Four less than five times a number is 11. Find the number.

Answer:

1 month

Step-by-step explanation:

mark me brainlyest????

Answer:

273984828kdjsssdjdjdjdjddddeejddfj

Answer:

47

Step-by-step explanation:

First, all triangles' angles add up to 180 degrees. We would first have to figure out the measure of <QSR. To do this, add all angles you know. We have to assume <SQR is 90 degrees since it is aligned with the other triangle. So, 90+27=117. Then, we would do 180-117 to find <QSR since all triangles angles 180 degrees. This is 63. Then, because these triangles are along a 180 degree (straight) line, we would do <PSQ, 70, so 70+63 which equal 133, and then 180-133 since all angles equal 180. This is 47.

Answer:

Fraction: 10 and 5/8

Step-by-step explanation:

17 × 5/8

85/8

Answer:[tex]10\frac{5}{8}[/tex] or 10.625

Step-by-step explanation:

First of all, note that 17 is the same as 17/1 since 17 divided by 1 is 17. Therefore, start by setting up the problem like this:

[tex]\frac{17}{1} X \frac{5}{8}[/tex]

Multiply the numerators together (17 x 5 = 85) and multiply the denominators together (1 x 8 = 8) and make it into one fraction like so:

[tex]\frac{85}{8}[/tex]

Convert the improper fraction above to a mixed number to get the answer:

[tex]=10\frac{5}{8}[/tex]

Answer:

1) 85

2) 150

Step-by-step explanation:

The measure of a minor arc is EQUAL to the central angle

"The measure of a minor arc is equal to the measure of the central angle that intercepts the arc. We can also say that the measure of a minor arc is equal to the measure of the central angle that is subtended by the arc."

Answer:

what do we have to do in this?????

Answer:

x=5

Step-by-step explanation:

Hello There!

The angle labeled 20x and the angle that has a measure of 80 degrees are supplementary angles meaning the sum of the two is 180

so we can create an equation to solve for x

180=80+20x

step 1 subtract 80 from each side

80 - 80 cancels out

180-80=100

100=20x

step 2 divide each side by 20

100/20=5

20x/20=x

we´re left with x=5

Answer:

d. The relative frequency of the people that chose drama is 0.1[tex]\overline 6[/tex]

e. The relative frequency of the people that chose action is 0.2

Step-by-step explanation:

The result of the survey is expressed as follows;

C, C, R, R, D, R, H, H, C, A, A, R, A, A, A, R, R, H, H, H, C, H, A, R, D, D, D, D, H, R

Sorting the data, with Microsoft Excel, we get;

A,  A,  A,  A,  A,  A,  C,  C,  C,  C, D,  D,  D,  D,  D,  H,  H,  H,  H,  H,  H,  H,  R,  R,  R,  R,  R,  R,  R,  R

From the pivot table created with Microsoft Excel, we have

The frequency of As = 6

The frequency of Cs = 4

The frequency of Ds = 5

The frequency of Hs = 7

The frequency of Rs = 8

The sum of all frequency = 6 + 4 + 5 + 7 + 8 = 30

d. The relative frequency of the people that chose drama is given as follows;

[tex]Relative \, frequency = \dfrac{Frequency \ of \ observation}{Sum \ of \ all \ frequencies}[/tex]

The frequency of the people that chose drama = 5

The sum of all frequency = 30

[tex]Relative \, frequency \ of \ the \ people \ that \ chose \ drama = \dfrac{5}{30} = \dfrac{1}{6} = 0.1\overline 6[/tex]

The relative frequency of the people that chose drama = 0.1[tex]\overline 6[/tex]

e. The relative frequency of the people that chose action, RF action, is given as follows;

[tex]RF \ action = \dfrac{Frequency \ of \ the \ people \ that \ chose \ action}{Sum \ of \ all \ frequencies} = \dfrac{6}{30} = \dfrac{1}{5} = 0.2[/tex]

The relative frequency of the people that chose action, RF action = 0.2.

Answer:

x≥-5

Step-by-step explanation:

Hope this helps.

Answer:  78.5

Step-by-step explanation:

Well i said  78.5  to get the radius you have to divide the diameter by 2 to get your answer but you have to make and the area might be 78.5 because thats what we do in my grade which is 7th

Answer:

all i know is 6 is 72/30 because I'm busy right now sorry that I don't have the simplest form of answer

Answer:

6. 2 2/5

7. 66/145

8. 1 1/5

Step-by-step explanation:

Answer:

3x + 5y + 2

Step-by-step explanation:

Given:

4x + 5y - ( x - 2 )

Find:

Subtract value

Computation:

4x + 5y - ( x - 2 )

4x + 5y - x + 2

3x + 5y + 2

Answer:

B

Step-by-step explanation:

Answer:

26

Step-by-step explanation:

You take the 65 plyers multiplied by the 40 % then you get 2600. You take that divided by 100 and get 26

Answer:

20.x≤8

Step-by-step explanation:

20.X+5≤13

x≤13-5

x≤8

Answer:(0,-2)

Step-by-step explanation:

Answer: 6*10^5 > 3*10^4

Step-by-step explanation:

6*10^5 = 600000

3*10^4 = 30000

Answer:

if I'm not mistaken I think your answer will be B

The equivalent expressions for [tex]\sqrt{\frac{36a^8}{225a^2} }[/tex] are A, B and E.

Square root of a number is the value such that the value when multiplied to itself two times gives the original number.

It is denoted by the symbol √.

