 0.5[/tex]
= [tex]1 \ second[/tex]
→ Horizontal distance will be:
= [tex]V_x\times T[/tex]
= [tex]10\times 1[/tex]
= [tex]10 \ meters[/tex]
(b)
→ The initial vertical velocity will be:
[tex]V_{yf} = V_y +gt[/tex]
[tex]0 = V_y - 9.8\times 0.5[/tex]
[tex]V_y = 4.9 \ m/s[/tex]
Thus the above answers are correct.
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Which two options describles physical properties of matter?
A. a substance's pH
B. a substance's resistance to flow
C. a substance's ability to conduct electricity
D. whether a substance rusts
E. a substance's inability to combine with other substances
The correct options that describe the physical properties of matter are "A substance's resistance to flow," and "A substance's ability to conduct electricity." The correct options are B and C.
What is the physical properties of matter?Physical properties of matter are characteristics that can be observed or measured without changing the substance's identity. These properties can help us identify and classify different substances.
Here in the Question,
Let's consider each option one by one:
A. A substance's pH is a chemical property of matter, which indicates whether a substance is acidic, neutral, or basic. It depends on the substance's chemical composition and the concentration of hydrogen ions in it. Therefore, this option is not a physical property.
B. A substance's resistance to flow is a physical property, also known as viscosity. It refers to how easily a substance can flow or be poured. For example, honey has a high viscosity, while water has a low viscosity. This property depends on the intermolecular forces between the molecules of the substance, which affect how closely they pack together. Therefore, this option is a physical property.
C. A substance's ability to conduct electricity is a physical property that depends on its structure and the presence of charged particles, such as ions or electrons. Substances that can conduct electricity are called conductors, while those that cannot are called insulators. Metals are good conductors of electricity, while plastics are good insulators. Therefore, this option is also a physical property.
D. Whether a substance rusts is a chemical property that indicates how a substance reacts with other substances, specifically with oxygen. Rusting occurs when iron or steel reacts with oxygen in the presence of water, forming a reddish-brown compound called iron oxide. Therefore, this option is not a physical property.
E. A substance's inability to combine with other substances is also a chemical property that depends on the substance's reactivity. Inability to combine with other substances may be due to a substance's stable electronic configuration, such as noble gases. Therefore, this option is also not a physical property.
Therefore, options B and C are true.
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some sedimentary rocks are made from smaller rounded stones that have been cemented together called what?
A: Intrusive rock
B: conglomerate rock
C: extrusive rock
D: marble
Answer:
B.
Explanation:
Intrusive and extrusive rocks are igneous rocks and marble is metamorphic, by the process of elimination, B would be the correct answer.
Answer:
answer is B
Explanation:
Explain how itis possible for electron-group geometry to difer trom molecular geometry. Use the Lewis dot diagram below to help in your explanation
Answer:
If lone pairs of electrons, electrons not bonded to other atoms, are located in the molecule, this will change the molecular geometry, not the electron geometry. If all the electron groups are bonded, with no lone pairs, then the electron geometry and molecular geometry are the same.
1. The coin remains at rest in the figure shown. This is due to
(a) inertia of rest
(b) two forces act on the coin which balance each other
(c) no unbalanced force acts on it
(d) all of these
How does the appearance of each phase of the moon related to the
moon's position relative to Earth and the sun?
Answer:Moon phases are determined by the relative positions of the Moon, Earth, and Sun.
Explanation:
Instead, the Moon's phase depends only on its position relative to Earth and the Sun. The Moon doesn't make its own light, it just reflects the Sun's light as all the planets do.
A helicopter flies over the arctic ice pack at a constant altitude, towing an airborne 137-kg laser sensor that measures the thickness of the ice (see the drawing). The helicopter and the sensor both move only in the horizontal direction and have a horizontal acceleration of magnitude 2.63 m/s2. Ignoring air resistance, find the tension in the cable towing the sensor. Incorrect: Your answer is incorrect.
