hello help me with this question thanks in advance​

Answer:

x=1

Step-by-step explanation:

Answer:

28 m

Step-by-step explanation:

Length = x

90 = 2(17 + x)

17 + x = 90/2 = 45

so

x = 45 - 17 = 28 m

Answer:

5.4

Step-by-step explanation:

Using the distance formula:

[tex] \sqrt{ {( - 7 - ( - 2))}^{2} + {(3 - 1)}^{2} } [/tex]

[tex] \sqrt{ {( - 5})^{2} + {2}^{2} } [/tex]

[tex] \sqrt{25 + 4} [/tex]

[tex] \sqrt{29} [/tex]

[tex]5.4[/tex]

Answer:

Last Option

Step-by-step explanation:

For this to be true, everyone who works at school must be getting a wage of 8$ so the hourly range of working students at the school IS 8$

The answer is -1331 because if you multiply -11x-11x-11 you get -1331.

Answer:

-1331

Step-by-step explanation:

Because i have a calculator

Answer:

Step-by-step explanation:

Not sure what you mean by quotient but 2956?0.03

=98,533.3333333333333333333333

Answer: 405 calories

Step-by-step explanation:

Answer:

Step-by-step explanation:

hello :

Polynomial:2x²+x-210 =0

Equation : x(2x+1)=210

Answer:

True

Step-by-step explanation:

y = -2x + 9 is already in slope-intercept form, so we can leave it be. 8x + 4y = 28, however, is not, so we have to convert it to find the answer.

To do this we have to separate the variable 4y from the rest.

We get 4y = -8x + 28.

But, y must equal zero, so to achieve this, we divide the entire equation by 4.

Then we get y = -2x + 7

Since the slopes are the same (-2x = -2x) the lines are parallel.

Step-by-step explanation:

x - the part

3x one part(first number)

4x second part (second number)

so u have

3x + 4x = 1001

7x= 1001

x = 1001/7

x= 143. First number : 3x = 3• 143 = 429

Second number : 4x = 4• 143= 572

So, 429 and 572 are the numbers

Answer:

Step-by-step explanation:

Angle CDB=angle BAC=42°(angles subtended by same chord)

CA is diameter,therefore angle ABC=90°(angle subtended by diameter is 90°)

In triangle CBA ,angle ACB=48°[angle

sum property]

Answer 80

Step-by-step explanation:

If the line is a straight line through two parallel lines then the angles of the two intersections should be the same. Basically because they are both on the bottom right they will be the same.

The value of 'y' is 80 degrees. option B

Note that alternate angles are equal

The intersections of a transversal with two parallel lines forms various types of pairs of angles such as

In this case, the transverse line forms alternate angles of line c and b

Angle at line c = 80 degrees

Angle at line b = y

Since they are alternate angles, y = 80 degrees

Therefore, the value of 'y' is 80 degrees. option B

Learn more about transverse lines here:

https://brainly.com/question/24607467

#SPJ9

Answer:

(6,9)

Step-by-step explanation:

The expression sin2x is a trigonometric expression

The equivalent of sin2x is (d) 2sinxcosx

The expression is given as:

sin2x

Rewrite properly as:

sin(2x)

To solve the expression, we make use of the following double angle ratio

sin(2a) = 2sin(a)cos(a)

Substitute x for a in the above equation

sin(2x) = 2sin(x)cos(x)

Rewrite the equation as

sin2x = 2sinxcosx

Hence, the equivalent of sin2x is (d) 2sinxcosx

Read more about trigonometric expressions at:

https://brainly.com/question/8120556

Answer:

D

Step-by-step explanation:

A P E X

Answer: x^2 + 4x + 7

Step-by-step explanation:

Answer:

What are the answer choices? I would help but you didn't attach or write them.

Step-by-step explanation:

Answer: x=0, 13/2......

Answer:

theres no expression..?

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

6

Solution:

[tex]\rightarrow \frac{4^{-3} \times 3^{4} \times 4^{2} }{3^{5} \times 4^{-2} }[/tex]

[tex]\rightarrow 4^{-3 + 2} \times 3^{4 - 5} \times 4^{2} }[/tex]

[tex]\rightarrow 4^{-1} \times 3^{-1} \times 16}[/tex]

[tex]\rightarrow \frac{1}{4} \times \frac{1}{3} \times 16}[/tex]

[tex]\rightarrow \frac{1}{12} \times 16}[/tex]

[tex]\rightarrow \frac{16}{12}[/tex]

[tex]\rightarrow \boxed{\bold{\frac{4}{3} \tex\text{ (Option B)}}}[/tex]

Answer:

[tex]\dfrac43[/tex]

Step-by-step explanation:

      [tex]\dfrac{4^{-3}\cdot3^4\cdot4^2}{3^5\cdot4^{-2}}[/tex]

Separate like terms:

[tex]\implies \dfrac{4^{-3}\cdot4^2}{4^{-2}}\cdot \dfrac{3^4}{3^5}[/tex]

Use exponent rule [tex]a^b \cdot a^c=a^{(b+c)}[/tex] :

[tex]\implies \dfrac{4^{(-3+2)}}{4^{-2}}\cdot \dfrac{3^4}{3^5}[/tex]

[tex]\implies \dfrac{4^{-1}}{4^{-2}}\cdot \dfrac{3^4}{3^5}[/tex]

Use exponent rule   [tex]\dfrac{a^b}{a^c}=a^{(b-c)}[/tex]

[tex]\implies 4^{(-1--2)}\cdot {3^{(4-5)}[/tex]

[tex]\implies 4^{1}\cdot {3^{-1}[/tex]

Use exponent rule  [tex]a^{-1}=\dfrac{1}{a}[/tex]

[tex]\implies 4\cdot \dfrac13[/tex]

[tex]\implies \dfrac43[/tex]

The negative solution is [tex]-\frac{3}{5}[/tex]

First, add 3 on both sides.

[tex]-2|5x-1|=-8[/tex]

Then, Divide both sides by -2

[tex]|5x-1|=4[/tex]

We know 5x-1 = 4     or 5x-1=-4

[tex]x=1[/tex]             (positive)

[tex]x=-\frac{3}{5}[/tex]          (negative)

Answer:

Vertex A'  (-8,4)

Vertex B'  (-12,12)

Vertex C'  (-4,12)

Step-by-step explanation:

Multiply all the coordinates by 4!

Answer:

[tex]A'(-8,4)\\B'(-12,12)\\C'(-4,12)[/tex]

Step-by-step explanation:

** Scale and/or dilate signal the operation symbol to be multiplication.

Definitions

[tex]A=(-2,1)\\B=(-3,3)\\C=(-1,3)[/tex]

Formulas

[tex]A'=A4\\B'=B4\\C'=C4[/tex]

Solve

[tex]A'=(-2,1)(4)=(-8,4)\\B'=(-3,3)(4)=(-12,12)\\C'=(-1,3)(4)=(-4,12)[/tex]

Answer:

no

Step-by-step explanation:

the sum of all 3 angles does not add up to 180 degrees, so no

Answer:

○ [tex]\displaystyle (2x + 1)(2x - 5) = 0[/tex]

Step-by-step explanation:

Find two quantities that when differed to 8, they also multiply to 20. Those will be 2 and 10. The TINIER quantity gets the plus symbol because the B-value is −8, therefore 10 gets the minus symbol, leaving 2 with the plus symbol. In extension, sinse we have a leading coefficient greater than one, we need to take extra procedures. Here is how it is done:

[tex]\displaystyle y = 4x^2 - 8x - 5 \\ \\ y = [4x^2 - 10x] + [2x - 5] \\ \:\:\:\:\:\:\:\:\:\:\:2x[2x - 5]+ 1[2x - 5] \\ \\ \boxed{[2x - 5][2x + 1] = 0}[/tex]

I am joyous to assist you at any time.

Answer:

D

Step-by-step explanation:

I is true. Limits don't care if the point defined or not. All they care about is if they are approaching a value from both sides, unequivocally.

II is not true. We need more information about the type of function.

III is true. Since the point isn't defined but the limit exist, we have a removable discontinuity