For the reaction C + 2H2 → CH4, how many moles of hydrogen are needed to make 192.3 grams of methane, CH4?

Answer:

Luster: Silicon for example appears lustrous, but is not malleable or ductile (it is brittle - a characteristic of some nonmetals). It is a much poorer conductor of heat and electricity than the metals.8 May 2021

Elements: Oxygen; Carbon

Explanation:

hope it helps

Answer:

A

Explanation:

Answer:

A Magnet or Magnetic Filtration

Answer:

Magnetic Filtration

Explanation:

That is the answer

(a) distance measured with metre rule or tape rule

    time measured with stopwatch/ stop clock/ timer

    Average speed = total distance / time

(b) (i) decrease in speed

    (ii) Change in speed = a * t

        4.5 m/s

hope this helps......

Answer:

28/23

Explanation:

28 : 23

this is written as ,

28/23

u can convert into simplest form but in this question u can't so leave it as it is.

Answer:

P2 = 1.94 kPa

Explanation:

Given the following data;

Initial pressure = 2.36 kPa

Initial temperature = 62°C

Standard temperature = 0°C

Conversion:

Kelvin = 273 + C

Kelvin = 273 + 62 = 335 K

Kelvin = 273 + 0 = 273 K

To find the final pressure, we would use Gay Lussac's law;

Gay Lussac states that when the volume of an ideal gas is kept constant, the pressure of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Gay Lussac's law is given by;

[tex] PT = K[/tex]

[tex] \frac{P1}{T1} = \frac{P2}{T2}[/tex]

Making P2 as the subject formula, we have;

[tex] P_{2}= \frac{P1}{T1} * T_{2}[/tex]

[tex] P_{2}= \frac{2.36}{335} * 273 [/tex]

[tex] P_{2}= 0.0071 * 273 [/tex]

P2 = 1.94 kPa

a) The genotype is Hh. We simply combine the two given letters together to get this genotype.

b) The phenotype is Widow's peak. The uppercase letter is the dominant allele, while the lowercase is recessive. Any presence of the dominant allele (even a single letter) will mean the dominant phenotype will present itself. We can see that HH leads to Widow's peak phenotype, so that applies to Hh as well. Only when there isn't a dominant allele at all, the genotype hh, is when the recessive phenotype will show up.

Answer:

Hydrogen bonds

Covalent bonds

Van Der Walls Forces

Ionic Bonding

London Dispersion forces

Metallic bonding

Chemical bonds

Answer:

Gain 2, and become negatively charged

Explanation:

A full valence shell, thus stablilized, has 8 electrons, and so it would need two more, and when atoms gain electrons, they become negatively charged because there are now more electrons than protons (and so, when they lose electrons, they become positively charged). Hope this helps! :)

Answer: The oxygen gas has a pressure of 4 atm if my volume decreases to 1 L.

Explanation:

Given: [tex]V_{1}[/tex] = 2 L,        [tex]P_{1}[/tex] = 2 atm

[tex]V_{2}[/tex] = 1 L,          [tex]P_{2}[/tex] = ?

Formula used to calculate the new pressure is as follows.

[tex]P_{1}V_{1} = P_{2}V_{2}[/tex]

Substitute the values into above formula as follows.

[tex]P_{1}V_{1} = P_{2}V_{2}\\2 atm \times 2 L = P_{2} \times 1 L\\P_{2} = 4 atm[/tex]

Thus, we can conclude that the oxygen gas has a pressure of 4 atm if my volume decreases to 1 L.

Answer:

non-conductors of electricity.

Explanation:

One of the auxiliary pleasures of drinking tea is selecting accoutrements: utensils, cups, kettles, storage tins, and, of course, teapots. The choices are legion with a dazzling array of shapes, sizes, decorative touches. Sometimes that blinds us to one of the most important decisions we must make in teapot selection: its function!

One of the auxiliary pleasures of drinking tea is selecting accoutrements: utensils, cups, kettles, storage tins, and, of course, teapots. The choices are legion with a dazzling array of shapes, sizes, decorative touches. Sometimes that blinds us to one of the most important decisions we must make in teapot selection: its function!Your teapot-buying decision should be based first and foremost on size (options often go from one to six cups, sometimes larger). The next most important aspects are your personal preference for material (glass, ceramic or porcelain) and whether it will be used for brewing tea or pouring brewed tea. Other important factors include: whether it's easy to hold, pours well, and, of course, fits into your budget. A gigantic Majolica pot, festooned with monkeys and in a brilliant highly-glazed green, may warm your heart; but if when filled with tea it weighs five pounds and holds more than your family can drink, it will probably be better suited for the collector�s shelf than the tea table.

brainly me pls

Answer:

Bases Do not Change the Color of Blue Litmus.

I'd go with Option C.

Sodium Hydroxide.

Answer:

El Niño is a climate cycle in the Pacific Ocean with a global impact on weather patterns. The cycle begins when warm water in the western tropical Pacific Ocean shifts eastward along the equator toward the coast of South America. Normally, these warm water pools near Indonesia and the Philippines.

Explanation:

Explanation:

a chemical reaction that absorbs energy is known to be endothermic since heat is being taken in by the reaction. The value of the transition state would be 150 because you have to subtract the product's enthalpy and the reactant's enthalpy to obtain it. A positive value for the transition state also corroborates that the reaction is endothermic.

Answer:

a)22.2°C after adding magnesium

b)17.3°C before adding magnesium

c) 4.9 is change

Answer:

42,07%and 18,90%

Explanation:

Explanation:

I. Because an explosion is a very fast exothermic reaction

ll. it depends on the it's particle size

Answer:29.9 or 30

Explanation:

Total, 30.38 grams of chlorine gas can be formed from 50.0 grams of sodium chloride through electrolysis.

