Find the maximum/minimum value of the quadratic function q² + 22q = y - 85 by
completing the square method.
O-36
O-48
C
-24
-64

Answer: C) 81

Step-by-step explanation:

Since Andy chooses a card and replaces it before choosing another card, each choice is independent and the total number of possible outcomes is the product of the number of choices for each card.

There are 4 red cards, 3 blue cards, and 2 green cards, so there are a total of 4+3+2=9 cards to choose from.

For each choice, Andy has 9 options. Since he does this twice, the total number of possible outcomes is:

9 x 9 = 81

Therefore, the answer is C) 81.

Answer:

If the fire truck is parked 25 feet away from the high rise and the ladder on the truck reaches 100 feet, we can use the Pythagorean theorem to find out how high up the high rise the ladder can reach.

Let's assume that the height the ladder can reach is "x". Then, we can set up the following equation:

25^2 + x^2 = 100^2

Simplifying this equation, we get:

625 + x^2 = 10000

Subtracting 625 from both sides, we get:

x^2 = 9375

Taking the square root of both sides, we get:

x = sqrt(9375)

x ≈ 96.81

Therefore, the ladder on the fire truck can reach a height of approximately 96.81 feet up the high rise

The value of d/c = 8, when the given graph represents the equation f(x) = 5.4321*(2)ˣ, and A (1, c), and B (4, d) pass through the graph.

The graph of an equation passes through all the points that satisfy the given equation. The graph shows a curve joining all those points.

In the question, we are given a graph and its equation f(x) = 5.4321*(2)ˣ.

We are given the coordinates of two points on graphs A: (1, c) and B: (4, d).

We know that any point of the form (x, y) which passes through the graph of the equation, satisfies the equation.

∴ A (1, c) and B (4, d) satisfies the equation f(x) = 5.4321*(2)ˣ.

∴ c = 5.4321*(2)¹ = 5.4321 * 2

d = 5.4321*(2)⁴ = 5.4321 * 16

∴ d/c = (5.4321*16)/(5.4321*2) = 16/2 = 8.

∴ The value of d/c = 8, when the given graph represents the equation f(x) = 5.4321*(2)ˣ, and A (1, c), and B (4, d) pass through the graph.

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When an isοsceles right triangle has a base οf x-2 and a height οf x-2. The area οf the triangle is 50 square inches then Using A=1/2 bh tο find the area οf a triangle is 1/2 (x-2)(x-2) = (x-2)²/2, and  12 inches is the value οf x?

An isοsceles right triangle has twο equal legs and the length οf the hypοtenuse is [tex]\sqrt{(2)[/tex] times the length οf a leg. In this case, bοth legs have the length x-2, sο the length οf the hypοtenuse is (x-2)*sqrt (2).

The area οf the triangle is given by A=1/2 bh, where b is the base and h is the height. In this case, b=h=x-2, sο the area is:

A = 1/2 (x-2)(x-2) = (x-2)²/2

Area is 50, sο we can set up an equatiοn:

(x-2)²/2 = 50

Multiplying bοth sides by 2 gives:

(x-2)² = 100

Taking the square rοοt οn bοth sides gives:

x-2 = 10 οr x-2 = -10

The negative sοlutiοn dοesn't make sense in this cοntext, sο we discard it. Therefοre, we have:

x-2 = 10

Adding 2 tο bοth sides gives:

x = 12

Therefοre, the value οf x is 12 inches.

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When an isοsceles right triangle has a base οf x-2 and a height οf x-2. The area οf the triangle is 50 square inches then Using A=1/2 bh tο find the area οf a triangle is 1/2 (x-2)(x-2) = (x-2)²/2, and  12 inches is the value οf x.

An isοsceles right triangle has twο equal legs and the length οf the hypοtenuse is  times the length οf a leg. In this case, bοth legs have the length x-2, sο the length οf the hypοtenuse is (x-2)*sqrt (2).

The area οf the triangle is given by A=1/2 bh, where b is the base and h is the height. In this case, b=h=x-2, sο the area is:

A = 1/2 (x-2)(x-2) = (x-2)²/2

Area is 50, sο we can set up an equatiοn:

(x-2)²/2 = 50

Multiplying bοth sides by 2 gives:

(x-2)² = 100

Taking the square rοοt οn bοth sides gives:

x-2 = 10 οr x-2 = -10

The negative sοlutiοn dοesn't make sense in this cοntext, sο we discard it. Therefοre, we have:

x-2 = 10

Adding 2 tο bοth sides gives:

x = 12

Therefοre, the value οf x is 12 inches.

