Help me(((((((please

Answer: yes they are

Step-by-step explanation:

Answer:

linear

Step-by-step explanation:

Answer:

yes this right cuz ye or nah?

Step-by-step explanation:

yes cuz 0 1 2 3 4 5 6 7 8 9 are the numbers

Answer: [?] is 6

Step-by-step explanation:

x=5

so, 2x=10

10-4 is 6

It would take 70 years for the deer population to reach 800.

An exponential function is in the form:

y = abˣ

where b is the multiplier, y, x are variables and a is the initial value.

Let y represent the population and x represent the time in years.

a = 200, b = 100% + 2% = 102% = 1.02

y = 200(1.02)ˣ

For a population of 800:

800 = 200(1.02)ˣ

ln(4) = xln(1.02)

x = 70 years

It would take 70 years for the deer population to reach 800.

Find out more on exponential function at: brainly.com/question/2456547

Answer: 200, 0.02, and 800

Step-by-step explanation:

[tex]~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{1}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{-4})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{(3-1)^2+(-4-1)^2}\implies d=\sqrt{2^2+(-5)^2}\implies d = \sqrt{29}[/tex]

Answer:

Yes.

Step-by-step explanation:

I had a problem just like this and you are correct.

Answer:

36n + 18

Step-by-step explanation:

6 * 6n = 36n

6 * 3 = 18

36n + 18 = 36n + 18

Answer:

36n+18

Step-by-step explanation:

6(6n+3)

(6×6n)+(6×3)

36n+18

But if you want it simplifed, you can divide both 36n and 18 by 18 and you will be left with 2n+1

Answer:

solution given:

let's see only in a right-angled triangle Δ ACD.

AC=3 units

AD=5 units

since Δ ACD is a right-angled triangle. It satisfies Pythagoras law

[tex]AD^{2}=AC^{2}+CD^{2}[/tex]

25=9+[tex]CD^2[/tex]

[tex]CD^2[/tex]=25-9=16

[tex]CD=\sqrt{16} =4 units[/tex]

Now

Area of rectangle Δ ACD=[tex]\frac{1}{2} CD*AC=\frac{1}{2}*4*3=6\: square \:units[/tex]

similarly,

[tex]\frac{1}{2} AD*CE=6\: square \:units\\ 5*CE=6*2\\CE=\frac{12}{5}=2.4 units[/tex]

since AB=CE=2.4 units

Δ ACE is a right-angled triangle. It satisfies Pythagoras law.

[tex]AC^{2}=AE^{2}+CE^{2}\\3^2=AE^2+2.4^2\\9-5.76=AE^2\\AE and BC=\sqrt{1.24} =1.11 units[/tex]

now

area of trapezoid=area ofΔACD+Area of ΔABC

=6+[tex]\frac{1}{2}AB*BC=6+\frac{1}{2}*2.4*1.11=6+1.33 =7.33\: square \:units[/tex]

Answer:

10/9

Step-by-step explanation:

Answer:ITS THE SECOND ONE

Step-by-step

Answer:

[tex]y=\frac{\frac{16}{3}(x+1)(x+6)}{(x-1)(x-4)}[/tex]

Step-by-step explanation:

Because x=1 and x=4 are the solutions to x-1=0 and x-4=0, then we have (x-1)(x-4) in the denominator.

Because (-1,0) and (-6,0) are the solutions to x+1=0 and x+6=0, then we have (x+1)(x+6) in the numerator.

Now we have [tex]y=\frac{a(x+1)(x+6)}{(x-1)(x-4)}[/tex] where we plug in (0,8) to solve for a:

[tex]y=\frac{a(x+1)(x+6)}{(x-1)(x-4)}[/tex]

[tex]8=\frac{a(0+1)(0+6)}{(0-1)(0-4)}[/tex]

[tex]8=\frac{6a}{4}[/tex]

[tex]32=6a[/tex]

[tex]\frac{32}{6}=a[/tex]

[tex]\frac{16}{3}=a[/tex]

Therefore, the equation for the rational function is [tex]y=\frac{\frac{16}{3}(x+1)(x+6)}{(x-1)(x-4)}[/tex]

Answer:

1. 1[tex]\frac{1}{2}[/tex]

2. 1[tex]\frac{3}{10}[/tex]

3. [tex]\frac{1}{3}[/tex]

4. 1[tex]\frac{2}{7}[/tex]

Step-by-step explanation:

I hope this helps!!

