Find the missing length to the nearest tenth of a unit.

Answer:

8? I think I'm not quite sure. lmk

Answer:

C

Step-by-step explanation:

it's rational because 6.24 can be 68/33

sorry if I'm wrong!!

Answer:

[tex]\frac{5^3s^3t^6}{s^4 x 50t}[/tex]

After that, all terms reduce as follows: the [tex]5^{2}[/tex] with the 25 in 50, the s at the numerator with the s in the denominator, and a t from the denominator with one unit from the exponent of t in the numerator.

Answer:

The ratio of pounds of chicken to cups of rice is 2 to 3.

Step-by-step explanation:

3 rice: 2 chicken

3:2 ratio

can be written either number first

Answer:

h s m s dhoni bold sin men farhan akhtar ne

its a triangle no? just  3D

Answer:

i cant see the picture with the question

Step-by-step explanation:

i cant see, sorry

Answer:

23,760/12=1980

1980x2=3960

Answer:

32%

Step-by-step explanation:

Let x be the mean of the values and σ their standard deviation.

Since the minimum value of the diameter of the washers is 1.53 mm, then

x - σ = 1.53 mm  (1)

Also, the maximum value of the diameter of the washers is 1.65 mm, then

x + σ = 1.65 mm  (2)

Adding (1) and (2), we have

x - σ = 1.53 mm

+

x + σ = 1.65 mm  

2x = 3.18

x = 3.18/2

x = 1.59 mm

Subtracting (1) and (2), we have

x - σ = 1.53 mm

-

x + σ = 1.65 mm  

-2σ = -0.12

σ = -0.12/-2

σ = 0.06 mm

Since the diameter of the washers are required to be between 1.53 millimeters and 1.65 millimeters long, and x - σ = 1.53 mm to x + σ = 1.65 mm are the required values, 68% of the washers lie in this range. The other values lie outside this range. The amount that the factory would have to discard is 100% - 68% = 32%

This question is based on the percentage. Thus, 32%  of washers will the factory have to discard.

Given:

The diameter of the washers are required to be between 1.53 millimeters and 1.65 millimeters long.

We need to determined the percentage of washers will the factory have to discard.

According to question,

Let x be the mean and σ be their standard deviation.

The minimum value of the diameter of the washers is 1.53 mm.

Then,

x - σ = 1.53 mm  (1)

Also, the maximum value of the diameter of the washers is 1.65 mm, then

x + σ = 1.65 mm  (2)

Adding (1) and (2), we have

   x - σ = 1.53 mm  

+  x + σ = 1.65 mm  

⇒ 2x = 3.18

We get,

x = 1.59 mm

Subtracting (1) and (2), we have

 x - σ = 1.53 mm

- x + σ = 1.65 mm  

⇒ -2σ = -0.12

We get,

σ = 0.06 mm

Therefore, the diameter of the washers are required to be between 1.53 millimeters and 1.65 millimeters long, and x - σ = 1.53 mm to x + σ = 1.65 mm are the required values, 68% of the washers lie in this range.

And the other values lie outside this range. The amount that the factory would have to discard is 100% - 68% = 32%.

Thus, 32%  of washers will the factory have to discard.

For more details, prefer this link:

https://brainly.com/question/13703753

Answer:

B) 54 and 54

Step-by-step explanation:

72 + x + x = 180

2x + 72 = 180

2x = 180 - 72

2x = 108

x = 54

Answer:

∠x = 32°

∠y = 58°

∠z = 32°

Step-by-step explanation:

∠x = 180° - 148° = 32°  

∠z = 32° because it is vertical to ∠X (32°)

∠y = 90° - 32° = 58°

Answer:

3

Step-by-step explanation:

Answer:

His friend took one from 61 and added it to 39. That made it easy to mentally add 40 and 60 to get 100. Then he mentally added 28 to 100 to get 128.

Answer: I think it’s uhh I think it’s uhh i think it’s uh carrot

Step-by-step explanation:

Answer: 0

anything times 0 is 0

Answer:

3 teams and 29students in each team.

let, the team be x,y,&z

given all the team r equal so, x=y=z

x+y+z=87

3x=87

x=87/3

x=29

we get, x=y=z=29

hope it helps.

Answer:

[tex]4h^2-48.6h-72.9[/tex]

Step-by-step explanation:

[tex](2h+2.7) (2h-27)\\4h^2-54h+5.4h-72.9\\4h^2-48.6h-72.9[/tex]

Answer:

4 miles per hour

Step-by-step explanation:

Answer:

4mph

Step-by-step explanation:

8 divided by 2 and boom the answer.Hope this helps.

Step-by-step explanation:

...hope it help u.... ..

Answer:

df(t)/dt = 10 - 0.8f(t)

Step-by-step explanation:

The net rate of change, df(t)/dt = rate in - rate out

The rate in = rate litter forms on ground = 10 g/cm²/yr

Since f(t) is the amount of litter present at time, t, in g/cm² the rate out = rate of decomposition = the percentage rate × f(t) = 80% per year × f(t) = 0.8f(t) g/cm²/yr

Since df(t)/dt = rate in - rate out

df(t)/dt = 10 - 0.8f(t)

So the desired differential equation is

df(t)/dt = 10 - 0.8f(t)

Answer:

i don't have lesion kau you forever i am sorry

Step-by-step explanation:

your browser to mo Lego house of blues festival

Using the Pythagorean theorem:

KL = sqrt( 8^2 + 5^2)

KL = sqrt( 64 + 25)

KL = sqrt(89)

KL = 9.43

The answer is 9.43

Answer:

Its already rounded. Rounded to tenths place would be 2.8

Step-by-step explanation:

5 or higher makes you round up. if its a 4 or lower it would stay the same.

Answer:

C. 10–15, 15–20, 20–25, 25–30, 30–35

Step-by-step explanation:

Answer:

D, 261

Step-by-step explanation:

Divide all of the answer choices by 9. The answer is the one with the whole number. 261/9=29 29=whole number so D is the answer.

Hope this helps! If it did, please give brainliest! It would help a lot! :D

Answer:

261

Step-by-step explanation:

If the farmer used 9 boxes and each had the same number, we need to find the number that's divisible by 9.

There's a great fact - a number is divisible by 9 if its sum of digits is divisible by 9.

Let's use that fact on the answers first:

281 -> 2 + 8 + 1 -> 11 -> 1 + 1 -> 2; not divisible by 9

273 -> 2 + 7 + 3 -> 12 -> 1 + 2 -> 3; not divisible by 9

261 -> 2 + 6 + 1 -> 9; divisible by 9

Please note that we could just say that 11 is not divisible by 9, but I wanted to show that we can do it again - nothing stops us and it still works.

To know why this method works, note that a number ABC is equal to:

100 * A + 10 * B + C = 99 * A + 9 * B + (A + B + C) = 9*(11*A + B) + (A + B + C)

And we know that 9*(11*A + B) is divisible by 9 because it's literally 9 times something. So A+B+C is equal to ABC minus something divisible by 9, and that proves what we needed.

[tex]hope \: it \: helps[/tex]