Find the length of the third side. If necessary, round to the nearest tenth.​

king jon un

Step-by-step explanation:

Answer: 16cm

Step-by-step explanation:

The radius is half of the diameter so you would have to double the radius.

Answer:

16cm

Step-by-step explanation:

The diameter of a circle is double the radius, so if a circle has a radius of 8cm, it has a diameter of 16cm because that's double 8cm.

Answer:

D

Step-by-step explanation:

{2l+2w=62}

1-2w=1

I don't know the answer its not in my syllabus nor I was thought this one

Answer:

8

Step-by-step explanation:

Answer: 8

Step-by-step explanation: 10 / 1.25 = 8

Answer:

y=-5x+9

Step-by-step explanation:

y=-5x+b

y=4 x=1

4=-5(1)+b

9=b

Answer:

x < - 10

Step-by-step explanation:

5 - 3x > 35

-3x > 35 - 5

-3x > 30

Divide both sides by 3

-x > 10

Divide both sides by - 1

x < - 10

The inequality sign will change due to the negative sign.

Answer:

5^9 : C

Step-by-step explanation:

I got the answer righttttt !!

Answer:

C

Step-by-step explanation:

i got it right

Answer:

the exact form is 22/5

decimal form is 4.4

mixed number form is 4 2/5

Step-by-step explanation

isolate the variable by dividing each side by factors that don't contain the variable

Answer: Look below =3

The greatest common factor of numerator and denominator is (x-4).

Answer:

Step-by-step explanation:

g(x) is vertical translation of f(x) by -12 units

Step-by-step explanation:

[tex] 200 = \pi{r}^{2} \\ {r}^{2} = \frac{200}{\pi} = 63.66 \\ r = 7.97 = 8[/tex]

Answer:

96

Step-by-step explanation:

Answer:

The answer is below

Step-by-step explanation:

The sprinklers have a radius of 5 ft each. Since the larger semicircle (entire lawn) has a diameter that is formed from the 2 semicircles, therefore the radius of the larger semicircle is 10 ft.

Area that wont be watered can be gotten by subtracting the area of the two smaller circles from the area of larger semicircle.

Area that wont be watered = 1/2(π * 10²) - 2[1/2(π * 5²)] = 50π - 25π = 25π ft²

Answer:

$1500

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 20%/100 = 0.2 per year,

then, solving our equation

I = 500 × 0.2 × 10 = 1000

I = $ 1,000.00

The simple interest accumulated

on a principal of $ 500.00

at a rate of 20% per year

for 10 years is $ 1,000.00.

Answer:

X=200

First your going to add all sides together. Once you finish you should get

50+55+90=195

after you got your answer your going to round to the tenths if it's higher than 5 your going to make it 200 but if it's lower than 5 than your going to make it 180.

So in our case because it's 195 we're going to turn it into a 200.

I hope this helps

Answer:

The answer is 40 degrees

Answer:

14-2x=4*2x-38

Step-by-step explanation:

Answer:

[tex] \frac{73}{48} [/tex]

Step-by-step explanation:

.......

Answer:

Bueno, sí y no. Si está multiplicando dos términos como (x - 2) y (x - 2), usaría el método FOIL: primero, adentro, afuera, último. Vea el diagrama adjunto. Los dos signos negativos se cancelarían entre sí solo al multiplicar los últimos valores. Avísame si necesitas más explicaciones.

-cjhunter.26

Answer:

6[tex]x^{3}[/tex]- 19[tex]x^{2}[/tex]+[tex]x[/tex]+6

Step-by-step explanation:

Answer:

6x³ - 19x² + x + 6

Step-by-step explanation:

Answer:

9x^2 - 10x -4

Step-by-step explanation:

It is set up like this

     9x^2 - 8x

-              (x-2)2

First solve (x-2)2

the answer is (2x-4)

so now you can do this instead

    9x^2 - 8x

-              2x - 4

----------------------------------

9x^2 - 10x +4

9x^2 minus zero is 9x^2

-8x-2x is -10x

0- -4 is 4 because that is like saying 0 + 4 because double negatives equal a positive

A simpler way is to change all the numbers to the opposite sign and then change the minus to a plus

like this

    9x^2 - 8x

+              -2x + 4

----------------------------------

9x^2 - 10x +4

Answer:

8x^2-4x-4

Step-by-step explanation:

On delta math

Answer:

It will take 3.65 seconds at the rate it's being poured.

Step-by-step explanation:

Answer:

$3

Step-by-step explanation:

Because you have to also think about tax of the item. Plus add them both up and it costs $2.24 without tax. Which means it's already above $2.

Answer:

products - -3x and 6x^2

factors - 8 and 2x

Step-by-step explanation:

Answer:

-8x would go in the box above -16x and -8 would go in the other box

Answer:

182

Step-by-step explanation:

Add them all which is 178 and subtract that number from 360.

370-178=182

Answer:

24 = x

Step-by-step explanation:

You use Pythagorean theorem. Since the normal equation is [tex]a^{2} + b^{2} =c^{2}[/tex], you already have the [tex]c^{2}[/tex] and another side which can be [tex]a^{2}[/tex] or [tex]b^{2}[/tex].

Because you have the hypotenuse and a side , your equation looks like this now: [tex]7^{2} +b^{2} = 25^{2}[/tex]

and when you solve for be you just subtract [tex]25^{2} -7^{2}[/tex] to get 24.

Answer:

Answer :

8/-11

y=8 x=-11

Answer:

16 - 8 / 9 - 20

Step-by-step explanation:

y2 = 16 y1 = 8

x2 = 9 x1 = 20

your answer is going to be 8/-11

Solution :

We have to prove that [tex]$\overline{A \cup B} = \overline{A} \cap \overline{B}$[/tex]   (De-Morgan's law)

Let  [tex]$x \in \bar{A} \cap \bar{B}, $[/tex] then [tex]$x \in \bar{A}$[/tex] and [tex]$x \in \bar{B} $[/tex]

and so [tex]$x \notin \bar{A}$[/tex] and [tex]$x \notin \bar{B} $[/tex].

Thus, [tex]$x \notin A \cup B$[/tex] and so [tex]$x \in \overline{A \cup B}$[/tex]

Hence, [tex]$\bar{A} \cap \bar{B} \subset \overline{A \cup B}$[/tex]   .........(1)

Now we will show that [tex]$\overline{A \cup B} \subset \overline{A} \cap \overline{B}$[/tex]

Let [tex]$x \in \overline{A \cup B}$[/tex] ⇒ [tex]$x \notin A \cup B$[/tex]

Thus x is present neither in the set A nor in the set B, so by definition of the union of the sets, by definition of the complement.

[tex]$x \in \overline{A}$[/tex] and  [tex]$x \in \overline{B}$[/tex]

Therefore, [tex]$x \in \overline{A} \cap \overline{B}$[/tex] and we have [tex]$\overline{A \cup B} \subset \overline{A} \cap \overline{B}$[/tex]  .............(2)

From (1) and (2),

[tex]$\overline{A \cup B} = \overline{A} \cap \overline{B}$[/tex]

Hence proved.