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Cold fronts generally move faster than warm fronts because cold air is denser and thus, moves more quickly. Precipitation with a cold front typically covers a broader area, especially during the winter.

On the other hand, warm fronts move more slowly as they are characterized by the gradual lifting of warm air over colder air. Cold fronts also typically have steeper slopes than warm fronts. This is because the leading edge of a cold front is more abrupt.

With a steep rise in the cold air mass. In contrast, the leading edge of a warm front has a gentler slope as the warm air gradually rises over the colder air.

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Answer:

$38.08

Step-by-step explanation:

12% of 34.00 as an equation would be [tex]34*0.12[/tex], [tex]34*0.12=4.08[/tex] so we add 4.08 to the total of the lunch already. [tex]34.00+4.08=38.08[/tex]. So the answer is $38.08. Hope this helps :)

The area of the circle is approximately 346.36 square centimeters.

Area is a mathematical concept that refers to the amount of space that is inside a two-dimensional shape or surface. It is typically measured in square units, such as square meters (m² or square centimeters (cm²).

The diameter of a circle is the distance across the circle passing through its center. It is twice the length of the circle's radius.If you know the diameter of a circle, you can calculate its radius by dividing the diameter by 2: radius = diameter/2

In the given question,

The diameter (d) of a circle is the distance across the circle passing through the center.

If the diameter of the circle is 21 cm, then the radius (r) of the circle (which is half of the diameter) is:

r = d/2 = 21/2 = 10.5 cm

The formula for the area (A) of a circle is:

A = πr²

where π (pi) is a mathematical constant that represents the ratio of the circumference of a circle to its diameter, approximately equal to 3.14159.

Substituting the value of r into the formula, we get:

A = π(10.5)² A = 346.36 cm²  (rounded to two decimal places)

Therefore, the area of the circle is approximately 346.36 square centimeters.

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99% confidence interval is that the true population proportion of adults who say national identity is strongly tied to birthplace in Country A is between 30.7% and 37.3%.

The confidence interval is a set of values that, with a given level of certainty, contains the real population parameter. The likelihood that the genuine population parameter falls inside the interval is represented by the degree of confidence. In this instance, we created 99% confidence intervals for the percentage of individuals in each demographic who claim that national identity is highly correlated with birthplace. This indicates that 99% of the intervals we build would include the genuine population percentage if the survey were to be repeated numerous times.

The confidence interval is given using the formula:

CI = p ± z*(√((p*(1-p))/n))

Using the given values for different intervals the 99% for different countries are:

For Country A we have:

p = 0.34

n = 1007

z = 2.58 (based on a 99% confidence level)

CI = 0.34 ± 2.58*(√((0.34*(1-0.34))/1007)) = 0.307 to 0.373

For Country B we have:

p = 0.22

n = 1005

z = 2.58

CI = 0.22 ± 2.58*(√((0.22*(1-0.22))/1005)) = 0.187 to 0.253

For Country C we have:

p = 0.29

n = 1016

z = 2.58

CI = 0.29 ± 2.58*(√((0.29*(1-0.29))/1016)) = 0.259 to 0.321

For Country D we have:

p = 0.5

n = 1016

z = 2.58

CI = 0.5 ± 2.58*(√((0.5*(1-0.5))/1016)) = 0.469 to 0.531

For Country E we have:

p = 0.14

n = 1000

z = 2.58

CI = 0.14 ± 2.58*(√((0.14*(1-0.14))/1000)) = 0.108 to 0.172.

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The profit-maximizing combination of resources for a firm is  MRPl / Pl = MRPc / Pc = 10/2 = 5/1 . The correct option is D).

The profit-maximizing combination of resources for a firm is determined by the equality of the marginal revenue product (MRP) per unit of input (labor, L, or capital, C) to the price per unit of input.

Therefore, the equation that represents the profit-maximizing combination of resources for a firm is:

MRPl / Pl = MRPc / Pc

where MRPl is the marginal revenue product of labor, Pl is the price of labor, MRPc is the marginal revenue product of capital, and Pc is the price of capital.

Among the given options, only option D satisfies the above equation. Therefore, option D represents the profit-maximizing combination of resources for a firm.

