Given f(x)=x^2 - 6x + 8 and g(x) = x - 2, solve f(x) = g(x) using a table of values.
Please show your work.

Answer:

13/8

Step-by-step explanation:

You first find the lcm of 8 and 4 which is 8

Then make a dividing line (/) with the lcm as the numerator.

After which you start diviing the lcm by each denominator of the two terms, and then multiplying with their numerators:

8/8 x 7 + 8/4 x 3 all over the lcm which is 8

(1 x 7 + 2 x 3)/8

(7 + 6)/8

13/8

Answer:

The absolute extrema is minimum at (-1, 2/9)

Step-by-step explanation:

Absolute extrema is a logical point that shows whether a the curve function is maximum or minimum.

Forexample a curve in the image attached. A, B and C are points of absolute maxima or absolute maximum. and P and Q are points of absolute minima or minimum.

Remember A, B, C, P, Q are critical points or stationary points.

How do we find absolute extrema?

The find the sign of the second derivative of the function.

From the question;

[tex]{ \sf{g(x) = \sqrt[3]{x} }} \\ \\ { \sf{g(x) = {x}^{ \frac{1}{3} } }} \\ [/tex]

Find the first derivative of g(x)

[tex]{ \sf{g {}^{l}(x) = \frac{1}{3} {x}^{ - \frac{2}{3} } }} \\ [/tex]

Find the second derivative;

[tex]{ \sf{g {}^{ll} (x) = ( \frac{1}{3} \times - \frac{2}{3}) {x}^{( - \frac{2}{3} - 1) } }} \\ \\ { \sf{g {ll}^{(x)} = - \frac{2}{9} {x}^{ - \frac{5}{3} } }}[/tex]

Then substitute for x as -1 from [-1, 1]

[tex]{ \sf{g {}^{ll}(x) = - \frac{2}{9} ( - 1) {}^{ - \frac{5}{3} } }} \\ \\ = \frac{ - 2}{9} \times - 1 \\ \\ = \frac{2}{9} [/tex]

Since the sign of the result is positive, the absolute extrema is minimum

A) Values of y will be 1, 0, -1, 0, 1

B) and C) plot the values as shown in below figure.

Trigonometric functions are a set of mathematical functions that relate the angles and sides of right triangles.

A) for f(x) = cos x; the values of x-y chart are:

  x                   y = f(x)

  0                      1

  [tex]\frac{\pi }{2}[/tex]                      0

  [tex]\pi[/tex]                      -1

  [tex]\frac{3\pi }{2}[/tex]                     0

  [tex]2\pi[/tex]                     1

B) the points are plotted as given figure below.

C) Connects the dots to show the graph of y = cos x; sown in figure below please check it.

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Parameterizing a surface over a rectangle Parameterizing the surface z = x²+2y² over the rectangular region R defined by -3 ≤ x ≤ 3, −1 ≤ y ≤ 1 are falls under the range of R.

Let's start by expressing x and y as functions of u and v. Since x varies between -3 and 3 over R, we can use the following parameterization for x:

x = u

where u varies between -3 and 3. Similarly, since y varies between -1 and 1 over R, we can use the following parameterization for y:

y = v

where v varies between -1 and 1.

Next, we can use these parameterizations for x and y to express z as a function of u and v. Substituting x = u and y = v into the equation z = x² + 2y², we get:

z = u² + 2v²

So, the parameterization of the surface z = x² + 2y² over the rectangular region R is given by:

x = u, y = v, z = u² + 2v²

where -3 ≤ u ≤ 3 and -1 ≤ v ≤ 1.

The parameterization allows us to study various properties of the surface z = x² + 2y² over the rectangular region R.

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Complete Question:

Parameterizing a surface over a rectangle Parameterizing the surface z = x²+2y² over the rectangular region R defined by -3 ≤ x ≤ 3, −1 ≤ y ≤ 1.

Answer: We can simplify the expression inside the absolute value first:

|(sqrt(2) + 3 - 5)|

= |(sqrt(2) - 2)|

Since sqrt(2) > 2, we know that sqrt(2) - 2 is negative. Therefore, we can rewrite the absolute value as a negative:

|sqrt(2) - 2| = -(sqrt(2) - 2)

So the expression without absolute value is:

-(sqrt(2) - 2)

Step-by-step explanation:

The area of the composite shape using the area formula for the different shapes is 460.48ft².

The area of composite shapes refers to the space occupied by any composite shape. A composite shape is a shape that is made by connecting a few polygons to form the required shape.

These figures or shapes can be built from a wide range of shapes, such as triangles, squares, quadrilaterals, etc. Divide a composite item into basic forms such a square, triangle, rectangle, or hexagon to get its area.

Now in the question,

First let us find the area of the semi-circle.

Area of semi-circle = πr²/2

= [3.14 × (16/2) ²]/2

= (3.14 × 8²)/2

= 200.96/2

= 100.48ft²

Now coming to the rectangle,

area of the rectangle = l × b

= 20 × 15

= 300ft²

Now for calculating the area of the triangle,

area = 1/2 × b × h

= 1/2 × 12 × 10

= 60ft²

Therefore, the area of the total figure = 100.48 + 300 + 60 = 460.48ft².

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Similar shapes are shapes whose lengths are in equivalent ratio. [tex]\Delta ABC[/tex] and [tex]\Delta DE[/tex][tex]F[/tex] are similar because the side lengths of both triangles are in equivalent ratio (refer to attachment)

Step 1: Draw a random triangle [tex]\Delta ABC[/tex]

The lengths of two sides and an angle are:

[tex]AB=10[/tex]

[tex]BC=6[/tex]

[tex]\angle C=90^o[/tex]

Step 2: Draw and measure the length of DE

[tex]DE=15[/tex]

Step 3: Calculate the ratio

The corresponding line segment to DE is line segment AB.

So, the ratio (k) is:

[tex]k=\dfrac{DE}{AB}[/tex]

[tex]k=\dfrac{15}{10}[/tex]

[tex]k=1.5[/tex]

Step 4: Multiply the ratio by the other line segment in step 1

In (1), we have:

[tex]BC=6[/tex]

So:

[tex]EF=k\times BC[/tex]

[tex]EF=1.5\times6[/tex]

[tex]EF=9[/tex]

Step 5: Draw a circle with center F and radius EF  

The center of the circle is point F and the radius of the circle is 9 units

Step 6: Draw a ray from the center (i.e. point F) to DE

Refer to the attached image for

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Answer:

x = 4

Step-by-step explanation:

using the rule of exponents

• [tex]a^{-m}[/tex] = [tex]\frac{1}{a^{m} }[/tex] , then

[tex]4^{-x}[/tex] = [tex]\frac{1}{4^{x} }[/tex]

and 256 = [tex]4^{4}[/tex]

then

[tex]\frac{1}{4^{x} }[/tex] = [tex]\frac{1}{4^{4} }[/tex]

so

[tex]4^{x}[/tex] = [tex]4^{4}[/tex]

since bases on both sides are equal, bot 4 then equate exponents

x = 4

The equivalent z-score for a raw score of 115 under a normal distribution with a mean of 100 and a standard deviation of 15 is 1.

Under the normal distribution, if the mean of the distribution of raw scores is equal to 100 and the standard deviation is known, we can use the z-score formula to calculate the equivalent z-score for any given raw score.

The z-score formula is given by:

z = (x - μ) / σ

where x is the raw score, μ is the mean of the distribution, σ is the standard deviation of the distribution, and z is the corresponding z-score.

Since the mean of the distribution is 100, we have μ = 100. To calculate the z-score, we need to know the standard deviation of the distribution or have information about the distance of the raw score from the mean in terms of standard deviations.

If we assume that the standard deviation is 15, which is a common value used in educational testing, and the raw score is 115, then the corresponding z-score would be:

z = (115 - 100) / 15 = 1

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TRUE. Combinations and permutations are used in probability calculations to determine the number of possible outcomes in a sample space.

When order is important, permutations are utilized, and when order is not important, combinations are used. The formula P(n,r) = n!/(n-r)!, where n! signifies the factorial of n, and the expression C(n,r) = n!/r!(n-r)!, give the number of permutations of n items taken r at a time and the number of combinations of n objects taken r at a time, respectively.

It is possible to count the number of ways that a subset of items can be chosen from a larger set using both permutations and combinations. These ideas are crucial for estimating probabilities because they let us know how many different outcomes could satisfy a certain condition.

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The value of the equation (fxg)(-1) is 10.

An equation is a mathematical statement that shows that two expressions are equal. It usually includes variables, which are represented by letters or symbols, and constants, which are fixed values.

There are several types of equations in mathematics. Here are some of the most common types:

Linear equation: An equation of the form "ax + b = c", where "a", "b", and "c" are constants and "x" is the variable. The graph of a linear equation is a straight line.Quadratic equation: An equation of the form "ax² + bx + c = 0", where "a", "b", and "c" are constants and "x" is the variable. The graph of a quadratic equation is a parabola.

Cubic equation: An equation of the form "ax³ + bx² + cx + d = 0", where "a", "b", "c", and "d" are constants and "x" is the variable. The graph of a cubic equation is a curve that can have one or two humps.

In the given question,

To find (f x g)(-1), we need to evaluate the product of f(-1) and g(-1).

First, we find f(-1):

f(-1) = -3(-1) - 1 = 2

Next, we find g(-1):

g(-1) = -1 - 4 = -5

Now, we can find the product (f x g)(-1):

(f x g)(-1) = f(-1) x g(-1) = 2 x (-5) = -10

Therefore, (f x g)(-1) = -10.

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By answering the presented questiοn, we may cοnclude that 0.4 οf an expressiοns hοur is 0.4 x 60 = 24 minutes in this situatiοn. As a result, 3.4 hοurs equals 3 hοurs and 24 minutes.

An expressive in mathematics is a collection of numbers, variables, and complicated mathematical operations (such as addition, subtraction, multiplication, division, multiplicands, and others) that convey a quantity's value. Expressions can be as straightforward as "3 + 4" or as complex as "(3x2 - 2) / (x + 1)". They could also include functions like "sin(x)" or "lg(y)".

The real way to evaluate an expression is to insert the variables with their values and carry out the arithmetic operations in the order specified. For instance, the phrase "3x + 5" means 3(2) + 5 = 11 if x = 2. In mathematics, expressions are typically used to describe actual situations, build equations, and decompose challenging mathematical diagrams.

3 hοurs and 24 minutes is cοmparable tο 3.4 hοurs.

Yοu may separate the full number (which represents the hοurs) frοm the decimal tο cοnvert decimal hοurs tο hοurs and minutes (which represents the fractiοn οf an hοur in minutes).

0.4 οf an hοur is 0.4 x 60 = 24 minutes in th

is situation. As a result, 3.4 hours equals 3 hours and 24 minutes.

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The length of the curve of intersection, correct to four decimal places, is 27.7128 units.

To find the length of the curve of intersection, we need to first parameterize the curve.

From the equation of the cylinder, we have:

4x² + y² = 4

Dividing both sides by 4, we get:

x²/1 + y²/4 = 1

This is the equation of an ellipse centered at the origin with semi-major axis a=1 and semi-minor axis b=2.

From the equation of the plane, we have:

x + y + z = 6

Solving for z, we get:

z = 6 - x - y

So the equation of the curve of intersection is:

r(t) = <t, 2sin(t), 6-t-2sin(t)>

where 0 <= t <= 2π.

To find the length of the curve, we need to integrate the magnitude of its derivative with respect to t:

L = ∫√(dx/dt)² + (dy/dt)² + (dz/dt)² dt

Taking the derivative of r(t), we get:

r'(t) = <1, 2cos(t), -1-2cos(t)>

So the magnitude of r'(t) is:

|r'(t)| = √(1² + (2cos(t))² + (-1-2cos(t))²) = √(9+9cos(t)²)

Therefore, the length of the curve is:

L = ∫_0⁽²π⁾ √(9+9cos(t)²) dt

This integral can be solved using the substitution u = tan(t/2), which gives:

L = 18∫_0∞ 1/√(1+u²) du

This integral can be evaluated using trig substitution, letting u = tanθ, which gives:

L = 18∫_0⁽π/²⁾ secθ dθ = 18 ln|sec(π/4)+tan(π/4)| = 18 ln(1+√2)

Using a calculator, we get:

L ≈ 27.7128

Therefore, the length of the curve of intersection, correct to four decimal places, is 27.7128 units.

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The range of the function m is [1, ∞). Thus, B is correct option.

The dοmain οf a functiοn is the cοllectiοn οf values that can be plugged intο it. This set represents the x values in a functiοn like f. (x). A functiοn's range is the set οf values that the functiοn can take οn. This is the set οf values returned by the functiοn when we enter an x value.

Tο determine the range οf functiοn m, we must first determine the set οf all pοssible functiοn οutput values.

Looking at the function graph, we can see that the lowest point is (3, 1) and the highest point is (∞, ∞).

As a result, the function m has a range of [1, ∞).

We can write: in interval notation:

m ∈ [1, ∞) range.

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The z-scores that represent the middle 50% of the standard normal distribution are between -0.6745 and 0.6745, the lowest 5% of the standard normal distribution is -1.645, and the 90% of the standard normal distribution is between -1.645 and 1.645.

The mean and variance of a standard normal distribution are both 0. A z distribution is another name for this.

Yes, here are the z-scores for the given standard normal areas:

A. Middle 50%: The area between the 25th and 75th percentiles corresponds to the middle 50% of the standard normal distribution. Using Excel's NORM.S.INV() function, we can calculate the z-scores that correspond to those percentiles as follows:

-0.6745 is the z-score corresponding to the 25th percentile.

The 75th percentile z-score is 0.6745.

As a result, the z-scores representing the middle 50% of the standard normal distribution range between -0.6745 and 0.6745.

B. Lowest 5%: The area to the left of the 5th percentile corresponds to the lowest 5% of the standard normal distribution. Using Excel's NORM.S.INV() function, we can calculate the z-score that corresponds to that percentile as follows:

The z-score associated with the fifth percentile is -1.645.

As a result, the z-score representing the bottom 5% of the standard normal distribution is -1.645.

C. Middle 90%: The area between the 5th and 95th percentiles corresponds to the middle 90% of the standard normal distribution. Using Excel's NORM.S.INV() function, we can calculate the z-scores that correspond to those percentiles as follows:

The z-score associated with the fifth percentile is -1.645.

The z-score associated with the 95th percentile is 1.645.

As a result, the z-scores representing the middle 90% of the standard normal distribution range between -1.645 and 1.645.

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Answer:

1 - [tex]\frac{2\sqrt{2} }{3}[/tex]

Step-by-step explanation:

[tex]\frac{\sqrt{3}-\sqrt{6} }{\sqrt{3}+\sqrt{6} }[/tex]

rationalise the denominator by multiplying the numerator and denominator by the conjugate of the denominator.

the conjugate of [tex]\sqrt{3}[/tex] + [tex]\sqrt{6}[/tex] is [tex]\sqrt{3}[/tex] - [tex]\sqrt{6}[/tex]

= [tex]\frac{(\sqrt{3}-\sqrt{6})(\sqrt{3}-\sqrt{6}) }{(\sqrt{3}+\sqrt{6})(\sqrt{3}-\sqrt{6}) }[/tex] ← expand numerator/ denominator using FOIL

= [tex]\frac{3-\sqrt{18}-\sqrt{18}+6 }{3-\sqrt{18}+\sqrt{18}+6 }[/tex]

= [tex]\frac{9-2\sqrt{18} }{3+6}[/tex]

= [tex]\frac{9-2(3\sqrt{2}) }{9}[/tex]

= [tex]\frac{9-6\sqrt{2} }{9}[/tex]

= [tex]\frac{9}{9}[/tex] - [tex]\frac{6\sqrt{2} }{9}[/tex]

= 1 - [tex]\frac{2\sqrt{2} }{3}[/tex]

Desmοnd receives a discοunt οf R183.675. We can rοund this tο R183.18 οr R183.18, depending οn the desired level οf precisiοn.

We all are eager abοut availing discοunts, but we barely knοw hοw we get these discοunts. There is a prοper way tο calculate discοunt and that we dο by using a discοunt fοrmula. The discοunt rate fοrmula can either be extracted by subtracting the selling price οf the prοduct frοm its marked price οr by multiplying the discοunt rate οffered and the marked price οf the prοduct. In terms οf Mathematics, the fοrmula fοr discοunt is represented as belοw,

Accοrding tο given infοrmatiοn,

Tο calculate the discοunt Desmοnd receives, we first need tο find 53.5% οf the οriginal price. We can dο this by multiplying the οriginal price by 0.535:

R395 x 0.535 = R211.325

Sο, Desmοnd pays R211.325 fοr his purchase after the discοunt.

Tο find the amοunt οf discοunt, we need tο subtract the discοunted price frοm the οriginal price:

R395 - R211.325 = R183.675

Therefοre, Desmοnd receives a discοunt οf R183.675. We can rοund this tο R183.18 οr R183.18, depending οn the desired level οf precisiοn.

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Answer:

$31,142

Step-by-step explanation:

To convert a percentage into a decimal, you move the decimal two places to the left. 1354% converted into a decimal is 13.54.

$23,000 * 13.54 = $31,142

The values of a such that p({z > 1.35}) or {z > 2.34}) is 0.0981.

Let z be a standard normal random variable.

The standard normal distribution is a probability distribution that is symmetric around a mean of zero and has a standard deviation of one. It is also referred to as the Gaussian distribution or the normal distribution. This distribution is commonly used in the field of statistics to measure the likelihood of certain outcomes.

We have to determine the values of a such that p({z > 1.35}) or {z > 2.34}).

p(z > 1.35) + p(z > 2.34) = p(z > a)

After using the standard normal distribution table.

0.0885 + 0.0096 = p(z > a)

p(z > a) = 0.0981

p(z > 1.29) = 0.0981

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The numbers of ways in which we can select the letters without replacement are: a. order relevant - 6 ways. b. order not relevant- 3 ways.

Both permutations and combinations count the number of possible ways to select a particular number of things from a bigger collection of options. The distinction is that whereas combinations ignore the order of the components, permutations do. In other words, combinations don't care about the order in which the elements are selected, but permutations require arranging the components in a certain sequence.

Given that, we want to choose 2 letters, without replacement.

a. When the order is relevant we have the following choices:

3 options for the first letter and 2 options for the second letter, that is:

3 x 2 = 6 ways

b. If the order is not relevant we use combinations:

n C r = n! / (r! (n-r)!)

3 C 2 = 3! / (2! (3-2)!) = 3

Hence, the numbers of ways in which we can select the letters are: a. order relevant - 6 ways. b. order not relevant- 3 ways.

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The complete question is:

Answer:

y = (-1/3)x^2 - 2x + 5/3

Step-by-step explanation:

To find the quadratic equation that passes through these points, we can start by using the standard form of a quadratic equation:

y = ax^2 + bx + c

We know that the graph passes through the point (-2,2), so we can substitute these values into the equation:

2 = a(-2)^2 + b(-2) + c

Simplifying this equation, we get:

4a - 2b + c = 2

We also know that the graph has x-intercepts at (-1,0) and (6,0). This means that when x = -1 and x = 6, the value of y (i.e., the height of the graph) is 0. We can use these two points to write two more equations:

0 = a(-1)^2 + b(-1) + c

0 = a(6)^2 + b(6) + c

Simplifying these equations, we get:

a - b + c = 0

36a + 6b + c = 0

Now we have a system of three equations:

4a - 2b + c = 2

a - b + c = 0

36a + 6b + c = 0

We can solve for a, b, and c using any method of solving systems of equations. One way is to use substitution:

From the second equation, we get:

c = b - a

Substituting this into the other two equations, we get:

4a - 2b + (b - a) = 2

36a + 6b + (b - a) = 0

Simplifying these equations, we get:

3a - b = 1

35a + 7b = -b

Multiplying the first equation by 7 and adding it to the second equation, we eliminate b:

21a = -7

a = -1/3

Substituting this value of a into the first equation, we can solve for b:

4(-1/3) - 2b + (b - (-1/3)) = 2

-4/3 - b + b + 1/3 = 2

b = -2

Finally, we can use either of the first two equations to solve for c:

c = a - b = (-1/3) - (-2) = 5/3

So the quadratic equation in standard form is:

y = (-1/3)x^2 - 2x + 5/3

Answer: 5p = 40

Step-by-step explanation:

5 X p = 40

5/5 40/5

p = 8

Answer:

Step-by-step explanation:

4x+4 = 4

Subtract 4 from both sides:-

4x+4-4 = 4-4

4x = 0

Divide both sides by 4:-

4x/4 = 0/4

x = 0

Answer:

The correct answer is:

315 ≤ t ≤ 385

This is because the oven temperature display can vary up to 35 degrees higher or lower than the actual temperature being produced. Therefore, the actual temperature (t) could be 35 degrees higher or lower than the displayed temperature (350 degrees), resulting in a range of possible temperatures from 315 to 385 degrees.

Answer: y = -x

Step-by-step explanation:

The equation of the hyperbola is x² - y² = 16.

Taking the derivative of the equation with respect to x, we get:

2x - 2yy' = 0

y' = x / y

At the point (2,-2), we have x = 2 and y = -2. Thus, the slope of the tangent is:

y' = 2 / (-2) = -1

So, the equation of the tangent through the point (2,-2) is:

y + 2 = -1(x - 2)

y + 2 = -x + 2

y = -x

The fig's right side of total surface = 42yds.

A solid object's surface area is a measurement of the total area that the surface of the object takes up.

The definition of arc length for one-dimensional curves and the definition of surface area for polyhedra (i.e., objects with flat polygonal faces), where the surface area is the sum of the areas of its faces, are both much simpler mathematical concepts than the definition of surface area when there are curved surfaces.

A smooth surface's surface area is determined using its representation as a parametric surface, such as a sphere.

This definition of surface area uses partial derivatives and double integration and is based on techniques used in infinitesimal calculus.

Henri Lebesgue and Hermann Minkowski at the turn of the century sought a general definition of surface area.

According to our question-

(17+17+8)yds

42yds

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Answer:

Highlight "x" then it's an acute angle

Step-by-step explanation:

As the triangles are similar to each other, using congruent theorem, we get the value of side JK = 63.8.

Comparable triangles are those that resemble one another but may not be precisely the same size. Comparable items are those that share the same shape but differ in size.

This shows that when shapes are amplified or demagnified, they superimpose one another. This feature of similar shapes is often known as "similarity".

As per the triangles,

Let JK be = x.

GF/GH = JI/JK

⇒ 11/18 = 36 /x

⇒ x = 36 × 18/11

⇒ x = 63.8.

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The first of these two events is the number displayed on the cube. The result of the coin toss is the second. There should be two columns in this tree, one for each occurrence.

a list or tree digrams to represnts the sample space in the given below figure . Observe the first column first. Let the number cube's result be. The following six values are possible:. Six branches, one for each outcome, result from that proceed to the following column. Let the result of the coin toss be. There would always be two possible results for, regardless of the number obtained for.

The first of these two events is the number displayed on the cube. The result of the coin toss is the second. There should be two columns in this tree, one for each occurrence.

Observe the first column first. Let N represent the number cube's result. Six values are possible: 1, 2, 3, 4, 5, and 6. Six branches, one for each outcome, result from that. proceed to the following column. Let the result of the coin toss be. There would always be two possible results for, regardless of the number obtained for.

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the actual question is :

The number cube is rolled and a coin is tossed . How can you sketch a tree diagram to represent the sample space ?