Explain two ways to restore the Florida Panther population.

Answer:

38 pounds of gold in cubic mile of seawater.

Answer:

Hg Pb are in one, Li and B and O are in one, and NaCl are in one, As is alone

Explanation:

Periods are horizontal

Hope this helps!

Finding molar mass of NaOH

We know that

Molar mass of Sodium (Na) = 23 g/mol

Molar mass of Oxygen (O) = 32 g/mol

Molar mass of Hydrogen (H) = 2 g/mol

So,

Mass of 1 mole of NaOH

=> 1 × 23 + 1 × 16 + 1 × 1

=> 23 + 16 + 1

=> 40 g/mol

Now,

Mass = 40 × 0.25

Mass = 10 g

Answer:

The first thing we have to do is change and state all the units so that we can use our ideal gas law equation ([tex]PV = nRT[/tex]).

650 mmHg is a pressure unit, we have to convert this to kiloPascals. We know that 760 mmHg gives us 101 kPa.

[tex]650 \ mmHg \ * \ \frac{101kPa}{760 mmHg} = 86 \ kPa[/tex]

P = 86kPa

T = 15°C + 273K = 288K

R (Gas constant) = 8.31 kj/mol  

Molar mass of Ammonia ([tex]NH_{3}[/tex]) = (1 x 3) + (14) = 17g/mol

n (moles) = [tex]\frac{mass}{molar \ mass}[/tex] [tex]= \frac{56.8}{17} =[/tex] 3.34 mol

V = ?

Rearrange the equation to solve for Volume:

[tex]V = \frac{nRT}{P}[/tex]

Substitute the values inside:

V = [tex]\frac{(3.34)(8.31)(288)}{(86)} = 93 L (rounded)[/tex]

Therefore 93 L of volume is occupied by the ammonia gas.

If Kelli and Jarvis maintain a forward force of 524 N for 1.44 seconds on a 158-kg piano, the acceleration will be 0.671 m/s² and the final velocity will be 0.966 m/s.

Kelli and Jarvis exert a force of 524 N on a 158- kg (m) piano.

The friction force, which opposes this force, is 418 N.

The net force (F) is the difference between both forces.

F = 524 N - 418 N = 106 N

We can calculate the acceleration (a) of the piano using Newton's second law of motion.

Newton's second law of motion states that the acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force and inversely proportional to the mass of the object.

a = F/m = 106 N/158kg = 0.671 m/s²

The piano start from rest (u = 0 m/s) and moves with an acceleration of 0.671 m/s² for 1.44 s.

We can calculate its final velocity (v) using the following kinematic equation.

v = u + a × t

v = 0 m/s + 0.671 m/s² × 1.44 s = 0.966 m/s

If Kelli and Jarvis maintain a forward force of 524 N for 1.44 seconds on a 158-kg piano, the acceleration will be 0.671 m/s² and the final velocity will be 0.966 m/s.

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a.

The atomic radius of iridium is 1.355 Å

For a face-centered cubic unit cell, with edge length, a and atomic radius r,

we have a² + a² = (4r)²

2a² = 16r²

r² = a²/8

r = a/√8

Since a = 3.833 Å,

Substituting this into the equation, we have

r = a/√8

r = 3.833 Å/√8

r = 3.833 Å/2.828

r = 1.355 Å

So, the atomic radius of iridium is 1.355 Å

b.

The density of iridium metal is 22.67 g/cm³

To find the density of the iridium metal, we need to find the mass of atoms per unit cell.

So, for the face centered cubic iridium atom, there are 6 faces per unit cell × 1/2 atoms per face + 4 corners per unit cell × 1/4 atoms per corner = 3 atoms + 1 atom = 4 atoms per unit cell.

So, the mass of the atoms in the unit cell is m = number of atoms/cell × number of moles/atom × molar mass of Iridium

= 4 atoms/cell × 1 mol/6.022 × 10²³ atoms × 192.22 g/mol

= 768.88/6.022 × 10²³ g/cell

= 127.68 × 10⁻²³ g/cell

= 1.2768 × 10⁻²¹ g/cell

Next, we need to find the volume of the unit cell which is V = a³

= (3.833 Å)³

= (3.833 × 10⁻¹⁰ m)³

= 56.314 × 10⁻³⁰ m

= 5.6314 × 10⁻²⁹ m

So, the density of iridium = mass of unit cell/volume of unit cell

= m/V

= 1.2768 × 10⁻²¹ g/cell ÷ 5.6314 × 10⁻²⁹ m

= 0.2267 × 10⁸ g/m³

= 0.2267 × 10⁸ g/m³ × 10⁻⁶ m³/cm³

= 0.2267 × 10² g/cm³

= 22.67 g/cm³

So, the density of iridium metal is 22.67 g/cm³

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We are given that–

[tex]\qquad[/tex]________________________

As we know –

[tex]\qquad[/tex][tex] \pink{\bf\longrightarrow {Mass = Volume \times Density } }[/tex]

[tex]\qquad[/tex][tex] \bf\longrightarrow Mass_{(Propane)} = 389 \times 19.3 [/tex]

[tex]\qquad[/tex][tex] \bf\longrightarrow Mass_{(Propane)} = 7507.7 \: g[/tex]

[tex]\qquad[/tex]______________________

Mass of a substance is the amount of the constituting particles per unit volume. The mass of the [tex]\bold { 389\ cm^3}[/tex] of propane is 7.507 kg.

Mass of a substance is the amount of the constituting particles per unit volume. It is measured in kilograms (kg).

