what do you notice about gravity in space?
Answer:
gravity is everywhere in space and objects in space are always falling: towards the earth, towards the sun, and towards the galactic center
Explanation:
Which term best matches the description of an earthquake?
Where all mass movements occur
Acts as a lubricant to reduce friction between soil grains
Determines how much material is available for mass movement
Occurs when a sheet of rock moves downhill on a sliding surface
Can trigger a sudden mass movement
A force that works to pull material downslope
can tigger sudden mass movement
An astronaut weighs 107 Newtons when he stands on the surface of Europa on one of Jupiter's moons if europa's gravitational acceleration is 1.3 m s squared what is the astronauts Mass
Answer:
I think it would be 179kb
A object with a mass of 1.5 kg is lifted from the ground to a height of 0.22 m what is the objects potential energy
Answer:
3.3 JExplanation:
The potential energy of a body can be found by using the formula
PE = mgh
where
m is the mass
h is the height
g is the acceleration due to gravity which is 10 m/s²
From the question we have
PE = 1.5 × 10 × 0.22
We have the final answer as
3.3 JHope this helps you
A 5 kg rifle fires a 15 g bullet at a muzzle velocity of 600 m/s. Find the recoil velocity of
the rifle
Answer:
v₂ = 1.8 [m/s]
Explanation:
To be able to solve this problem we must raise the principle of conservation and quantity of movement. It is going to study the momentum before and after the firing of the rifle.
P = m*v
where:
P = momentum [kg*m/s]
m = mass [kg]
v = velocity [m/s]
Now we need to analyze the moment before and after the shot.
[tex](m_{1}+m_{2})*v_{1}=-(m_{1}*v_{2})+(m_{2}*v_{3})[/tex]
where:
m₁ = mass of the rifle = 5 [kg]
v₁ = velocity of the rifle and the bullet before firing = 0 (no movement)
m₂ = mass of the bullet = 15 [g] = 0.015 [kg]
v₂ = velocity of recoil [m/s]
v₃ = velocity of the bullet after firing = 600 [m/s]
Now replacing:
[tex](5+0.015)*0 = -(5*v_{2})+(0.015*600)\\9 = (5*v_{2})\\v_{2}=1.8 [m/s][/tex]
Momentum is the product of mass and velocity. The recoil velocity of the rifle weighing 5 kg is 1.8 m/s.
What is conservation of momentum?According to the law of conservation of momentum if two objects are in contact with each other then for that system of the two objects the momentum of the object before will be equal to the momentum of the object after the collision.
GIven to us
Mass of the rifle, M = 5 kg
Mass of the bullet, m = 15 g = 0.015 kg
Velocity of the bullet afterwards, v₂ = 600 m/s
We know that according to the law of conservation of momentum, the momentum of the bullet and riffle before shooting will be equal to the momentum of the bullet and riffle after shooting.
[tex]Mu_1 + mu_1 = Mv_1 + mv_2[/tex]
Since, before shooting the bullet was in the riffle and the velocity of both was 0,
[tex]M(0) + m(0) = Mv_1 + mv_2\\\\-Mv_1 = mv_2\\\\v_1 = -\dfrac{m \times v_2}{M}[/tex]
Substitute the values,
[tex]v_1 = -\dfrac{0.015 \times 600}{5}\\\\v_1 = -1.8\rm\ m/s[/tex]
Thus, the recoil of the rifle is -1.8 m/s, the negative sign denotes that the velocity of recoil was in opposite direction to the bullet.
Hence, the recoil velocity of the rifle weighing 5 kg is 1.8 m/s.
Learn more about Momentum:
https://brainly.com/question/4956182
A baseball is thrown upward at 20m/s. At what time is the ball 10m above the point at which it was released?
Answer:
0.583 seconds
Explanation:
We are dealing with free-fall motion, which has a constant acceleration of -g, acceleration due to gravity, so we can use a constant acceleration equation to solve this problem.
List out known variables and the variable that we want to solve for:
v_0 = 20 m/sa = -9.8 m/s² Δx = 10 mt = ?Find the kinematic equation that contains all four of these variables:
Δx = v_0 t + 1/2at²Plug known values into the equation.
10 = 20 t + 1/2(-9.8)t²Distribute 1/2 inside the parentheses.
10 = 20t - 4.9t²Set the equation equal to 0 and rearrange the terms so they are in descending degree order.
