Help picture below problem 10

Answer:

85 dogs have signed up to compete

Step-by-step explanation:

its 85 small dogs because 49+36=85

Answer:

(0,5)

Step-by-step explanation:

I'm really not sure but I'm pretty positive that this is the answer if not than my bad

Answer:

Step-by-step explanation:

1.  If y =2x

solve for y in (6x +3y) = 12

6x + 3(2x) = 12,   6x + 6x =12

12x = 12 ,  x= 1

to find y ,   from y =2x

y = 2(1)  , ( x = 1 and y = 2)

2.  y = -4x + 2

    y = 6x -8

y = (-4x + 2)(6x-8)

= -4x ( 6x -8) + 2(6x-8)

-24[tex]x^{2}[/tex] + 32x + 2(6x-8)

-24x2 + 44x - 16

3.  y = x -4

  -4x -6y = -16

  -4x - 6(x - 4) = -16

 -4x - 6x - 24 = -16

-10x - 24 = -16

-10x = -16 + 24,   -10x = -8

x = 0.8 , to get y , we input x value into eqn(y = x-4)

y = 0.8 -4,   y = -3.2

x = 0.8,   y = -3.2.

4.  x = 3y + 1

 2x + 4y =12

2(3y + 1)  + 4y = 12

6y + 2 + 4y = 12

10y + 2 = 12

10y = 12 -2

10y = 10

y = 1,  to get x

x = 3y + 1

x = 3(1) + 1 ,  x = 4

( x = 4 and y = 1).

[tex]xy - 2x = - 3[/tex]

[tex]xy = 2x - 3[/tex]

____________________________________________

[tex]3 {x}^{2} + 5xy + 4 = 0[/tex]

[tex]3 {x}^{2} + 5(2x - 3) + 4 = 0[/tex]

[tex]3 {x}^{2} + 10x - 15 + 4 = 0[/tex]

[tex]3 {x}^{2} + 10x - 11 = 0[/tex]

[tex]delta = {10}^{2} - 4(3)( - 11)[/tex]

[tex]delta = 100 + 132[/tex]

[tex]delta = 232[/tex]

Thus;

[tex]x = \frac{ - 10 + \sqrt{232} }{6} \: \: or \: \: x \frac{ - 10 - \sqrt{232} }{6} \\ [/tex]

[tex]x = \frac{ - 10 + 15.23}{6} \: \: or \: \: x = \frac{ - 10 - 15.23}{6} \\ [/tex]

[tex]x = \frac{5.23}{6} \: \: or \: \: x = \frac{ - 25.23}{6} \\ [/tex]

[tex]x = 0.8716 \: \: or \: \: x = - 4.205[/tex]

____________________________________________

[tex]0.8716 \: y = 2(0.8716) - 3[/tex]

[tex]0.8716 \: y = 1.7432 - 3[/tex]

[tex]0.8716 y= - 1.2568[/tex]

[tex]y = \frac{ - 1.2568}{0.8716} \\ [/tex]

[tex]y = - 1.4419[/tex]

[tex] - 4.205 \: y = 2( - 4.205) - 3[/tex]

[tex] - 4.205 \: y = - 8.410 - 3[/tex]

[tex] - 4.205 \: y = - 11.410[/tex]

[tex]y = \frac{ - 11.410}{ - 4.205} \\ [/tex]

[tex]y = 2.7134[/tex]

And we're done

Have a great day ♡

Answer:

Hope the picture will help

[tex]\frac{16}{7}[/tex]Answer:

X = -16/7

Step-by-step explanation:

Multiply the numbers

4 x 2 + 8 = -7x

8 + 8 = -7x

Add the numbers

8 + 8 = -7x

16= -7x

Divide both sides by the same factor

16= -7x

16 divided bu -7x and -7x divided by -7x

Simplify

-16 divided by 7 not negative 7 and -7 divided by -7

Cancel terms that are in both the numerator and denominator

cancel out -7 divided by -7 and you get -16/7 left

so, therefore x= -16/7

Answer:

x=23

Step-by-step explanation:

2x-6/4 = 10

2x-6 = 10(4)

2x-6 = 40

2x = 40+6

2x = 46

x = 46/2

x = 23

Answer:

x = -3.5

y = 1.5

so W = (-3.5, 1.5)

Step-by-step explanation:

Answer:B

Step-by-step explanation:the slope is 1/4, and it crosses the y axis at -2.

Answer:

See below ↓

Step-by-step explanation:

Part A

Part B

Part C

Answer:

Part A

The x-intercepts are when f(x) = 0.

