Answer:
₹2520
Step-by-step explanation:
First, converting R percent to r a decimal
r = R/100 = 10%/100 = 0.1 per year,
then, solving our equation
I = 12600 × 0.1 × 2 = 2520
I = ₹ 2,520.00
The simple interest accumulated
on a principal of ₹ 12,600.00
at a rate of 10% per year
for 2 years is ₹ 2,520.00.
How would I solve this?? My math course didn't teach me anything related to this sort of problem..
Answer:
See below
Step-by-step explanation:
The larger is
7-6 = 1 unit bigger than the smaller....and this unit = 24 gallons
each unit is 24 gallons
larger barrel holds 24 * 7 = 168 gal
smaller barrel holds 24 * 6 = 144 gal
Answer:
Small barrel=144 large barrel=168
Step-by-step explanation:
The ratio is 6 to 7 so lets assign x as a factor.
6x=Small barrel (S)
7x=Large barrel (L)
7x-6x=x
x is the difference so x is 24
x=24
6*24=144=S
7*24=168=L
Which expression is equivalent to startfraction 3 x superscript negative 6 baseline y superscript negative 3 baseline over 15 x squared y superscript 10 baseline endfraction? assume x not-equals 0, y not-equals 0
The equivalent expression of [tex]\frac{3x^{-6}y^{-3}}{15x^2y^{10}}[/tex] is [tex]\frac{1}{5x^{8}y^{13}}[/tex]
How to determine the equivalent expression?The expression is given as:
[tex]\frac{3x^{-6}y^{-3}}{15x^2y^{10}}[/tex]
Divide 3 and 15 by 3
[tex]\frac{x^{-6}y^{-3}}{5x^2y^{10}}[/tex]
Apply the law of indices
[tex]\frac{1}{5x^{2+6}y^{10+3}}[/tex]
Evaluate the sum
[tex]\frac{1}{5x^{8}y^{13}}[/tex]
Hence, the equivalent expression of [tex]\frac{3x^{-6}y^{-3}}{15x^2y^{10}}[/tex] is [tex]\frac{1}{5x^{8}y^{13}}[/tex]
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Someone help me please
Answer:
2√10
Step-by-step explanation:
We can use the Pythagorean theorem to solve this because it is a right triangle. a^2+b^2 = c^2
7^2-3^2 = x^2
49-9 = x^2
40 = x^2
√4*√10 = 2√10
An account pays 8% per year simple interest. in year 1, the amount in the account is $850. how much is in the account in year 6?
Answer:
Step-by-step explanation:
$1,248.92
what is the circumference?
In a math class of $30$ students, $12$ out of $15$ girls are freshmen and $11$ out of $15$ boys are freshmen. What is the probability that in a randomly selected group of five students from the class, there will be two freshmen girls and three freshmen boys
The probability of selecting five students from the class, where there will be two freshmen girls and three freshmen boys is 0.23 approximately.
What is Probability ?Probability is the game of chance. Probability of an event is the ratio of the required outcome to the total possible outcome.
Given that In a math class of 30 students, 12 out of 15 girls are freshmen and 11 out of 15 boys are freshmen. In Probability, the word "and" means multiplication
The probability that in a randomly selected group of five students from the class, there will be two freshmen girls and three freshmen boys can be expressed as follow
12/15 x 11/14 x 11/15 x 10/14 x 9/13
132/210 x 990/2730
130680/573300
0.2279
Therefore, the probability that in a randomly selected group of five students from the class, there will be two freshmen girls and three freshmen boys is 0.23 approximately.
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PLEASE HELP IM STUCK
Step-by-step explanation:
[tex] \frac{y2 - y1 }{x2 - x1} = \frac{3 - - 2}{5 - 0} = \frac{5}{5} = 1[/tex]
The function f has the property that, for all x, 5(f)x=f(5x). If f(20)=40, what is the value of f(4)?
Using the given property, we conclude that:
f(4) = 8
What is the value of f(4)?
