find inverse of function in form of ordered pair

Answer:

x = 28/97

y = 532/

Step-by-step explanation:

x + 5y = 20x + 3y

=> 5y - 3y = 20x - x

=> 2y = 19x

=> y = (19x)/2

x + 5y = 14

=> x + 5((19x)/2) = 14

=> x + (95x)/2 = 14

=> (2x + 95x)/2 = 14

=> 97x = 14(2)

=> 97x = 28

=> x = 28/97

=>y = (19x)/2 = (19(28))/(97(2)) = 532/194

Answer:

1/5=0.2

0.3=3/10

1/2=0.5

7/10=0.7

3/4=0.75

Answer:

384 ft, this is the required answer

Answer:

area of shaded part = 512 ft^2

Step-by-step explanation:

find area of rectangle

length = 32 +8

=40 ft

breadth = 8 + 8

=16 ft

area of rectangle = l*b

=40*16 ft

=640 ft

since there are two square .we should find the area of two sqaure.

length = 8 ft

area of square = l^2

=8^2

=64 ft^2

area of another square = l^2

=8^2

=64 ft^2

area of shaded part = area of rectangle - (area of square + area of square)

=640 -(64 + 64) ft^2

=640 - 128 ft^2

=512 ft^2

Answer:

Not similar

Step-by-step explanation:

In triangle MLN & WXY,

Right angles - > 1

There is nothing common in these 2 triangles other than (1)

Therefore,

Not similar

Answer:

[tex]g(x)=\sqrt{x+2}[/tex]

Step-by-step explanation:

Parent function of the given graph is,

f(x) = [tex]\sqrt{x}[/tex]

If the parent function is shifted 2 units to he left the new function or image function will be,

g(x) = [tex]\sqrt{x+2}[/tex]

Therefore, graph will represent the graph of the function g(x) = [tex]\sqrt{x+2}[/tex].  

Answer:

i think C because both of the percentages shown should get what the question is asking

Step-by-step explanation:

Answer:

I assume that this is a quadratic equation, something like:

y = -47*x^2 - 24x + (-36)

we can rewrite it as:

y = -47x^2 - 24x - 36

Ok, this is a quadratic equation and we want to find the maximum value.

First, you can notice that the leading coefficient is negative.

This means that the arms of the graph will open downwards.

Then we can conclude that the vertex of the equation is the "higher" point, thus the maximum value will be at the vertex.

Remember that for a general function

y = a*x^2 + b*x + c

the vertex is at:

x = -b/2a

So, in our case:

y = -47x^2 - 24x - 36

The vertex will be at:

x = -(-24)/(2*-47) = -12/47

So we just need to evaluate the function in this to find the maximum value.

Remember that "evaluating" the function in x = -12/47 means that we need to change al the "x" by the number (-12/47)

y = -47*(-12/47)^2 - 24*(-12/47) - 36

y = -32.94

That is the maximum value of the function, -32.94

Answer:

6.25

Step-by-step explanation:

3x+25=7x

3x-7x=-25

-4x=-25

x=6.25

Answer:

[tex]\sin(105) = \frac{\sqrt 2 + \sqrt 6}{4}[/tex]

Step-by-step explanation:

Given

[tex]\sin(105^o)[/tex]

Required

Solve

Using sine rule, we have:

[tex]\sin(A + B) = \sin(A)\cos(B) + \sin(B)\cos(A)[/tex]

This gives:

[tex]\sin(105^o) = \sin(60 + 45)[/tex]

So, we have:

[tex]\sin(60 + 45) = \sin(60)\cos(45) + \sin(45)\cos(60)[/tex]

In radical forms, we have:

[tex]\sin(60 + 45) = \frac{\sqrt 3}{2} * \frac{\sqrt 2}{2} + \frac{\sqrt 2}{2} * \frac{1}{2}[/tex]

[tex]\sin(60 + 45) = \frac{\sqrt 6}{4} + \frac{\sqrt 2}{4}[/tex]

Take LCM

[tex]\sin(60 + 45) = \frac{\sqrt 6 + \sqrt 2}{4}[/tex]

Rewrite as:

[tex]\sin(60 + 45) = \frac{\sqrt 2 + \sqrt 6}{4}[/tex]

Hence:

[tex]\sin(105) = \frac{\sqrt 2 + \sqrt 6}{4}[/tex]

Answer:

Step-by-step explanation:

Let's call Joseph "J", Mark "M", and Kevin "K" for ease. We need a system of equations to solve this, 3 equations for 3 unknowns. The first equation is

J + M = 230. The second equation is

J + K = 130. The third equation is

M = 3K. Sub that 3K into the first equation and get

J + 3K = 230. Now take th second equation and solve it for J:

J = 130 - K. Now sub 130 - K into the re-written first equation to get a whole new equation in terms of K only:

130 - K + 3K = 230 and

2K = 100 so

K = 50

Kevin has $50

Step-by-step explanation:

The answer is 24 I think.

using the formula for finding the area of a triangle, which is....