Answer:

The number 9490 is called the numerator or dividend, and the number 5 is called the denominator or divisor.

The quotient of 9490 and 5, the ratio of 9490 and 5, as well as the fraction of 9490 and 5 all mean (almost) the same:

9490 divided by 5, often written as 9490/5.

Read on to find the result of 9490 divided by 5 in decimal notation, along with its properties.

Answer:

y = -1/2x + 6

Step-by-step explanation:

We know that the slope intercept form of a line is .

Also, if two lines are parallel, they have the same slope. So re-writing the given equation 2x + 4y = 10 in the slope intercept form to find know its slope.

So the slope of the equation will be .

Finding the y-intercept (c):

Therefore, the equation of the line n slope intercept form that is parallel to 2x + 4y = 10 and passes through the point (8, 2) is y = -1/2x + 6.

Δ PQR has: PM is a median

so: MR = QM = 3 cm

ANSWER: MR = 3 cm

Ok done. Thank to me :>

Answer:

a

Step-by-step explanation:

(x-2)(x-11) less than or equal to 0

which means x is between 2 and 11 when it is less than 0

Answer:

B. 70

Step-by-step explanation:

If 199.50 PHP gets you 2.85KG of rice.

A kilogram of rice would cost = Total Amount / Total Weight.

199.50/2.85

= 70PHP

Answer:

6:4:3

Step-by-step explanation:

each can be divided by 7

Answer:

6 4 3

Step-by-step explanation:

Answer:

The lines would be parallel.

Step-by-step explanation:

lines with the same slope are parallel.

[tex]x+x(2x)=x+2x^2\\\\\text{when x =2}\\\\2+ 2(2)^2 = 2+ 2(4) = 2+ 8 = 10[/tex]

[tex]\text{So, the answer is (a).}[/tex]

Answer:

17

Step-by-step explanation:

Let the smaller number = x

Let the larger number = y

y = 2x + 8

y - x = 25                Add x to both sides

y = x + 25               Substitute this into the first equation

x + 25 = 2x + 8       Subtract 8 from both sides

x + 25 - 8 = 2x        Combine

x + 17 = 2x               Subtract x from both sides.

17 = 2x - x                Combine

17 = x

Answer:

It does not matter, since, from your second case, [tex]5\sqrt5 +11 = 11+5\sqrt5[/tex].

In general is a matter of personal preference but in general I like to start with a positive number (I like [tex]\sqrt2 -1[/tex] more than [tex]-1+\sqrt2[/tex] since if there's an equal sign before I'm guaranteed to have the two signs mesh together in a few steps).

If everything you are adding together is positive, I just go first come first served and pick a new term in order it appears in the previous passage.

[tex]\stackrel{\textit{reciprocal ident.}}{csc(\theta)=\cfrac{1}{sin(\theta)}} ~\hfill \stackrel{\textit{symmetry ident.}}{sin(-\theta )=-sin(\theta)}~\hfill \begin{array}{llll} \stackrel{\textit{pythagorean ident.}}{sin^2(\theta)+cos^2(\theta)=1}\\ sin^2(\theta)=1-cos^2(\theta)\\ cos^2(\theta)=1-sin^2(\theta) \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}[/tex]

[tex]\cfrac{csc^2(-x)-1}{1-cos^2(-x)}\implies \cfrac{~~\frac{1}{sin^2(-x)}-1~~}{sin^2(-x)}\implies \cfrac{~~ \frac{1-sin^2(-x)}{sin^2(-x)}~~}{\frac{sin^2(-x)}{1}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{keeping in mind that}~\hfill }{sin^2(-x)\implies [sin(-x)]^2\implies [-sin(x)]^2\implies [sin(x)]^2\implies sin^2(x)} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\cfrac{~~ \frac{1-sin^2(x)}{sin^2(x)}~~}{\frac{sin^2(x)}{1}}\implies \cfrac{1-sin^2(x)}{sin^2(x)}\cdot \cfrac{1}{sin^2(x)}\implies \cfrac{cos^2(x)}{sin^2(x)}\cdot \cfrac{1}{sin^2(x)} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill cot^2(x)csc^2(x)~\hfill[/tex]

Answer:

Solve for n

n=log5  (− 2 /y  −20x−5),y<−40x−10

Step-by-step explanation:

Answer:

1,2,4,5,8,10,20,40

Step-by-step explanation:

Have a nice day