Find the point(s) at which the function f(x) = 5 - 2x equals its average value on the interval [0,4]. The function equals its average value at x=

Answers

Answer 1

Thus, the point(s) at which f(x) = 5 - 2x equals its average value on the interval [0,4] is x=5/2.

To find the point(s) at which the function f(x) = 5 - 2x equals its average value on the interval [0,4], we first need to find the average value of the function on this interval. The formula for the average value of a function f(x) on an interval [a,b] is:

average value = (1/(b-a)) * ∫[a,b] f(x) dx

In this case, a=0 and b=4, so the average value of f(x) on [0,4] is:

average value = (1/(4-0)) * ∫[0,4] (5-2x) dx
average value = (1/4) * [5x - x^2] from 0 to 4
average value = (1/4) * [(5(4) - 4^2) - (5(0) - 0^2)]
average value = (1/4) * (0)
average value = 0

So the average value of f(x) on [0,4] is 0. Now we need to find the point(s) where f(x) equals 0. We can set the function equal to 0 and solve for x:

5 - 2x = 0
2x = 5
x = 5/2

So the function f(x) equals its average value of 0 at x=5/2. Therefore, the point(s) at which f(x) = 5 - 2x equals its average value on the interval [0,4] is x=5/2.

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

Step 1

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Step-by-step explanation:

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Step-by-step explanation:

I hope this helps you have a wonderful day! :D

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Answers

Answer:

x = -2

Step-by-step explanation:

Answer:

x is -2

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

The equation of a line in slope- intercept form is

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Answers

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