Area= b times height divided by 1/2 or 2

First step is to multiply 6 which is the base by the height 8 to get 48. Then 48 divided by 2 is 24.

Step-by-step explanation:

the area of the triangle can be find by using the heron's formula...

that is:

√s-a×s-b×s-c

So,

a=8cm,b=6cm,c=10cm

Semi perimeter= 8+6+10/2=24/2=12

√12(12-8)(12-6)(12-10)

=√12×4×6×2

=√ 2×2×3×2×2×2×3×2

= √2×2×2×3

= 12 cm...

Answer:

1.2

Step-by-step explanation:

We want to find the y value when x = -6

When x = -6, y = 1.2

Answer:

2

Step-by-step explanation:

Convert the equation to slope-intercept form:

[tex]y+5=2(x+1)\\y+5=2x+2\\y=2x-3[/tex]

Therefore, the slope of the line is 2.

Answer:

2

Step-by-step explanation:

y+5=2(x+1) will turn into y=2x-3. Then you can see that the slope is 2 because 2x is = mx and m is slope.

Answer:

A

Step-by-step explanation:

Given

[tex]\frac{x}{6}[/tex] = [tex]\frac{36}{24}[/tex] ( cross- multiply )

24x = 216 ( divide both sides by 24 )

x = 9 → A

Step-by-step explanation:

Height of the right circular cone = 18.8 metres

And base is 19.3 metres

Volume of the right circular cylinder is given by,

= πr²h

= 3.14 × (19.3)² × 18.8

= 21999.98(approx.) cubic metre

Rounding off nearest tenth

= 21999 cubic metres

The volume of the right circular cone is 280,199.5 m³

'A right circular cone is a cone where the axis of the cone is the line meeting the vertex to the midpoint of the circular base.'

According to the given problem,

Height = 18.8 m

Radius = 19.3 m

Volume of right circular cone = [tex]\frac{\pi r^{2}h }{3}[/tex]

                                                 = [tex]\frac{\pi * 19.3^{2} * 18.8}{3}[/tex]

                                                 = 280199.499 m³

                                                 = 280199.5 m³

Hence, we can conclude that the volume of the right circular cone is 280199.5 m³.

Learn more about right circular cone here: https://brainly.com/question/16655425

#SPJ2

Answer:

1. X-intercepts

2. Midpoint

3. Vertex

4. Y-Intercept

Step-by-step explanation:

Answer:

41/30

Step-by-step explanation:

4/5 ---> 24/30

1/10 ---> 3/30

2/3 ---> 20/30

(24/30 - 3/30) + 20/30 =

21/30 + 20/30 =

41/30

Answer:

4

Step-by-step explanation:

Notice each side was increased by 4 times

You can set up a ratio of

[tex]\frac{new}{old}[/tex]

then reduce or divide

Given:

Consider the equation is:

[tex]\dfrac{1-x}{11}=6[/tex]

To find:

The value of x.

Solution:

We have,

[tex]\dfrac{1-x}{11}=6[/tex]

After multiplying both sides by 11, we get

[tex]1-x=66[/tex]

[tex]-x=66-1[/tex]

[tex]-x=65[/tex]

Multiply both sides by -1.

[tex]x=-65[/tex]

Therefore, the value of x is -65.

Answer:

yes it does because men comes before women

Answer:

x = 3

Step-by-step explanation:

7x-8=13

Add 8 to each side

7x-8+8=13+8

7x = 21

Divide each side by 7

7x/7 = 21/7

x = 3

Answer:

b= (3z-6)/(1+3z)

Step-by-step explanation:

z=(-b+6)/(3b-3)

cross multiple

z(3b-3)=-b+6

open the bracket

3bz-3z=-b+6

make -b the subject of the formula

-b = 3bz-3z-6

-b - 3bz = -3z - 6

factorize the left hand side...

