Gradually increasing resistance, increasing repetition, increasing sets are examples of which principle?

Answer:

Explanation:

The time taken can be found by using the formula

[tex] t = \frac{d}{v} \\ [/tex]

d is the distance

v is the velocity

From the question we have

[tex]t = \frac{3.5}{4.8} \\ = 0.72916...[/tex]

We have the final answer as

Hope this helps you

Answer:

Friction of the mountain on the skier in the opposite direction

Explanation:

answered it on khan academy

Friction of the mountain on the skier in the opposite direction.

A force is a push or a pull that acts upon an object as a results of its interaction with another object. Forces result from interactions.

Forces result from contact interactions (normal, frictional, tensional, and applied forces are examples of contact forces) and other forces are the result of action-at-a-distance interactions (gravitational, electrical, and magnetic forces).

There are two forces resulting from this interaction - a force on the chair and a force on your body. These two forces are called action and reaction forces and are the subject of Newton's third law of motion.

Therefore, Friction of the mountain on the skier in the opposite direction.

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Answer:7800

work=force x distance

Force in Newtons

Distance in Meters

Work in Joules

Question:

At a sports event, the car starts from rest. in 5.0 s its acceleration is 5.0 m/s2.  Calculate the distance travelled by car.

Answer:

62.5 metres

Explanation:

Given

[tex]u = 0[/tex] -- Initial Velocity

[tex]a = 5.0m/s^2[/tex] --- acceleration

[tex]t =5.0s[/tex] -- time

Required

Calculate the distance

This question will be solved using the following equation of motion

[tex]S = ut + \frac{1}{2}at^2[/tex]

Where S represents the distance

Substitute values for u, t and a

[tex]S = 0 * 5.0 + \frac{1}{2} * 5.0 * 5.0^2[/tex]

[tex]S = 0 + \frac{1}{2} * 5.0 * 25.0[/tex]

[tex]S = \frac{1}{2} * 5.0 * 25.0[/tex]

[tex]S = \frac{1}{2} * 125.0[/tex]

[tex]S = 62.5m[/tex]

Hence, the distance travelled is 62.5m

Answer:

3

Explanation:

I had this question before

Answer:

A screw

Explanation:

The forces constant (spring constant) of the spring will be 41.09 N/m.

The force required to extend or compress a spring by some distance scales linearly concerning that distance is known as the spring force. Its formula is;

F = kx

The given data in the problem is;

F is the spring force = 30 N

K is the spring constant= ?

x is the displacement of spring = 0.73 m

The spring constant is;

K =F/x

K=30/0.73

K=41.09 N/m

Hence the force constant (spring constant) of the spring will be 41.09 N/m.

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Answer:

B. [tex]5\,\frac{m}{s^{2}}[/tex] South

Explanation:

The correct statement is:

A washing machine is being dragged with a starting force of 380.8 N to the South, but this is reduced by friction. If the mass of the washing machine is 37 kg  and the coefficient of friction is 0.54, what was the Net acceleration experienced by the washing machine?

The net force of the washing machine moving on the horizontal ground is equal to the external force minus the friction force, where the normal force from the ground on the washing machine is equal to its weight. The free body diagram of the washing machine is presented below. The equation of equilibrium associated with the acceleration of the washing machine is:

[tex]\Sigma F = P -\mu_{k}\cdot m \cdot g = m\cdot a[/tex] (1)

Where:

[tex]P[/tex] - External force exerted on the washing machine, measured in newtons.

[tex]\mu_{k}[/tex] - Kinetic coefficient of friction, dimensionless.

[tex]m[/tex] - Mass, measured in kilograms.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]a[/tex] - Net acceleration of the washing machine.

If we know that [tex]P = 380.8\,N[/tex], [tex]m = 37\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]\mu_{k} = 0.54[/tex], then the net acceleration experienced by the washing machine is:

[tex]a = \frac{P}{m}-\mu_{k}\cdot g[/tex]

[tex]a = \frac{380.8\,N}{37\,kg}-(0.54)\cdot \left(9.807\,\frac{m}{s^{2}} \right)[/tex]

[tex]a = 4.996\,\frac{m}{s^{2}}[/tex]

The correct answer is B.

Answer:

Okay I might be wrong and sorry if i am either its 12 or 0.402

Explanation:

* I recommend the second one cause its more logical

Be aware I might be wrong

Answer:

Tailed star

Explanation:

Tailed star

Answer:

Energy that is dependant on height is called gravitational potential energy.

The formula for potential energy is:

                    G.P.E.=mgh

Weight (mass x gravity) determines the amount of potential energy.

Is there potential energy in the 5 forms of energy?

Yes, potential energy can be found in fossil fuels, within the foods you eat, and the batteries that you use.  

Conservation of Energy:

It is important to understand that each form of energy does not exist separately but undergoes change from one to another without a net loss in energy.  Consider this example:

As a projectile is launched into the air KE is at its maximum.  As the projectile gains altitude PE becomes greater than KE.  At the top of its arc, PE is at its maximum.  The whole cycle reverses itself on the way down.

As you can see, the loss in KE is a gain in PE.  Energy is not lost but conserved.

Law of conservation of energy.

   Energy cannot be created nor destroyed.  It can be transformed from one form to another, but the total amount of energy never changes.

∞infinaty stones∞

because why not

A 40 N force would move a load 9.875 m high when 395 J of work is done on the load.

The total amount of energy transferred when a force is applied to move an object through some distance

The work done is the multiplication of applied force with displacement.

The SI  unit of work done by an object is Joules.

IJ is the work done when a force of 1 N displaces an object by 1 m .

Work Done = Force * Displacement

For the given problem Force =40N and work done = 395 J

By using the above formula

Work Done = Force * Displacement

395 j = 40 N × height

height =9.875 m

Thus a 40 N force supported by a work done of 395 J moves the load up to 9.875 m height

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Distance walked to the west= 15m

" " " " north= 20m

" " " " east = 15m

Total Distance= (15+ 20+ 15) m

= 50m

Asha covered 50m distance in total.

Answer:

3,544.375Joules

Explanation:

Kinetic energy is the energy possessed by a body by virtue of its motion, It is expressed as;

Kinetic energy = 1/2mv²

m is the mass of the body

v is the velocity

For the ball carrier;

KE = 1/2(75)(6.5)²

KE = 3168.75/2

KE = 1584.375Joules

For the defender;

KE = 1/2(80)(7)²

KE = 3920/2

KE = 1960Joules

The kinetic energy of the ball carrier/defender system BEFORE the tackle = KE for the carrier + KE for the defender

kinetic energy of the ball carrier/defender system BEFORE the tackle= 1584.375+1960 = 3,544.375Joules

Answer:

P = 1412.82 [Watt]

Explanation:

First we must calculate the total mass that makes up the barbell and the two free weights at each end of the barbell.

[tex]m=30+30+20\\m= 80 [kg][/tex]

Weight is now defined as the product of mass by gravitational acceleration.

[tex]w=m*g[/tex]

where:

m = mass = 80 [kg]

g = gravity acceleration = 9.81 [m/s²]

[tex]w=80*9.81\\w=784.8[N][/tex]

Now using the product of the weight by the distance traveled we can calculate the work.

[tex]W=w*d[/tex]

where:

W = work [J]

w = weight = 784.8 [N]

d = distance = 0.9 [m]

[tex]W=784.8*0.9\\W=706.41[J][/tex]

And power is defined as the relationship of work at a certain time. The potency is expressed by means of the following formula.

[tex]P=W/t\\P=706.41/0.5\\P=1412.82[W][/tex]

Answer:

30 killograms is 85.9803

and 300 milligrams is 0.000661387 pounds

Explanation:

The free-body diagram of the forces acting on a book resting on a table is shown in the figure.

When a body is at rest, the net force on the body is zero. So, no acceleration is produced in it. If a body is in contact with another body or surface, a normal contact force acts on it perpendicular to the surface in contact.

So, the forces acting on a book resting on a tabletop are:

1. Weight of the book, W(downward)

2. Normal force (N) perpendicular to the surface in contact.

Therefore, the free-body diagram of the forces acting on a book resting on a table is shown in the figure.

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Answer:

The net force acting on the wagon is 63 N

Explanation:

Net Force

According to the second Newton's law, the net force exerted by an external agent on an object of mass (m) is:

F = m.a

Where (a) is the acceleration of the object.

The wagon has a mass of m=42 Kg is accelerated at [tex]a=1.5\ m/s^2[/tex]. The net force is:

F = 42*1.5

F = 63 N

The net force acting on the wagon is 63 N

Answer:

400N

Explanation:

Given the following parameters

Mass m = 200g = 0.2kg

initial velocity u = 48m/s

Final velocity v = 52m/s

Time t = 2.0x10-3 s.

Impulse is expressed as I = Ft = m(v-u)

Ft = m(v-u)

F =  m(v-u)/t

Substitute the given values into the formula

F = 0.2(52-48)/0.002

F = 0.2(4)/0.002

F = 0.8/0.002

F = 400N

Hence the average force of the bat on the ball is 400N

Answer:dummy

Explanation:

Dum dum

Answer:

The speed with which a rock would have to be thrown to put it in 234 Ida's orbit, near its surface is approximately 12.917 m/s

Explanation:

The given parameters are;

The mass of Ida, M = 4 × 10¹⁶ kg

The radius of 234 Ida, r = 16 km = 16,000 m

The speed, v, required to put a rock in 234 Ida's orbit near its surface is given by the orbital velocity equation as follows;

[tex]v = \sqrt{{\dfrac{G \times M}{r} } }[/tex]

Where;

G = The universal gravitational constant = 6.67408 × 10⁻¹¹ m³·kg⁻¹·s⁻²

Substituting the known values gives;

[tex]v = \sqrt{{\dfrac{6.67408 \times 10^{-11} \times 4 \times 10^{16}}{16,000} } } \approx 12.917[/tex]

Therefore, the speed required to put a rock in 234 Ida's orbit near its surface = v ≈ 12.917 m.

Answer:

go up the street as you exit the house and make a right and keep going up for 3 blocks and you should see the school

Answer:

Electromagnetic waves

Explanation:

Answer:

oooh thats hard

Explanation:

well i would probaly search the page number or anthing on the page that   should help

Answer:

False

Explanation:

Since it is on the bus, it would not move forward because the outside acceleration cannot be considered.

The energy transfer which cannot be happened is option c , at the bottom of the swing, the kinetic energy gets converted completely into its potential energy thus, it have no speed when it reached the bottom.

Kinetic energy of a body is generated by virtue of its motion. Kinetic energy increases as its mass and velocity increases. Potential energy of a body is the energy stored on it when it comes to rest.

When an object is falling freely to the ground its kinetic energy is converting to the potential energy up to the point it reaches the ground. When it touches the ground, the kinetic energy converts back to potential energy.

Therefore, when the child in the swing comes down from a height its speed is increasing and have greater kinetic energy but this is converted to potential energy when it reach the bottom. Hence no speed it have at the bottom.

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Answer:

Explanation:is the law means that the police are the law

Answer:

Part A:

The other two ways we can rewrite F = m·a are;

1) F = dp/dt

2) F = m × d(v)/dt

Part B:

The mass of the wheelbarrow is 60 kg

Explanation:

Part A:

The other two ways of rewriting the equation are;

1) Force as the rate of change of momentum, F = dp/dt = d(m·v)/dt and

2) From the above equation, where, m is constant, we have;

F = d(m·v)/dt  = m × d(v)/dt

∴ F = m × d(v)/dt

Part B:

The force with which we push the wheelbarrow = 240 N

The acceleration, a, given to the wheelbarrow (by the applied force) = 4 m/s²

From F = m × a

Where;

m = The mass of the wheelbarrow

m = F/a = 240 N/(4 m/s²) = 60 kg

The mass of the wheelbarrow = m = 60 kg.

Answer:

Springs when non compressed has potential energy.