Answers
Answer:
I'm pretty sure it's half
Answer:
half
Explanation:
.................................
Related Questions
May you please help me?
Answers
Answer:
The first one is 9 times the original
The second one is 1/2 times
The third one is 1/3 times
1 HELP
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A box is connected to a spring is extended to 200mm, and it stored 3578J of energy. Find the
force.
Answers
Answer:
The force applied to the spring is 35,780 N
Explanation:
Given;
extension of the spring, x = 200 mm = 0.2 m
energy stored in the spring, E = 3578 J
The force applied to the spring is calculated as;
E = ¹/₂Fx
where;
F is the applied force
F = 2E/x
F = ( 2 x 3578) / 0.2
F = 35,780 N
Therefore, the force applied to the spring is 35,780 N
If Calcium has 2 valence electrons and Chlorine has 7 valence electrons, how many Cl-1 ions would need to combine with 1 Ca+2 ion?
Answers
Answer:
CALCIUM IDENINE ADEININE AND PHOSPHATE
Explanation:
Can someone PLEASE help me with this. Anyone that’s good in physics pls
A simple circuit has three resistors connected in series. The resistors are 14 ohms 12 ohms and 9 ohms. What is the total resistance of the circuit?
Answers
Answer:
RT = 35 Ohms
Explanation:
Let the three resistors be R1, R2 and R3 respectively.
Given the following data;
R1 = 14 Ohms
R2 = 12 Ohms
R3 = 9 Ohms
To find the total resistance, RT;
Since all the resistors are connected in series, the total resistance is equal to the sum of all three resistance of the resistors.
RT = R1 + R2 + R3
Substituting into the equation, we have
RT = 14 + 12 + 9
RT = 35 Ohms.
Therefore, the total resistance of the circuit is 35 Ohms.
2. A large collection of stars, gas, and dust is called a _____?
Answers
How efficient is a pulley system if it enables you to lift a 700.0 Newton engine (Fr) 0.550 meters (dr) if you exerted 35.7 Newtons (Fe) of force while pulling 11.43 meters (de) of rope?
Answers
Answer:
96.3%
Explanation:
Efficiency = Work input/Work output * 100%
Work done = Force * distance\
Work done by the engine is the work output = 700 * 0.55
Work output = 423.5Nm
Work done by you is the work input = 35.7*11.43
Work input = 408.051Nm
Efficiency = 408.051/423.5 * 100
Efficiency = 0.963 * 100
Efficiency = 96.3%
Hence the efficiency of the pulley system is 96.3%
Imagine that someone is walking across a carpeted room and then touches a metal doorknob. Describe what happens when a doorknob is touched if there’s a buildup of static electricity.
Answers
Answer: if the door knob is metal the static electricity will exit your body, but shock you in the process
Explanation:
Un bloque de 3 kg en reposo se deja libre a una altura de 5 m sobre una rampa curva y sin rozamiento. Al pie de la rampa se encuentra un resorte de constante k = 400 N/m, como se muestra en la fig. El objeto desliza por la rampa y llega a chocar contra el resorte comprimiéndolo una distancia x antes de que quede en reposo momentáneamente. Determinar: a) La velocidad con la que el bloque alcanza al resorte. ____________________ b) La distancia x que el bloque comprime al resorte. __________________ c) La velocidad con la que el bloque es expulsado por el resorte. ____________________ d) La altura que alcanza sobre la parte curva. ________________ e) ¿Alcanzará la misma altura si la rampa no está libre de rozamiento? ___________________
Answers
Answer:
a) La velocidad del bloque cuando llega al resorte es de aproximadamente 9,9 m / s
b) La distancia a la que se comprime el resorte es de aproximadamente 0,86 m
c) La velocidad con la que el resorte expulsa el bloque es de aproximadamente 9,9 m / s
d) La altura que alcanza el bloque es de 5 metros.