0 = -4.9t² + 20t - 10Factor this equation by using the quadratic formula. You should get:
t = 3.498 s, t = 0.583 sLet's look at these numbers within the context of the problem. If the ball's speed is 20 m/s, then after 1 second, it would reach a height of 20 m.
However, we want to find the time that it would take the ball to reach a height of 10 m, which is half of 20 m. Therefore, the time to reach 10 m should be around 0.5 seconds.
t = 0.583 is the closest to 0.5 seconds, and it fits within the context of the problem. Therefore, the answer is 0.583 seconds.
What is the kinetic energy of a 0.5 kg puppy that is running 1.5m/s
Answer:
0.5625 Joules
Explanation:
The equation to calculate kinetic energy is:
[tex]KE = \frac{1}{2}mv^2[/tex]
So, plug in all given info and calculate:
[tex]KE = \frac{1}{2}(0.5)(1.5)^2 = 0.5625J[/tex]
And that's your answer! :)
A hunter shoots a tranquilizer dart straight at a monkey who is
hanging on a tree branch that is 1.5 meters high. The tree is 16 meters
away from the hunter. The man shot the dart at the monkey with an
initial sideways velocity of 40 m/s, and at the same time, the monkey
let go of the branch. what time will the monkey reach the same height
of the arrow?
t= _S
Answer:
The donkey might be dead
How long does it take the lava bomb to reach its maximum height? Answer with three significant digits and the correct unit. A small volcano's steam pressure belches vertically upward a lava bomb from an initial height of 64.4 m and with an initial upward velocity of 31.4 m/s. Remember gravity's acceleration near earth is g = 9.8 m/s2 down.
Answer:
The time taken to reach the maximum height is 3.20 seconds
Explanation:
The given parameters are;
The initial height from which the volcano erupts the lava bomb = 64.4 m
The initial upward velocity of the lava bomb = 31.4 m/s
The acceleration due to gravity, g = 9.8 m/s²
The time it takes the lava bomb to reach its maximum height, t, is given by the following kinematic equation as follows;
v = u - g·t
Where;
v = The final velocity = 0 m/s at maximum height
u = The initial velocity = 31.4 m/s
g = The acceleration due to gravity = 9.8 m/s²
t = The time taken to reach the maximum height
Substituting the values gives;
0 = 31.4 - 9.8 × t
∴ 31.4 = 9.8 × t
t = 31.4/9.8 ≈ 3.204
The time taken to reach the maximum height rounded to three significant figures = t ≈ 3.20 seconds
A 10 Kg dog is running with a speed of 5.0 m/s what is the minimum work required to stop the dog
Answer:
25J
Explanation:
Given parameters:
Mass of the dog = 10kg
Speed of the dog = 5m/s
Unknown:
The minimum energy required to stop the dog = ?
Solution:
The dog is moving with a kinetic energy and to stop the dog, an equal amount of kinetic energy generated must be applied to the dog.
To find the kinetic energy;
K.E = [tex]\frac{1}{2}[/tex] m v²
m is the mass
v is the velocity
Now insert the parameters and solve;
K.E = [tex]\frac{1}{2}[/tex] x 10 x 5 = 25J
Which of the four spheres is this pictures/scene?
A) hydrosphere
B) biosphere
C) geosphere
D) atmosphere
I believe the correct answer is atmosphere (D).
Answer:
D) atmosphere
Explanation:
but the correct answer is troposhare
If a current of 2.5 Ampere flow through a circuit in 15 minutes calculate amount of charge through a crcuit
Answer:
Q = 2250 Coulombs
Explanation:
We are given;
Current: I = 2.5 A
Time: t = 15 minutes = 15 × 60 seconds = 900 s
Now formula for the amount of charge through the circuit is given by:
Q = It
Thus;
Q = 2.5 × 900
Q = 2250 Coulombs
1. The lamp in your room is marked (100
W, 220 V). What do these readings mean?
Calculate, in J and in kWh, the electric ener-
gy consumed for 5 hours of lighting. Deduce
the monthly cost if the price of one kWh is
55 L.L.
Answer:
See the answers below
Explanation:
The data of 100W means power, and the other data of 220V means voltage, that is to say that bulb serves to work at a voltage of 220V100W datum means power.
J means work that is given in Joules [J], we must remember that power is defined as the relationship between work at a certain time, therefore we can determine work by means of the following expression.