The formula for mass,

M =  v x d

Where,

M - mass

v - volume = [tex]\bold { 389\ cm^3}[/tex]

d - density = 19.3 g/cm

Put the values in the formula,

M =  [tex]\bold { 389\ cm^3}[/tex]  x   19.3 g/cm

M = 7507.7 g

M  = 7.507 kg

Therefore, the mass of the [tex]\bold { 389\ cm^3}[/tex] of propane is 7.507 kg.

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Explanation:

The Mechanical Hound is a robotic animal that firemen can deploy to hunt and catch fugitives. It can be trained and programmed to hunt its prey very quickly by smell. Once it catches its prey, the Hound injects the person with a sedative; unable to run, the drugged fugitive is easily captured.

The enthalpy of this reaction is -296. 8 kJ/mol.

The equation of the reaction is;

S(s) + O2(g) -----> SO2(g)

Recall that the enthalpy of the reaction can be obtained from the formula;

ΔHrxn = ΔHf(products) - ΔHf(reactants)

We know that;

ΔHf S(s) = 0 KJ/mol

ΔHf O2(g) =  0 KJ/mol

ΔHf SO2(g) = -296. 8 kJ/mol

Hence;

ΔHrxn =  -296. 8 kJ/mol - [0 KJ/mol + 0 KJ/mol]

ΔHrxn = -296. 8 kJ/mol

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Answer:

Raise

Explanation:

H+ ions are acidic and lower the PH of water.

Answer:

Dived the numbers by each other

Explanation:

25.3/19.9

Answer:

C. Al and O2

Explanation:

The reactants are the elements or compounds that is becoming the result

So Al and O2

Hope this helps!

Answer:

Covalent compounds (solid liquid solutions)  

non-metal elements are insulators but not conductors of electricity.

Explanation:

Metal elements and carbon (graphite) are conductors of electricity

Answer:

True

Explanation:

its true don't lie on here please

In giant covalent structures such as graphite or diamond, the atoms form strong bonds by sharing electrons. Therefore, the given statement is true.

A covalent bond can be defined as a chemical connection formed by the sharing of electron sets between particles. A covalent bond can be created by the mutual sharing of electrons from both atoms.

The pair of electrons that are shared in this kind of bonding is known as the shared or bonding pair. Covalent bonds are the sharing of bonding pairs of electrons that will provide the stability of the atom in its outer shell.

Elements that have very high ionization energies are incapable of exchanging electrons or elements having low electron affinity cannot accept electrons. Covalent bonding between two non-metallic atoms is characterized by the equal sharing of electrons between the atoms and covalent bonds with an electronegativity difference of participating atoms is more than 2.0.

Therefore, a giant structure like a diamond has strong covalent bonds that require a lot of energy to break.

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Archaea (Archaeon ): Single-celled microorganisms without nuclei and with membranes different from all other organisms. Once thought to be bacteria.

Unicellular organism

-A unicellular organism, also known as a single-celled organism, is an organism that consists of a single cell, unlike a multicellular organism that consists of multiple cells. Unicellular organisms fall into two general categories: prokaryotic organisms and eukaryotic organisms.

Answer:

The conductance will increase as the concentration of the electrolyte is increased.  

Explanation:

The ions are what carry the charges from one electrode to another.  The more there are, the easier it is for electrons to get across the solution of electrolyte,

Let's check the equation

[tex]\\ \sf\longmapsto {CH_4\atop 1mol}+{4S\atop 4moles}\longrightarrow {CS_2\atop 1mol}+{2H_2S\atop 2moles}[/tex]

[tex]\\ \sf\longmapsto 10.6(0.25)=2.65moles\:of\:CS_2[/tex]

C9H8O. .....................

Answer:

0.185moles

Explanation:

1mole of bicarbonate produces 1mole of CO2

so 0.185 mole produces 0.185 moles of CO2

Answer:

hydrogen and helium is the answer.

Answer:

[tex] \huge{5.632 \times {10}^{ - 19} \: J}[/tex]

Explanation:

The energy of the proton can be found by using the formula

where

E is the energy in J

f is the frequency in Hz

h is the Planck's constant which is

6.626 × 10-³⁴ Js

From the question we have

E = 6.626 × 10-³⁴ × 8.5 × 10¹⁴

We have the final answer as

[tex]5.632 \times {10}^{ - 19} \:J[/tex]

Hope this helps you

Answer:

It's option b) Aquifer.

Answer:

where are the answers?

Explanation:

Answer:

It is strongly recommended that students do NOT wear contacts lenses in the laboratory. Chemical vapors may penetrate the contact lens material and cause the lens to adhere to one's eye, which could be detrimental to the eye. Goggles are not vapor tight and do not completely eliminate this absorption.

Answer:

A-10

Explanation:

In the SI, designations of multiples and subdivision of any unit may be arrived at by combining with the name of the unit the prefixes deka, hecto, and kilo meaning, respectively, 10, 100, and 1000, and deci, centi, and milli, meaning, respectively, one-tenth, one-hundredth, and one-thousandth.

IM NOT SURE PO

The answer is going to be a nuclear reactor

Answer:

Is there be suppose a file with this?

Explanation:

Answer:

non-metals

Explanation covalent bonds occur between elements that are far apart on the periodic table.

The types of elements that are significantly involved in covalent bonding are known as non-metals.

Covalent bonding may be defined as a type of chemical bonding that may involve the mutual sharing of electrons in order to construct electron pairs between atoms of non-metals. These electron pairs which are formed between atoms are known as bonding pairs or shared pairs.

According to the context of this question, covalent bonds are generally formed between nonmetals. While metallic bonds are the type of chemical bonds which are typically formed between the metallic element.

Another type of bonding may also be formed between elements. This type of bonding is known as Ionic bonding. This chemical bonding mat generally arises between metals and non-metals.

Therefore, the types of elements that are significantly involved in covalent bonding are known as non-metals.

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