e) El bloque no alcanzará la misma altura si la rampa no está libre de fricción
Explanation:
a) Los parámetros dados del bloque son;
La masa del bloque, m = 3 kg
La altura a la que se coloca el bloque, h = 5 m
La constante de resorte, k = 400 N / m
La aceleración debida a la gravedad, g = 9,8 m / s²
La energía potencial de un cuerpo, P.E. = m · g · h
Por tanto, la energía potencial inicial del bloque, P.E. se da como sigue;
P.E. = 3 kg × 9,8 m / s² × 5 m = 147 julios
P.E. = 147 julios
La energía cinética del bloque al pie de la rampa, K.E. = 1/2 · m · v²
Dónde;
v = La velocidad del bloque cuando llega al resorte
Por lo tanto, para el bloque dado tenemos;
K.E. = 1/2 · m · v² = 1/2 × 3 kg × v²
Por el principio de conservación de la energía, tenemos;
El PE. del bloque en reposo a una altura de 5 m = La energía cinética al pie de la rampa. K.E.
∴ P.E. = K.E.
147 J = 1/2 × 3 kg × v²
v² = 147 J / (1/2 × 3 kg) = 98 m² / s²
v = √ (98 m² / s²) = 7 · √2 m / s
v = 7 · √2 m / s ≈ 9,9 m / s
b) La energía recibida por el resorte comprimido, E = 1/2 · k · x²
Dónde;
k = La constante del resorte = 400 N / m
x = La distancia a la que se comprime el resorte
Por el principio de conservación de la energía, tenemos;
La energía recibida por el resorte comprimido, E = La energía potencial inicial del resorte, P.E.
∴ E = 1/2 · k · x² = P.E.
De lo que tenemos;
E = 1/2 × 400 N / m × x² = 147 julios
x² = 147 Julios / (1/2 × 400 N / m) = 0,735 m²
x = √ (0,735 m²) = 0,7 · √ (3/2) m ≈ 0,86 m
La distancia a la que se comprime el resorte = x ≈ 0.86 m
c) La velocidad con la que el resorte expulsa el bloque se indica a continuación;
La energía en el resorte = 1/2 · k · x² = La energía cinética dada al bloque, 1/2 · m · v²
∴ 1/2 · k · x² = 1/2 · m · v²
∴ La velocidad con la que el bloque es expulsado por el resorte, v = La velocidad con la que el bloque llega al resorte = 7 · √2 m / s
La velocidad con la que el resorte expulsa el bloque, v = 7 · √2 m / s ≈ 9,9 m / s
d) La altura que alcanza el bloque también viene dada por la siguiente relación anterior;
P.E. = K.E.
∴ m · g · h = 1/2 · m · v²
v = 7 · √2 m / s
De donde tenemos h = La altura inicial del bloque en la rampa = 5 metros
e) El bloque no alcanzará la misma altura si la rampa no está libre de fricción porque se utilizará energía para superar la fuerza de fricción
a) La velocidad final del bloque es aproximadamente 9.903 metros por segundo.
b) El resorte se deforma 0.858 metros.
c) Por el principio de la conservación de energía y sabiendo la ausencia de fuerzas disipativas, la velocidad del objeto expulsado del resorte es aproximadamente 9.903 metros por segundo.
d) Por el principio de la conservación de energía y si existieran fuerzas disipativas, la altura máxima sería menor a la hallada en el punto a).
a) Conforme a la situación de este problema, la energía cinética traslacional final ([tex]K[/tex]), en joules, es igual a la energía potencial gravitacional inicial ([tex]U[/tex]), en joules.