Answer:
The value is [tex]T = 1702.91 \ N[/tex]
Explanation:
From the question we are told that
The mass of the laser sensor is [tex]m = 137 \ kg[/tex]
The horizontal acceleration of the helicopter and the sensor is [tex]a = 2.63 \ m/s^2[/tex]
Generally the net force on the cable is
[tex]F = T - W = ma[/tex]
Here W is the weight of the sensor which is evaluated as [tex]W = m * g = 137 * 9.8 = 1342.6 \ N[/tex]
So
[tex]T - 1342.6 = 137 * 2.63[/tex]
=> [tex]T = 360.31 + 1342.6[/tex]
=> [tex]T = 1702.91 \ N[/tex]
please help..................
Answer:
PART A
In a solid
The attractive forces keep the particles together tightly enough so that the particles do not move past each other. ... In the solid the particles vibrate in place. Liquid – In a liquid, particles will flow or glide over one another, but stay toward the bottom of the container.
In a liquid
Particles are quite close together and move with random motion throughout the container. Particles move rapidly in all directions but collide with each other more frequently than in gases due to shorter distances between particles.
A gas
The particles move rapidly in all directions, frequently colliding with each other and the side of the container. With an increase in temperature, the particles gain kinetic energy and move faster.
PART B
The molecules are continually colliding with each other and with the walls of the container. When a molecule collides with the wall, they exert small force on the wall The pressure exerted by the gas is due to the sum of all these collision forces. The more particles that hit the walls, the higher the pressure.
Explanation:
GOOD LUCK!!! :)
400 N pushes on a 25-kg box. Starting from rest, the box achieves
a velocity of 2.0 m/s in a time of 4.0 s. Find the coefficient of kinetic friction between box and
floor.
Answer:
The kinetic coefficient of friction between box and floor is 0.443.
Explanation:
Let suppose that the box is accelerated uniformly, the acceleration ([tex]a[/tex]), measured in meters per square second, is determined by the following kinematic formula:
[tex]a = \frac{v_{f}-v_{o}}{t}[/tex] (1)
Where:
[tex]v_{o}[/tex], [tex]v_{f}[/tex] - Initial and final speeds of the box, measured in meters per second.
[tex]t[/tex] - Time, measured in seconds.
If we know that [tex]v_{o} = 0\,\frac{m}{s}[/tex], [tex]v_{f} = 2\,\frac{m}{s}[/tex] and [tex]t = 4\,s[/tex], then the acceleration experimented by the box is:
[tex]a = \frac{2\,\frac{m}{s}-0\,\frac{m}{s} }{4\,s}[/tex]
[tex]a = 0.5\,\frac{m}{s^{2}}[/tex]
Based on the body diagram, we proceed to form the equations of equilibrium:
[tex]\Sigma F_{x} = P\cdot \cos \theta -\mu_{k}\cdot N = m\cdot a[/tex] (1)
[tex]\Sigma F_{y} = N - m\cdot g - P\cdot \sin \theta = 0[/tex] (2)
Where:
[tex]P[/tex] - Magnitude of the force exerted on the box, measured in newtons.
[tex]\theta[/tex] - Direction of the force exerted on the box, measured in sexagesimal degrees.
[tex]\mu_{k}[/tex] - Kinetic coefficient of friction between box and floor, dimensionless.
[tex]N[/tex] - Normal force from the floor to the box, measured in newtons.
[tex]m[/tex] - Mass of the block, measured in kilograms.
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
Now we proceed to solve the system of equation for the kinetic coefficient of friction between box and floor:
By (1)
[tex]\mu_{k}\cdot N = P\cdot \cos \theta -m\cdot a[/tex]
[tex]\mu_{k} = \frac{P\cdot \cos \theta - m\cdot a}{N}[/tex]
By (2)
[tex]N = m\cdot g +P\cdot \sin \theta[/tex]
And then, we get the resulting expression:
[tex]\mu_{k} = \frac{P\cdot \cos \theta - m\cdot a}{m\cdot g + P\cdot \sin \theta}[/tex] (3)
If we know that [tex]P = 400\,N[/tex], [tex]\theta = 50^{\circ}[/tex], [tex]m = 25\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]a = 0.5\,\frac{m}{s^{2}}[/tex], then the kinetic coefficient of friction between box and floor is:
[tex]\mu_{k} = \frac{(400\,N)\cdot \cos 50^{\circ}-(25\,kg)\cdot \left(0.5\,\frac{m}{s^{2}} \right)}{(25\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)+(400\,N)\cdot \sin 50^{\circ}}[/tex]
[tex]\mu_{k} = 0.443[/tex]
The kinetic coefficient of friction between box and floor is 0.443.
The kinetic coefficient of friction between box and floor is 0.443.It is the ratio of friction force and the normal recation force.
What is the friction force?It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N).
Mathematically it is defined as the product of the coefficient of friction and normal reaction.
The given data in the problem is;
F is the force =400 N
m is the mass of box= 25-kg
u is the velocity starting from rest=0
v is the velocity achieved = 2.0 m/s
t is the time = 4.0 s.
[tex]\rm \mu[/tex] is the coefficient of kinetic friction between box and floor.
The aceleration is found as;
[tex]\rm a= \frac{v_f-v_u}{t} \\\\ \rm a= \frac{2-0}{4} \\\\ \rm a= 0.5 m/sec^2[/tex]
The normal reaction force is find as;
[tex]N= mg +P sin \theta[/tex]
The cofficient of the kinetic coefficient of friction between box and floor;
[tex]\rm \mu_k = \frac{Pcos \theta - ma }{N } \\\\ \rm \mu_k = \frac{Pcos \theta - ma }{ mg +P sin \theta } \\\\ \rm \mu_k = \frac{400 cos 50^0 - 25 \times 0.5 }{ 25 \times 9.81 +400 \times sin 50^0 } \\\\ \rm \mu_k =0.443[/tex]
Hence he kinetic coefficient of friction between box and floor is 0.443.
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a golf ball has a mass 0.046 kkg rests on a tee it is struck by a golf club with an effectiv mass of 0.22 and speed of 44 assuming the collision is elastic, find the speed of the ball when it leaves the tee
Answer:
210 m/s
Explanation:
We will use this equation for an elastic collision:
m₁v₁ + m₂v₂ = m₁v₁ + m₂v₂ The left side of the equation is before the collision; the right side is after the collision.In this case, m₁ = mass of golf ball (0.046 kg) and m₂ = mass of the golf club (0.22 kg).
Left side of equation:v₁ is 0 m/s since the ball is at rest on the tee.
v₂ is 44 m/s, given in the problem.
Right side of equation:v₁ is what we are trying to find.
v₂ is 0 m/s since the ball will be at rest on the ground.
⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯Plug these values into the elastic collision equation:
(0.046 kg)(0 m/s) + (0.22 kg)(44 m/s) = (0.046 kg)(v₁) + (0.22 kg)(0 m/s)Simplify this equation.
(0.22 kg)(44 m/s) = (0.046 kg)(v₁)Get rid of the units.
(0.22)(44) = 0.046v₁Multiply the left side of the equation.
9.68 = 0.046v₁Divide both sides by 0.046.
210.434782609 = v₁ 210 m/s = v₁The speed of the ball when it leaves the tee is about 210 m/s.
Which of the following describes Electrical Energy?
A. The energy Associated With Electrical Charges
B. The energy stored in atomic nuclei.
C. The energy that travels through space;also called light energy
D. The energy stored in chemical bonds
A student is eating french fries and needs ketchup. He shakes the ketchup bottle as it is turned upside down but the ketchup won't move. He then smacks the bottle and the ketchup moves. However, the ketchup won't stop moving until he turns the bottle upright. This is an example of ____.
Answer:
I'm thinking Newton's first law of motion.
Explanation:
"An object at rest remains at rest, or if in motion, remains in motion at a constant velocity unless acted on by a net external force."