help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! 39 points and will give branlist asap!

Examine the diagram below and answer the following questions for 2 points each: Identify which graph shows an object that is not moving. Explain why. Identify which graph shows an object that is speeding up over time. Explain why. Identify which graph shows an object that is moving at a constant speed. Explain why. Question 15 options:

Answer:

the motion of the coin taping the balloon is the balloon squshing down

Answer:

The science of the conversions between heat and other forms of energy is thermodynamics.

Hope it helps :)

Answer:

thermodynamic is the branch of physics that deals with the  relationship between heat and  other forms of energy .it describes  how thermal energy is converted to  other forms  and how it will affect matter.

Explanation:

Answer:

The value is [tex]N = 1.107 *10^{45 } \ photons[/tex]    

Explanation:

From the question we are told that

   The  power output from the sun is  [tex]P_o = 4 * 10^{26} \ W[/tex]

   The average wavelength of each photon is  [tex]\lambda = 550 \ nm = 550 *10^{-9} \ m[/tex]

Generally the energy of each photon emitted is mathematically represented as

        [tex]E_c = \frac{h * c }{ \lambda }[/tex]

Here  h is the Plank's constant with value  [tex]h = 6.62607015 * 10^{-34} J \cdot s[/tex]

          c is the speed of light with value  [tex]c = 3.0 *10^{8} \ m/s[/tex]

So

       [tex]E_c = \frac{6.62607015 * 10^{-34} * 3.0 *10^{8} }{ 550 *10^{-9} }[/tex]          

=>   [tex]E_c = 3.614 *10^{-19} \ J[/tex]          

Generally the  number of photons emitted by the Sun in a second is mathematically represented as

         [tex]N = \frac{P }{E_c}[/tex]

=>      [tex]N = \frac{4 * 10^{26} }{3.614 *10^{-19}}[/tex]

=>      [tex]N = 1.107 *10^{45 } \ photons[/tex]    

Answer:

10 mph faster than car 1 is going

Explanation:

Explanation:

ans is equal to 504j* 23 m* 10 ms

Answer:

a. the average kinetic energy of hydrogen atoms is  1.20 × 10^-19J

b. the average kinetic energy of helium atoms is 1.24 × 10^-17J

Explanation:

The computation is shown below;

As we know that

Kinetic energy = 3 ÷ 2 kT

where,

K = Boltzmann constant

And, T = Temperature

a. Now the temperature in kelvin is

T = (5,500 × (°C ÷ K) + 273.15 K)

= 5773.15 K

As

Kinetic energy = 3 ÷ 2 kT

So now 1.38 × 10^-23 J/K for K would be substituted and 5773.15 K for Temperature T

Now Kinetic energy is

= 3 ÷ 2 (1.38 × 10^-23 J/K) ( 5773.15 K)

= 1.20 × 10^-19J

hence, the average kinetic energy of hydrogen atoms is  1.20 × 10^-19J

b. As

Kinetic energy = 3 ÷ 2 kT

now 1.38 × 10^-23 J/K for K would be substituted and 6 × 10^5K for Temperature T

Now Kinetic energy is

= 3 ÷ 2 (1.38 × 10^-23 J/K) (6 × 10^5K )

= 1.24 × 10^-17J

hence, the average kinetic energy of helium atoms is 1.24 × 10^-17J

Answer:

3.88 × 10^-4 m

Explanation:

Given that a  person who weighs 614 N is riding a 85-N mountain bike. Suppose the entire weight of the rider plus bike is supported equally by the two tires. If the gauge pressure in each tire is 9.00 x 10^5 Pa. What is the area of contact between each tire and the ground?

The total weight = 614 + 85

The total weight = 699N

Let the total area of contact = A

Pressure = Force / A

Substitute all the parameters into the formula

900000 = 699 /A

A = 699 / 900000

A = 7.77 × 10^-4 m

The area of contact between each tire and the ground will be = A/2

That is, 7.77 / 2 = 3.88 × 10^-4 m

Therefore, the area of contact between each tire and the ground is 3.88 × 10^-4 m approximately.

Answer:

Oppositely charged objects will exert an attractive influence upon each other. In contrast to the attractive force between two objects with opposite charges, two objects that are of like charge will repel each other.

Explanation:

Answer:  The initial volume of the gas is 7.72 L

Explanation:

For an isothermal process the temperature is constant.  

[tex]PV=nRT[/tex]

as P = pressure = 1 atm ,

V = Volume =  25 L

n = moles

R= gas constant

T = temperature

[tex]PV=1atm\times 25L[/tex]

[tex]nRT=25Latm=25\times 101.3J=2532.5J[/tex]     (1Latm=101.3 J)

For isothermal reaction :

[tex]w=-2.303nRT\log\frac{V_2}{V_1}[/tex]

where , w = work done by  system = -ve

n = moles = 1

[tex]V_2[/tex] = final volume = 25 L

[tex]V_1[/tex] = initial volume = ?

[tex]-3000J=-2.303\times 2532.5\log \frac{25}{V_1}[/tex]

[tex]V_1=7.72L[/tex]

Thus initial volume of the gas is 7.72 L

Answer:

0.37 m

Explanation:

Let the shoulder be the origin.

The center of mass of the arm bones is 0.60 m/2 = 0.30 m and the center of mass of the hand bones is 0.10 m/2 = 0.05 m since they are modeled as straight rods with uniform density and the center of mass of a rod is x = L/2 where L is the length of the rod.

The center of mass y = (m₁y₁ + m₂y₂)/(m₁ + m₂) where m₁ = mass of arm bones = 4.0 kg, y₁ = distance center of mass of arm bones  from shoulder = 0.30 m, m₂ = mass of hand bones = 1.0 kg and y₂ = distance of center of mass hand bones from shoulder = x₁ + distance of center of hand bones from wrist = 0.60 m + 0.05 m = 0.65 m

Substituting these into the equation for the center of mass, we have

y = (m₁y₁ + m₂y₂)/(m₁ + m₂)

y = (4.0 kg × 0.30 m + 1.0 kg × 0.65 m)/(4.0 kg + 1.0 kg)

y = (1.20 kgm + 0.65 kgm)/5.0 kg

y = 1.85 kgm/5.0 kg

y =  0.37 m

The distance of the center of mass from the shoulder is thus y = 0.37 m

Answer:

58.56 J

Explanation:

Since the formula for gravitational potential energy is:

GE = m x g x h - where m = mass (kg), g = acceleration due to gravity (9.81 m/s²), h = height (m)

GE= 3 x 9.81 x 2

GE = 58.86 J

Hope this helps

Hello!!

For the maximum height the final velocity is zero, because can't up more.

Then, use the formula:

V = Vi + gt

Replacing, we have:

0 m/s = 5,3 m/s + (-9,8 m/s² * t)

0 m/s - 5,3 m/s = -9,8 m/s² * t

(-5,3 m/s) / -9,8 m/s² = t

t = 0,54 s

The time it will take to reach the maximum height is 0,54 seconds.

a= 1156× 6.13= 7086.28

Explanation:

a = m× m/ s^2

Answer:

Explanation:

the lowest points of a transverse wave are called the troughs what is the wavelength of a wave traveling through a rope if the distance from one crest to the next is 1 meter a. 2 m

4. Low points are called troughs

5. Medium: substance through which a wave can travel

The required average speed of bicycle rider is 12 km/h.

Given data:

The distance travelled by the bicycle rider is, d = 15 km.

Time taken to cover the distance is, t = 1.25 h.

Here, we need to use the simple relation between the speed, time and distance. The distance covered covered by any object per unit of time is known as average speed of object. And the mathematical expression for the average speed is given as,

[tex]v = \dfrac{d}{t}[/tex]

Here, v is the average speed.

Solving as,

[tex]v = \dfrac{15}{1.25}\\\\v = 12\;\rm km/h[/tex]

Thus, we can conclude that the required average speed of bicycle rider is 12 km/h.

Learn more about the average speed here:

https://brainly.com/question/12322912

Answer: no because you have left the number

Explanation:

Answer:

Explanation:

The formula for weight is

W = mg, where

W = the weight of the object or person

m = mass of the object or person

g = acceleration due to gravity

Now, we're given the mass of the person to be 60 kd, and thus, the weight of that person would be

W = 60 * 9.81

W = 588.6 N

On the surface of the moon, the weight of the person would be

W = 60 * 1.625

W = 97.5 N

Therefore, the weight of the person on both surfaces are 588.6 and 97.5 respectively

Answer:

.

Explanation:

Answer:

The value is  [tex]\theta = 16.38^o[/tex]

Explanation:

From the question we are told that

    The  radius is  [tex]r = 50 \ m[/tex]

    The  velocity is  [tex]v = 12 \ m/s[/tex]

Generally the angle is mathematically represented as

          [tex]\theta = tan^{-1} [\frac{v^2}{ gr} ][/tex]

=>       [tex]\theta = tan^{-1} [\frac{12^2}{ 9.8 * 50 } ][/tex]

=>       [tex]\theta = tan^{-1} [ 0.2939 ][/tex]

=>        [tex]\theta = 16.38^o[/tex]

Given :

A spring with a spring constant of 1730 N/m is compressed 0.136 m from its equilibrium position with an object having a mass of 1.72 kg.

To Find :

The embankment in the height.

Solution :

Since no external force is acting in the system, therefore total energy will be conserved.

Initial kinetic energy of the object = Energy stored in spring

[tex]K.E _i = \dfrac{kx^2}{2}\\\\K.E_i = \dfrac{1730\times 0.136^2}{2}\\\\K.E_i = 16\ J[/tex]

Also, initial potential energy is 0.

Now,

[tex]K.E_i + P.E_i = K.E_f + P.E_f\\\\16 + 0 = \dfrac{1.72\times 2.45^2}{2}+ mgh\\\\mgh =16 - 5.16\\\\h = \dfrac{16 - 5.16}{1.72 \times 9.8}\\\\h = 0.64\ m[/tex]

Therefore, the embankment height is 0.64 m.

Answer:

2.51 kg * m/s

Explanation:

In order to find momentum, use the equation below:

momentum = mass * velocity.

Since neither mass nor velocity was given, you must solve for both variables.

In order to solve for mass, use the force equation for its weight / gravitational force.

Fg (gravitational force) = 3.2 N = ma = 9.8m

mass = 3.2 N / 9.8 m/s^2 = 0.326531 kg

In order to solve for velocity, use the equation:

velocity = displacement / time

velocity = 10m / 1.3 s = 7.69231 m/s

Momentum = mass * velocity = 0.326531 kg *  7.69231 m/s = 2.51177 kg * m/s = 2.51 kg * m/s

Answer:

The second one I think

Explanation:

B

Answer:

1200cm²

Explanation:

Width= 30cm

Length= 40cm

Area of base(A) = Width×Length

= 30cm×40cm

= 1200cm²

Taking into account the definition of reactanguar prism and area of rectangle, the area of its base is 1200 cm².

A rectangular prism is a polyhedron whose surface is formed by two equal and parallel rectangles called bases and by four lateral faces that are also parallel and equal rectangles two by two.

So, the base being a rectangle, its area is calculated as the multiplication between the base and the height. In this case, these values ​​correspond to the width and length of the figure.

Then, in this case, you know:

Being:

Area of base (A) = Width×Length

Then, the are of base (A) is calculated as:

Area of base (A)= 30cm×40cm

Solving:

Area of base (A)= 1200cm²

Finally, the area of its base is 1200 cm².

Learn more:

Answer:

Horizontal distance covered is  270.63ft

Time of flight is 3.125secs

Height to which it rises is 39.06feet

Explanation:

The horizontal distance covered is the range;

Range = U²sin2theta/g

Range = 100²sin2(30)/32

Range = 10000sin60/32

Range = 10000(0.8660)/32

Range = 8660/32

Range = 270.625ft

Hence the  horizontal distance covered is  270.63ft

The time of flight is expressed using the formula;

T = 2Usin theta/g

g is the acceleration due to gravity

T = 2(100)sin30/32

T = 200(0.5)/32

T = 100/32

T = 3.125secs

Hence the time of flight is 3.125secs

Maximum height H = u²sin²theta/2g

H = 100²(sin30)²/2(32)

H = 10000(0.5²)/64

H = 10000(0.25)/64

H = 2500/64

H = 39.0625

Hence the height to which it rises is 39.06feet

Answer:

Positively Charge formation on the electroscope pulls the electrons so no emission happens.

Explanation:

Photoelectric effect is the process by which the electrons get ejected when light of certain frequency falls on the material. The energy from the electromagnetic radiation excites the electron by providing it enough energy as a result it gets ejected.

The Ultraviolet(UV) light is a form of electromagnetic radiation, If the UV radiation strikes an uncharged electroscope, it is predicted that it will cause the electrons in the electroscope to excite and to be emitted.  But on the contrary no noticeable effect is observed on the electroscope this happened because when UV light makes the electroscope positively(+) charged this creates a pull for the electrons, as a result rather emitting the electrons gets pulled by the positively charged electroscope.

Therefore the positively charge formation on the electroscope hinder the electrons emission and there is no noticeable effect.  

Answer:

The value is  [tex]v = 2.3359 *10^{4} \ m/s[/tex]

Explanation:

From the question we are told that

  The  initial speed is [tex]u = 2.05 *10^{4} \ m/s[/tex]

 Generally the total energy possessed by the space probe when on earth is mathematically represented as

             [tex]T__{E}} = KE__{i}} + KE__{e}}[/tex]

Here  [tex]KE_i[/tex] is the kinetic energy of the space probe due to its initial speed which is mathematically represented as

          [tex]KE_i = \frac{1}{2} * m * u^2[/tex]

=>       [tex]KE_i = \frac{1}{2} * m * (2.05 *10^{4})^2[/tex]

=>       [tex]KE_i = 2.101 *10^{8} \ \ m \ \ J[/tex]

And  [tex]KE_e[/tex] is the kinetic energy that the space probe requires to escape the Earth's gravitational pull , this is mathematically represented as

       [tex]KE_e = \frac{1}{2} * m * v_e^2[/tex]

Here [tex]v_e[/tex] is the escape velocity from earth which has a value [tex]v_e = 11.2 *10^{3} \ m/s[/tex]

=>    [tex]KE_e = \frac{1}{2} * m * (11.3 *10^{3})^2[/tex]

=>    [tex]KE_e = 6.272 *10^{7} \ \ m \ \ J[/tex]

Generally given that at a position that is very far from the earth that the is Zero, the kinetic energy at that position is mathematically represented as

        [tex]KE_p = \frac{1}{2} * m * v^2[/tex]

Generally from the law energy conservation we have that

        [tex]T__{E}} = KE_p[/tex]

So

       [tex]2.101 *10^{8} m + 6.272 *10^{7} m = \frac{1}{2} * m * v^2[/tex]

=>     [tex]5.4564 *10^{8} = v^2[/tex]

=>     [tex]v = \sqrt{5.4564 *10^{8}}[/tex]

=>     [tex]v = 2.3359 *10^{4} \ m/s[/tex]