[tex]U = K[/tex] (1)
Por las definiciones de las energías cinética traslacional y potencial gravitacional expandimos la ecuación anterior:
[tex]m\cdot g\cdot h = \frac{1}{2}\cdot m\cdot v^{2}[/tex] (1)
Ahora despejamos la velocidad de esa ecuación:
[tex]v = \sqrt{2\cdot g\cdot h}[/tex]
Donde:
[tex]m[/tex] - Masa del bloque, en kilogramos.[tex]g[/tex] - Aceleración gravitacional, en metros por segundo al cuadrado.[tex]h[/tex] - Altura inicial del bloque, en metros.[tex]v[/tex] - Velocidad final del bloque, en metros por segundo.Si sabemos que [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] y [tex]h = 5\,m[/tex], entonces la velocidad final del bloque es:
[tex]v = \sqrt{2\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (5\,m)}[/tex]
[tex]v\approx 9.903\,\frac{m}{s}[/tex]
La velocidad final del bloque es aproximadamente 9.903 metros por segundo.
b) Por el principio de conservación de la energía, la energía cinética traslacional inicial es igual a la energía potencial elástica final, cuyas fórmula es la siguiente:
[tex]\frac{1}{2}\cdot k\cdot x^{2} = \frac{1}{2}\cdot m \cdot v^{2}[/tex] (2)
Where:
[tex]k[/tex] - Constante de resorte, en newtons por metro.[tex]x[/tex] - Deformación del resorte, en metros.Ahora despejamos la deformación del resorte:
[tex]x = \sqrt{\frac{m}{k} }\cdot v[/tex] (3)
Si sabemos con [tex]k = 400\,\frac{N}{m}[/tex], [tex]m = 3\,kg[/tex] y [tex]v \approx 9.903\,\frac{m}{s}[/tex], entonces la deformación del resorte es:
[tex]x = \sqrt{\frac{3\,kg }{400\,\frac{N}{m} } }\cdot \left(9.903\,\frac{m}{s} \right)[/tex]
[tex]x \approx 0.858\,m[/tex]
El resorte se deforma 0.858 metros.
c) Por el principio de la conservación de energía y sabiendo la ausencia de fuerzas disipativas, la velocidad del objeto expulsado del resorte es aproximadamente 9.903 metros por segundo.
d) Por el principio de la conservación de energía y si existieran fuerzas disipativas, la altura máxima sería menor a la hallada en el punto a).
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what do fluorine, sodium, and aluminum have in common
Answers
Now set the tension to low and wiggle the wrench to create more waves. Can you explain how moving the first point on the string, the one closest to the wrench, affects the next point on the spring? How does this fit with your understanding of the force of a stretched spring?
Answers
Answer:
When the string moves, it creates a very small change in the distance to the next point, th
Explanation:
When the string moves, it creates a very small change in the distance to the next point, this generates a restoring force that tends to push the string back, this small disturbance propagates along the string and is what creates the pulse.
This is similar to what happens when a spring is stretched and a restoring force is generated shaved by the law of shortening.
F = k Dx
Answer:
As the first particle travels upward, it pulls on the next particle, which follows the first particle upward. Then next in line is pulled up in turn, and so on. The motion of each particle follows the one before it, either up or down, with a slight lag in time. This succession of particles moving up or down travels along the string as a wave. Eventually, it pulls every particle along the string up and down in series.
Explanation:
How do the metal aluminum coils in an air conditioner help keep a house cool? They insulate the house from outside thermal energy. They conduct thermal energy from inside the house and release it outside the house. They insulate the surrounding air from indoor thermal energy. They conduct thermal energy from outside the house and release it inside the house.
Answers
Answer:
They conduct thermal energy from inside the house and release it outside the house.
Explanation:
An air conditioner works to by conducting thermal energy or heat from inside the house and releasing this heat energy outside the house, thus making inside of the house cooler than the outside.
Warm air from inside the house is circulated around the evaporator fins. The refrigerant liquid is made to pass through the evaporator coil made of aluminum ,where the coils exchanges the heat it absorbs from the air surrounding it with the refrigerant. Aluminum metal is used in making the evaporator coils because it is a good conductor of heat. The heat absorbed by the refrigerant coverts it to vapor, which is then reconverted into liquid by the condenser removing the heat absorbed from inside the outside by means of a fan. As the heat is removed from the air, the air is cooled and blown back inside the house. This process is repeated several times until the desired temperature is attained inside the house.