Since x represents the price of pens, and f(x) represents the company's profit, the x-intercepts give the price of the pens when the profit is zero.

⇒ the profit is zero when the price of pens are $0 and $6

The maximum value of the graph (vertex) represents the cost of pens when the profit is at its highest.  Therefore, the optimal amount to price the pens to get the maximum profit.

⇒ maximum profit of $120 occurs when the pens are priced at $3

Part B

[tex]\sf average \ rate \ of \ change=\dfrac{change \ in \ y}{change \ in \ x}[/tex]

From inspection of the graph, f(3) = 120 and f(5) ≈ 60

[tex]\sf \implies average \ rate \ of \ change=\dfrac{60-120}{5-3}=-30[/tex]

This means that as the price of the pens increases by $1 (between $3 and $5), the average profit decreases by approximately $30.

Part C

The domain is the set of input values (x-values).  As the price of a pen cannot be less than zero, the domain will be x ≥ 0

Unless the company is happy to make a loss, the restricted domain should be 0 ≤ x ≤ 6

Step-by-step explanation:

1.3+1.45/2

= 1.75/2

=0.875

A: 1.9 Kilograms of oranges for rs 665.

B: 12 liters of petrol will make a car travel 120 km.

Answer: [tex]\frac{11}{14}[/tex]

Step-by-step explanation:

1) Identify Format

(x1,y1) = (−10,−3)

(x2,y2) = (4,8)

2) Use the Slope Formula

m=y2−y1x2−x1

=8−−3/4−−10

=11/14

=11/14

Bonus: Graph

Answer provided by Education Point

The rate which the walk-in guest is how fast a guest needs a room

The rate which the walk-in guest pay for the night is $189.75

The given parameters are:

Average rate = $165 per night

The walk-in guest is 15% greater than the average rate.

So, the rate of the walk-in guest is:

Walk-in = 165 * (1 + 15%)

Evaluate the product

Walk-in = $189.75

Hence, the rate which the walk-in guest pay for the night is $189.75

Read more about rates at:

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in 20 days 4 half life will be completed

so n = 4

formula :-

[tex] \frac{ A\degree}{ {2}^{n} } = \frac{9056}{ {2}^{4} } = \frac{9056}{16} = 566grams[/tex]

The radioactive kind of promethium will have 566 grams left after 20 days.

Half-life is the time required for a quantity to reduce to half of its initial value.

Given, A radioactive kind of promethium with 9,056 grams and a half-life is 5 days.

∴ In the next 5 days, it'll have (9056/2) = 4528 grams.

Next 5 days it'll have (4528/2) = 2269 grams.

As it has a half-life in 5 days and 20 is multiple (4×5).

After 20 days the radioactive material will have (9056/2⁴) grams.

= 566 grams left.

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Answer:

Step-by-step explanation:

Line segments:  MN ,  NO  , MO

Line segment has beginning and ending point

Answer:

1 container per batch so 1 batch is 1 comtsiner

Answer: I think 5000

Step-by-step explanation:

I’m probably completely wrong lol sorry

The tree grew about 3.83 inches between the first and third week.

An equation is an expression that shows the relationship between two or more numbers and variables.

On the first week, the tree was 27 1/2 inches (27.5) tall. On the second week, it was 29 1/4 inches (29.25) tall. On the third week, it was 31 1/3 inches (31.33) tall.

The length grown = 31.33 - 17.5 = 3.83 inches

The tree grew about 3.83 inches between the first and third week.

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The LCD of the given terms of expression will be x² - 4 since others can divide it.

The least common denominator is the smallest number or expression of all the common multiples of the denominators when 2 or more fractions or expressions are given.

Given the terms of the expressions

(x+2)(x-2) and (x^2 - 4)

Expand (x^2 - 4) using the difference of two square:

x² - 4 = x² - 2²

x² - 4 = (x+2)(x-2)

Based on the expansion, we can conclude that the LCD of the given terms of expression will be x² - 4

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Answer: 200 seconds

Okay - so then Oliver would take 3 minutes and 20 seconds. There are 60 seconds in a minute so it would be 30 times 60 = 180 + 20 = 200

Answer:

[tex]10 \frac{9}{25} [/tex]

Step-by-step explanation:

[tex] \bigg( \frac{3}{5} \bigg)^{2} + 4 \times 3 - 2 \\ \\ = \frac{9}{25} + 12 - 2 \\ \\ = \frac{9}{25} + 10 \\ \\ = \frac{9 + 10 \times 25}{25} \\ \\ = \frac{9 + 250}{25} \\ \\ = \frac{259}{25} \\ \\ = 10 \frac{9}{25} [/tex]

The outputs are addition of 4 to their inputs therefore,if the input is n then the output will also be an addition of 4 hence n+4

no. correct answer: 16(x)

using BODMAS rule:

Answer:

no they are not, explanation down.

Step-by-step explanation:

4(3x + x)

4(3×6 + 6)

4(18 + 6)

4(24)

96

12x

12×6

72

hope dis helps!!!!!

Answer:

the measure of 3 is 80 because its l is parlell to r so 80 will be vertical with 3

Step-by-step explanation:

Answer:

Zero, based on the information provided.

Step-by-step explanation:

The output rate of the teller machine is (1 transaction/6 minutes).  The input rate is (1 customer/10 minutes).  This means that the machine completes a cycle faster than the customers arrive, on the average.  I don't know how an average can be calculated without more information.  If we assume customers arrive every 10 minutes, and no one screws up the machine, that there should be no waiting line.   Is there more information about when the customers arrive?  E.g., 50 arrive in the first hour the machine is open.

If the average transaction at an automatic teller can be completed in six minutes and customers arrive at the average rate of one every ten minutes. The average number of customers in the queue is: B. 0.900 customers.

M represent Markovian (memoryless) arrivals and service times

1 represents a single server.

Arrival rate (λ) is 1 customer every 10 minutes and the service rate (μ) is 1 customer every 6 minutes.

The formula to determine the average number of customers in the queue (Lq) is:

Lq = (λ^2) / (μ * (μ - λ))

Plugging in the values:

λ = 1/10

μ = 1/6

Lq = ((1/10)^2) / ((1/6) * ((1/6) - (1/10)))

Lq = (1/100) / ((1/6) * (10 - 6)/60))

Lq = (1/100) / ((1/6) * (4/60))

Lq = (1/100) / ((1/6) * (1/15))

Lq = (1/100) / (1/90)

Lq = (1/100) * (90/1)

Lq = 90/100

Lq = 0.9

Therefore, the correct option is B.

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Answer:

706.5m^2

Step-by-step explanation:

The sign is a circle

Area of a circle is (pi)r^2

d = 30 in -> r = d/2  = 30/2 = 15

Area = 3.14 x (15)^2 = 706.5m^2

Answer:

about 706.5 or 706.86

Step-by-step explanation:

to find this answer we need to use the area formula of a circle which is A = πr ^2

we know the diameter is 30, and the radius is half the of diameter, so we take 30 and divide it by 2, which should give us 15 for the radius. ( 30/2 = 15, so r = 15)

depending on how your teacher wants u to answer this you can use π on a calculator or use 3.14

now just plug in your numbers to formula

A = 3.14 * 15^2 or A = π * 15^2

and should equal about 706.5 or 706.86 (depending on if you use 3.14 or π)

Answer:

Exact: [tex]4\sqrt{55}[/tex] m

Approximate: 29.7 m

Step-by-step explanation:

[tex]a^2+b^2=c^2[/tex]

[tex]9^2+b^2=(31\sqrt{5} )^2[/tex]

[tex]81+b^2=31^2(5)[/tex]

[tex]b^2=961-81[/tex]

[tex]b=\sqrt{880} =4\sqrt{55}[/tex]

[tex]4\sqrt{55}[/tex] ≈ 29.7 m

Hope this helps!

Using the z-distribution, as we have the standard deviation for the population, it is found that 215 students must be sampled.

The confidence interval is:

[tex]\overline{x} \pm z\frac{\sigma}{\sqrt{n}}[/tex]

In which:

The margin of error is:

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In this problem, we have a 95% confidence level, hence[tex]\alpha = 0.95[/tex], z is the value of Z that has a p-value of [tex]\frac{1+0.95}{2} = 0.975[/tex], so the critical value is z = 1.96.

The margin of error is of M = 0.25, with a population standard deviation of [tex]\sigma = 1.87[/tex], hence we solve for n to find the minimum sample size.

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

[tex]0.25 = 1.96\frac{1.87}{\sqrt{n}}[/tex]

[tex]0.25\sqrt{n} = 1.96(1.87)[/tex]

[tex]\sqrt{n} = \frac{1.96(1.87)}{0.25}[/tex]

[tex](\sqrt{n})^2 = \left(\frac{1.96(1.87)}{0.25}\right)^2[/tex]

[tex]n = 214.9[/tex]

Rounding up, 215 students must be sampled.

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Answer:

2.5

Step-by-step explanation:

Answer: 2.5

Step-by-step explanation: do it yourself jk lol first you add then divide by 6.5