give answer in decimal to the nearest tenth of a cm

I think it is 18(c.m)2 but their is no unit for the length,width,height

Answer:

hope it helps...

Explanation:

The length an object moves through its motion is called the distance. ... The motion of an object takes time to occur. That is, moving from one place to another happens in the course of time. Such a time interval is called the elapsed time.

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Distance is a numerical representation of the distance between two objects or locations. The elapsed time is the name given to such a period of time.

Distance is a numerical representation of the distance between two objects or locations.

The distance can refer to a physical length or an estimate based on other factors in physics or common use. |AB| is a symbol for the distance between two points A and B.

The relation between the distance and the time is found as;

distance = speed × time

[tex]\rm d = v \times t[/tex]

The distance is the length of time an item moves during its motion. An object's motion needs time to occur. That is, traveling from one location to another occurs across time.

The elapsed time is the name given to such a period of time. It is denoted by t.

Hence the denotation and the defination of both physical quantity is different.

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Answer:

Cable  B will more stretch the most.

Explanation:

Given that,

Length of material A =[tex]l_{A}[/tex]

Length of material B =[tex]l_{B}[/tex]

If A has a greater Young's Modulus than B.

We know that,

The deflection is defined as,

[tex]\delta=\dfrac{Wl}{AE}[/tex]

For material A,

[tex]\delta_{A}=\dfrac{W_{A}l_{A}}{A_{A}E_{A}}[/tex]

[tex]\delta_{A}\propto\dfrac{1}{E_{A}}[/tex]

For material B,

[tex]\delta_{B}=\dfrac{W_{B}l_{B}}{A_{B}E_{B}}[/tex]

[tex]\delta_{B}\propto\dfrac{1}{E_{B}}[/tex]

The deflection is inversely proportional to the young's modulus.

We need to find which cable  will stretch the most when loaded

Using formula of deflection

[tex]\dfrac{\delta_{A}}{\delta_{B}}=\dfrac{\dfrac{W_{A}l_{A}}{A_{A}E_{A}}}{\dfrac{W_{B}l_{B}}{A_{B}E_{B}}}[/tex]

Put the value into the formula

[tex]\dfrac{\delta_{A}}{\delta_{B}}=\dfrac{\dfrac{Wl}{AE_{A}}}{\dfrac{Wl}{AE_{B}}}[/tex]

[tex]\dfrac{\delta_{A}}{\delta_{B}}=\dfrac{E_{B}}{E_{A}}[/tex]

So, [tex]\delta_{B}>\delta_{A}[/tex]

Hence, Cable  B will more stretch the most.

Answer:

A concave lens is thinner at the center and thicker at the edges while a convex lens is thicker at the centre and thinner at the edges.

Answer:

Read below.

Explanation:

Convex lenses: have a thicker centre than their edges. Converges light rays to a point.

Concave lenses: have thicker edges than their centre. Diverges the light rays passing through it.

Answer:

The first one is A gravity does not effect wind and the second one is A also because the we know right a way that the moon is closest to Earth

What is wrong with the diagram is : ( 4 )

The maximum gravitational potential energy is located at the highest peak which the roller coaster attains while as the roller coaster comes down from the peak the gravitational potential energy decreases while the kinetic energy increases.

The point at which the roller coaster should attain it maximum kinetic energy should be at the lowest point ( i.e far left side of the bottom ).

Hence we can conclude that error in the diagram is the spot with the "maximum kinetic energy" should be on the lowest point of the roller coaster at the far left side on the bottom.

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Answer:

A -- Correct (what you have on the paper)

B -- (Sphere A - negative 6 ) (Sphere B - negative 6) (Sphere C - positive 9)

(Total - negative 3)

Explanation:

Hope this helps! Please let me know if you need more help, or if you think my answer is incorrect. Brainliest would be MUCH appreciated. Have a wonderful day!

Answer:

Explanation:

a. Total charge = sum of charges of A, B and C

= -4 + -8 + 9

= -3.0C

b. After touching each other, the charges on A and B will equalized. When separated, they have the same charge = (-4 + -8) / 2 = -6.

Charge on C and the total charge will not change.

A : -6.0C

B : -6.0C

C : +9.0C

Total : -3.0C

Answer:

no yes

Explanation:

Answer:

The person has to move at the speed of 2.30 m/s towards the dropping point to catch the box.

Explanation:

Let t be the time taken by the box to reach the ground and v be the speed of the person on the ground standing 10 m away from the dropping

point.

As distance=(speed) x (time), so

[tex]10=vt\cdots(i)[/tex]

Initially, the height of the box from the ground is 92.4 m.

So, the displacement, s, covered by the box when it reached the ground,

[tex]s=92.4[/tex] m in the downward direction.

The gravitational force action of the box is also in the downward direction.

The initial velocity of the balloon, u=0.

According to the equation of motion,

[tex]s=ut+\frac1 2 at^2[/tex]

where a is the acceleration, u is initial velocity and.

Here, [tex]a=g=9.81 m/s^2[/tex] (acceleration due to gravity) and s and a are having the same direction.

So, on putting the values in the equation, we have

[tex]92.4=0\timest+ \frac 1 2 (9.81)t^2[/tex]

[tex]\Rightarrow t^2=\frac{92.4\times 2}{9.81}[/tex]

[tex]\Rightarrow t=\sqrt{\frac{92.4\times 2}{9.81}}[/tex]

[tex]\Rightarrow t=4.34[/tex] seconds.

So, the time available for the man on the ground to catch the bot is 4.34 seconds.

Now, from equation (i),

[tex]10=v\times 4.34[/tex]

[tex]\Rightarrow v = 10/4.34[/tex]

[tex]\Rightarrow v = 2.30[/tex] m/s.