Answer:
B is the answer
Explanation:
pls give me brainliest
1. A truck of mass 3120 kg is accelerated from rest to a speed of 22.1 m/s. How much work was done on the truck to achieve that speed?
Answers
Answer:
.5(3120kg)(22.1m/s)^2 = 7.62x10^5 J
Explanation:
The work done on the truck to achieve given speed is [tex]7.62*10^{6}[/tex] Joules.
The work done on the truck is equivalent to the kinetic energy.
Work done = Kinetic energy = [tex]\frac{1}{2} mv^{2}[/tex]
Where m is mass of truck and v is final velocity of truck.
Given that, [tex]m=3120Kg,v=22.1m/s[/tex]
Substitute values in above equation
[tex]Workdone=\frac{1}{2}*3120*(22.1)^{2} \\\\Workdone=0.5*3120*488.41=7.62*10^{6} KJ[/tex]
Thus, The work done on the truck to achieve given speed is [tex]7.62*10^{6}[/tex] Joules.
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How do you find mass in physics
Answers
please watch this video, hope it helps
What is the half-life of isotope X?
How many radioactive atoms of isotope X are left after
3 half-lives?
How many half-lives must have occurred if only 7
atoms of isotope X are left?
Answers
Answer:
What is the half-life of isotope X? 25 seconds
How many radioactive atoms of isotope X are left after 3 half-lives? 13
How many half-lives must have occurred if only 7 atoms of isotope X are left? 4
Explanation:
The half-life of isotope X is 25 seconds
The radioactive atoms of isotope X left after 3 half-lives are 13
Number of half-lives must have occurred if only 7 atoms of isotope X left are 4.
What is half life?Half life is the time taken by a radioactive material for the radioactivity of to reduce by half its original value.
The half life equation is:
A = A₀ (½)^(t / T)
where A is the final amount, A₀ is the initial amount, t is the amount of time, and T is the half life.
The half-life of isotope X is 25 seconds
The radioactive atoms of isotope X left after 3 half-lives are 13
Number of half-lives must have occurred if only 7 atoms of isotope X left are 4.
Thus, the questions are answered.
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What changes into energy in the sun?
Answers
Answer:
The sun generates energy from a process called nuclear fusion. During nuclear fusion, the high pressure and temperature in the sun's core cause nuclei to separate from their electrons. Hydrogen nuclei fuse to form one helium atom. During the fusion process, radiant energy is released. :D
the breakdown of rocks by chemical action of air and water is called
Answers
Answer:
Chemical weathering
Explanation:
This changes the molecular structure of rocks and soil. For instance, carbon dioxide from the air or soil sometimes combines with water in a process called carbonation. This produces a weak acid, called carbonic acid, that can dissolve rock.
The adult house fly lives for only about 1 month, or 8 x 10^-2 y. The oldest recorded age of a tortoise was 1.8800 x 10^2 y. What is the difference between these two ages?
Answers
187.92 years
8*10^-2= .08
1.88*10^2= 188
188-.08=187.92
5.0 kg, with a bullet of mass 0.1 kg. The target was mounted on
low-friction wheels and as the bullet struck the target, the target with
bullet embedded bullet sped off with a velocity of 6.0 ms.
Calculate the velocity of the bullet just before it hit the stationary
target.
Answers
Answer:
306 m/s
Explanation:
Law of conservation of momentum
m1v1 + m2v2 = (m1+m2)vf
m1 is the bullet's mass so it is 0.1 kg
v1 is what we're trying to solve
m2 is the target's mass so it is 5.0 kg
v2 is the targets velocity, and since it was stationary, its velocity is zero
vf is the velocity after the target is struck by the bullet, so it is 6.0 m/s
plugging in, we get
(0.1 kg)(v1) + (5.0 kg)(0 m/s) = (0.1 kg + 5.0 kg)(6.0 m/s)
(0.1)(v1) + 0 = 30.6
(0.1)(v1) = 30.6
v1 = 306 m/s
The initial velocity of the bullet can be determined from the total momentum of the system. The velocity of the bullet was 306 m/s.