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_____The given question is incomplete, the complete question is given below:

Which of the following equations represent the profit-maximising combination of resources for a firm?

A. MRPl / Pl = MRPc / Pc = 1

B. MRPl / Pl = MRPc / Pc = 5

C. MRPl / Pl = MRPc / Pc = 10/10 = 5/5

D. MRPl / Pl = MRPc / Pc = 10/2 = 5/1

The equation of the line is y = -1/2 + 13/2.

The point is (3, 5).

An equation of line is x + 2y = 5.

To determine the slope intercept form of the equation using the point and line we first determine the slope of the equation from the given line.

Convert the equation of line in slope intercept form.

x + 2y = 5

Subtract x on both side, we get

2y = -x + 5

Divide by 2 on both side, we get

y = -1/2 x + 5

On comparing with y = mx + c, where m is slope, we get

m = -1/2

Now the equation of the line is;

y - y₁ = m(x - x₁)

y - 5 = -1/2(x - 3)

Simplify the bracket

y - 5 = -1/2x + 3/2

Add 5 on both side, we get

y = -1/2x + 3/2 + 5

y = -1/2 + 13/2

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The complete question is:

Write an equation of the line containing the given point and parallel to the given line. Express your answer in the form y = mx + b.

(3, 5); x + 2y = 5

The equation of the line is ____ . (Type an equation Type your answer in slope intercept form. Use integers or fractions for any numbers in the equation. Simplify your answer)

The proof that the lines CD and XY are parallel is shown below in paragraghs

Given that

∠CAY ≅ ∠XBD

This means that the angles CAY and XBD are congruent angles

The above means that

By the corresponding angles, we have

∠BXY = ∠AYX

∠ACD = ∠BDC

By the congruent angles above, the following lines are parallel

Line AC and BX

Line AY and BD

Line CD and XY

Hence, the lines CD and XY are parallel

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In the context of data-flow diagrams (DFDs), a(n) option a. data-flow line shows either the source or destination of the data.

In data-flow diagrams (DFDs), an entity symbol represents an external agent or entity that interacts with the system being modeled. It could be a person, organization, or system that sends or receives data from the system being modeled. An entity symbol is represented as a rectangle with its name written inside it. It shows either the source or destination of the data in the DFD. An example of an entity symbol in a DFD could be a customer who provides orders to a company, or a supplier who delivers goods to a company. The entity symbol helps to illustrate the flow of data between external entities and the system being modeled.

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Answer:

Step-by-step explanation:

Since they are traveling in the same direction, the distance between them increases at a rate of the difference of their speeds.

The relative speed of train A with respect to train B is:

105 kmph - 87 kmph = 18 kmph

In three hours, the distance between them will be:

Distance = Speed x Time

Distance = 18 kmph x 3 hours

Distance = 54 km

Therefore, the two trains will be 54 kilometers apart after three hours.

For the standard normal curve, the area to the left of 0.1 is the same as the area to the right of 0.9 is true . So, the correct answer is D.

The standard normal curve is a normal distribution with a mean of 0 and a standard deviation of 1. This curve is often used in statistics to model natural phenomena, and it has many important properties.

Option A is incorrect because the area under the standard normal curve between 0 and 2 is not twice the area between 0 and 1. The area under the curve increases as we move away from the mean, so the area between 0 and 2 will be greater than the area between 0 and 1.

Option B is also incorrect because the area under the standard normal curve between 0 and 2 is not half the area between -2 and 2. The area between -2 and 2 covers more of the curve than the area between 0 and 2, so the area between 0 and 2 will be smaller than half the area between -2 and 2.

Option C is incorrect because the standard normal curve does not have a fixed IQR (interquartile range). The IQR depends on the quartiles of the distribution, which can vary depending on the sample size and the distribution's shape.

Option D is the correct answer because the standard normal curve is symmetric around the mean of 0. This means that the area to the left of any point on the curve is the same as the area to the right of its negative counterpart. Therefore, the area to the left of 0.1 is equal to the area to the right of 0.9.

Therefore, Correct option is D.