Given expression is [tex]\sqrt{\frac{36a^8}{225a^2} }[/tex].

There are five expressions in the left.

A. [tex]\sqrt{\frac{2(2)(3)(3)(a)(a)(a)(a)(a)(a)(a)(a)}{3(3)(5)(5)(a)(a)} }[/tex]

Here we have to multiply the terms in the numerator as well as in the denominator.

2(2)(3)(3) = 36 and 3(3)(5)(5) = 225

So this expression is equivalent to the given  [tex]\sqrt{\frac{36a^8}{225a^2} }[/tex].

B. [tex]\sqrt{\frac{4a^6}{25} }[/tex]

We know that, greatest common factor of 36 and 225 is 9.

36/9 = 4 and 225 / 9 = 25

Also a⁸ / a² = a⁸⁻² = a⁶

So this is also an equivalent expression.

C. [tex]\frac{6}{25} \sqrt{ \frac{a^8}{a^2} }[/tex]

This is not equivalent since √225 = 15, not 25.

D. [tex]\frac{6}{15} a^4[/tex]

This is also not equivalent since  [tex]\sqrt{ \frac{a^8}{a^2} }[/tex] = [tex]\sqrt{a^6}[/tex] = a³, not a⁴.

E. [tex]\frac{2}{5} a^3[/tex]

This is equivalent expression since √36 = 6 and √225 = 15.

[tex]\sqrt{\frac{36a^8}{225a^2} }[/tex] = [tex]\frac{6}{15}[/tex] [tex]\sqrt{ \frac{a^8}{a^2} }[/tex] = [tex]\frac{2}{5}[/tex] [tex]\sqrt{a^6}[/tex] = [tex]\frac{2}{5} a^3[/tex]

Hence the equivalent expressions are A, B and E.

Learn more about Expressions here :

https://brainly.com/question/28170201

#SPJ7

Your question is confusing. The image of the question is attached below.

Answer: 21 degrees

Step-by-step explanation:

In the evening, the temperature is 28 degrees and by midnight it has dropped 31 degrees lower, the temperature by midnight will be:

= 28° - 31°

= -3°

Between midnight and 4 am it goes down 6 more degrees. The temperature by 4am will be:

= -3° - 6°

= -9°

Then, by 9 am, the temperature goes up 30 degrees, the temperature at 9 am will then be:

= -9° + 30°

= 21°

Answer:

60° + 35° = x

Step-by-step explanation:

The line CG is cutting the angle m<BCG to have m<BCF and m<FCG. Hence;

m<BCG = m<BCF + m<FCG

Given the following

∠BCF = 60°

∠FCG = 35°

Substitute

m<BCG = m<BCF + m<FCG

m<BCG = 60°+35°

hence the required expression is 60° + 35° = x  where m<BCG is x

Answer:

5/11

Step-by-step explanation:

I hope this helps a bit.

Answer:

2

Step-by-step explanation:

Answer:

-43

Step-by-step explanation:

f(-3) = 4(-3) - 7 = -12 - 7 = -19

g(4) = -7(4) + 4 = -28 + 4 = -24

-19 + (-24) = -43

Answer: 28.3

Step-by-step explanation:

Answer:

y = 10x + 15

Step-by-step explanation:

y +25 = 10(x+4)

y = 10x + 40 - 25

y = 10x + 15

Answer:

[tex]\sin\,\theta =-\frac{\sqrt{21} }{5}[/tex]

[tex]\tan\,\theta =\frac{\sqrt{21} }{2}[/tex]

[tex]\sec\,\theta = \frac{-5}{2}[/tex]

[tex]cosec\,\theta =\frac{-5}{\sqrt{21} }[/tex]

[tex]\cot\,\theta =\frac{2}{\sqrt{21} }[/tex]

Step-by-step explanation:

[tex]\cos\theta =\frac{-2}{5}<0\\sin\theta <0[/tex]

As both [tex]sin\,\theta<0,\,\cos\,\theta <0[/tex],

[tex]\theta[/tex] lies in the third quadrant.

In the third quadrant,

[tex]\sin\theta<0,\,\cos\,\theta <0\,,\,\sec\,\theta<0,\,cosec\theta<0,\,tan\,\theta>0,\,cot\,\theta>0[/tex]

[tex]\sin\,\theta =-\sqrt{1-\cos^2\,\theta} \\=-\sqrt{1-(\frac{-2}{5})^2 } \\\\=-\sqrt{1-\frac{4}{25} }\\\\=-\sqrt{\frac{25-4}{25} }\\\\=-\frac{\sqrt{21} }{5}[/tex]

[tex]\tan\,\theta = \frac{\sin\,\theta}{\cos\,\theta }\\\\=\frac{\frac{-\sqrt{21} }{5} }{\frac{-2}{5} }\\\\=\frac{\sqrt{21} }{2}[/tex]

[tex]\sec\,\theta =\frac{1}{\cos\,\theta }\\\\=\frac{1}{\frac{-2}{5} }\\\\=\frac{-5}{2}[/tex]

[tex]\ cosec \,\theta = \frac{1}{sin\,\theta }\\\\=\frac{1}{\frac{-\sqrt{21} }{5} }\\\\=\frac{-5}{\sqrt{21} }[/tex]

[tex]\cot\,\theta =\frac{1}{\tan\,\theta}\\\\=\frac{1}{\frac{\sqrt{21} }{2} }\\\\=\frac{2}{\sqrt{21} }[/tex]