What is momentum ?Momentum of a body is the product of its mass and velocity. For a collision, the momentum before and after collision will be the same for the colliding system.
Let m1 and m2 be the masses and u be the initial velocity and v is the final velocity.
then, m1 u1 + m2 u2 = m1 v1 + m2 v2.
Given m1 = 5 kg
m2 = 0.1 kg
The velocity of the combined mass v = 6 m/s.
The momentum of the target is zero since it was stationary.
(0.1 × u1) = (0.1 + 5)6 m/s
(0.1 × u1) = 30.6 m/s
then u1 = 30.6/0.1 = 306 m/s
Therefore, the velocity of the bullet before hitting was 306 m/s.
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How would you describe your appetite over the past couple of weeks? Have your eating habits altered in any way?
Answers
Answer:
no im in a rehab program so we eat the sam shi every day
Explanation:
brainlest?
Explanation:
During lockdown, I ate LOADS OF JUNK FOOD. TRUST ME!!
I gained 14 kg of weight and became 68 kg
just due to junk food.I am 13 btw and at that time I was 5 feet 4 so definitely fat. all those pizzas and burgers and all.then I realised that I have gained weight. I have to REDUCE MY WEIGHT. I am quite determined on what I say. it took me 3 months or so and I finally got back to my original weight. How? just by going for a stroll everyday, eating healthy and constantly working out. eating less is not the solution,eating less calories is the solution.Also, by eating healthy food,I grew taller. I am 5 feet 6 now. So yes, definitely it helps put alot and keep eating healthy food and you will definitely be healthy.
Thank You.
A student attaches a block to a vertical spring of unknown spring constant so that the block-spring system will oscillate if the block-spring system is released from rest at a vertical position that is not the system’s equilibrium position. The student varies the object’s mass and uses a stopwatch to determine the time it takes the object to make one oscillation. The student creates the graph that is shown. The slope of the line of best fit is equal to which of the following quantities?
Answers
Answer:
D: 2π/√k0
Explanation:
I got it right
The slope of the line of best fit is the quantity 2π/√ko.
The line of best fits is used to show the relationship between two variables. The nature of the graph shows the relationship between the variables.
We can see that this is a graph of the period of oscillation against the square root of the mass of the body. The slope of the line of best fit is the quantity 2π/√ko.
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can someone help me please
Answers
Mile
AP physics! Will give brainliest to correct answer!
Answers
Answer:
D
Explanation:
Answer:
HELLO THERE
Explanation:
D
You are designing a spaceship, and you want it to have an artificial gravity of 9.8 m/s2 at the center of mass of an average human. The average human has a center of gravity that is about 90 cm above their feet. Through other engineering constraints, you have determined the rotational speed of the ship to be 0.2 rad/s. What should the radius of the ship be (in m)? (Round your answer to the nearest whole number!)
Answers
Answer:
The tangential acceleration is 0 m/s².
Explanation:
Answer:
The tangential acceleration is 0 m/s².
Explanation:
If a bicycle travels 1200m, and it takes 300seconds, what is its speed in m/s.
Answers
Explanation: speed= distance/time
The radio is playing at the front of the room. How does the sound get from the speakers to your ears? A: A breeze blows from the speakers and pushes the sound along. B: Vibrations are sent through the air to your ears. C: The sound bounces off a satellite and back to Earth. D: The speakers produce invisible laser beams that carry sound.
Answers
Answer:
Vibrations are sent through the air to your ears.
Explanation:
Sound is a form of energy that is transmitted in compression and rare factions. Sound is a mechanical wave. All mechanical waves require a material medium for propagation.