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The probability of P(B U E) is 0.5984, the probability of the complement of G (i.e. Gᶜ) is 0.6818, and the probability of C given F is 0.4706

To find the probability P(B U E), we need to add the frequencies in column B and row E, but since the cell where they intersect has already been counted in both, we need to subtract it once. Therefore:

P(B U E) = (6+13+17) + (15+20+10+45) - 43 = 73

Then we divide by the total number of observations:

P(B U E) = 73/122 = 0.5984 (rounded to four decimal places)

To find the probability of the complement of G (i.e. Gᶜ), we need to subtract the frequency in the cell where G and Total intersect from the total number of observations:

P(Gᶜ) = 1 - 39/122 = 0.6818 (rounded to four decimal places)

To find the probability of C given F, we need to divide the frequency in the cell where C and F intersect by the total frequency in the row where F is located:

P(C|F) = 24/51 = 0.4706 (rounded to four decimal places)

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Complete question is attached below

Answer: D 30

Step-by-step explanation:

4/10 + 30/100

2/5 + 3/10

7/10

NB: LEFT-HAND SIDE IS EQUAL TO THE RIGHT-HAND SIDE

you need to match it to the percentage of the fraction for example 1/2 is 50 percentage and than you do 1/4 is 25 percent.

Answer:

9 cm

Step-by-step explanation:

By the Triangle Inequality, any two sides of a triangle must be greater than the remaining side.

In order to minimize the perimeter, we will assume that 4 cm is the longest side.

Thus, the two remaining sides must be greater than 4.

Since we are given that the sum of the two remaining sides is a whole number, the smallest whole number value greater than 4 is 5.

Hence, the smallest perimeter possible 9 cm.

Answer: Below :)

Step-by-step explanation:

(a) The percentage of students and teachers who bought tickets to go on the trip is 65%. So the number of students and teachers who bought tickets can be found by multiplying the total number of students and teachers by 65%:

65/100 x 360 = 234

Therefore, 234 students and teachers bought tickets to go on the trip.

(b) Let the number of teachers who bought tickets be x. Then the number of male students who bought tickets is 3x, and the number of female students who bought tickets is 5x.

The total number of students and teachers who bought tickets is:

x + 3x + 5x = 9x

We know that 234 students and teachers bought tickets, so we can set up the following equation:

9x = 234

Solving for x, we get:

x = 26

So the number of teachers who bought tickets is 26, the number of male students who bought tickets is 78 (3x), and the number of female students who bought tickets is 130 (5x).

However, 4 of the female students who bought tickets did not go on the trip, so the actual number of female students who went on the trip is:

130 - 4 = 126

(c) The ratio of the number of male students who went on the trip to the number of female students who went on the trip is:

78/126

Simplifying this ratio by dividing both numerator and denominator by 6, we get:

13/21

Therefore, the ratio of the number of male students who went on the trip to the number of female students who went on the trip is 13:21.

Answer:

9 CDs

Step-by-step explanation:

r u d0mb? 45 divided by 5 = 5 10 15 20 25 30 35 40 45

count the numbers

BOOM ANSWER

A parametric equation is one where the x and y coordinates of the curve are both written as functions of another variable called a parameter; this is usually given the letter t or θ . And the value of a= 8, b= 1, c= -2 and d= 0.

Equation of this form is known as a parametric equation; it uses an independent variable known as a parameter (often represented by t) and dependent variables that are defined as continuous functions of the parameter and independent of other variables.
You require 4 independent solutions because there are 4 unknowns.  You can put two equations at each end point if you know t at each end point. (one for the x value and one for the y value).
At (8,-2), time is equal to zero as follows: 8 = a + bt = a + b(0)  a = 8 -2 = c + dt = c + d(0)  c = -2
At (9,-2), t = 1 because 9 = a + bt = 8 + b(1)  b = 1 and -2 = c + dt = -2 + d(1)  d = 0.
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Answer:

[tex]\dfrac{4096\pi}{5}\approx 2573.593\; \sf (3\;d.p.)[/tex]

Step-by-step explanation:

The shell method is a calculus technique used to find the volume of a solid revolution by decomposing the solid into cylindrical shells. The volume of each cylindrical shell is the product of the surface area of the cylinder and the thickness of the cylindrical wall. The total volume of the solid is found by integrating the volumes of all the shells over a certain interval.

The volume of the solid formed by revolving a region, R, around a vertical axis, bounded by x = a and x = b, is given by:

[tex]\displaystyle 2\pi \int^b_ar(x)h(x)\;\text{d}x[/tex]

where:

[tex]\hrulefill[/tex]

We want to find the volume of the solid formed by rotating the region bounded by y = 0, y = √x, x = 0 and x = 16 about the y-axis.

