HELP NEEDED ASAP PLZZZZZZ

Michele is making a kite based on the pattern below. About how much binding does Michele need to cover the edges of the kite?

HELP NEEDED ASAP PLZZZZZZMichele Is Making A Kite Based On The Pattern Below. About How Much Binding

Answers

Answer 1

Answer:

about 52.1 in.

Step-by-step explanation:

PM=PE=5 inches, PR=4 inches, and OP=19 inches.

Since the figure is a kite, the diagonals ME and OR are perpendicular and form right triangles with their hypotenuses forming the sides of the kite, OM, MR, RE, and EO.

The figure shows the same kite O M R E as in the beginning of the task. Diagonal O R is perpendicular to diagonal M E.

Use the Pythagorean Theorem to calculate the length of OM.

OM=OP2+PM2−−−−−−−−−−√

Substitute 19 for OP and 5 for PM.

OM=192+52−−−−−−−√

=361+25−−−−−−−√

=386−−−√

Therefore, OM=386−−−√ in.

By the definition of a kite, OM≅EO. So, EO is also equal to 386−−−√ inches.

Use the Pythagorean Theorem to calculate the length of MR.

MR=PM2+PR2−−−−−−−−−−√

Substitute 5 for PM and 4 for PR.

MR=52+42−−−−−−√

=25+16−−−−−−√

=41−−√

Therefore, MR=41−−√ in.

By the definition of a kite, MR≅RE. So, RE is also equal to 41−−√ inches.

The figure shows the same kite O M R E as in the beginning of the task. Sides O M and E O are square root of 386 inches long. Sides M R and R E are square root of 41 inches long.

The perimeter of the kite is the sum of the four sides.

Perimeter of OMRE=OM+MR+RE+EO

=386−−−√+41−−√+41−−√+386−−−√

=2386−−−√+241−−√

Use a calculator to approximate.

Perimeter of OMRE≈52.1 in.

So, the perimeter of OMRE is about 52.1 inches.

Therefore, about 52.1 inches of binding are needed to cover the edges of the kite.


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4, -3

Step-by-step explanation:

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It is defined as the change in coordinates and the shape of the geometrical body. It is also referred to as a two-dimensional transformation. In the geometric transformation, changes in the geometry can be possible by rotation, translation, reflection, and glide translation.

It is given that:

The figures are given in the picture:

For the red figure: Translate 1 unit down then 3 units left.

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answers

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33.3%

Step-by-step explanation:

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Answers

Answer:

Step-by-step explanation:

They sold $42 worth of tickets in one hour. Need more information to determine the number of tickets.

The Wilson Student Government sold $42 worth of tickets in one hour. Total amount of money earned from ticket sales = $126

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Step 1: Divide the total amount of money earned by the number of hours to find the average ticket sales per hour.

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Tickets sold in one hour = $126 / 3

Step 2: Perform the division.

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([?], [ ])

Answers

Answer:

The centroid of ABC is (3 , 2).

Step-by-step explanation:

The steps are :

[tex]centre = ( \frac{x1 + x2 + x3}{3} \: , \: \frac{y1 + y2 + y3}{3} )[/tex]

[tex]centre = ( \frac{2 + ( - 1) + 8}{3} \: , \: \frac{2 + 0 + 4}{3} )[/tex]

[tex]centre = ( \frac{9}{3} \: , \: \frac{6}{3} )[/tex]

[tex]centre = (3 \: , \: 2)[/tex]

Answer:

The centroid of ∆ABC is (3 , 2).

Step-by-step explanation:

Solution :

Here's the required formula to find the centroid of ∆ABC :

[tex]{\star{\footnotesize{\purple{\underline{ \boxed{\sf{\pink{Centroid = \bigg( \dfrac{x_1 + x_2 + x_3}{3} \: , \: \dfrac{y_1 + y_2 + y_3}{3} \bigg)}}}}}}}}[/tex]

Where :

[tex]\rightarrow\rm{x_1}[/tex] = 2[tex]\rightarrow\rm{x_2}[/tex] = -1[tex]\rightarrow\rm{x_3}[/tex] = 8[tex]\rightarrow\rm{y_1}[/tex] = 2[tex]\rightarrow\rm{y_2}[/tex] = 0[tex]\rightarrow\rm{y_3}[/tex] = 4

Substituting all the given values in the formula to find the centroid of ∆ABC

[tex]{\implies{\small{\sf{Centroid = \bigg( \dfrac{x_1 + x_2 + x_3}{3} \: , \: \dfrac{y_1 + y_2 + y_3}{3} \bigg)}}}}[/tex]

[tex]{\implies{\small{\sf{Centroid = \bigg( \dfrac{2 + ( - 1) + 8}{3} \: , \: \dfrac{2 +0 + 4}{3} \bigg)}}}}[/tex]

[tex]{\implies{\small{\sf{Centroid = \bigg( \dfrac{2 - 1 + 8}{3} \: , \: \dfrac{2 +0 + 4}{3} \bigg)}}}}[/tex]

[tex]{\implies{\small{\sf{Centroid = \bigg( \dfrac{10 - 1}{3} \: , \: \dfrac{2 + 4}{3} \bigg)}}}}[/tex]

[tex]{\implies{\small{\sf{Centroid = \bigg( \dfrac{9}{3} \: , \: \dfrac{6}{3} \bigg)}}}}[/tex]

[tex]{\implies{\small{\sf{Centroid = \bigg( \cancel\dfrac{9}{3} \: , \: \cancel\dfrac{6}{3} \bigg)}}}}[/tex]

[tex]{\implies{\small{\sf{Centroid = \Big( 3\: , \: 2 \Big)}}}}[/tex]

[tex]\star{\underline{\boxed{\rm{\red{Centroid = \Big( 3\: , \: 2 \Big)}}}}}[/tex]

Hence, the centroid of ∆ABC is (3 , 2).

[tex]\rule{300}{1.5}[/tex]

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Answers

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Step-by-step explanation:

Answer:

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Answers

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

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Answer:

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Answers

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation

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Step-by-step explanation:

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