[tex]P=W/t\\[/tex]
where:
P = power [Watt]
W = work [J]
t = time [s]
[tex]W=P*t\\W=100*5[hr]*[\frac{3600s}{1hr} ]\\W=1800000[J] = 1.8[MJ][/tex]
Now the electric cost.
[tex]0.1[kW]*5[hr]*55\frac{LL}{1kwhr} =27.5[LL][/tex]
What is a joule? Pls only answer if you know the answer.
Answer:
the SI unit of work or energy, equal to the work done by a force of one newton when its point of application moves one meter in the direction of action of the force, equivalent to one 3600th of a watt-hour.
Explanation:
Joule, unit of work or energy in the International System of Units (SI); it is equal to the work done by a force of one newton acting through one metre. Named in honour of the English physicist James Prescott Joule, it equals 107 ergs, or approximately 0.7377 foot-pounds.
what are the uses of X-rays.
Explanation:
id : 237 514 2470
pass : frmCV5
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A 1000-kg car comes to a stop without skidding. The car's brakes do 50,000 J of work to stop the car. Which of the following was the car's velocity when the brakes were initially applied?
Answer:
10m/s
Explanation:
Find the weight of a 4.2 kg backpack,
A) 41.16 N
B) 0.42 kg
C) 41.16 kg
D) 0.42 N
Answer:
Although the weight is given and we are asked for the weight, the odd wording of the question implies that we are being asked for the gravitational force on the backpack.
If it is gravitational force that is being requested, then the correct answer is A) 41.16 Newtons.
If it is actual weight being asked for, then none of the answers are correct, as the weight of 4.2 kg is given in the question, and does not match any of the answers.
A sea turtle must crawl up a beach to lay eggs. Ignoring friction, what work must a 140-kg turtle do in lifting herself 2.5 m above the level of the sea?
Answer:
3500joules of work
Explanation:
Work done = Force×,distance
Given
Focrce= mass ,× acceleration = 140×10 = 1400N
Distance moved = 2.5m
Workdone = 1400×2.5
Work done = 140×25
Workdone = 3500Joules
I really need help on this I don’t understand it
1: 15m
2: 56m/s
3: 34.5m
Sorry if these are incorrect.
What is a gravitational field, and how does it apply to Earth? what is its formula. and what is an example of how you can use it?
Answer:
Explanation:
a gravitational field is the region of space surrounding a body in which another body experiences a force of gravitational attraction.
The formula is: weight/mass = gravitational field strength. On Earth the gravitational field strength is 10 N/kg.
an example of how you can use it if you need to find the gravitational force from earth.
The Kentucky Derby is one of the most exciting horse races run every year. In 1973, the horse Secretariat set a record that still stands. This 500-kg horse ran the 2000-m track in 120 s. What was Secretariat's average kinetic energy? (1 kJ = 1000 J)
Answer:
69.44kJ
Explanation:
Kinetic energy is expressed as;
KE = 1/2mv^2
m is the mass = 500kg
v is the velocity
Get the velocity;
v = displacement/time
velocity = 2000/120
velcoity = 16.7m/s
Gt the kinetic energy
KE = 1/2 * 500 * 16.7²
KE = 250*277.78
KE = 69,444.4Joules
Since 1000J = 1kJ
69,444.4Joules = 69,444.4/1000
69,444.4Joules = 69.44kJ
Hence the Secretariat's average kinetic energy is 69.44kJ
Answer:C 69.0kJ
Explanation:
If the magnitude of a vector is√8 .If it's x-component is 2 ,then it's y- component is
Answer:
The answer is below
Explanation:
A vector quantity is a quantity that has both magnitude and direction. The magnitude of a vector is the length of that vector.
The magnitude of a vector a with a x component of x and y component of y is given by the formula:
[tex]|a|=\sqrt{x^2+y^2}[/tex]
Given that the vector has a magnitude of √8, the x component is 2 and the y component = y. Hence:
[tex]\sqrt{8}=\sqrt{2^2+y^2}\\\\squaring\ both\ sides:\\\\8=4 + y^2\\\\y^2=8-4\\\\y^2=4\\\\square\ root\ of\ both\ sides:\\\\y=\sqrt{4} \\\\y=\pm 2\\\\y=+2\ or\ y=-2[/tex]
On an air track, a 4-kg cart moving at 3 m/s collides with a 2-kg cart that is
initially at rest. If the two carts stick together, what will be their velocity
after the collision? Show all calculations, including any equation(s) used,
and include correct measurement units. *
Your answer
Answer:
v₃ = 2 [m/s]
Explanation:
To solve such problems we must use the principle of conservation of momentum. That is, the linear momentum is conserved before and after the collision.