As the axis of rotation is the y-axis, r(x) = x.

Therefore, in this case:

[tex]r(x)=x[/tex]

[tex]h(x)=\sqrt{x}[/tex]

[tex]a=0[/tex]

[tex]b=16[/tex]

Set up the integral:

[tex]\displaystyle 2\pi \int^{16}_0x\sqrt{x}\;\text{d}x[/tex]

Rewrite the square root of x as x to the power of 1/2:

[tex]\displaystyle 2\pi \int^{16}_0x \cdot x^{\frac{1}{2}}\;\text{d}x[/tex]

[tex]\textsf{Apply the exponent rule:} \quad a^b \cdot a^c=a^{b+c}[/tex]

[tex]\displaystyle 2\pi \int^{16}_0x^{\frac{3}{2}}\;\text{d}x[/tex]

Integrate using the power rule (increase the power by 1, then divide by the new power):

[tex]\begin{aligned}\displaystyle 2\pi \int^{16}_0x^{\frac{3}{2}}\;\text{d}x&=2\pi \left[\dfrac{2}{5}x^{\frac{5}{2}}\right]^{16}_0\\\\&=2\pi \left[\dfrac{2}{5}(16)^{\frac{5}{2}}-\dfrac{2}{5}(0)^{\frac{5}{2}}\right]\\\\&=2 \pi \cdot \dfrac{2}{5}(16)^{\frac{5}{2}}\\\\&=\dfrac{4\pi}{5}\cdot 1024\\\\&=\dfrac{4096\pi}{5}\\\\&\approx 2573.593\; \sf (3\;d.p.)\end{aligned}[/tex]

Therefore, the volume of the solid is exactly 4096π/5 or approximately 2573.593 (3 d.p.).

[tex]\hrulefill[/tex]

[tex]\boxed{\begin{minipage}{4 cm}\underline{Power Rule of Integration}\\\\$\displaystyle \int x^n\:\text{d}x=\dfrac{x^{n+1}}{n+1}(+\;\text{C})$\\\end{minipage}}[/tex]

Answer:

The probability that Sara whassell four extended warranties tomorrow is 0.1046

Step-by-step explanation:

Please hit brainliest if this helped! If you have any questions, please comment.

We can use the Poisson probability formula to calculate the probability of selling 4 extended warranties tomorrow:

P(X = k) = (e^(-λ) * λ^k) / k!

where λ is the average number of extended warranties sold per day and k is the number of extended warranties sold.

In this case, λ = 2.7 and k = 4. So, plugging in the values, we get:

P(X = 4) = (e^(-2.7) * 2.7^4) / 4!

P(X = 4) ≈ 0.1046

Therefore, the probability that Sara will sell four extended warranties tomorrow is approximately 0.1046, rounded to four decimal places.

Answer:

52

Step-by-step explanation:

10.40 TIMES 3

Answer:

Area = 559.17 square feet

Perimeter = 94.26 ft

Step-by-step explanation:

Make sure all the units are the same and consistent.

r = radius of semi-circle

 = [tex]\frac{Diameter}{2}[/tex]

 = [tex]\frac{18}{2}[/tex] ft

 = 9 ft

Area of composite figure = Area of rectangle + Area of semi-circle:

                                          = [Length × Breadth] + [[tex]\frac{1}{2}[/tex] × (Area of circle)]
                                          = [24 ft × 18 ft] + [[tex]\frac{1}{2}[/tex] × ([tex]\pi r^{2}[/tex])]

                                          = 432 [tex]ft^{2}[/tex] + [[tex]\frac{1}{2}[/tex] × ([tex]\pi 9^{2}[/tex])] [tex]ft^{2}[/tex]

                                          = 432 + [[tex]\frac{1}{2}[/tex] × (3.14) ×(81)]

                                          = 559.17[tex]ft^{2}[/tex]

Perimeter of composite figure =

     Circumference of semi-circle + 3 outer sides of rectangle:

 = [[tex]\frac{1}{2}[/tex] × [tex]2\pi r[/tex]] + [24 + 18 + 24]

 = ( [tex]\pi r[/tex] + 66) ft

 = [(3.14)(9) + 66] ft

 = 94.26 ft

The given statements are true or false are shown below, about linear system has n variables and m equations, then the augmented matrix has n rows.

First, let's write how A and C look like.

A = [C|b], where b is the constant matrix.

(a) False.

Example

[tex]\left[\begin{array}{ccc}1&0&2\\0&1&3\\\end{array}\right][/tex]

We can see that z = t and so we have infinitely many solutions but there's no row of zeros.

(b) False.

Example

[tex]\left[\begin{array}{cc}1&0&0\1&1&0&0\\\end{array}\right][/tex]

Here; x1 = 1 and x2 = 1 is a unique solution and we have a row of zeros.

(c) True.

In the row-echelon form, the last row is either a row of zeros or a row that contains a leading 1. If the row has a leading 1, then there is a solution. Since we assume there is no solution, then the row must be a row of zeros.

(d) False.

Example

[tex]\left[\begin{array}{cc}1&3\\0&0\end{array}\right][/tex]

Here; x₁ = 1 − 3t and x2 = t. Thus, the system is consistent.

(e) True.

Suppose we have a typical equation in a system

а1x1 + A2X2 + ··· + anxn = b

Now, if b≠0 and x1 = x2 = ··· = x₂ = 0, then the system is Xn inconsistent. But, if b = 0, then we have a solution.

(f) False.

Example

[tex]\left[\begin{array}{cc}1&2&0&0\end{array}\right][/tex]

If a = 0, then it's consistent(infinitely many solutions) but if a 0, then it's inconsistent.

(g) Ture.

Since the rank would be at most 3 and this will lead to a free variable (4 columns in C and the rank is 3, so there is at leat 1 free variable). Thus, the system has more thatn one solution.

(h) True.

Because the rank is the number of leading 1's lying in different rows and A has 3 rows. Thus, the rank ≤ 3.

(i) False.

Because we could have a row of zeros in C and a leading 1 in A. In other words, a31 = a32 = A33 = A34 = 0 and c3 1. This makes the system inconsistent.

(j) True.

If the rank of C = 3, then there will be a free variable and this means the system is consistent.

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Complete question:

In each case either show that the statement is true, or give an example showing it is false. (a) If a linear system has n variables and m equations, then the augmented matrix has n rows. quations • ( *b) A consistent linear system must have infinitely many solutions. . (c) If a row operation is done to a consistent linear system, the resulting system must be consistent. (d) If a series of row operations on a linear system results in an inconsistent system, the original system is inconsistent.

Answer:

a)220 4 leaf clovers, 780 3 leaf clovers b)440 four leaf clovers, 1560 3 leaf clovers

Step-by-step explanation:

100:1000=1:10 22:x=1:10 x=220

220x2=440

1000-220=780

780x2=1560

The perimeter of the pond is 2.92 meters.

A right-angled triangle is a triangle in which one of the angles measures exactly 90 degrees, also known as a right angle.

The side opposite the right angle is called the hypotenuse, and the other two sides are called the legs.

The perimeter of a right-angled triangle is the sum of the lengths of its three sides.

Here we have

The Hypotenuse of the triangle is 1.46 m    

The angle between hypotenuse and perpendicular height = 73°

From triagonometric ratios,

=> cos A = Perpendicular height/ Hypotenuse.

=> cos (73) = Perpendicular height/1.46

=> Perpendicular height = 1.46 × 0.29 = 0.42 m

As we know from Pythagoras' theorem,

Hypotenuse² = side² + side²    

Side = √Hypotenuse² - side²  

= √[(1.46)²- (0.42)²]  = 1.04

Therefore, the sides of the pond are 1.46 m, 0.42 m, and 1.04

Hence, perimeter of the pond =  1.46 + 0.42 + 1.04 = 2.92 meters  

Therefore,

The perimeter of the pond is 2.92 meters.

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The complete Question is given below

Answer:

x²

Step-by-step explanation:

[tex]{ \tt{ \frac{ {x}^{ - 3} . {x}^{2} }{ {x}^{ - 3} } }} \\ \\ \dashrightarrow{ \tt{x {}^{( - 3 + 2 - ( - 3))} }} \\ \dashrightarrow{ \tt{ {x}^{( - 3 + 2 + 3)} }} \: \: \: \: \\ \dashrightarrow{ \boxed{ \tt{ \: \: \: \: {x}^{2} \: \: \: \: \: \: }}} \: \: \: \: [/tex]