Hence, the person has to move at the speed of 2.30 m/s towards the dropping point to catch the box.

Answer:

10 m/s

Explanation:

vi = 70 m/s

a = -1.5 m/s²

t = 40 s

vf = vi + at

= 70 + (-1.5 x 40)

= 10 m/s

The final velocity will be "10 m/s".

Given:

Initial velocity,

Deceleration,

Time,

As we know,

→ Final velocity, [tex]v_f = v_i+at[/tex]

By substituting the values, we get

                               [tex]= 70+(-1.5\times 40)[/tex]

                               [tex]= 70+(-60)[/tex]

                               [tex]= 70-60[/tex]

                               [tex]= 10 \ m/s[/tex]

Thus the above answer is appropriate.

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Answer:

pacer test

Explanation:

Answer:

It's ellipticals!!

Explanation:

hope its right

Answer:

Matching principle

Explanation:

Matching principle is an accounting principle for recording revenues and expenses. It requires that a business records expenses alongside revenues earned.

Answer:

She only looked at the results for lunch and no other meals. She did not define what “healthy” means. She tested a different number of girls and boys and did not factor that into her results. Her study is biased.

Explanation:

Answer:

She only looked at the results for lunch and no other meals. She did not define what “healthy” means. She tested a different number of girls and boys and did not factor that into her results. Her study is biased.

Explanation:

Explanation:

Answer:

level HAHAHAHAHAH chariss

Question :-

Answer :-

Explanation :-

As per the provided information in the given question, we have been given that the Mass of the trailer is 360 kg . Force is given as 7200 Newton . And, we have beena asked to calculate the Acceleration of the Truck .

For calculating the Acceleration , we will use the Formula :-

[tex] \bigstar \: \: \: \boxed {\sf{ \: Acceleration \: = \: \dfrac {Force}{Mass} \: }} [/tex]

Therefore , by Substituting the given values in the above Formula :-

[tex] \dag \: \: \: \sf {Acceleration \: = \: \dfrac {Force}{Mass}} [/tex]

[tex] \longmapsto \: \: \: \sf {Acceleration \: = \: \dfrac {7200}{360}} [/tex]

[tex] \longmapsto \: \: \: \textbf {\textsf {Acceleration \: = \: 20 }} [/tex]

Hence :-

[tex] \underline {\rule {180pt} {4pt} } [/tex]

Answer:

A Truck is Pulling a Trailer down a Highway . The Total Mass of the Trailer is 360kg and the Force at which the Truck is pulling is 7200 Newton . What is the Acceleration of the Truck ?

Answer :-

Acceleration of the Truck is 20 m/s² .

Explanation :-

As per the provided information in the given question, we have been given that the Mass of the trailer is 360 kg . Force is given as 7200 Newton . And, we have beena asked to calculate the Acceleration of the Truck .

For calculating the Acceleration , we will use the Formula :-

\bigstar \: \: \: \boxed {\sf{ \: Acceleration \: = \: \dfrac {Force}{Mass} \: }}★

Acceleration=

Mass

Force

Therefore , by Substituting the given values in the above Formula :-

\dag \: \: \: \sf {Acceleration \: = \: \dfrac {Force}{Mass}}†Acceleration=

Mass

Force

\longmapsto \: \: \: \sf {Acceleration \: = \: \dfrac {7200}{360}}⟼Acceleration=

360

7200

\longmapsto \: \: \: \textbf {\textsf {Acceleration \: = \: 20 }}⟼Acceleration = 20

Hence :-

Acceleration = 20 m/s² .

Answer:

30watts

Explanation:

P = IV = 5 x 6 = 30watts

Answer:

s ≈ 35.8 m

Explanation:

Let's apply the uniform acceleration equation to find the vertical height travelled after 2.7 seconds.

[tex]s = ut + \frac{1}{2}at^2[/tex]

s = distance travelled

u = initial vertical velocity

t = time taken

a = gravitational acceleration

The gun is fired horizontally, hence there is no initial vertical velocity.

[tex]s = 0(2.7) + \frac{1}{2}(9.81)(2.7)^2[/tex]

[tex]s = 35.75745 m[/tex]

s ≈ 35.8 m

If a space rover has a mass of 3900 kg on Earth, then its mass when it lands on Mars will be the same i.e. 3900 kg.

Mass is the amount of matter present in the object.

The mass of the object is always constant, anywhere it is on the Earth or Moon or any other planet.

Thus, If a space rover has a mass of 3900 kg on Earth, the mass on Mars when it lands will be 3900kg.

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F = ma

F = 3*5

F = 15 N

Hope it helps :)

Answer:

F=15

Explanation:

The image will form at the focal point

1/object + 1/image = 1/focal

If the object distance is infinite then the image distance equals the focal distance

Explanation:

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A circus truck full of monkeys has a mass of 3175 kg. The kinetic energy of the circus truck is 128,587.5 J. The speed of the truck is 9 m/sec

The speed of an object is the magnitude of the change of its position over time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.

Kinetic Energy =(.5) Mass. (Velocity)²

K.E = 0.5 m.v²

81 = v²

v = 9 m/sec

A circus truck full of monkeys has a mass of 3175 kg. The kinetic energy of the circus truck is 128,587.5 J. The speed of the truck is 9 m/sec

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For an object to move in a uniform motion it has to have either a constant velocity or a constant acceleration. If the object has a constant velocity then it is moving at zero acceleration and this means moving with out slowing down or speeding up.

Answer:

9800 N

Explanation:

F = mg

I am assuming the question is what is the weight of a 1000kg on earth

Explanation:

Option B is correct

Answer:

they reflect light waves

Explanation:

The tiny drops or ice particles in clouds scatter between 20 and 90 percent of the sunlight that strikes them

Answer:

They reflect light waves

Explanation: