Help me with the matching pls

Answer:

i cant help you with this sorry

Step-by-step explanation:

Answer:ugh is there an picture maybe i can understand it better?

Step-by-step explanation:

Answer:

x = 3

Step-by-step explanation:

Answer: x = 3

Step-by-step explanation:

Answer:

can you show us the graph

Answer:

Explanation:

(-6 + 3i) + (6 + 4i)

-6 + 6 = 0

3i + 4i = 7i

Answer:

15

Step-by-step explanation:

8^2 + b^2 = 17^2

64 + b^2 = 289

289 - 64 = 225

square root of 225 = 15

Answer:

you add 40+45

Step-by-step explanation:

40+45=85

then you subtract 180 - 85 = 95

then divide x into 95 that will give you x=95

The fractional form is 7/10.

The fractional bar is a horizontal bar that divides the numerator and denominator of every fraction into these two halves.

Given:

We have to divide 7 by 10.

The common factor for 7 and 10

7 = 7 x 1

and, 10= 2 x 5 x 1

so, there is only one factor common is 1.

Thus, the fraction is 7/10.

Learn more about Equivalent Fraction here:

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Answer:

a=4

Step-by-step explanation:

8=3a-4

12=3a

a=4

Answer:

d 5 tan theta

Step-by-step explanation:

5 sin theta x 1/cos theta

5 (sin theta/cos theta)

5 tan theta

Answer:

7x+77

Step-by-step explanation:

7(x+11)

=(7)(x+11)

=(7)(x)+(7)(11)

=7x+77

The equivalent expression from the distributive property is 7x+77.

Expression in maths is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

Given that the expression is 7(x + 11). From the distributive property, the expression will be calculated as:-

E = 7(x+11)

E=(7)(x+11)

E=(7)(x)+(7)(11)

E=7x+77

Therefore, the equivalent expression from the distributive property is 7x+77.

To know more about an expression follow

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Answer:

la eneria es muy importante

Answer:

eight hundred seventy-five thousand six hundred eighty-seven

hope this helps :)

Answer:

A. {–8, –2, 18}

Step-by-step explanation:

y = 5x − 2

x = −1.2 ----> y = 5(−1.2) − 2 = −6 − 2 = −8

x = 0 -----> y = 5(0) − 2 = 0 − 2 = −2

x = 4 -----> y = 5(4) − 2 = 20 − 2 = 18

Answer:

13

Step-by-step explanation:

Given data

flat amount =$10

let the number of dogs walked be x

and let the money earned be y

y= 10+5x

for y= 75

let us find x

75= 10+5x

75-10= 5x

65= 5x

divide both sides by 5

x= 65/5

x=13

Hence the number of dogs is 13

Answer:

[tex]x > \frac{1}{4} [/tex]

Step-by-step explanation:

[tex]12x - 5 > - 2[/tex]

Lets add +5 in both the sides.

[tex] = > 12x - 5 + 5 > - 2 + 5[/tex]

[tex] = > 12x > 3[/tex]

Now lets divide 12 on both the sides.

[tex] = > \frac{12x}{12} > \frac{3}{12} [/tex]

[tex] = > x > \frac{1}{4} [/tex]

Answer:

12 because u use the other shapes to reference your measurements.

Answer:

3√3−x=3√2x

Graph each side of the equation. The solution is the x-value of the point of intersection.

x≈0.46567646

image of graph

Step-by-step explanation:

Hope it is helpful.....

Answer:

[tex]\displaystyle \lim_{x\to 1^+}(x-1)^\ln(x)}=1[/tex]

Step-by-step explanation:

We are given:

[tex]\displaystyle \lim_{x\to 1^+}(x-1)^\ln(x)[/tex]

And we want to evaluate it using L'Hopital's Rule.

First, using direct substitution, we will acquire:

[tex]=(1-1)^\ln(1)}=0^0[/tex]

Which is indeterminate.

In order to apply L'Hopital's Rule, we first need to manipulate the expression. We will let:

[tex]y=(x-1)^\ln(x)[/tex]

By taking the natural log of both sides:

[tex]\ln(y)=\ln(x)\ln(x-1)[/tex]

And by taking the limit as x approaches 1 from the right of both functions:

[tex]\displaystyle \lim_{x\to 1^+}\ln(y)=\lim_{x\to 1^+}\ln(x)\ln(x-1)[/tex]

Rewrite:

[tex]\displaystyle \lim_{x\to 1^+}\ln(y)= \lim_{x\to 1^+}\frac{\ln(x-1)}{\ln(x)^{-1}}[/tex]

Using direct substitution on the right will result in 0/0. Hence, we can now apply L'Hopital's Rule:

[tex]\displaystyle \lim_{x\to 1^+}\ln(y)= \lim_{x\to 1^+}\frac{1/(x-1)}{-\ln(x)^{-2}(1/x)}[/tex]

Simplify:

[tex]\displaystyle \lim_{x\to 1^+}\ln(y)= \lim_{x\to 1^+}\frac{1/(x-1)}{-\ln(x)^{-2}(1/x)}\Big(\frac{-x\ln(x)^2}{-x\ln(x)^2}\Big)[/tex]

Simplify:

[tex]\displaystyle \lim_{x\to 1^+}\ln(y)= \lim_{x\to 1^+}-\frac{x\ln(x)^2}{x-1}[/tex]

Now, by using direct substitution, we will acquire:

[tex]\displaystyle \Rightarrow -\frac{1\ln(1)^2}{1-1}=\frac{0}{0}[/tex]

Hence, we will apply L'Hopital's Rule once more. Utilize the product rule:

[tex]\displaystyle \lim_{x\to 1^+}\ln(y)= \lim_{x\to 1^+}-(\ln(x)^2+2x\ln(x))[/tex]

Finally, direct substitution yields:

[tex]\Rightarrow -(\ln(1)^2+2(1)\ln(1))=-(0+0)=0[/tex]

Thus:

[tex]\displaystyle \lim_{x\to 1^+}\ln(y)=0[/tex]

By the Composite Function Property for limits:

[tex]\displaystyle \lim_{x\to 1^+}\ln(y)=\ln( \lim_{x\to 1^+}y)=0[/tex]

Raising both sides to e produces:

[tex]\displaystyle e^{\ln \lim_{x\to 1^+}y}=e^0[/tex]

Therefore:

[tex]\displaystyle \lim_{x\to 1^+}y=1[/tex]

Substitution:

[tex]\displaystyle \lim_{x\to 1^+}(x-1)^\ln(x)}=1[/tex]

Answer:

x = 11

Step-by-step explanation:

3(11 - 10) + 7 =

3 + 7 = 10

hope this helped

Answer:

-7

Step-by-step explanation:

Answer:

hard to read, can you take another picture please?

Step-by-step explanation:

Answer:

x=7

Step-by-step explanation:

∠STP=∠SWT+∠TSW(exterrior ∠ of Δ)

15x=7x+1+7x+6

x=7