To calculate the mass of chlorine that can be formed from 50.0g of sodium chloride (NaCl) through electrolysis, we need to consider the balanced chemical equation for the electrolysis of NaCl;

2 NaCl (aq) → 2 Na (s) + Cl₂ (g)

From the balanced equation, we can see that 2 moles of NaCl produce 1 mole of chlorine gas (Cl₂).

Convert given mass of sodium chloride to moles.

Molar mass of NaCl = 22.99 g/mol (Na) + 35.45 g/mol (Cl)

= 58.44 g/mol

Moles of NaCl = 50.0 g / 58.44 g/mol ≈ 0.856 mol

Calculate moles of chlorine gas formed.

From the balanced equation, 2 moles of NaCl produce 1 mole of Cl₂.

Moles of Cl₂ = 0.856 mol / 2 ≈ 0.428 mol

Convert the moles of chlorine gas to mass.

Molar mass of Cl₂ = 2 × 35.45 g/mol

= 70.90 g/mol

Mass of Cl₂ = 0.428 mol × 70.90 g/mol

≈ 30.38 g

So, approximately 30.38 grams of chlorine gas can be formed from 50.0 grams of sodium chloride through electrolysis.

To know more about chlorine gas here

https://brainly.com/question/18981083

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Answer:

Organic molecules are important to living things because life is based on the properties of carbon.

Properties of Carbon

Carbon is an important element because it can form four covalent bonds.

Carbon skeletons can vary in length, branching, and ring structure.

The carbon skeletons contain the functional groups that are involved in biochemical

Explanation:

Hope it helps

Answer:

0.017 M

Explanation:

The balanced equation for the reaction is given below:

2H₃PO₄ + 3Ba(OH)₂ ⇌ Ba₃(PO₄)₂ + 6H₂O

From the balanced equation above,

The mole ratio of acid, H₃PO₄ (nₐ) = 2

The mole ratio of base, Ba(OH)₂ (n₆) = 3

Finally, we shall determine the concentration of the phosphoric acid, H₃PO₄. This can be obtained as follow:

Volume of acid, H₃PO₄ (Vₐ) = 125 mL

Volume of base, Ba(OH)₂ (V₆) = 63.7 mL

Concentration of base, Ba(OH)₂ (C₆) = 0.050M

Concentration of acid, H₃PO₄ (Cₐ) =?

CₐVₐ / C₆V₆ = nₐ/n₆

Cₐ × 125 / 0.05 × 63.7 = 2/3

Cₐ × 125 / 3.185 = 2/3

Cross multiply

Cₐ × 125 × 3 = 3.185 × 2

Cₐ × 375 = 6.37

Divide both side by 375

Cₐ = 6.37 / 375

Cₐ = 0.017 M

Thus, the concentration of the phosphoric acid, H₃PO₄ is 0.017 M

Answer:

This question is incomplete, the gravitational potential energy is 2.65 x 10^5 J

mass of the boulder = 866.7g

Explanation:

Potential energy (P.E) refers to the energy due to the position of a body. It can be calculated as follows:

P.E = m × g × h

Where;

m = mass of substance (g)

g = acceleration due to gravity (m/s²)

h = height (m)

According to the information provided in this question,

h = 31.2 m

g = 9.8m/s²

m = ?

P.E = 2.65 x 10^5 J

Using P.E = m × g × h

2.65 x 10^5 = m × 9.8 × 31.2

2.65 x 10^5 = 305.76m

265000 = 305.76m

m = 265000 ÷ 305.76

m = 866.69

mass of the boulder = 866.7g

What does botanist study?

[tex]\implies {\blue {\boxed {\boxed {\purple {\sf {D.\: Plants}}}}}}[/tex]

[tex]\bold{ \green{ \star{ \orange{Hope\:it\:helps.}}}}⋆[/tex]

Answer:

the pair of isotopes are b and e

the element with mass no of 19 is C

the element with atomic no 7is D

Explanation:

B and E are isotopes bcos they have the same atomic no, i.e no of protons. They bother have atomic no of 17 BUT have different mass no i.e sum of neutrons and protons.

(b)C is correct because the sum of the protons and neutrons is 19

(c) D because it has 7 protons

Answer:

La respuesta correcta es la opción A.

Explicación:

La densidad del corcho es 0.95g / cm3 por lo que se hundirá en la solución de acetona porque el corcho es más denso que la solución de acetona mientras que por otro lado, el corcho flotará en otros dos líquidos porque la densidad del corcho es menor que en otros dos líquidos o, en otras palabras, los dos líquidos son más densos que el corcho, por eso el corcho flotará en estos dos líquidos.

Explanation:

When a base dissolves in water it is an alkali and makes an alkaline solution.

...

Litmus.

Red Litmus Blue Litmus

Acidic solution Stays red Turns red

Neutral solution Stays red Stays blue

Alkaline solution Turns blue Stays blue

Answer:

17. 3,101.922

18. 1.2447441822

19. 288,057.12

20. 0.74497354

Answer:

this is the answer

I hope it helps you although

Answer:

i) ciclobutano

ii) 3-etil-4-metil ciclopenteno

Explanation:

Toda la idea de la nomenclatura IUPAC es permitir que la estructura de la sustancia se derive de su nombre y viceversa.

La nomenclatura IUPAC es un sistema universalmente aceptado para nombrar compuestos químicos.

los nombres de los compuestos enumerados son;

i) ciclobutano

ii) 3-etil-4-metil ciclopenteno