-b(1+3z) = -3z-6

make -b the subject of the formula again

-b = -(3z-6)/(1+3z)

cancel the minus at both sides...

b = (3z-6)/(1+3z)

Answer:

b = [tex]\frac{3z + 6}{3z+1}[/tex]

Step-by-step explanation:

Simply solve for "b" , so the formula will be

b = .....

z = [tex]\frac{-b+6}{3b-3}[/tex] ( b > 0 )

z(3b - 3) = - b + 6

3zb - 3z = - b + 6

3zb + b = 3z + 6

b( 3z + 1 ) = 3z + 6

b =  [tex]\frac{3z + 6}{3z+1}[/tex]

Answer:

1st entry: 41

3rd entry: 17

Step-by-step explanation:

The 1st and 3rd entry are incorrect.

We will use the following for the 1st and 3rd:

[tex]|z+w|=|z|^2+|w|^2+2R(z\overline{w})[/tex]

[tex]|z-w|=|z|^2+|w|^2-2R(z\overline{w})[/tex]

where [tex]R(z\overline{w})[/tex] means 'real part of [tex]z\overline{w}[/tex]'.

Let's do part 1 now)

25+4+2(6)

29+12

41

Let's do part 3 now)

25+4-2(6)

29-12

17

Answer:

It's maximum value is 28.

Step-by-step explanation:

Cosine function:

The cosine function has the following format:

[tex]f(x) = A\cos{x}[/tex]

The difference between the maximum and minimum point is 2A.

y=16 cos(x)+k

A = 16, so 2A = 32.

Minimum value of -4. What is its maximum value?

[tex]M - (-4) = 32[/tex]

[tex]M + 4 = 32[/tex]

[tex]M = 32 - 4 = 28[/tex]

It's maximum value is 28.

Answer:

C) divide the numerator by the denominator

Step-by-step explanation:

Example

6/3=2/1

Answer:

1/2 or 0.5 hours

Step-by-step explanation:

r = time for repairman to fix one pair of shoes.

a = time for assistant to fix one pair of shoes.

a = r×1.5

x×r + y×a = 6

x = number of pairs of shoes repaired by repairman.

y = number of pairs of shoes repaired by assistant.

x+y = 10

y = 10-x

x = y×1.5 (based on the a/r ratio : as the assistant needs 1.5 times longer, the repairman will have repaired 1.5 times more pair of shoes in the same time)

y = 10 - y×1.5

y + y×1.5 = 10

2.5×y = 10

y = 4

=> x = 6

6×r + 4×r×1.5 = 6

6×r + 6×r = 6

12×r = 6

r = 6/12 = 1/2 or 0.5 hours

Answer: $206

Step-by-step explanation: 9(22)+8. 9 is the 9 tickets 22 is the cost of each ticket so they multiply to find the total cost of all tickets. and 8 from shipping and handling.

Answer:

x = 22.5

Step-by-step explanation:

∠2 and ∠7 are known as alternate exterior angles. This makes them equal to each other.

100 = 4x + 10

90 = 4x

22.5 = x

Answer:

[tex]10 \frac{2}{5}[/tex]

Step-by-step explanation:

Using BODMAS

[tex]6\frac{1}{2} \times (\frac{8}{9} \div\frac{13}{18}) + ( \frac{3}{4} )\ of \ 3\frac{1}{5} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ [ \ solving \ expression \ inside \ bracket \ ]\\\\\frac{13}{2} \times (\frac{8}{9} \times \frac{18}{13}) + (\frac{3}{4}) \ of \ \frac{16}{5} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ [ \ \frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c} \ ]\\\\\frac{13}{2} \times (\frac{16}{13}) + (\frac{3}{4}) \ of \frac{16}{5} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ [ \ solving \ of \ ] \\\\[/tex]

[tex]\frac{13}{2} \times (\frac{16}{13} ) + (\frac{3}{4} \times \frac{16}{5} )\\\\\frac{13}{2} \times (\frac{16}{13} ) + \frac{12}{5} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ [\ solving \ \times \ expressions \ ] \\\\(\frac{13}{2} \times \frac{16}{13}) + \frac{12}{5}\\\\8 + \frac{12}{5}\\\\\frac{40 + 12}{5}\\\\\frac{52}{5}\\\\10\frac{2}{5}[/tex]