The material medium for the propagation of sound is air. When the sound is produced by the speakers, the molecules of air are set into vibration and this vibration carries the sound from the speaker to your ears.
Calculate the wavelength of light that has a frequency of 5.2 x 1012 1/s.
Answers
Answer:
Wavelength = 5.77 * 10^-5 meters.
Explanation:
Given the following data:
Frequency of light = 5.2 *10^12 Hz
We know that the Speed of light = 3.0 * 10^8 m/s
To find the wavelength of light;
Mathematically, wavelength is calculated using this formula;
[tex] Wavelength = \frac {speed}{frequency} [/tex]
Substituting into the equation, we have;
[tex] Wavelength = \frac {3*10^{8}}{5.2 *10^{12}} [/tex]
Wavelength = 5.77 * 10^-5 meters.
How many seconds does it take for net force 20N to change the velocity to a 5kg mass by 2m/s?
Answers
Answer:
0.5 second
Explanation:
We are given that
Force, F=20 N
Mass, m=5 kg
Change in velocity,=2m/s
We have to find the time taken to change the velocity .
We know that
Force, F=ma
Where
Acceleration, a=Change in velocity/time
[tex]a=\frac{2}{t}[/tex]
Substitute the values
[tex]20=5\times \frac{2}{t}[/tex]
[tex]t=\frac{5\times 2}{20}[/tex]
[tex]t=0.5 s[/tex]
The planet Mercury travels around the Sun with a mean orbital radius of 5.8x100 m. The mass of the Sun is 1.99x1030 kg. Use Newton's version of Kepler's third law to determine how long it takes Mercury to orbit the Sun. Give your answer in seconds.
Answers
7.6 million seconds
Basically 88 days
The time taken for Planet Mercury to orbit around the sun is determined as 1.21 x 10⁶ s.
Period of the planet mercury
The time of motion of the planet around the sun is calculated as follows;
[tex]T = 2\pi \sqrt{\frac{a^3}{Gm} } \\\\[/tex]
where;
a is the mean radius of the planet MercuryG is universal gravitation constantM is mass of the sun[tex]T = 2\pi \sqrt{\frac{(5.8 \times 10^{10})^3}{(6.67 \times 10^{-11})(1.99\times 10^{30})} } \\\\T = 1.21 \times 10^6 \ s[/tex]
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How can we define force?
Answers
Explanation:
A force is a push or pull upon an object resulting from the object's interaction with another object. Whenever there is an interaction between two objects, there is a force upon each of the objects. When the interaction ceases, the two objects no longer experience the force.
Answer:
There are 2 definitions chose the suitable one for ur question
Explanation:
1. strength or energy as an attribute of physical action or movement.
2. coercion or compulsion, especially with the use or threat of violence.
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Select all the correct answers.
An unmanned spacecraft leaves for Venus. Which statements about the spacecraft's journey are true?
O
The weight of the spacecraft keeps changing.
The mass of the spacecraft keeps changing.
The weight of the spacecraft remains the same.
The mass of the spacecraft remains the same.
The gravitational pull on the spacecraft remains the same.
Answers
An unmanned spacecraft leaves for Venus. The statements, The weight of the spacecraft keeps changing and The mass of the spacecraft remains the same. This 2 statements A and D are true.
What is Spacecraft ?A spaceship is a machine or vehicle built to travel through space. Spacecraft are a form of artificial satellite utilised for a wide range of tasks, such as communications, Earth observation, meteorology, navigation, space colonisation, planetary exploration, and freight and person transfer. All spacecraft, with the exception of single-stage-to-orbit vehicles, need a launch vehicle (carrier rocket) to get into space.
A spacecraft that is performing a sub-orbital spaceflight launches into space and then lands without gaining enough momentum or energy to complete a full orbit of the Earth. Spacecraft enter confined orbits around the Earth or other celestial bodies for orbital spaceflights. Only humans are carried on human spacecraft either as crew or guests from launch or while in orbit (space stations).
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