We know that our function has the property:
5*f(x) = f(5*x)
Now, we also know that:
f(20) = 40
Notice that we can rewrite:
f(20) = f(5*4)
Using the above property, we know that:
f(20) = f(5*4) = 5*f(4) = 40
Using the last part:
5*f(4) = 40
f(4) = 40/5 = 8
f(4) = 8
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Please help with this
Answer:
the answer is 8
Step-by-step explanation:
thats what i got
30 points please help me
The area of the shaded region = area of larger circle - area of smaller circle = 423.9 yd².
What is the Area of a Circle?Area = πr²
Area of the shaded region = area of larger circle - area of smaller circle
Area of larger circle = πr² = (3.14)(16²) = 803.84 yd²
Area of smaller circle = πr² = (3.14)(11²) = 379.94 yd²
Area of the shaded region = 803.84 - 379.94 = 423.9 yd².
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What numbers are zeros of g(x) = x^2 - 2x - 4? take your time if you need to!
Answer:
[tex]x = 1 + \sqrt5, x = 1 - \sqrt5[/tex]
Step-by-step explanation:
Hello!
We can solve the quadratic by using the quadratic formula.
Standard form of a quadratic: [tex]ax^2 + bx + c = 0[/tex]
Quadratic Formula: [tex]x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}[/tex]
Given our Equation: [tex]g(x) = x^2 - 2x - 4[/tex]
a = 1b = -2c = -4Plug the values into the equation and solve.
Solve[tex]x = \frac{-b\pm\sqrt{b^2 - 4ac}}{2a}[/tex][tex]x = \frac{-(-2)\pm\sqrt{(-2)^2 - 4(1)(-4)}}{2(1)}[/tex][tex]x = \frac{2\pm\sqrt{4 +16}}{2}[/tex][tex]x = \frac{2\pm\sqrt{20}}{2}[/tex][tex]x = \frac{2\pm\sqrt{4 * 5}}{2}[/tex][tex]x = \frac{2\pm(\sqrt4 * \sqrt5)}{2}[/tex][tex]x = \frac{2\pm2\sqrt5}{2}[/tex][tex]x = 1 + \sqrt5, x = 1 - \sqrt5[/tex]Which are correct representations of the inequality –3(2x – 5) < 5(2 – x)? Select two options.
x < 5
–6x – 5 < 10 – x
–6x + 15 < 10 – 5x
A number line from negative 3 to 3 in increments of 1. An open circle is at 5 and a bold line starts at 5 and is pointing to the right.
A number line from negative 3 to 3 in increments of 1. An open circle is at negative 5 and a bold line starts at negative 5 and is pointing to the left.
The correct statements are –6x + 15 < 10 – 5x and a number line from negative 3 to 3 in increments of 1. An open circle is at 5 and a bold line starts at 5 and is pointing to the right.
Inequality expressionInequality are expressions not separated by an equal sign. Given the inequality expression:
–3(2x – 5) < 5(2 – x)
Expand
-6x +15 < 10 - 5x
Collect the like terms
-6x+5x < 10 - 15
-x <-5
x > 5
Hence the correct statements are –6x + 15 < 10 – 5x and a number line from negative 3 to 3 in increments of 1. An open circle is at 5 and a bold line starts at 5 and is pointing to the right.
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terrell watched 300 dogs being groomed. He found that 0.35 of the groomed dogs tried to bite the groomer. what percent of dogs did not try to bite the groomer?
The percentage of dogs who didn't try to bite the groomer is; 65%.
What is the percentage of dogs that did not try to bite the groomer?If follows from the task content that the number of dogs is 300 of which, 0.35 faction of the whole tried to bite the groomer.
Hence, the faction that did not try to bite the groomer is; 0.65 which corresponds to 65% when expressed as a percentage.
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What are the solutions of the equation (2x 3)2 8(2x 3) 11 = 0? use u substitution and the quadratic formula to solve.
Answer:
Step-by-step explanation:
Determine the missing coordinate in the ordered pair (?,5) so that it will satisfy x+6y=18
(14x2 + 13x + 12) + (7x2 + 20x + 4)
Answer:
21x^2 + 33x + 16
Step-by-step explanation:
(14x^2 + 13x + 12) + (7x^2 + 20x + 4)
Combine like terms:
14x^2 + 7x^2 = 21x^2
13x + 20x = 33x
12 + 4 = 16
Thus:
21x^2 + 33x + 16
Answer:
21x^2 + 33x + 16.
Step-by-step explanation:
(14x2 + 13x + 12) + (7x2 + 20x + 4) Remove the parentheses:
= 14x2 + 13x + 12 + 7x2 + 20x + 4 Bring like terms togethher:
= 14x^2 + 7x^2 + 13x + 20x + 12 + 4
= 21x^2 + 33x + 16.
The water was pumped out of a backyard pond. What is the domain of this graph?
quick answer (A)
ALL real numbers less than or equal to 8
Alek is taking an inventory of styles of compression bandages for work. Here is the data he has collected.
The individuals in this data set that can be gotten is B) Compression bandage styles and this data set contains A) 3 variables, 1 of which is categorical.
What is categorical variable ?A categorical variables serve as the variable type that posses two or more categories.
This categories could be nominal variable, however considering the data , we can see that the first two are quantitative data and the data are:
WidthTotal lengthColorTHE COMPLETE QUESTION IS:
Alek is taking an inventory of styles of compression bandages for work. Here is the data he has collected.
The individuals in this data set are:Choose 1 answer:
A) Blood Centers
B) Compression bandage styles
C) Nurses
This data set contains:Choose 1 Answer:
A) 3 variables, 1 of which is categorical
B) 3 variables, 3 of which are categorical
C) 6 variables, 1 of which categorical
D) 6 variables, 3 of which are categorical
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the number 40 cannot be decomposed into prime factors
True
either
False
[tex]\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: {\large{\textsf{\textbf{\underline{\underline{Answer : \:}}}}}}[/tex]
False, because the number 40 is a composite number, those that cannot be broken down are called Prime Numbers.
Prime numbers are numbers that are used to decompose any number, but prime numbers cannot be decomposed, since they only have two Divisors, which are 1 and itself.
[tex]~\sf{Atte: Murdock:)}[/tex]
Answer: False
Step-by-step explanation:
All whole numbers can be decomposed into prime factors. For the number 40, the prime factorization would be [tex]2 * 2 * 2*5[/tex]. Since all 4 of those numbers are prime numbers, the answer is false.
Consider a circle whose equation is x2 + y2 – 2x – 8 = 0. Which statements are true? Select three options.
The radius of the circle is 3 units.
The center of the circle lies on the x-axis.
The center of the circle lies on the y-axis.
The standard form of the equation is (x – 1)² + y² = 3.
The radius of this circle is the same as the radius of the circle whose equation is x² + y² = 9.
The center of the circle lies on the x-axis
The radius of the circle is 3 units.
The radius of this circle is the same as the radius of the circle whose equation is x² + y² = 9.
How to determine the statements
The standard equation of a circle is expressed as:
[tex]x^2 + y^2 + 2gx + 2fy + C = 0[/tex]
Where
Centre is (-g, -f)radius = √g²+f²-CGiven a circle whose equation is
Let's get the center of the circle
2gx = -2x
2g = -2
We have that;
g = -1
Similarly, 2fy = 0
given that
f = 0
Centre = (-(-1), 0) = (1, 0)
This explains that the center of the circle lies on the x-axis
We move further to the radius
r = radius = √g²+f²-C
radius = √1²+0²-(-8)
radius =√9
= 3 units
The radius of the circle is 3 units.
For the circle x² + y² = 9, the radius is expressed as:
r² = 9
r = 3 units
Hence the radius of this circle is the same as the radius of the circle whose equation is x² + y² = 9.
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determine the fall (drop) on 20' of drainage piping with a 1/4" per ft. grade
The Fall (drop) of drainage piping is: A. 5".
Fall (drop) of drainage pipingIn order to determine the fall (drop) of drainage piping we would need to multiply the drainage piping by the inch per feet.
Hence:
Using this formula
Fall (drop) of drainage piping = Drainage piping× inch per feet
Where:
Drainage piping=20
Inch per feet=1/4"
Let plug in the formula
Fall (drop) of drainage piping =20×1/4"
Fall (drop) of drainage piping =5"
Therefore the correct option is A. 5".
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there are three red marbles 5 green marbles 2 blue marbles in a bag which of the follwing are true
Answer:
4 and 1
Step-by-step explanation:
Speedy Swift is a package delivery service that serves the greater Atlanta, Georgia, metropolitan area. To maintain customer loyalty, one of Speedy Swift's performance objectives is on-time delivery. To monitor its performance, each delivery is measured on the following scale: early (package delivered before the promised time), on-time (package delivered within 15 minutes of the promised time), late (package delivered more than 15 minutes past the promised time), or lost (package never delivered). Speedy Swift's objective is to deliver 99% of all packages either early or on-time.
Speedy collected the following data for last month's performance:
On-time On-time Early Late On-time On-time On-time On-time Late On-time
Early On-time On-time Early On-time On-time On-time On-time On-time On-time
Early On-time Early On-time On-time On-time Early On-time On-time On-time
Early On-time On-time Early Early Early On-time Loss On-time Early
Late Late Late On-time On-time On-time On-time On-time On-time On-time
On-time Late Early On-time Early On-time Lost On-time On-time On-time
Early Early On-time On-time Late Early Early On-time On-time On-time
On-time On-time Early On-time Early On-time Early On-time Late On-time
On-time Early On-time On-time On-time Late On-time Lost On-time On-time
On-time On-time On-time On-time On-time Early Early On-time On-time On-time
(a) What scale is used to measure delivery performance? What kind of variable is delivery performance?
(b) Construct a frequency table for delivery performance for last month.
(c) Construct a relative frequency table for delivery performance last month.
(a) The scale used in the analysis is qualitative as the data is not assigned any numeric value.
The daily performance is an ordinal variable, as the values assigned are ranked according to an order of the delivery time.
(b) The frequency table of the given data is:
Variable Frequency
Early 23
On-time 65
Late 9
Lost 3
Total 100.
(c) The relative frequency table for the given data is:
Variable Frequency Relative frequency
Early 23 23/100 = 0.23 = 23%
On-time 65 65/100 = 0.65 = 65%
Late 9 9/100 = 0.09 = 9%
Lost 3 3/100 = 0.03 = 3%
(a) The scale used in the analysis is qualitative as the data is not assigned any numeric value.
The daily performance is an ordinal variable, as the values assigned are ranked according to an order of the delivery time.
(b) The frequency table is a table showing frequency of each variable for the number of times they appear in the data.
The frequency table of the given data is:
Variable Frequency
Early 23
On-time 65
Late 9
Lost 3
Total 100.
(c) The relative frequency for a variable is the ratio of its frequency to the total frequency.
The relative frequency table for the given data is:
Variable Frequency Relative frequency
Early 23 23/100 = 0.23 = 23%
On-time 65 65/100 = 0.65 = 65%
Late 9 9/100 = 0.09 = 9%
Lost 3 3/100 = 0.03 = 3%
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Answer:
C.
Step-by-step explanation:
(4x⁴-4x²-x-3) ÷ (2x²-3)
so far i have 2x²+1+?/2x²-3
what is the question mark?
Answer:
[tex]2x^2+1-\dfrac{x}{2x^2-3}[/tex]
Step-by-step explanation:
Use the long division method to divide polynomials:
[tex]\large \begin{array}{r}2x^2\phantom{)))))}+1\phantom{)}\\2x^2-3{\overline{\smash{\big)}\,4x^4-4x^2-x-3\phantom{)}}}\\\underline{-~\phantom{(}(4x^4-6x^2)\phantom{-b))))))}}\\0+2x^2-x-3\phantom{)}\\\underline{-~\phantom{()}(2x^2\phantom{))))}-3)}\\-x\phantom{))))))}\end{array}[/tex]
Therefore:
[tex]\dfrac{4x^4-4x^2-x-3}{2x^2-3}=2x^2+1-\dfrac{x}{2x^2-3}[/tex]
how do you graph y=12/x
Answer: [tex]\frac{12}{x}[/tex] is an asymptote
Step-by-step explanation:
Apply a table, and plug in values of x into the equation. For example f(2)=[tex]\frac{12}{2} =6[/tex]. That's one of the points on the graph that we just found (2,6)
What three-dimensional object would be generated by the rotation of the semi circle about the x axis ?
If a semicircle is rotated about the x axis of the graph then the resulting three dimensional shape will be a sphere.
Given a semicircle on a graph.
A semicircle is a half circle .A sphere is a geometrical object that is a three dimensional shape , It is the set of points that are all at the same distance r from given point in three dimensional shape.
Rotation is basically an action of rotating around an object or an axis.
If a semicircle is rotated about x axis then the resulting figure will be a sphere. This is because of the fact that when the semi circle is rotated about the x axis then all the points will be at equal distance in all directions from the center.
Hence if a semicircle is rotated about x axis then the resulting figure will be a sphere.
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Calculate the first difference between 7, and where 7,-688. 2
The difference between the numbers given is 6.882.
How to illustrate the information?Based on the information given, it should be noted that difference means subtraction.
The difference between the numbers given will be:
= 7 - (7 - 6.882)
= 7 - 0.118
= 6.882
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Which system of equations can you use to find the roots of the equation 2x3 4x2 – x 5 = –3x2 4x 9? y = 2x3 x2 3x 5 y =9 y = 2x3 x2 y = 3x 14 y = 2x3 4x2 – x 5 y = –3x2 4x 9
Finding the roots of an equation is done using the equation systems [tex]y=2x^{3}+4x^{2} -x+5[/tex] & [tex]y= -3x^{2} +4x+9[/tex] .
Determining the roots of the equationThis equation seems to have the following form:[tex]2x^{3}+4x^{2} -x+5= -3x^{2} +4x+9[/tex]
We must assess the appropriate set of equations that may be utilized to identify the equation's roots.
By drawing the equations' graph, we may determine the equation's root. We can suppose that the left and right sides of the following equations are two independent equations for the sake of graphing.
Therefore,
[tex]y=2x^{3}+4x^{2} -x+5[/tex]
[tex]y= -3x^{2} +4x+9[/tex]
The graphs of these two equations are now shown in the identical coordinate plane. The roots of the equation given will be the crossing point(s).
The equation system that we may utilize to get the root of the formula given is thus,
[tex]y=2x^{3}+4x^{2} -x+5[/tex]
[tex]y= -3x^{2} +4x+9[/tex]
So, the correct answer is option C.
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2. Rotate the following points 180°.
a.) B(-2,-5) →B'( )
b.) B(-4,1) B'( )
c.) In the graphs above connect the pre-image point B to the origin. Then connect
the origin to the image point B. What angle has been formed?
Answer:
hi helo bol ke gatu jama gol ke
The area of a sector of a circle of radius 8cm is 45cm². Find the size of the angle subtended at the centre of the circle, correct to one decimal place. (Take π = 22/7)
The size of the angle subtended at the center of the circle is θ = 80.5397°
What is the Area of the Sector?In circles, a sector is said to be a part of a circle made of the arc of the circle together with its two radii. This means that it is a portion of the circle formed by a portion of the circumference (arc) and radii of the circle at both endpoints of the arc.
The formula for Area of a sector is given as;
A = θ/360 x πr²
where;
θ is the central angle of the sector
r is radius
Given data ,
The area of a sector of a circle of radius 8cm is 45cm²
On simplifying , we get
A = θ/360 x πr²
45 = θ/360 ( 22/7 ) ( 8 )²
45 = ( θ/360 ) ( 201.1428 )
Divide by 201.1428 on both sides , we get
( θ/360 ) = 0.22372159
Multiply by 360 on both sides , we get
θ = 80.5397
Hence , the angle is θ = 80.5397°
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