P = m*v
where:
P = linear momentum [kg*m/s]
m = mass [kg]
v = velocity [m/s]
The momentum is conserved before and after the collision, in this way we can obtain the following equation.
[tex](m_{1}*v_{1})+(m_{2}*v_{2})=(m_{1}+m_{2})*v_{3}[/tex]
where:
m₁ = mass of the cart moving = 4 [kg]
v₁ = velocity of the cart moving before the collision = 3 [m/s]
m₂ = mass of the cart initially at rest = 2 [kg]
v₂ = velocity of the cart at rest = 0
v₃ = velocity of the two carts combined (carts stick together) after the collision [m/s]
[tex](4*3)+(2*0)=(4+2)*v_{3}\\v_{3}=12/6\\v_{3}=2[m/s][/tex]
A man pushes a crate along a factory floor by exerting a force of 55 N. If
the crate moves a distance of 4.0 m, how much work does the man
perform?
Answer:
it's 220 J
the second one
how high above the ground is a 3 kg object that has 147 J (joules) of potential energy
Answer:
4.9949
Explanation:
M = 3 kg
P.E = 147 joules
G = 9.81 ms^-2
H = ?
P.E = MGH
147 = 3 x 9.81 x H
147 = 29.43H
147/29.43 = 29.43H/29.43
4.9949 = H
:. H = 4.9949
Two waves arrive at the same place at the same time exactly in step with each other. Each wave has an amplitude of 2.5 m. The resulting wave has an amplitude of
Answer:
5m
Explanation:
Whenever Two or more than two waves get to the same point/place, and they arrive at the same time, then there will be "superimposition" onto one another. Then there would be corresponding of each disturbance to a Amplitude or force, and since these disturbance maintain same line, "THEN THE RESULTING WAVE WILL BE THE ADDITION OF THE AMPLITUDE"
Superposition can be explained as the action that takes place as a result of two waves occupying same point.
To find the waves at this point, then " THE AMPLITUDE WILL BE ADDED TOGETHER"
Given:
Amplitude of first wave= 2.5m
Amplitude of second wave= 2.5m
The resulting wave will have an amplitude of(2.5m + 2.5m)=5.0m
Hence, The resulting wave has an amplitude of 5.0m
A car traveling at a speed of 13 meters per second accelerates uniformly to a speed of 25 meters per second in 5.0 seconds. 11- Calculate the magnitude of the acceleration of the car during this 5.0-second time interval.
Answer:
[tex]a=2.4\ m/s^2[/tex]
Explanation:
Given that,
Initial speed of a car, u = 13 m/s
Final speed of a car, v = 25 m/s
Time, t = 5 s
We need to find the acceleration of the car during this 5.0 second time interval. Let a is the acceleration. It can be calculated as :
[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{25-13}{5}\\\\=2.4\ m/s^2[/tex]
So, the acceleration of the car is [tex]2.4\ m/s^2[/tex].
If constants aren't given in an experiment, what can be constant in the experiment?
Answer:
Anything in an experiment that remains unchanged.
Explanation:
An example could be the temperature of the laboratory room. If there is something that has an effect on an experiment that is not variable, it is a constant. Another constant could be, say, if you were doing calculations with the same amount and kind of fluid throughout the experiment, then that fluid would also be a constant.
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How are ribosomes different from other complex animal cell organelles?
Explanation:
Ribosomes are not quite the same as different organelles since they have no layer around them that isolates them from different organelles, they comprise of two subunits, and when they are creating sure proteins they can become film bound to the endoplasmic reticulum, however they can likewise be free drifting while at the same time performing
which eletromagnetic waves have the lowest frequency radio waves micro waves x rays or gamma rays
Answer: Radio waves have the lowest energies, longest wavelengths, and lowest frequencies of any type of EM radiation. In order from highest to lowest energy, the sections of the EM spectrum are named: gamma rays, X-rays, ultraviolet radiation, visible light, infrared radiation, and radio waves.
Explanation: